Answer the question below in the picture. Thank you! Have a wonderful day.

(a) A man, a woman, a boy, and a girl can be selected in 312 ways.

(b) A man or a girl can be selected in 57 ways.

(c) One person can be selected in 25 ways.


(a) To select a man, a woman, a boy, and a girl, use the multiplication principle. There are 13 men, 6 women, 2 boys, and 4 girls, so the number of ways is 13 * 6 * 2 * 4 = 312 ways.

(b) To select a man or a girl, there are 13 men and 4 girls, so the number of ways is 13 + 4 = 17 ways.

(c) To select one person, there are a total of 13 men + 6 women + 2 boys + 4 girls = 25 people, so there are 25 ways to choose one person.

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The required answer is the solid D1 in spherical coordinates is defined by: - sqrt(3) ≤ ρ ≤ sqrt(7) - 0 ≤ θ ≤ π/2 - 0 ≤ φ ≤ π/2

To express the solid D1 in spherical coordinates, we need to first understand the given conditions and the equations of the spheres.

D1 is in the octant where x≥0, y≤0, and z≥0. The two spheres have the equations x^2+y^2+z^2=3 and x^2+y^2+z^2=7.

Now, let's convert these equations into spherical coordinates. Recall that the spherical coordinates (ρ, θ, φ) are related to the Cartesian coordinates (x, y, z) as follows:

x = ρ * sin(φ) * cos(θ)
y = ρ * sin(φ) * sin(θ)
z = ρ * cos(φ)

Since x^2+y^2+z^2=ρ^2, the given spheres can be represented in spherical coordinates as:

1. ρ^2 = 3, so ρ = sqrt(3)
2. ρ^2 = 7, so ρ = sqrt(7)
A spherical coordinate system is a coordinate system for three-dimensional space where the position of a point is specified by three numbers: the radial distance of that point from a fixed origin, its polar angle measured from a fixed zenith direction, and the azimuthal angle of its orthogonal projection on a reference plane that passes through the origin and is orthogonal to the zenith, measured from a fixed reference direction on that plane.

Now, we need to determine the range for θ and φ that corresponds to the specified octant. Since x≥0, y≤0, and z≥0, we have the following constraints on the angles:

- 0 ≤ θ ≤ π/2 (due to x≥0 and y≤0)
- 0 ≤ φ ≤ π/2 (due to z≥0)

So, the solid D1 in spherical coordinates is defined by:

- sqrt(3) ≤ ρ ≤ sqrt(7)
- 0 ≤ θ ≤ π/2
- 0 ≤ φ ≤ π/2

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Answer:

Nemani has paid $1250 for a TV on hire purchase. The cash price was $1250, so the total cost to Nemani was $1300. Nemani has paid $450 deposit and 12 monthly instalments of $95, for a total of $1445.

So, Nemani has paid an interest rate of 10% on his total payment.

The surface area of the cylinder given is approximately calculated as: 960.84 square meters.

The surface area of a cylinder can be found by adding the areas of its curved surface (lateral area) and its two circular bases.

If the cylinder has a radius of r and a height of h:

Surface Area = 2πr(h + r)

Given the following:

Radius (r) = 9 m

Height (h) = 8 m

π = 3.14

Substitute:

Surface area of the cylinder = 2 * 3.14 * 9(8 + 9)

= 56.52(17)

= 960.84 square meters.

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Let's consider the specific product of packaged food items, such as canned goods and dry goods, which are transported from a warehouse to a grocery store.

Distance: The distance between the warehouse and grocery store will affect the transportation cost. The farther the distance, the higher the freight rate will be.

Weight: The weight of the packaged food items will also impact the freight rate. The heavier the items, the higher the cost of transportation.

Density: The density of the packaged food items is a measure of how much space they occupy in relation to their weight. If the items are low in density, they may take up more space on a truck, and therefore, the freight rate will be higher.

Stowability: The stowability of the packaged food items refers to how easy they are to store and stack on a truck. If the items are difficult to stack, more space may be required, and the freight rate will be higher.

Handling: The handling of the packaged food items is also a factor in determining the freight rate. If the items require special handling, such as refrigeration or careful stacking, the freight rate will be higher.

Liability: Liability refers to the risk of damage or loss of the packaged food items during transportation. If the items are fragile or perishable, the freight rate will be higher to cover the higher risk of damage or loss.

