(answer it or get reported) Solve it w the steps ty​

Explanation:

When the wire is connected to a battery, the compass needle moves and changes its position. This happens because the needle magnetizes the copper wire, thus,  creating a force.

While the current in the wire produces a magnetic field and exerts a force on the needle. The insulation on the wire becomes energized and exerts a force on the needle. Hence, the compass needle moves and changes its position.

Answer:

Actually, the substance is the one that changes from liquid to gas.

The molecule just gains energy which overcomes the attraction force between it and neighboring molecule.

Answer:

The 60 Ohm bulb would be brighter than the 20 Ohm bulb.

Explanation:

Hi there!

Ohm's Law: [tex]V=IR[/tex] where V is voltage, I is current and R is resistance

Power equation: [tex]P=VR[/tex]

The greater the power of a bulb, the brighter it is.

The bulbs are connected in series, meaning the the current travelling through each will be the same. Plug Ohm's law into the power equation so we just have I and R:

[tex]P=I^2R[/tex]

Because the current stays the same, the bulb with greater resistance will have greater power, hence being brighter. Therefore, the 60 Ohm bulb would be brighter than the 20 Ohm bulb.

I hope this helps!

Answer:

The 60 Ohm bulb would be brighter than the 20 Ohm bulb.

Explanation:

Hi there!

Ohm's Law: V=IRV=IR where V is voltage, I is current and R is resistance

Power equation: P=VRP=VR

The greater the power of a bulb, the brighter it is.

The bulbs are connected in series, meaning the the current travelling through each will be the same. Plug Ohm's law into the power equation so we just have I and R:

P=2RP=I

2

R

Because the current stays the same, the bulb with greater resistance will have greater power, hence being brighter. Therefore, the 60 Ohm bulb would be brighter than the 20 Ohm bulb.

I hope this helps!

Answer:

v = 34.128 km/hr

Explanation:

Given that,

The initial speed of a truck, u = 0

Acceleration of the truck, a = 0.3 m/s²

Distance moved, d = 150 m

Let the final speed of the truck is v. Using third equation of motion i.e.

[tex]v^2-u^2=2ad\\\\v=\sqrt{u^2+2ad}[/tex]

Put all the values,

[tex]v=\sqrt{0^2+2\times 0.3\times 150}\\\\v=9.48\ m/s[/tex]

or

v = 34.128 km/h

So, the final speed of the truck is equal to 34.128 km/h.

Answer:

Rmains constant

Explanation:

The equation of the trajectory of a projectile motion is presented as follows;

[tex]Y = x \cdot tan \theta -\dfrac{g \cdot x^2}{2 \cdot u^2 \cdot cos^2 \theta}[/tex]

The vertical componet of the prjectile motion is

y = (u·sinθ)·t - g·t²/2

Where;

θ = The angle with which the projectile is launched

x = The horizontal distance

u = The initial velocity of the projectile

g = The acceleration due to gravity = Constant

t = The time of motion

The acceleration acting on the projectile is the 'g' which is the constant acceleration due to gravity

Therefore, for general projectile motion with no air resistance, the vertical component of the projectile acceleration remains constant

Answer:

c) time

Explanation:

time is a fundamental quantity from which other quantities are derived

Answer:

Without the ability to measure, it would be difficult for scientists to conduct experiments or form theories. Not only is measurement important in science and the chemical industry, it is also essential in farming, engineering, construction, manufacturing, commerce, and numerous other occupations and activities.

Explanation:

Answer:

"1155 N" is the appropriate solution.

