At its maximum speed, a typical snail moves about 4.0 m in 5.0 min.

What is the average speed of the snail?

Answers

Answer 1

Answer:

Explanation:

Given

Distance = 4.0m

Time = 5.0 mins = 300secs

Required

Average speed

Average speed = Distance/Time

Average speed = 4.0/300

Average speed = 0.01333m/secs

Hence the average speed of the snail is 0.01333m/s


Related Questions

What is the magnitude of the change in potential energy of the block-spring system when it travels from its lowest vertical position to its highest vertical position?

Answers

Answer:

 ΔU = 2 mg h

Explanation:

In a spring mass system the potential energy is U = m g h

where h is measured from the equilibrium point of the spring

the potential energy at the highest point is

         U₁ = m g h

the potential energy at the lowest point is

         U₂ = m g (-h)

instead in this energy it is

          ΔU = 2 mg h

In this two points the kinetic energy is zero, but there is elastic potential energy that has the same value in the two points, so its change is zero

Potential energy is defined as the energy stored in a body which may convert into kinetic energy when moved.

The Formule of the potential energy is [tex]mgh[/tex] The correct answer is 0

Hence, [tex]U = 2 mg h[/tex]

 The H stated as the measured from the equilibrium point of the spring

Therefore, the potential energy at the maximum point is  [tex]U_1 = m g h[/tex]  and the potential energy at the minimum point is    [tex]U_2 = m g (-h)[/tex]

Hence, after solving it we got

         [tex]U_1 -U_2 = 2 mg h[/tex]

Therefore, the energy change in the process is 0.

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. A car going initially with a velocity 15 m/s accelerates at a rate of 2 m/s2 for 10 seconds. It then accelerates at a rate of -1.5 m/s until stop. Find the car’s maximum speed. Calculate the total distance traveled by the car.

Answers

Answer:

The maximum speed of the car is 35 m/s

The total distance traveled by the car is 658.33 m

Explanation:

Given;

initial velocity of the car, u = 15 m/s

acceleration of the car, a = 2 m/s²

time of car motion, t = 10 s

(i)

Initial distance traveled by the car is given by;

d₁ = ut + ¹/₂at²

d₁ = (15 x 10) + ¹/₂(2)(10)²

d₁ = 150 + 100

d₁ = 250 m

The maximum speed of the car during this is given by;

v² = u² + 2ad₁

v² = (15)² + (2 x 2 x 250)

v² = 1225

v = √1225

v = 35 m/s

(ii)

The final distance cover by the car during the deceleration of 1.5 m/s².

Note: the final or maximum speed of the car becomes the initial velocity during deceleration.

v² = u² + 2ad₂

where;

v is the final speed of the car when it stops = 0

0 = u² + 2ad₂

0 = (35²) + (2 x - 1.5 x d₂)

0 = 1225 - 3d₂

3d₂ = 1225

d₂ = 1225 / 3

d₂ = 408.33 m

The total distance traveled by the car is given by;

d = d₁ + d₂

d = 250 m + 408.33 m

d = 658.33 m

Three moles of a monatomic ideal gas are heated at a constant volume of 1.20 m3. The amount of heat added is 5.22x10^3 J.(a) What is the change in the temperature of the gas?________ ? K(b) Find the change in its internal energy.________ ? J(c) Determine the change in pressure.________ ? Pa

Answers

Answer:

A) 140 k

b ) 5.22 *10^3 J

c) 2910 Pa

Explanation:

Volume of Monatomic ideal gas = 1.20 m^3

heat added ( Q ) = 5.22*10^3 J

number of moles  (n)  = 3

A ) calculate the change in temp of the gas

since the volume of gas is constant no work is said to be done

heat capacity of an Ideal monoatomic gas ( Q ) = n.(3/2).RΔT

make ΔT subject of the equation

ΔT = Q / n.(3/2).R

    = (5.22*10^3 ) / 3( 3/2 ) * (8.3144 J/mol.k )