Market: The market conditions, such as supply and demand, will also influence the freight rate. If there is a high demand for transportation services or a shortage of trucks, the freight rate will be higher.

Overall, the freight rate for transporting packaged food items will depend on multiple factors, including distance, weight, density, stowability, handling, liability, and market conditions. Transport companies will consider all of these factors when determining the freight rate for a particular shipment.

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Answer:

-7+0.75n

I would give an explanation but im bad at explaining

The quadratic function with the given features is defined as follows:

y = 0.86x² - 5.86x + 5.

The standard definition of a quadratic function is given as follows:

y = ax² + bx + c.

When x = 0, y = 5, hence the coefficient c is given as follows:

c = 5.

Hence:

y = ax² + bx + 5.

When x = 1, y = 0, hence:

a + b + 5 = 0

a + b = -5.

The discriminant is given as follows:

D = b² - 4ac.

Hence:

D = b² - 20a

The minimum value is of -4, hence:

-D/4a = -5

(b² - 20a)/4a = -5

b² - 20a = 20a

b² = 40a

Since a = -5 - b, we have that the value of b is obtained as follows:

b² = 40(-5 - b)

b² + 40b + 200 = 0.

b = -5.86.

Hence the value of a is of:

a = -5 + 5.86

a = 0.86.

Then the equation is:

y = 0.86x² - 5.86x + 5.

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The characteristic equation for the differential equation y′′ − y = 0 is r^2 - 1 = 0. This has roots r = ±1. Therefore, the general solution to the differential equation is y(t) = c1 e^t + c2 e^(-t).

Using the initial conditions, we can solve for the values of c1 and c2:

y(0) = 5/4 = c1 + c2

y'(0) = -3/4 = c1 - c2

Solving these equations simultaneously, we get c1 = 1/2 and c2 = 3/4. Therefore, the solution to the initial value problem is:

y(t) = 1/2 e^t + 3/4 e^(-t)

To find the minimum value of the solution, we can take the derivative of y(t) and set it equal to 0:

y'(t) = 1/2 e^t - 3/4 e^(-t)

y'(t) = 0 when e^t = (3/2) e^(-t)

e^(2t) = 3/2

t = ln(sqrt(3/2))

Substituting this value of t back into the original equation, we get the minimum value of the solution:

y(ln(sqrt(3/2))) = 1/2 e^(ln(sqrt(3/2))) + 3/4 e^(-ln(sqrt(3/2)))

y(ln(sqrt(3/2))) = sqrt(3)/4 + 3/(4sqrt(3))

y(ln(sqrt(3/2))) = (4sqrt(3) + 3)/(4sqrt(3))

Therefore, the minimum value of the solution is (4sqrt(3) + 3)/(4sqrt(3)) which is approximately 1.068.

To plot the solution for 0 ≤ t ≤ 2, we can use a graphing calculator or software to graph y(t) = 1/2 e^t + 3/4 e^(-t) and then set the viewing window to show the interval [0, 2].

True, The One Way Repeated Measures ANOVA is used when you have a quantitative DV and an IV with three or more levels that is within subjects in nature.

The statement is true and explained as follows:

The One Way Repeated Measures ANOVA is a statistical technique that is used to analyze data from experiments where the same participants are exposed to multiple levels of an independent variable (IV). This type of experimental design is known as a within-subjects design, as opposed to a between-subjects design, where different participants are used for each level of the IV.

One of the main advantages of using a within-subjects design is that it allows for more efficient use of participants. By exposing each participant to all levels of the IV, the variability between participants is reduced, which in turn increases the power of the statistical analysis.

The One Way Repeated Measures ANOVA is specifically used when the dependent variable (DV) is quantitative, meaning that it can be measured using numerical values. Additionally, the IV must have three or more levels, meaning that there are at least three different conditions that participants are exposed to.

The basic idea behind the One Way Repeated Measures ANOVA is to compare the mean scores of the DV across the different levels of the IV while taking into account the fact that the same participants are being used for each level. This is done by calculating the within-subjects variability, which is the variability in the scores of the DV that is due to individual differences between participants. The within-subjects variability is then compared to the between-subjects variability, which is the variability in the scores of the DV that is due to the different levels of the IV.

The statistical output from the One Way Repeated Measures ANOVA includes an F-test, which compares the within-subjects variability to the between-subjects variability. If the F-test is statistically significant, this indicates that there is a significant difference between at least two of the levels of the IV.