Explanation:

Given:

Acceleration,

[tex]a=3 \ m/s^2[/tex]

Forces resisting motion,

[tex]F_f=432 \ N[/tex]

Mass,

[tex]m = 241 \ kg[/tex]

By using Newton's second law, we get

⇒ [tex]F-F_f=ma[/tex]

Or,

⇒         [tex]F=ma+F_f[/tex]

By putting the values, we get

⇒             [tex]=(3\times 241)+432[/tex]

⇒             [tex]=723+432[/tex]

⇒             [tex]=1155 \ N[/tex]

Explanation:

apparent apparent weight is how hard astronaut pushes against it which is the normal force

n m a y + mgm open parenthesis y + and close parenthesis and = m open parenthesis a y + and so i need the acceleration of the astronaut since initial velocity is 0 and yby over l 45 m per second over 15 x 30.0 m m per second squared

Answer:

Explanation:

Use F - f = ma since we are on a flat surface. We are given the applied Force as 8.25, the frictional force as 2.19, and a mass of 2.50. Filling in:

8.25 - 2.19 = 2.50a. Doing the subtraction on the left gives us:

6.06 = 2.50a and we divide to 3 sig figs to get

a = 2.42 m/s/s

Answer:

Answer is letter B

Answer:  THE CORRECT ANSWER IS :  The partiles that make up material B are more closely packed together than the partiles that make up material A

Explanation:     I TOOK THE TEST    apex

Answer:

a)  3.0  10⁴ m / s, b) 3.7 10¹ m, c) 0.750 kg, d) 4 10¹² m²,  e)  75 m, f) 60 m²

g) 5.207 10³ m², e) 4.847 10⁷ s

Explanation:

The international system (SI) of measurements has as fundamental units the meter for length, the second for time and kilogram for mass.

Let's reduce the different magnitudes to the SI system

a) 30 km / h (1000m / 1 km) (1 h / 3600 s) = 3.0 10⁴ m / s

b) 37 Dm (10 m / 1 Dm) = 3.7 10¹ m

c) 750 g (1 kg / 10,000 g) = 0.750 kg

d) 4 10⁶ km² (1000 m / 1km) ² = 4 10¹² m²

e) 7500 cm (1 m / 100 cm) = 75 m

f) 600000 cm² (1m / 10² cm) ² = 60 m²

g) 520700000 mm³ (1 m / 10³ mm) ³ = 5.20700000 109/10 ^ 6

  = 5.207 10³ m²

e) 3.4 years (l65 days / 1 yr) (24 h / 1 day) (3600 s / 1h) = 4.847 10⁷ s

I = 7 N-s

Explanation:

Impulse is defined as

I = ∆p = m(vf - vi)

We are given

m = 0.2 kg

vi = -10 m/s (to the left)

vf = +25 m/s (to the right)

Therefore, the impulse imparted on the puck is

I = (0.2 kg)[25 m/s - (-10 m/s)]

= (0.2 kg)(35 m/s)

= 7 N-s

Answer:

A and C

Explanation:

Covalent bonding involves sharing by the atoms involved

Statements that can be considered as true statement about covalent bonding between two atoms are:

A. Electrons are shared.

B. The electronegativities of the two atoms are close to each other.

C. The two atoms can be of the same element.

Therefore, option A,B,C are correct.

Learn more at

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Answer:

non metals and non metals=covalent bond

metals and non metals =ionic bond

transfer all the valence electron to form ionic bond

share valence electron to form covalent bond

Answer: physical or mechanical weathering

Explanation:

Mechanical weathering which is also referred to as the physical weathering occurs when a rock is broken down into smaller pieces. In this case, there will be a physical change of the rock but its composition will not change.

Some examples include ice freezing and expansion of the cracks in the rock, Smstrong winds that carrycpieces of sand which then sandblast surfaces, moving water which causes abrasion etc.