    = 140 K

B) Calculate the change in its internal energy

ΔU = Q  this is because no work is done

therefore the change in internal energy = 5.22 * 10^3 J

C ) calculate the change in pressure

applying ideal gas equation

P = nRT/V

therefore ; Δ P = ( n*R*ΔT/V )

                        = ( 3 * 8.3144 * 140 ) / 1.20

                        = 2910 Pa

A) The change in the temperature of the gas is; ΔT = 139.5 K

B) The change in internal energy of the gas is; ΔU = 5.22 × 10³ J

C) The change in pressure of the gas is; ΔP = 2899.5 Pa

We are given;

Volume of Monatomic ideal gas; V = 1.2 m³

Amount of heat added; Q = 5.22 × 10³ J

number of moles; n = 3

A) To calculate the change in temperature of the monatomic idea gas, we will use formula;

Q = ³/₂nRΔT

Where R is a constant = 8.314 J/mol.K

ΔT is the change in temperature

Making ΔT the subject of the formula;

ΔT = ²/₃(Q/(nR))

ΔT = ²/₃(5.22 × 10³)/(3 × 8.314)

ΔT = 139.5 K

B) Due to the fact that no work was done, then from first law of thermodynamics, we can say that;  

ΔU = Q

Thus;

change in internal energy; ΔU = 5.22 × 10³ J

C) The change in pressure will be calculated from the formula;

ΔP = (n*R*ΔT)/V

ΔP = (3 * 8.314 * 139.5)/1.2

ΔP = 2899.5 Pa

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Suppose you put an ice cube into a cup of hot tea. In what direction does energy in the form of heat flow? What happens to the ice cube as this flow of energy occurs?

Answers

Answer:

The energy flows between the ice and the tea equally. The table below shows the temperatures of several different objects made of the same material.

You are hanging on to the edge of a merry-go-round, and must exert a force of 100 N to hang on. If the speed of the merry-go-round doubles, how much force will you need to exert to hang on?

Answers

Answer:

If the speed of the merry-go-round doubles, the force you will need to exert to hang on is 400 N.

Explanation:

Given;

initial force exerted to hang on, F₁ = 100 N

The force exerted on the merry-go-round in order to hang on must be an inward force known as centripetal force.

Centripetal force is given by;

[tex]F_c = \frac{mv^2}{r} \\\\keeping \ "m" \ and \ "r" \ constant, we \ will \ have \ the \ following \ equation;\\\\\frac{F_c_1}{v_1^2} = \frac{F_c_2}{v_2^2} \\\\F_c_2 = \frac{F_c_1*v_2^2}{v_1^2}\\\\when \ the \ speed\ doubles \ i.e, v_2 = 2v_1\\\\ F_c_2 = \frac{F_c_1*(2v_1)^2}{v_1^2}\\\\ F_c_2 = \frac{F_c_1*4v_1^2}{v_1^2}\\\\F_c_2 = F_c_1 *4\\\\F_c_2 = 4(F_c_1)\\\\F_c_2 = 4 (100 \ N)\\\\F_c_2 = 400 \ N[/tex]

Therefore, If the speed of the merry-go-round doubles, the force you will need to exert to hang on is 400 N.

Calculate the gravitational potential energies of the melon and the pomegranate. Which one has potential energy

Answers

Answer:

The mellon

Explanation:

I just know

A step-down transformer converts 120 V to 5 V in a phone charger. If the primary coil has 600 turns, how many turns are in the secondary coil? Show all work with correct answer and unit as well.

Answers

Answer:

25 turns

Explanation:

Given the following data;

Input voltage = 120V

Output voltage = 5V

Number of turns in primary coil = 600 turns

[tex] \frac {Ns}{Np} = \frac {Vs}{Vp} [/tex]

Where;

Ns is the number of turns on the secondary coil. Np is the number of turns on the primary coil. Vs is the voltage across the secondary coil (output voltage). Vp is the voltage across the primary coil (input voltage).

