The height of the tree is closest to 40 feet.
We can use the proportion of similar triangles to determine the height of the tree.
Let h be the height of the tree and s be the length of the shadow cast by the tree.
We know that the height of the building is 60 feet and the length of its shadow is 21.5 feet. So:
(h/s) = (60/21.5)
We also know that the length of the shadow cast by the tree is 18 feet.
So we can substitute that into the proportion and solve for h:
h = (60/21.5) * 18
h = (60*18)/21.5
h ≈ 40
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Does 12 20 and 16 form a Pythagorean triple?
No, 12, 20, and 16 do not form a Pythagorean triple. A Pythagorean triple is a set of three whole numbers, a, b, and c, such that a^2 + b^2 = c^2.
To determine if 12, 20, and 16 form a Pythagorean triple, we can substitute each number into the equation and solve for c.
Start by substituting 12 for a, 20 for b, and 16 for c:
12^2 + 20^2 = 16^2
144 + 400 = 256
544 ≠ 256
Since 544 does not equal 256, the numbers do not form a Pythagorean triple. We can also verify this by calculating the square of c to see if it is equal to the sum of the squares of a and b.
Start by substituting 12 for a, 20 for b, and 16 for c:
a^2 + b^2 = c^2
12^2 + 20^2 = c^2
144 + 400 = c^2
544 = c^2
Taking the square root of both sides:
√544 = √c^2
23.2 ≠ c
Since 23.2 does not equal c, the numbers do not form a Pythagorean triple.
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David owns a food truck that sells tacos and burritos. He only has enough ingredients to make 87 tacos or burritos.Write an inequality that could represent the possible values for the number of tacos sold, tt, and the number of burritos sold, bb, that would satisfy the constraint.
Find the percent of change. Round to the nearest tenth, if necessary.
During the winter, the grill was marked at $85. In June, the price was changed to $110. 50.
PLEASE THIS IS URGENT
During the winter, the grill was marked at $85. In June, the price was changed to $110. 50. So, 23.08% is the change in percentage.
What is percentage?When the denominator is 100, percentages are really just fractions. We place the percent sign (%) next to the number to indicate that the number is a percentage.
Comparing two amounts while re basing the second amount to 100 is the simplest way to use percentages. The word percentage comes from the Latin term per centum, which means "by the hundred." In the 16th century, the Latin term made its way into English. It was later abbreviated to %.
Given that,
the grill was marked at $85
the price was changed to $110. 50.
Now, percentage change:
= [{(110. 50 - 85)/110.50} × 100]
= (0.2308 × 100)
= 23.08%
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True or false:
If f(x) is a cubic function
and f(1) = 0, f(3) = 0 and
ƒ(4) = 0,
then f(5)=8
Answer:
FALSE
Step-by-step explanation:
It is not necessarily true that ƒ(5)=8 just because ƒ(1)=0, ƒ(3)=0, and ƒ(4)=0. In fact, it is possible for ƒ(x) to be a cubic function and for ƒ(5) to equal any number, depending on the specific form of the function and the values of its coefficients.
An arithmetic sequence begins with 56, 59, 62, 65, 68, ...
Which option below represents the formula for the sequence?
O f(n) = 56 + 3(n − 1)
-
Of(n) = 53+ 3(n-1)
O f(n) = 56 + 3(n)
Of(n) = 53 + 3(n + 1)
f(n) = 56 + 3(n − 1) is the correct option represents the formula for the sequence.
What is an arithmetic sequence?In arithmetic sequences, each term is made larger by the addition or removal of a constant called k. Unlike a geometric sequence, where each term increases by being multiplied by or divided by a fixed constant k,
If there is a consistent difference between the words in a sequence of numbers, the sequence is referred to as an arithmetic progression. Think about the mathematical progression where the numbers 5, 7, 9, 11, 13, and so on all have a common difference of 2.
An is defined as a1 + d(n - 1), where d is the average difference between terms in the series, and a1 is the first term.
Given data :
This is the formula of an arithmetic sequence.
f(n) = a1 + d(n - 1)
An arithmetic sequence begins with 56, 59, 62, 65, 68,
= = 56.
d = 59 - 56 = 3
so the formula is f(n) = 56 + 3(n − 1)
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How many variable terms are in the expression 3x3y 5x2 Y 9?
The variable terms in the expression 3[tex]x^{3}[/tex]y + 5[tex]x^{2}[/tex] + y + 9 are [tex]x^{3}[/tex]y, [tex]x^{2}[/tex], and y.