Answer:

=>8x+9x+5+3

=>8x+9x+5+3=>17x+8

Answer:

t = 8.94 s

Explanation:

We will use the second equation of motion to calculate the time taken by the cart:

[tex]s = v_it + \frac{1}{2} at^2[/tex]

where,

s = distance = 200 m

vi = initial speed = 0 m/s

t = time taken = ?

a = acceleration = 5 m/s²

Therefore,

[tex]200\ m = (0\ m/s)(t)+\frac{1}{2}(5\ m/s^2)t^2\\\\t^2 = \frac{(200\ m)(2)}{5\ m/s^2}\\\\t = \sqrt{80\ s^s}[/tex]

t = 8.94 s

Answer:

Explanation:

The equation for acceleration is

[tex]a=\frac{v_f-v_0}{t}[/tex]. We have the initial velocity since we are told that the car started from rest. What we don't have is the final velocity. But we can find it because we were told that the car undergoes uniform acceleration, so the equation

d = rt will give us that final velocity.

120 = r(6.32) so the velocity or rate of the car is

r = 19 m/s. Plug that in to find the acceleration of the car:

[tex]a=\frac{19-0}{6.32}[/tex] so

a = 3.0 m/s/s

Answer:

See explanation

Explanation:

The ability of the Kangaroo to jump higher is due to the stretching of its tendons as its speed increases.

As the tendons are being stretched more and more, the elastic potential energy increases with each increasing stretch.

This elastic potential energy is translated into gravitational potential energy hence the Kangaroo jumps higher as it's speed increases.

The kangaroo can  jump higher as it's speed increases due to the ability of its tendons to stretch more and more.

The jumping of kangaroo can be related with the concept of spring force and spring potential energy. The spring force is given as,

F = kx

And spring elastic potential energy is,

[tex]U=\dfrac{1}{2}kx^{2}[/tex]

In both the cases, k is the spring constant and x is the stretching distance.

Thus, we can conclude that the kangaroo can  jump higher as it's speed increases due to the ability of its tendons to stretch more and more, such that more energy conversion of energy takes place.

Learn more about the elastic potential energy here:

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Answer:

Your answer is given below:

Explanation:

Answer:

I think C? I'm not sure totally though...

Explanation:

Answer:

The law of conservation of energy states that when one form of energy is transformed to another, no energy is destroyed in the process. According to the law of conservation of energy, energy cannot be created or destroyed. So the total amount of energy is the same before and after any transformation

Explanation:

The energy in a system always transforms from one form to another without any significant loss or addition. It simply changes from one form to another with the effect of numerous external influences.

Energy transformation may be defined as the process through which energy can convert from one form to another. It also illustrates the migration of energy from one place to another due to physical factors.

According to the law of conservation of energy, in a closed system energy can neither be created nor destroyed. The total amount of energy remains the same before and after the process of transformation.

Therefore, the energy in a system always transforms from one form to another without any significant loss or addition.

To learn more about Energy transformations, refer to the link:

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Answer:

h = 0.46 m

Explanation:

According to the law of conservation of energy:

Potential Energy Lost by Roller Coaster = Kinetic Energy Gained by Roller Coaster

[tex]mgh = \frac{1}{2}mv^2\\\\2gh = v^2\\\\h = \frac{v^2}{2g}[/tex]

where,

h = height = ?

v = speed at bottom = 3 m/s

g = acceleration due to gravity = 9.81 m/s²

Therefore,

[tex]h = \frac{(3\ m/s)^2}{(2)(9.81\ m/s^2)}[/tex]

h = 0.46 m

Answer:

b 60 N force

Explanation:

The change in the momentum is given by the force•distance from the attached point. We don't have any distance, but apparently, the stick forces are being applied in each quarter of the stick, so let's use fractions of 4 to solve it:

150 N:

150•1/4 = 37.5

30 N:

30•2/4 = 30•1/2 = 15

60 N:

60•3/4 = 45

40 N:

40•4/4 = 40•1 = 40

Answer:

v = 771.75 mile / h

Explanation:

The speed of sound is v = 343 m / s  at T= 20C

the transformation ratios are

     1 mile = 1600 m

     1 h = 3600 s

Let's reduce

    v = 343 m / s (1 mile / 1600 m) (3600 s / 1 h)

    v = 771.75 mile / h