Substituting into the equation, we have;

[tex] \frac {Ns}{600} = \frac {5}{120} [/tex]  

Cross-multiplying, we have;

[tex] 120*Ns = 600*5[/tex]

[tex] 120Ns = 3000[/tex]

[tex] Ns = \frac {3000}{120}[/tex]

Ns = 25 turns

Therefore, the number of turns in the secondary coil is 25 turns.

Hence, it is a step-down transformer because the number of turns on the primary coil is greater than the number of turns on the secondary coil. Consequently, the output voltage (5V) will be lesser than the input voltage (120V).

When the current through a circular loop is 6.0 A, the magnetic field at its center is 2.0 * 10-4 T. What is the radius of the loop?

Answers

Answer:

ill get back to this question once i get the answer

The radius of the loop is 13 cm

To find the radius of the loop, the values are given as,

Current I = 6A

Magnetic field, B = 2* 10⁻⁴ T

How to find the radius of the loop?

     The magnetic field in a circular loop will have same magnitude and direction. The current carrying loops will be formed due to the magnetic field and there will be n times of loops adds up for every turns.

Formula for magnetic field in the circular loop is,

                   B = µ₀ I 2R Tesla

Here, we have to find the radius of the loop,

                    R = B / µ₀ I × 2

µ₀ = 4π × 10-7 H/m.

Substituting all the values in the equation,

                   R = ( 2 × 10⁻⁴ ) / ( 4π × 10-7 × 6 × 2)

                      = ( 2 × 10⁻⁴ ) / ( 0.0000150796)

    Radius, R  = 13 cm

Thus, the radius of the loop is 13 cm.

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In principle, when you fire a rifle, the recoil should push you backward. How big a push will it give? Let's find out by doing a calculation in a very artificial situation. Suppose a man standing on frictionless ice fires a rifle horizontally. The mass of the man together with the rifle is 70 kg, and the mass of the bullet is 10 g. If the bullet leaves the muzzle at a speed of 500 m/s, what is the final speed of the man?

Answers

Answer:

Explanation:

m1v1=m2v2

m1=70 kg

m2=10 g=0.01 kg

v2=500 m/s

m1v1=m2v2

v1=m2v2/m1

v1=0.01*500/70

v1=0.07

What does fitness means to you

Answers

Answer:

Exercising, yoga

Explanation:

Exercising and staying fit

Is Natural Gas nonrenewable or renewable? Why? Use in your own words.

Answers

Answer:

Natural gas is non renewable energy.

Explanation:

Because they were formed from the buried reamains of plants and animals that live a million years ago. It is formed from fossil fuels.

A bug crawls 2.25 m along the base of a wall. Upon reaching a corner, the bugs direction of travel changes from south to west. THe bug that crawls 3.15 m before stopping. What is the magnitude of the bugs displacment?A) 5.40 m.B) 2.72m.C) 3.45 m.D) 3.87 in.E) 4.29 m.

Answers

Answer:

The magnitude of the bugs displacement is 3.87 m

Explanation:

An illustrative diagram for the scenario is given in the attachment below.

In the diagram, the bug's displacement is given by x. The diagram shows a right angle triangle with x as the hypotenuse. We can determine x from the Pythagorean theorem which states that " the square of the hypotenuse equals sum of squares of the other two sides". That is

x² = 2.25² + 3.15²

x² = 5.0625 + 9.9225

x² = 14.985

x = √14.985

x = 3.87 m

Hence, the magnitude of the bugs displacement is 3.87 m.

A swinging door that weighs w=400.0Nw=400.0N is supported by hinges A and B so that the door can swing about a vertical axis passing through the hinges The door has a width of b=1.00m,b=1.00m, and the door slab has a uniform mass density. The hinges are placed symmetrically at the door’s edge in such a way that the door’s weight is evenly distributed between them. The hinges are separated by distance a=2.00m.a=2.00m. Find the forces on the hinges when the door rests half-open.

