Answer:
18 km
Explanation:
What is the acceleration of a car moving in a straight line that increases from 0m/s to 50 m/s in 5 seconds?
Answer:
10m/s^2
Explanation:
a=change in velocity/change in time
50/5=10m/s^2
A graduated cylinder contains 17.5 ml of water. When a metal cube is placed onto the cylinder, its water level rises to 20.3 ml.
Answer:
V=2.8 ml
Explanation:
volume of the cube is it would be 20.3 - 17.5 ml so 2.8 ml.
Identify the reaction type shown and describe the clues that were used to identify it.
Fe2O3 + 2SiO2 → Fe2Si2O7
Answer:
This chemical equation represents a synthesis reaction. This identification is based on the fact that the reactant chemical compounds combine to form a single chemical substance that is different from the initial chemical substance.
Explanation:
At a race car driving event, a staff member notices that the skid marks left by the race car are 9.06 m long. The very experienced staff member knows that the deceleration of a car when skidding is -40.52 m/s2. What can the staff member estimate for the original speed of the race car if it came to a stop during the skid?
Answer:
27.1 m/s
Explanation:
Given that at a race car driving event, a staff member notices that the skid marks left by the race car are 9.06 m long. The very experienced staff member knows that the deceleration of a car when skidding is -40.52 m/s2.
Using third equation of motion,
V^2 = U^2 + 2aS
Since the car is decelerating, the final velocity V = 0
Substitute all the parameter into the equation above,
0 = U^2 - 2 * 40.52 * 9.06
U^2 = 734.22
U = [tex]\sqrt{734.22}[/tex]
U = 27.096
U = 27.1 m/s approximately
Therefore, the staff member can estimate for the original speed of the race car to be 27.1 m/s if it came to a stop during the skid
matter makes up all ? and ?
An space probe built on Earth has a mass of 750 kg. Calculate the weight of the space probe on Earth.
Answer:
7357.5N
Explanation:
Weight is the force used to pull a mass of object towards the centre of the Earth. The force is 9.81 N/kg.
so, Weight = mass × 9.81
the weight of the space probe should be: 750 × 9.81 = 7357.5 N
Answer:
7350N
Explanation:
Data
m-750kg
g-9.8
W=mg
=750 x 9.8
=7350N
The y-axis of a position-time graph represents
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Answer:
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Give reasons.
a. A stretched catapult has potential energy.
b A stone on ground has zero energy.
C. Rolling a drum is work against friction.
d. Lifting a stone is work against gravity.
e. Work and energy both have same unit.
Choose the scientific theories that have been disproved through scientific advancement. Select all that apply.
a) steady-state theory
b) theory of evolution
c) big bang theory
d) geocentric universe
e) phrenology
Which of the statements below is true?
An object’s weight and mass are equal.
An object’s weight is proportional to its mass.
An object’s weight is inversely proportional to its mass.
An object’s weight is always twice its mass.
Answer:
An object’s weight is proportional to its mass.
the momentum of a bullet
Answer:
When a bullet is fired from a gun, total momentum before is zero since nothing is moving. After firing the bullet there is a momentum in the forward direction. ... The faster an object is moving or the more mass it has, the more momentum it has in the direction of its motion (momentum = mass velocity).
find fk and f in the picture shown
what pair of features best characterizes a sound wave?
Answer:
The only thing you need to know which pair of features that best characterizes a sound wave is to view the graph or the image of monitor.
Explanation:
What is the displacement of an object that moves from the origin to a position at - 12m
Answer:
Displacement, d = 12 meters
Explanation:
The displacement of an object that moves from the origin to a position at −12 m is 12 meters.
The distance from the origin to the maximum position is called displacement of an object. The maximum displacement of the particle in a wave is called crest and the minimum displacement is called the trough. -12 shows the displacement in negative axis.
So, the displacement of an object is 12 meters.
How could you categorize or classify the five major types of
forces?
Answer:
Contact forces can be classified according to six types: tensional, spring, normal reaction, friction, air friction, and weight. Noncontact forces: Forces that take place when two objects do not touch. These forces can be classified according to three types: gravitational, electrical, and magnetic.