In conclusion, the One Way Repeated Measures ANOVA is a useful statistical technique for analyzing data from within-subjects experiments with a quantitative DV and an IV with three or more levels. By taking into account the fact that the same participants are used for each level, the One Way Repeated Measures ANOVA can provide a more efficient and powerful analysis of experimental data.

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Therefore, the student reads 2,436 pages on Thursday by the given equation.

According to the given information, the student reads three times as many pages on Thursday as on Wednesday. Let's say that the number of pages read on Wednesday is represented by the variable w. Then, we can write the equation:

Pages on Thursday = 3 * Pages on Wednesday

In this equation, we know that Pages on Wednesday = w. So we can substitute w into the equation and get:

Pages on Thursday = 3w

We are also given that on Wednesday, the student read 812 pages. So we can substitute 812 for w and get:

Pages on Thursday = 3 * 812

Simplifying, we get:

Pages on Thursday = 2,436

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Given

1.  y'-y = x

2. y' = sqrt(x+y+1) -1

Solution

To solve the differential equation y' - y = x, we can use the method of integrating factors.First, we must rewrite the equation as follows:

y' - y = f(x)

where f(x) = x. Then, we can multiply both sides by the integrating factor e^(-x):

e^(-x) y' - e^(-x) y = xe^(-x)

The product rule can be used to rewrite the left side:

(e^(-x) y)' = xe^(-x)

When we integrate both sides in relation to x, we get:

e^(-x) y = ∫xe^(-x) dx + C

where C is the constant of integration. The integral on the right-hand side can be evaluated using integration by parts:

∫xe^(-x) dx = -xe^(-x) - ∫e^(-x) dx = -xe^(-x) - e^(-x) + D

where D is another constant of integration. As a result, the differential equation's solution is:

y = e^x (∫xe^(-x) dx + C) + De^x

Substituting the integral back in, we get:

y = x - 1 + Ce^x + De^x

where C and D are constants.

To solve the differential equation y' = sqrt(x+y+1) -1, we can use separation of variables. First, we can add 1 to both sides of the equation:

y' + 1 = sqrt(x+y+1)

Then, we can square both sides:

(y' + 1)^2 = x+y+1

Expanding the left-hand side and simplifying, we get:

y'^2 + 2y' + 1 = x+y+1

Rearranging the terms, we get:

y'^2 + 2y' - y = x

This is a nonlinear first-order differential equation, which cannot be solved using separation of variables or integrating factors. However, we can recognize it as a Bernoulli equation, which can be transformed into a linear differential equation by making the substitution:

u = y' - 1

Then, we have:

y' = u + 1

y'' = u''

We get by substituting these expressions into the original equation and simplifying:

(u+1)^2 - (u+1) - y = x

u^2 + u - y - x = 0

This is a quadratic equation in u, which can be solved using the quadratic formula:

u = (-1 ± sqrt(1 + 4y + 4x))/2

Substituting back the expression for u, we get:

y' = (-1 ± sqrt(1 + 4y + 4x))/2 + 1

y' = (-1 ± sqrt(1 + 4y + 4x))/2 + 2/2

y' = (-1 ± sqrt(1 + 4y + 4x) + 2)/2

y' = (sqrt(1 + 4y + 4x) - 1)/2

This is the solution to the differential equation.

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The equation is separable. The solution to the initial value problem is y(t) = e^(4 * e^t) , therefore option A is correct.

To determine whether the given equation is separable and solve the initial value problem:

We will follow these steps:

STEP 1: Identify the given differential equation: y'(t) = 4y * e^t
STEP 2: Rewrite the equation in terms of dy/dt: dy/dt = 4y * e^t
STEP 3:Rearrange the terms to separate variables: (1/y) dy = 4 * e^t dt
STEP 4:Integrate both sides: ∫(1/y) dy = ∫4 * e^t dt
STEP 5:Evaluate the integrals: ln|y| = 4 * e^t + C1 (we can drop the absolute value since y > 0)
STEP 6:Solve for y: y = e^(4 * e^t + C1)
STEP 7:Apply the initial condition y(0) = 1: 1 = e^(4 * e^0 + C1)
STEP 8:Solve for C1: C1 = 0
STEP 9:Substitute C1 back into the solution: y(t) = e^(4 * e^t)

The equation is separable. The solution to the initial value problem is y(t) = e^(4 * e^t) (Type an exact answer in terms of e).