Answers

Answer:

SO I TESTED POSITIVE FOR CORONA IS A SIMPTOM DIEURREUH C SINCE I GOT CORNA I HAVE BEEN HAVE big DIEURREE UH

Explanation:

Define Hydrostatic Equilibrium

Answers

Answer:

well, in my view,

In fluid mechanics, hydrostatic equilibrium or hydrostatic balance (also known as hydrostasy) is the condition of a fluid or plastic solid at rest. This occurs when external forces such as gravity are balanced by a pressure-gradient force.

Assume a hockey player accelerates from 0 ft/s to 24 ft/s over a period of 2
seconds. What is his acceleration if his direction does not change? Explain in
words what this acceleration means.

Answers

Answer:

12ft/s or 4m/s

Explanation:

David Wetterman drops a 5 kg watermelon from the top of a 30 m building. What is the velocity of the watermelon as it smashes
into the ground (neglecting air resistance)?
-(1)
A)
24.25 m/s
B)
32.45 m/s
C)
60 m/s
D)
588 m/s

Answers

Answer:

A. 24.25 m/s

Explanation:

velocity = [tex]\sqrt{2 * g * d}[/tex]

velocity = sqr 2 * 9.8 * 30 = sqr 588 = 24.25 m/s

The velocity of the watermelon as it smashes into the ground will be 24.2 m/s

State the third equation of motion?

The third equation of motion is -

v² - u² = 2aS

Given David Wetterman drops a 5 kg watermelon from the top of a 30 m building.

Height of building [S] = 30 m

Mass of watermelon [M] = 5 Kg

Initial velocity [v] = 0 m/s

acceleration [g] = 9.8 m/s²

Using the third equation of motion -

v² - u² = 2aS

v² = 2aS

v² = 2 x 9.8 x 30

v² = 588

v = 24.2 m/s

Therefore, the velocity of the watermelon as it smashes into the ground will be 24.2 m/s.

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A wave has a period 2.00 s, an amplitude 20.0 cm, and a wavelength 3.00 m. What is the speed of the wave?

a. 10.0 cm/s
b. 0.100 cm/s
c. 340 m/s
d. 0.667 m/s
e. 1.50 m/s

Answers

Answer:

a)

Explanation:

because if in 2 seconds have 20.0 cm/2s cm in 1 second have 10.0 cm/s

How much work is done by the gravitational force on the block?

Answers

Answer:

Work = Mass * Gravity * Height and is measured in Joules. Imagine you find a 2 -Kg book on the floor and lift it 0.75 meters and put it on a table. Remember, that “force” is simply a push or a pull. If you lift 100 kg of mass 1-meter, you will have done 980 Joules of work.

Explanation:

If the initial oscillation of the pendulum has an amplitude of 2.5m , what is the amplitude d of oscillation after 20 s ?

Answers

Answer:

The value is  [tex]y = 0.0458 \ m[/tex]

Explanation:

From the question we are told that

   The initial amplitude is  A =  2.5 \  m

    The time considered is   t = 20 s

Generally the amplitude at time  t is mathematically represented as

      [tex]y = Ae^{- \frac{t}{\tau} }[/tex]

Here [tex]\tau[/tex] is the time constant let assume the value to be [tex]\tau = 5 \ s[/tex]

So

       [tex]y = 2.5 * e^{- \frac{20}{5} }[/tex]

=>  [tex]y = 0.0458 \ m[/tex]

 

True or False when an object speeds up it gains momentum

Answers

Yes ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Answer: True

Explanation:

7. It is the art of drawing solid objects on two-dimensional surfaces.

Answers

Explanation:

Perspective- the art of drawing solid objects on a two-dimensional surface so as to give the right impression of their height, width, depth, and position in relation to each other when viewed from a particular point.