The expression provided is
3[tex]x^{3}[/tex]y + 5[tex]x^{2}[/tex] + y + 9
In the expression, each variable is represented by a letter.
Let's look at the variables for each term.
The variable in the first term, 3[tex]x^{3}[/tex]y, is [tex]x^{3}[/tex]y.
The variable in the second term, 5[tex]x^{2}[/tex] , is [tex]x^{2}[/tex] .
Y is the variable in the third term.
There is no variable in term 9's final equation.
The variables in the expression are [tex]x^{3}[/tex]y, [tex]x^{2}[/tex] , and y.
As a result, the variables [tex]x^{3}[/tex] and y are the variable terms.
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a group of classmates surveyed how other students travel to school the results of the survey are shown in the table at right make a circle graph showing the results of the survey using percents, bus- 90, ride bike- 30, ride in car- 75, walk- 45.
So, on solving the provided question, we can say that equation of diagonal WY is 13.03 units
What is equation?An equation is a mathematical formula that connects two assertions using the equal sign (=) to denote equivalence. In algebra, an equation is a mathematical statement that establishes the equivalence of two mathematical expressions. For instance, an equal sign separates the components 3x + 5 and 14 in the equation 3x + 5 = 14. A mathematical formula is used to explain the connection between two sentences on either side of a letter. Frequently, there is just one variable, which is also the symbol. for example, 2x - 4 = 2.
by d=√((x2 – x1)² + (y2 – y1)²).
Coordinates of W = (-4,5) and Y = (3,-6)
= √((3 – (-4))² + (-6 – 5)²)
= √170
= 13.03 units
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What is the vector equivalent to the directed line segment from the point?
The vector equivalent to the directed line segment from the point (x1, y1) to the point (x2, y2) is the vector <x2-x1, y2-y1>.
The vector of a directed line segment is the difference between the two endpoints of the line segment. In this case, the endpoints are the points (x1, y1) and (x2, y2). Therefore, the vector of the directed line segment is equal to the vector <x2-x1, y2-y1>.
The vector equivalent of a directed line segment from the point (x1, y1) to the point (x2, y2) is the vector with initial point (x1, y1) and terminal point (x2, y2). This vector is equal to the vector form <x2-x1, y2-y1>, which describes the displacement from the initial point to the terminal point. This vector can also be written in component form, meaning the magnitude of the vector in the x-direction is x2-x1, and the magnitude of the vector in the y-direction is y2-y1.
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For problems 1 - 6, determine whether the relationships represented are A. Exponential., B. Linear., or C. Neither.
Step-by-step explanation:
a linear function is following
y = ax + b
that means the ratio of the y and x differences between the data points is constant (a).
an exponential function is in the form y = a^x. or some constant variations of it.
the base is constant (a), and the exponent of the constant is the variable (x).
1.
clearly exponential.
this is the typical graph of an exponential function.
it looks like y = 2^x, as e.g. f(4) = 2⁴ = 16, and the graph seems to be at least very close to this.
2.
exponential.
y = 3^(x - 0.5)
3¹ = 3
3² = 9
3³ = 27
3⁵ = 243
this is just y = 3^x shifted to the right by 0.5 units.
3.
linear.
the difference ratio between the data points is constant :
x is the row number (1, 2, 3, 4, 5, ...).
y is the number of seats per row (14, 16, 18, 20, 22, ...).
so,
(16-14)/(2-1) = 2/1 = 2
(18-16)/(3-2) = 2/1 = 2
...
(22-14)/(5-1) = 8/4 = 2
always constant (2).
4.
neither.
it is y = x²
when you compare 4. and 1. you see the clear difference between the 2 graphs.
5.
exponential.
remember, y = a^x.
well, here, a = 1/2. but that is still constant and doesnot change the principle.
the factor 10 stretches the graph a bit up (in fact, this 10 is the starting number of an exponential growth). but the function in its core is still exponential.
6.
linear.
when written that way, it just means that x = n, and for every increase of n by 1, y (f(n)) increases by +4.
so, the difference ratio stays constant (4/1 = 4).
The scale factor of the blueprint of a garage door to the actual garage door is 0.05. The area of the actual garage door is 220 ft2 . What is the area of the garage door on the blueprint
The area of the garage door on the blueprint is 0.55 ft^2.
The size of a patch on a surface is determined by its area. The area of an open surface or the boundary of a three-dimensional object is referred to as the surface area, whereas the area of a plane region or plane area refers to the area of a form or planar lamina.