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The value of ℒ{e−3t} is 1 / (s + 3).

Explanation: -

Given the Laplace transform of e^(-3t), you need to fill in the blank with the answer in terms of 's'.

The Laplace transform of e^(-at) is given by the formula:

ℒ{e^(-at)} = 1 / (s + a)

In your case, a = 3. Now, we can substitute this value into the formula:

ℒ{e^(-3t)} = 1 / (s + 3)

This function has a pole at s = 3, which means it is undefined at that point. However, for all other values of s, the Laplace transform is well-defined and can be used to solve differential equations that involve e^(-3t).

It's important to note that the Laplace transform is a powerful tool for solving differential equations, but it is not always necessary or convenient to use.

In some cases, it may be more efficient to solve the differential equation directly using other methods. However, when the Laplace transform is applicable, it can greatly simplify the solution process and provide valuable insights into the behavior of the system.

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The answer of the given question based on differential equation is ,

y² = (3/13)(C - x⁴)

An equation is mathematical statement that indicates  equality of two expressions. It consists of variables, constants, and mathematical operations like addition, subtraction, multiplication, division, exponentiation, etc. An equation can be written in different forms depending on the type of equation, like linear, quadratic, polynomial, trigonometric, exponential, or logarithmic.

The given differential equation is:

dy/dx = 4x³/(3x² + 13y²)

To find  general solution, we need to separate variables and integrate both sides:

(3x² + 13y²) dy = 4x³ dx

Integrating both sides:

∫(3x² + 13y²) dy = ∫4x³ dx

Simplifying and solving the integrals:

x⁴ + (13/3)y³ = x⁴ + C

where C is the constant of integration.

Therefore, the general solution to the given differential equation is:

y² = (3/13)(C - x⁴)

where C is an arbitrary constant.

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Based on her results, the statement that describes the relationship between m, the speed of the car in miles per hour, and k, the speed of the car in kilometers per hour is A.. The relationship is proportional because the ratio of m to k is constant.

To ascertain whether the relationship is indeed proportional, we shall evaluate if the ratio of m to k remains consistent.

For each specified speed:

m = 11.0 mph, k = 17.699 kph

Ratio = 11.0 / 17.699 ≈ 0.621

m = 26.0 mph, k = 41.834 kph

Relation = 26.0 / 41.834 ≈ 0.622

m = 34.0 mph, k = 54.706 kph

Relation = 34.0 / 54.706 ≈ 0.621

The ratios - which are almost identical (0.621, 0.622, and 0.621) - lead us to believe that the correlation between m and k is a proportional one.

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The slope for this linear relationship is -2, and it means that the amount of bait decreases by 2 pieces each hour in this situation.

The slope for this linear relationship is -2, which means that the amount of bait in the bucket decreases by 2 pieces for every hour of fishing. This slope indicates a constant rate of change in the amount of bait over time.

To understand this further, we can interpret the slope as the rate of consumption of bait per hour. Since the fisherman uses 2 pieces of bait every hour, the amount of bait in the bucket decreases by 2 pieces every hour. This linear relationship can be represented by the equation:

y = -2x + 20

where y is the amount of bait remaining in the bucket after x hours of fishing.

Therefore, the slope of -2 in this context is an important characteristic of the linear relationship between the amount of bait remaining and the time spent fishing. It tells us the rate at which the bait is being consumed, and helps the fisherman predict how much bait he will have left after a certain amount of time.

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Answer:

12 feet × 10 feet

Step-by-step explanation:

12 feet × 10 feet is the size of a modest bedroom.

60in × 36in is only 5×3 feet, more like a closet.

20×18m is around 60×54feet something like a whole studio apartment or 1-bedroom apartment.

100×80cm is like 3 feet by lessthan 3 feet like a doormat size or maybe a coat closet.

Answer:

Cost of item = $2500 + $200

Cost of item = $2700

Step-by-step explanation:

0_0

Step-by-step explanation:

To show that the system is uneconomical if four deliveries are made in a day, we need to find the profit (Y) for x machines and 4 deliveries:

Y = 12x - 2a - a (for 4 deliveries)

Y = 12x - 3a

We know that processing all deliveries must be done in a single day, so we have:

a = 4x

Substituting this into the profit formula, we get:

Y = 12x - 3(4x)

Y = 0

This means that the profit (Y) is zero when four deliveries are made in a day, making the system uneconomical.