An 7.40 kg block drops straight down from a height of 0.83 m, striking a platform spring having a force constant of 9.50 102 N/m. Find the maximum compression of the spring.

Answers

Answer:

0.25 m.

Explanation:

mass of the block = 7.40 kg, height = 0.83 m, force constant of the spring = 9.50 x [tex]10^{2}[/tex] N/m.

The maximum compression on the spring can be determined by;

Potential energy stored in the spring = [tex]\frac{1}{2}[/tex] K[tex]x^{2}[/tex]

But, potential energy = mgh

So that,

mgh = [tex]\frac{1}{2}[/tex] K[tex]x^{2}[/tex]

7.4 x 9.8 x 0.83 = 9.50 x [tex]10^{2}[/tex] x [tex]x^{2}[/tex]

60.1916 = 9.50 x [tex]10^{2}[/tex] x [tex]x^{2}[/tex]

[tex]x^{2}[/tex]= [tex]\frac{60.1916}{9.50*10^{2} }[/tex]

  = 0.06336

x = 0.2517

x = 0.25 m

The maximum compression of the spring is 0.25 m.

Wind comes from the Sun
WWW.
A heating up the Earth's surface unevenly
B being brighter during the day
C blasting wind to the Earth
D heating up the air.

Answers

Answer:

I am pretty sure is either C or D hope this helps

Answer:

A heating up the Earth's surface unevenly

Explanation:

Wind comes from the sun heating up the earth's surface unevenly. This causes air masses to have different temperatures. Differences in temperature causes the density of the air masses on the earth surface to differ.

This leads to the movement of air from regions of high density to places with low density. Therefore, convection cells are then set up by the implication of this. The movement of the air masses causes wind.

A solid sphere rolling without slipping on a horizontal surface. If the translational speed of the sphere is 2.00 m/s, what is its total kinetic energy?

Answers

Answer:

The total kinetic energy is 2.8m J. (NOTE: m is mass of the sphere)

Explanation:

The total kinetic energy of a sphere is given by the sum of the rotational kinetic energy and the translational kinetic energy. That is,

[tex]K_{Total} = K_{R} + K_{T}[/tex]

The rotational kinetic energy [tex]K_{R}[/tex] is given by

[tex]K_{R} = \frac{1}{2}I\omega^{2}[/tex]

Where [tex]I[/tex] is the moment of inertia

and [tex]\omega[/tex] is the angular velocity

The translational kinetic energy [tex]K_{T}[/tex] is given by

[tex]K_{T} = \frac{1}{2}mv^{2}[/tex]

Where [tex]m[/tex] is the mass

and [tex]v[/tex] is the translational speed (velocity)

∴ [tex]K_{Total} = \frac{1}{2}I\omega^{2} + \frac{1}{2}mv^{2}[/tex]

But, the moment of inertia [tex]I[/tex] of a sphere is given by

[tex]I = \frac{2}{5}mr^{2}[/tex]

Where [tex]m[/tex] is mass

and [tex]r[/tex] is radius

∴ [tex]K_{Total} = \frac{1}{2}\times \frac{2}{5}mr^{2} \omega^{2} + \frac{1}{2}mv^{2}[/tex]

[tex]K_{Total} = \frac{1}{5}mr^{2} \omega^{2} + \frac{1}{2}mv^{2}[/tex]

Also, [tex]\omega = \frac{v}{r}[/tex]

∴ [tex]\omega^{2} = \frac{v^{2} }{r^{2} }[/tex]

Then,

[tex]K_{Total} = \frac{1}{5}mr^{2} \times \frac{v^{2} }{r^{2} } + \frac{1}{2}mv^{2}[/tex]

[tex]K_{Total} = \frac{1}{5}mv^{2} + \frac{1}{2}mv^{2}[/tex]

∴ [tex]K_{Total} = \frac{7}{10}mv^{2}[/tex]