Explanation:
determine the accelerations that result when a 45 N net force is applied to 3kg object
Answer:
acceleration is 18
Explanation:
45N/3kg=18
Answer:
18
Explanation:
Two ropes are attached a wagon one horizontal to the west with a tension force of 75N and other east and at an angle of 38 degrees upward from horizontal with a lension force of 125 N Find the components of the net force on the cart Show your work
Answer:
The components of the net force acting on the cart are;
Horizontal force, Fₓ ≈ 23.5 N acting east
The vertical force, [tex]F_y[/tex] ≈ 76.96 N
Explanation:
The parameters given in the question are;
The magnitude of the force on the rope acting horizontally to the west = 75 N
The magnitude of the force on the other rope east acting at an angle to the horizontal = 125 N
The angle to the horizontal of the force on the other rope east to the horizontal = 38°
Therefore, we have;
The horizontal component of the force acting east = 125 × cos(38°) ≈ 98.5 N
The net sum of the horizontal forces, ∑Fₓ noting that the horizontal forces are acting in opposite direction is given as follows;
∑Fₓ = 75 - 125 × cos(38°) = 75 - 98.3 = -23.5N
Given that the difference in forces is negative, and hat we took the force acting east as negative, we have that the net horizontal force is acting east with a horizontal component of 23.5N
The net vertical force, ∑F[tex]_y[/tex], is given as follows;
∑F[tex]_y[/tex] = 125 × sin(38°) ≈ 76.96 N
Therefore, the components of the net force acting on the cart are;
Horizontal force, Fₓ ≈ 23.5 N, the vertical force, [tex]F_y[/tex] ≈ 76.96 N
The components of the net force on the cart are 23.5 Newton and 76.96 Newton.
Given the following data:
Tension force (horizontal) due west = 75 NTension force (horizontal) due east = 125 NAngle of inclination = 38°To find the components of the net force on the cart:
First of all, we would determine the horizontal component of the force acting due east.
[tex]F_y = Fcos(\theta)\\\\F_y = 125cos(38)\\\\F_y = 125 \times 0.7880\\\\F_y = 98.5 \; Newton[/tex]
Next, we would find the resultant horizontal forces:
[tex]\sum F_y = F + F_y\\\\\sum F_y = 75 + (- 98.5)\\\\\sum F_y = -23.5 \;Newton[/tex]
Therefore, the horizontal component of the net force acts in the opposite direction due east.
Horizontal component of the net force = 23.5 Newton
For the vertical component of the net force:
[tex]\sum F_x = Fsin(\theta)\\\\\sum F_x = 125cos(38)\\\\ \sum F_x = 125 \times 0.6157\\\\ \sum F_x = 76.96\; Newton[/tex]
Read more: https://brainly.com/question/17742679
A cannonball is fired on flat ground
at 520 m/s at a 58.0° angle.
How much time is it in the air?
(Unit = s)
Answer:
90 seconds
Explanation:
What groups of animals are heterotrophs?
a.) herbivores
b.) carnivores
c.) omnivores
d.) all the above
Answer:
All of the above.
Explanation:
As a review, remember that carnivores eat other animals and omnivores eat both plants and animals. There is yet another term used when talking about food chains, the word heterotroph. Anything that is not an autotroph is a heterotroph. The word means “other feeding” or feed off of others.
A rocket is fired vertically upwards with initial velocity 92 m/s at the ground level. Its engines then fire and it is accelerated at 4m/s2 until it reaches an altitude of 1200 m. At that point the engines fail and the rocket goes into free-fall. Disregard air resistance.
Answer:
The rocket above the ground is in 44 sec.
Explanation:
Given that,
Initial velocity = 92 m/s
Acceleration = 4 m/s²
Altitude = 1200 m
Suppose, How long was the rocket above the ground?
We need to calculate the time
Using equation of motion
[tex]s=ut-\dfrac{1}{2}at^2[/tex]
Put the value into the formula
[tex]1200=92t+\dfrac{1}{2}\times4t^2[/tex]
[tex]2t^2+92-1200=0[/tex]
[tex]t=10\ sec[/tex]
We need to calculate the velocity
Using equation of motion
[tex]v=u+at[/tex]
Put the value into the formula
[tex]v=92+4\times10[/tex]
[tex]v=132\ m/s[/tex]
When the rocket hits the ground,
Then, h'=0
We need to calculate the time
Using equation of motion
[tex]h'=h+ut-\dfrac{1}{2}at^2[/tex]
Put the value into the formula
[tex]0=1200+132t-\dfrac{1}{2}\times9.8t^2[/tex]
[tex]4.9t^2-132t-1200=0[/tex]
[tex]t=34\ sec[/tex]
When the rocket is in the air it is the sum of the time when it reaches 1000 m and the time when it hits the ground
So, the total time will be
[tex]t'=34+10[/tex]
[tex]t'=44\ sec[/tex]
Hence, The rocket above the ground is in 44 sec.
According to Newton’s First Law of Motion, what will happen to a baseball thrown in outer space
Answer:
The baseball will stay in motion until another force act upon it.
Explanation:
Answer:
Newton's First Law of Motion is that an object in motion will stay in motion unless acted upon by an outside force. Due to the lack of gravity in space, until a different outside force acts upon the object, the baseball will continue to move at a constant speed in the same direction for all time (until acted upon by something else).
What do zooplankton and krill have in common?
Krill and plankton are two groups of organisms found in the ocean. Krill are species of crustacean related to shrimp, and serve as a very important link in the food chain of the sea. Plankton consist of a larger group of organisms with much more variety, including bacteria, algae, protozoans, jellyfish and some species of cephalopods.