Given in question,
Scale factor = 0.05
Since this scale factor is for length.
The scale factor for the area = 0.05*0.05
= 0.0025
Original Area = 220
The area on the blueprint = 0.0025*220
= 0.55
Hence, the area of the garage door on the blueprint is 0.55 ft^2.
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please help me out will give brainliest
Answer:
I think it would be 10 inches but I am not sure
A 2.2 GB game is being downloaded onto your laptop. when you have downloaded half a gigabyte you notice that your computer has been downloading at a rate of .01GB/min.
Answer:
it takes 110 minutes
Step-by-step explanation:
Answer:
it takes approximately 110 minutes
The radius $r$ of a circle inscribed within three mutually externally tangent circles of radii $a$, $b$ and $c$ is given by \[\frac{1}{r}
The formula yields the radius $r$ of a circle that is inscribed within three circles with radii $a$, $b$, and $c$ that are mutually external tangents.
[tex][\frac{1}{r} = \frac{1}{a} + \frac{1}{b} + \frac{1}{c}][/tex]
The radius of the inscribed circle is related to the radii of the three mutually externally tangent circles using a method known as the radical centre formula. According to this equation, the reciprocals of the radii of the three externally tangent circles add up to the radius of the circle that is inscribed.
The power of point theorem states that the product of the distance between the point and the three points of tangency is equal to the product of the distance between the point and the centres of the circles. This formula is based on the fact that the circles are mutually externally tangent and their centres are collinear. It is crucial to note that the formula can only be used if the circles are mutually externally tangent; otherwise, it is invalid.
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If f(x)=3x, g(x)=x+4, and h(x)=x2-1, find the value of h[f(5)]
Answer:
29
Step-by-step explanation:
Please help, it's much appreciated! <3333 It's midterms studying. 20 points!
A manufacturer makes trusses, or triangular supports, for the roofs of houses. Each truss is the shape of an isosceles triangle in which the sides are congruent. The length of the base is 4/3 the length of the congruent sides.
The perimeter of each truss is 60ft. Find each side length
Answer: The length of each side of the triangle is;
Equal sides, x = 21.02 = PQ = PR
QR = 28.03
Step-by-step explanation: The trusses made by the manufacturer have the shape of an isoscellestriangle and as such two congruent sides PQ ≅ PR) are equal and QR is the third side whose length is 4/3 of the congruent sides.
The perimeter of each truss is 70ft.
Let the length of each congruent side be x ft.
Therefore,
Perimeter = x + x + (4/3)x
Perimeter, p = 70 = 3.33x
x = 70/3.33
x = 21.02
Therefore, Length of QR is; QR = (4/3) x
QR = (4/3) × 21.02
QR = 28.03
How do you find the domain and range of a graph in Algebra 2?
Another way to identify the domain and range of functions is by using graphs. Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis.
Now, According to the question:
How do you find the domain?
Let y = f(x) be a function with an independent variable x and a dependent variable y. If a function f provides a way to successfully produce a single value y using for that purpose a value for x then that chosen x-value is said to belong to the domain of f.
How do you find the range?
The range is calculated by subtracting the lowest value from the highest value.
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is two displacement vectors add to give a total displace,ment of 0 what do you know about the two diplacemenst
The two vectors are equal in magnitude and opposite in direction. This means that they cancel each other out, resulting in a net displacement of 0.
If the total displacement of two vectors is 0, it means that the final position of an object after being displaced by the two vectors is the same as its initial position. This can happen in a few ways:
The two vectors are equal in magnitude and opposite in direction. This means that they cancel each other out, resulting in a net displacement of 0.
The two vectors are parallel but pointing in opposite directions. This means that the object is displaced in one direction and then back again, resulting in a net displacement of 0.
The two vectors are perpendicular and the magnitude of each vector is the same. This means that the object is displaced in one direction and then back again in the perpendicular direction, resulting in a net displacement of 0.
Therefore, In all cases, it can be inferred that the two vectors are in some way related to each other in terms of direction and magnitude.