From the question, [tex]v = 2.00 m/s[/tex]

Then,

[tex]K_{Total} = \frac{7}{10}m(2.00)^{2}[/tex]

[tex]K_{Total} = \frac{7}{10}m\times 4.00[/tex]

[tex]K_{Total} = 2.8m J[/tex]

Hence, the total kinetic energy is 2.8m J. (NOTE: m is mass of the sphere)

A scuba diver wears weights as well as a buoyancy compensator to establish neutral buoyancy while diving. The buoyancy compensator can either be inflated with air or the air in it can be released. Explain how a scuba diver uses the buoyancy compensator to dive and to rise back to the surface.

Answers

Answer:

With more air is more buoyancy. When deflated or released the scuba diver is less buoyant.

Explanation:

The compensator is a Buoyancy control device that has an inflatable air bladder.When we have more air out into the inflatable bladder, then one is more buoyant. If the air is released from the bladder, then one is less buoyant. We add air through an air inflation valve. Air is also then released using air-deflation valves.

Buoyancy can be defined as an upward force which is exerted on an object that is fully or partially immersed in water

when one is less buoyant than water, it means that the upward pressure is more than the downward pressure of that person and his equipment. Then he will float. In a case of negative buoyancy, we have downward pressure of this person and his equipment to be more than the upward pressure of the water. Then sinking will happen.

Which describes the genetic disorder that causes neurons in the brain to break down? scribes the genetic disorder that causes neurons in the brain to break down need help will mark brainliest

Answers

Genetic disorders and Parkinson's disease.

What would happen if there is more male hyenas than female hyenas in a population?



Choices:
Male hyenas will compete to mate with the females.

Some male hyenas will die.

Male hyenas for wait for more females to join the population.

Answers

A. Because that’s how the wild works.

Answer:

Option 1

Explanation:

I always see animals do that

A school bus drives north and then east through the city as it takes students to school. The bus crosses a city block every 10 seconds. If all the city blocks are the same length, what can be said about the motion of the bus?

Answers

Answer:

The bus is moving at a constant speed.

Explanation:

We have the following facts from the question;

- The bus crosses a city block every 10 seconds.

- all the city blocks are the same length

Since all the city block are the same length, let's say the distance is d.

Since it crosses the city block every 10 seconds, we know that;

Speed = distance/time

Thus, Speed = d/10

Thus,it is moving at this speed of d/10 all through.

Therefore we can conclude that the bus is moving at a constant speed.

How much work would be done on a particle with 5.0 C of charge on it if it moved from an equipotential line at 5.5 volts to another equipotential line at 3.5 volts?

Answers

Answer:

10J

Explanation:

In this question we have the following information

The charge of the particle is q = 5 C

The equipotenetial level is V1 = 5.5 v

and also the

equipotenetial level is V2 = 3.5 v

So we calculate the

work done W=q x (v1-v2)

workdone = 5 x (5.5-3.5)

= 5x2

=10 J

Workdone = 10 J

So we conclude that the workdone on a particle with these information is 10j

Give real-world examples of evidence that supports the evolution of Earth in each category:
Deposition -
Chemical weathering -
Volcanic eruption -

Answers

Answer:

concave shape of the waverock

Explanation:

The wave rock is formed by the weathering of the surrounding area. This helps in proving the deposition part, as the wave rock was below the ground, occurred due to deposition of rock years over the years. It is made from very tough material from its surroundings. The weathering reduces the surrounding terrain, while the bedrock remains to witness for the history.  Also, volcanic eruptions have been changing earth for a long time. (first of all, the theory that a volcanic eruption helped in making dinos go extinct.) Real world examples include: Ash and sulfur went pretty high into Earth's atmosphere because of the Tambora eruption which in turn dimmed incoming sunlight, and lowered global temperatures by about 3°F. The Mount Pinatubo eruption in the Philippines in 1991 cooled the planet by about 1°F.

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