To find the number of machines that would be used in order for profit to be maximized for four deliveries in a day, we need to differentiate the profit formula with respect to x and set it equal to zero to find the maximum:

dY/dx = 12 - 6a = 0 (for a = 4x)

Solving for x, we get:

12 - 6(4x) = 0

12 - 24x = 0

x = 1/2

Therefore, the maximum profit would be obtained by using 1/2 of a machine (which is not physically possible, so we would round up to one machine) for processing four deliveries in a day.

The solutions are given below.

1) Variables:

- Speed of the kayaker (unknown, let's call it x)

- Speed of the current = 3 mph (given)

- Distance kayaked one way = 1 mile (given)

- Total distance covered (round trip) = 2 miles (given)

- Total time of the trip = 3 hours 20 minutes = 3.33 hours (converted to hours for convenience)

Table:

Photo attached.

2) The equation to model the problem is:

distance = rate × time

Using this equation for each kayaking portion, we get:

1 = (x - 3) t

1 = (x + 3) t

We also know that the total time of the trip is 3.33 hours:

t + t = 3.33

2t = 3.33

t = 1.665

3) Now we can solve for x by substituting t = 1.665 in either of the above equations:

1 = (x - 3) (1.665)

x - 3 = 0.599

x = 3.599

Thus, the kayakers are paddling at a speed of 3.599 miles per hour.

4) The kayakers are paddling at a speed of 3.599 miles per hour. This solution is obtained by calculating the average speed of the kayakers over the entire trip, taking into account the opposing speed of the river current. The kayakers are traveling faster downstream (with the current) than upstream (against the current).

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A is invertible if and only if both B and C are invertible.

To prove the converse statement, we need to show that if both B and C are invertible, then A is also invertible.

Assume that B and C are invertible. We need to find the inverse of A.

Let D = BC. Since B and C are invertible, D is also invertible. Moreover, we have:

A = [D 0; 0 I]

where 0 is a square matrix of the same size as B and I is the identity matrix of the same size as C.

To find the inverse of A, we need to find a matrix A-1 such that:

AA-1 = A-1A = I

Let:

A-1 = [E F; G H]

where E, F, G, and H are matrices of appropriate sizes.

Then we have:

AA-1 = [D 0; 0 I][E F; G H] = [DE GF; DG+HI]

and

A-1A = [E F; G H][D 0; 0 I] = [ED FG; GH+I]

Setting these equal to I and equating corresponding entries, we get:

DE = ED = I (since D is invertible)

GF = 0

DG + HI = 0

ED = DE = I (since D is invertible)

FG = 0

GH + I = 0

From the first equation, we have E = D-1. From the second equation, we have F = 0. From the third equation, we have G = -D-1H. Substituting these values into the fourth and sixth equations, we get:

-HD-1H + I = 0

which implies that HD-1H = D-1.

Since D = BC and both B and C are invertible, we have D-1 = C-1B-1. Substituting this into the above equation, we get:

HC-1B-1H = I

which implies that H(BH)-1(C-1H)-1 = I. Since B and C are invertible, BH and C-1H are also invertible. Therefore, H is invertible and we have:

A-1 = [D-1 0; -D-1HC-1B-1 D-1]

Thus, A is invertible if and only if both B and C are invertible.

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The major problem in the passage is that it assumes the existence of a smallest element in the set A, which is not true for all non-empty subsets of the real numbers .a real number is a number that can be used to measure a continuous one-dimensional quantity such as a distance, duration or temperature. Here, continuous means that pairs of values can have arbitrarily small differences. Every real number can be almost uniquely represented by an infinite decimal expansion.

The real numbers are fundamental in calculus (and more generally in all mathematics), in particular by their role in the classical definitions of limits, continuity and derivatives. Real intervals play an important role in the theory of integration, because they are the simplest sets whose "length" (or "measure" or "size") is easy to define. The concept of measure can then be extended to more complicated sets of real numbers, leading to the Borel measure and eventually to the Lebesgue measure.

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Answer:

B

Step-by-step explanation:

If a figure is enlarged by a scale factor of 1, the new figure will have the same size and shape as the original figure.