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A large green jar of candy contains red, green, and yellow candy. The probability of pulling a red candy out of the jar is 1/4. The probability of pulling a green candy out of the jar is 5/8. What is the probobility of randomly pulling a yellow candy out of the jar
Answer:
1/8
Step-by-step explanation:
total probability = 1
total probability = probability of red + probability of green + probability of yellow
1 = 1/4 + 5/8 + yellow
we want to find a common denominator
in this case, we know 4 * 2 = 8, so we can multiply 1/4 by 2/2 = 1 to get
1/4 * 2/2 = 2/8
1 = 2/8 + 5/8 + yellow
1 = 7/8 + yellow
subtract 7/8 from both sides to isolate yellow
1 = 8/8
1 - 7/8 = 8/8 - 7/8 = 1/8 = yellow
What does log2 mean on a calculator?
The log base 2 calculator quickly computes the value of the logarithm function with base two, i.e., log₂(x) for arbitrary (positive) x
What do we mean by an expression?
An expression or mathematical expression is a finite combination of symbols that is well-formed according to context-dependent rules.
To help determine the order of operations and other aspects of logical syntax, mathematical symbols can designate numbers (constants), variables, operations, functions, brackets, punctuation, and grouping.
To find which expression is equivalent to log₅32:
Law of logarithms:
The law of logarithms states that: log(a) b = log(10)b/log(10)a
Given the log function, which is written as log₅32
a = 5
b = 32
Substitute as: log₅32 = log32/log5
Therefore, the given expression log₅32 is equivalent to the expression log32/log5.
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round 34.171875 to the nearest 100th
The rounding off of 34.171875 to the nearest 100th gives us= 34.17
The nearest hundredth should be the second digit after the decimal point. To round off any decimal figures, we need to see if the digit after the hundredth is greater than or equal to 5. If such is the case, then add 1 to the hundredth, or else remove the digits.
Here, the nearest hundredth digit is 7, and the digit after it (i.e, the third place after decimal) is smaller than 5. So, there is no need of adding an extra 1 to the hundredth. Now, after casting off the remaining digits, we get 34.17.
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A circle has centre C and radius 4 cm.
The diagram shows the circle with a point
D which lies on the circle. The tangent at D
passes through the point E. EC = √65 cm.
Find
a) the size in radians of angle DCE
b) the area of the shaded region
Step-by-step explanation:
EC = 165 cm (Given) Tangent of circle also makes 90°.
a) sind = Perpendicular Hypotenuse = CD = EC 165 => 0 = Sin = 0.519 ~ 0.52 =29.7448 ~ 29.75° =<E
By angle sum property of triangle. <D+<E+ <C = 180°
90° + 29.75 + LC = 180°
<C = 180-90-29.75 = 60.25° <C= 60.25°
<DCE = <C = 60.25 x π/180 = 1.052 radians.
(b) Area of triangle DCE = 1/2 x b x h = 1/2 x ED X 4
ED² + CD² = EC² ED² + 4² = (√65)² => EC² = 65-16 = 49 ED=7
Area = 1/2 x 7 x 4 = 14 cm²
Area of sector a π x 4²x 60.25/360 = 8.4125 cm2
Area of shaded region= Area ADCE Area of sector -
= 14-8.4125 = 5.5875 cm²
(a) <DCE = 1.052 radians b) Area shaded of region = 5.5875cm²
3/4 of the tudent paed an Examination. 28 tudent appeared for the exam. How many tudent failed the examination?
7 students failed the examination out of 28 students who appeared for the examination.
What is the Proportion?
A proportion is an equation in which two ratios are set equal to each other. For example, if there is 1 boy and 3 girls you could write the ratio as 1 : 3 (for every one boy there are 3 girls)
When we say that a proportion is two ratios that are equal to each other, it means this in the sense of two fractions being equal to each other.
For instance, 5/10 equals 1/2.
If 3/4 of the students passed the exam, this means that 1 - 3/4 = 1/4 of the students failed the exam.
We can use this information to find the number of students who failed the exam by multiplying the total number of students who appeared for the exam by the proportion of students who failed:
Number of students who failed = Total number of students * Proportion of students who failed
Number of students who failed = 28 students * 1/4 = 28 students * 0.25 = 7 students
Hence, 7 students failed the examination out of 28 students who appeared for the examination.
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I don’t if is good and the last I don’t know how to do it
From the given data, the first and third graph are correct.
1. For the first graph,
the two equation are -
y = -2x - 4
-4x + y = 2
Let us check the common points for the given graph,
(-1,-2)
y = -2x - 4 - 4x + y = 2
-2 = -2(-1) - 4 -4(-1) + (-2) = 2
-2 = -2 2 = 2
Hence it is correct.
2. For the second graph,
y = -3/2x - 2
y = -1/4x + 3
Common points are - (4,4)
y = -3/2x - 2 y = -1/4x + 3
4 ≠ -8 4 ≠ 2
Hence it is not correct.
3. For the third graph,
y = -5
y = 3x + 1
Common points are - (-2,-5)
y = 3x + 1
-5 = -5
Hence it is correct.
The correct graph for 2, graph is below,
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Use pattern blocks to represent each multiplication equation. Use the trapezoid to
represent 1 whole.
a. 3 • 1/3 = 1
b. 3 • 2/3 = 2
when the area of the trapezoid is 70 units, and its first and second bases are at 4.6 units,
Describe area.The size of a region on a flat or curved surface is expressed mathematically as area. The area of a form is defined as the "space encompassed inside the perimeter or the border." The area of various shapes is calculated using mathematical methods.
given
The trapezoid's surface area is 70 units.
first base is worth 20 units, while second base is worth 10 units.
how long CE
[tex]1/2(b1 + b2)*h is the area of a trapezoid.\\70= 1/2 (20 + 10 )*h\\70 = 1/2(30)*h\\4.6 units of h[/tex]
when the area of the trapezoid is 70 units, and its first and second bases are at 4.6 units,
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Colin invests £3300 into his bank account. He receives 3% per year compound interest. How much will Colin have after 4 years? Give your answer to the nearest penny where appropriate
Answer:
Below
Step-by-step explanation:
3% = .03 in decimal 4 (yearly) periods
The effective interest and deposit amount after 3 years compounded yearly will be
3300 (1 +.03)^4 = £ 3714.18
Point lies on the diagonal of square with . Let and be the circumcenters of triangles and respectively. Given that and , then , where and are positive integers. Find .
Point P lies on the diagonal AC of square ABCD with AP > CP. Let [tex]$O_1$[/tex] and [tex]$O_2$[/tex] be the circumcenters of [tex]$\triangle \mathrm{ABP}$[/tex] and [tex]$\triangle \mathrm{CDP}$[/tex] respectively. Given that AB = 12 and [tex]$\angle \mathrm{O}_1 \mathrm{PO}_2=120^{\circ}$[/tex], then [tex]$\mathrm{AP}=\sqrt{\mathrm{a}}+\sqrt{\mathrm{b}}$[/tex],
where a and b are positive integers.
The value of a + b is 96.
Let mid-point of DC be E and mid-point of AB be F.
Since [tex]$\mathrm{O}_1$[/tex] and [tex]$\mathrm{O}_2$[/tex] are circumcenters, therefore both lie on the perpendicular bisectors of DC and AB passing through E and F.
Now, [tex]$\mathrm{O}_1 \mathrm{P}=\mathrm{O}_1 \mathrm{~B}$[/tex] and [tex]$\mathrm{O}_2 \mathrm{P}=\mathrm{O}_2 \mathrm{D}$[/tex]
Also [tex]$\angle \mathrm{CAB}=\angle \mathrm{ACD}=45^{\circ}$[/tex]
Therefore [tex]\angle \mathrm{BO}_1 \mathrm{P}=2 \times 45^{\circ}=90^{\circ}=\angle \mathrm{DO}_2 \mathrm{P}$[/tex]
Angle subtended by an arc of a circle at its center = 2 × the angle subtended at its circumference
Therefore [tex]\angle \mathrm{O}_1 \mathrm{~PB}$[/tex] and [tex]$\angle \mathrm{O}_2 \mathrm{PD}$[/tex] are isosceles right triangles.
Using the above information and symmetry,
[tex]$\angle \mathrm{DPB}=120^{\circ}$[/tex]
Also, [tex]$\triangle[/tex]ABP is congruent to [tex]$\triangle[/tex]ADP (SAS)
and [tex]$\triangle[/tex]CPB is congruent to [tex]$\triangle[/tex]CPD (SAS)
Therefore [tex]\angle \mathrm{APB}=\angle \mathrm{APD}=60^{\circ}[/tex]
And [tex]\angle \mathrm{CPB}=\angle \mathrm{CPD}=120^{\circ}[/tex]
Now, [tex]$\angle \mathrm{ABP}=(180-60-45)^{\circ}=75^{\circ}$[/tex]
[tex]\Rightarrow \angle \mathrm{O}_1 \mathrm{BF}=30^{\circ}[/tex]
And [tex]$\angle \mathrm{PDC}=(180-120-45)^{\circ}=15^{\circ}$[/tex]
[tex]\Rightarrow \angle \mathrm{O}_2 \mathrm{DE}=30^{\circ}[/tex]
Therefore [tex]\triangle \mathrm{O}_1 \mathrm{BF}$[/tex] and [tex]$\triangle \mathrm{O}_2 \mathrm{DE}$[/tex] are right angled triangles.