If a figure is enlarged by a negative scale factor, the new figure will be on the other side of the centre of enlargement and will be inverted (the figure appears upside down).

Therefore, if you enlarge shape X by a scale factor of -1, it will have the same size and shape as shape X, but it will be upside down.

Further information

A is a reflection across a vertical line.

C is a reflection across a horizontal line.

D is a rotation of 90° clockwise.

E is a rotation of 90° anticlockwise.

F is an enlargement of scale factor 1.

Okay, let's solve this step-by-step:

* Points J, K, L, M have polar coordinates:

J (6, 130°)

K (6, 160°)

L (6, 200°)

M (6, 250°)

* To find the angle between two points, we subtract their theta values (polar angle coordinates).

* Angle KJM = 160° - 130° = 30°

* Angle KLM = 250° - 200° = 50°

* Sum of angles KJM and KLM = 30° + 50° = 80°

* Since the sum of angles in any triangle is 180°, and we have 80°, the remaining angle must be 180° - 80° = 100°.

* Therefore, the sum of angles KJM and KLM is 180°.

Does this make sense? Let me know if you have any other questions!

The area under the given standard normal curve is approximately 0.1463

To find the area under the standard normal curve to the left of z=-1.51 and to the right of z=1.4, follow these steps:

1. Look up the z-scores in the standard normal table (also known as the z-table).
2. Find the area associated with z=-1.51 and z=1.4.
3. Add the areas together.

Using the z-table:
- For z=-1.51, the area to the left is 0.0655.
- For z=1.4, the area to the right is 1 - 0.9192 = 0.0808.

Now, add the areas together:
0.0655 + 0.0808 = 0.1463

So, the area under the standard normal curve to the left of z=-1.51 and to the right of z=1.4 is approximately 0.1463, rounded to four decimal places.

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The quantity of ounces for each bag would be as follows:

walnut= 8.82

almonds = 4.29 and

cashew = 11.89 ounces.

The quantity of walnut used = 21 ounces

The quantity of almonds used = 10.2 ounces

The quantity of cashew used = 28.3 ounces

Total = 59.5ounces.

The total ounces makes up = 25 bags

The ounce of each bag;

walnut = 21/59.5×25/1

= 8.82

almonds= 10.2/59.5 × 25/1

= 4.29

cashew = 28.3/59.5 × 25/1

= 11.89

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The x and y components of acceleration are:-  [tex]ax = (1/k)(c(dy^2/dt^2)),- ay = c(d^2y/dt^2)[/tex]

To find the x-component of acceleration, we need to take the second derivative of the position function with respect to time:

2 = 4kx
2v = 4kx'  (taking the derivative with respect to time)
2a = 4kx''  (taking the derivative of v with respect to time)

So the x-component of acceleration is a_x = 2kx''.

To find the y-component of acceleration, we can use the given information about the velocity along the y-axis:

v_y = 1y ct

Taking the derivative with respect to time, we get:

a_y = c

So the y-component of acceleration is simply a_y = c.
To determine the x and y components of acceleration for the given path of a particle and the component of velocity along the y-axis, we'll use the given equations and find the second derivatives with respect to time.

The path of the particle is defined by [tex]y^2[/tex] = 4kx. First, differentiate this equation with respect to time (t) to find the relation between the x and y components of velocity:

(1) 2y(dy/dt) = 4k(dx/dt)

The component of velocity along the y-axis is given as vy = dy/dt = cy. Substituting this into equation (1):

(2) 2y(cy) = 4k(dx/dt)

Now, solve for dx/dt (vx):

[tex]vx = (1/k)(cy^2/2)[/tex]

Next, differentiate both vx and vy with respect to time to find the x and y components of acceleration:

[tex]ax = d^2x/dt^2 = (1/k)(c(dy^2/dt^2))[/tex]
[tex]ay = d^2y/dt^2 = c(d^2y/dt^2)[/tex]

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The value of x , given the angle and the lines drawn , would be 142 degrees .

The fact that a straight line was drawn such that x degrees and 38 degrees make up the angles of that line , means that the total angular measure would be 180 degrees because this is the angle of a straight line.

This therefore means that to find the value of x, the formula would be :

x = 180 - 38

x  = 180 - 38

x = 142 degrees

In conclusion, the value of x would be 142 degrees.

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Answer:

SOLUTION

EQUATION

DIVIDE

VOTE

F