BF = DE = [tex]\frac{12}{2}[/tex] = 6
[tex]\Rightarrow O_1 B=O_2 D=4 \sqrt{3}[/tex]
And PB = PD = [tex]\frac{4 \sqrt{3}}{\cos 45^{\circ}}=4 \sqrt{6}[/tex]
Now, Let x = AP
Using law of cosine on [tex]$\triangle[/tex]ABP, we have
[tex]& 96=x^2+144-24 x \times \frac{1}{\sqrt{2}} \\[/tex]
[tex]& \Rightarrow x^2-12 \sqrt{2} x+48=0 \\[/tex]
[tex]& \Rightarrow x=\sqrt{72} \pm \sqrt{24}[/tex]
Taking the positive root, AP = [tex]\sqrt{72}+\sqrt{24}$[/tex]
Therefore a + b = 72 + 24 = 96
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Point P lies on the diagonal AC of square ABCD with AP > CP. Let [tex]$O_1$[/tex] and [tex]$O_2$[/tex] be the circumcenters of [tex]$\triangle \mathrm{ABP}$[/tex] and [tex]$\triangle \mathrm{CDP}$[/tex] respectively. Given that AB = 12 and [tex]$\angle \mathrm{O}_1 \mathrm{PO}_2=120^{\circ}$[/tex], then [tex]$\mathrm{AP}=\sqrt{\mathrm{a}}+\sqrt{\mathrm{b}}$[/tex], where a and b are positive integers. Find a + b. (correct answer +5, wrong answer 0 )
Is halting problem is unsolvable?
Therefore, the answer to the provided problem of tractable problem turns out to be the most common problem that has been shown to be insoluble.
What exactly is a tractable problem?a method that takes a polynomial amount of time to finish a manageable task. It makes advantage of the polynomial upper bound. Intractable refers to a problem that cannot be addressed in a polynomial amount of time. The bound has an exponential minimum.
Here,
It is the most common issue that has been shown to be intractable since there is no program that can fix the stopping trouble for sufficiently general computer programs.
We need to be clear about the kind of computer program we're talking about.
Therefore, the answer to the provided problem of tractability turns out to be the most common problem that has been shown to be insoluble.
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pleasee helpp !! <33
there can be more than one answer
The spring constant is 30 N/m and the stretch when the 420 N force is applied is 14 cm.
What is spring force?The force needed or applied to compress or extend a spring on any attached object is known as the spring force.
A spring exerts an equal and opposite force on an object when the object exerts a force on it. It always takes action to get mass back to where it should be for equilibrium.
Given that when 180 N force is applied the spring stretched by 6 cm. The spring stretch when the 420 N force is applied is calculated as,
First, calculate the spring constant,
F = kx
180 = k x 6
k = 30 N / m
Calculate the deformation,
x = F / k
x = 420 / 30
x = 14 cm
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Given right triangle ABC with altitude BD drawn to hypotenuse AC. If AB = 8
and AD 4, what is the length of AC ? (Note: the figure is not drawn to scale. )
The required length of the side AC of the given right triangle is 32 units.
What is the right triangle?A right triangle is a triangle with one right angle or two perpendicular sides.
It is also referred to as a right-angled triangle, right-perpendicular triangle, orthogonal triangle, or formerly rectangle triangle.
The relationship between the sides and various angles of the right triangle serves as the basis for trigonometry.
A triangle is referred to be a right triangle when one of the interior angles is 90 degrees or a right angle.
So, using the hypotenuse AC as the point of convergence for the right triangle ABC,
AB is 8 and AD is 2.
Verify whether the triangle ΔABD resembles ΔACB.
∠ BCA = ∠ DBA (90 - ∠ DBC)
∠ A = ∠ A
As a result, ΔABD and ΔACB share an AAS resemblance.
Utilize the similarity property to determine the length of AC.
AC/AB = AB/AD
x / 8 = 8 / 2
x = 32
Therefore, the required length of the side AC of the given right triangle is 32 units.
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Correct question:
Given a right triangle, ABC with altitude BD drawn to hypotenuse AC. If AB = 8 and AD = 2, what is the length of AC?