Propulsion
The primary factor that determines whether a species is plankton or not is propulsion. Plankton organisms lack the ability to swim against the tide, and instead float from place to place on sea currents. They may be capable of some movement, and some types of plankton can even hunt for food, but none is powerful enough to make its own headway through the ocean. Adult krill are capable of swimming against currents, but their larvae and eggs fall into the plankton category.
Variation
Krill are crustaceans of the Euphausiacea order, which consists of 86 different species. Plankton, on the other hand, can come from a wide variety of different species and orders. Plankton fall into three broad categories, depending on their primary function. Phytoplankton are plant-like organisms, capable of photosynthesis. Zooplankton are animal plankton species that get their nutrients by eating other microscopic organisms. Bacterioplankton are the smallest plankton, and often serve as food for zooplankton and other lifeforms.
Appearance
Krill species have similar characteristics and generally resemble tiny shrimp. Most species reach around 2 centimeters (0.8 inches) as adults, while the largest species can reach sizes of up to 15 centimeters (5.9 inches). Plankton, on the other hand, consists of organisms of many different shapes and sizes. The smallest categories include microscopic viruses, protozoans, small crustaceans, and other tiny organisms. At the larger end of the scale, megaplankton are any plankton over 2 centimeters (0.8 inches) in size, and include large animals, such as cephalopods and jellyfish. The largest plankton is the lion's mane jellyfish, which can reach 2.5 meters (8.2 feet) in diameter and grow tentacles more than 36.5 meters (120 feet) long.
Role
Plankton and krill serve similar, but slightly different, roles in the food chain. Phytoplankton synthesize nutrients, while bacterioplankton recycle nutrients from decomposing matter in the ocean, providing some of the fundamental sources of nutrition for all ocean creatures. Zooplankton serve to concentrate those nutrients by eating smaller plankton and serving as food for larger creatures. Krill are one step up in the food chain, eating plankton and serving as a nutrient bridge from microscopic life forms to larger fish and mammals.
You mix 1 glass of water at 20 C and 1 glass of water at 80 C. What will be temperature of mixture
30
40
50
60
Explanation:
When Two Samples of Water are Mixed, what Final Temperature Results?
Go to Mixing Two Amounts of Water: Problems 1 - 10
Go to calculating the final temperature when mixing water and a piece of metal
Worksheet #2
Back to Thermochemistry Menu
Example #1: Determine the final temperature when 32.2 g of water at 14.9 °C mixes with 32.2 grams of water at 46.8 °C.
This is problem 8a from Worksheet #2.
First some discussion, then the solution. Forgive me if the points seem obvious:
1) The colder water will warm up (heat energy "flows" into it). The warmer water will cool down (heat energy "flows" out of it).
2) The whole mixture will wind up at the SAME temperature. This is very, very important.
3) The energy which "flowed" out (of the warmer water) equals the energy which "flowed" in (to the colder water)
This problem type becomes slightly harder if a phase change is involved. For this example, no phase change. What that means is that only the specific heat equation will be involved
Solution Key Number One: We start by calling the final, ending temperature 'x.' Keep in mind that BOTH water samples will wind up at the temperature we are calling 'x.' Also, make sure you understand that the 'x' we are using IS NOT the Δt, but the FINAL temperature. This is what we are solving for.
The warmer water goes down from to 46.8 to x, so this means its Δt equals 46.8 − x. The colder water goes up in temperature, so its Δt equals x − 14.9.
That last paragraph may be a bit confusing, so let's compare it to a number line:

To compute the absolute distance, it's the larger value minus the smaller value, so 46.8 to x is 46.8 − x and the distance from x to 14.9 is x − 14.9.
These two distances on the number line represent our two Δt values:
a) the Δt of the warmer water is 46.8 minus x
b) the Δt of the cooler water is x minus 14.9
Solution Key Number Two: the energy amount going out of the warm water is equal to the energy amount going into the cool water. This means:
qlost = qgain
However:
q = (mass) (Δt) (Cp)
So:
(mass) (Δt) (Cp) = (mass) (Δt) (Cp)
With qlost on the left side and qgain on the right side.
Substituting values into the above, we then have:
(32.2) (46.8 − x)(4.184) = (32.2) (x − 14.9) (4.184)
Solve for x
Which of the following is a solution?
OA.
ocean water
OB. oil in water
OC. sand in water
OD. all of these
OA. Ocean water
Answer:
OA. ocean water is a solution
Explanation:
What type of glass is heat resistant?
A.leaded glass
B.tinted glass
C.borosilicate glass
D.tempered glass
Answer:
D.
Explanation:
Tempered glass is the less expensive alternative, and is best for lower temperature applications. It can withstand constant temperatures of up to 470 degrees F. Tempered glass is regular glass that has been strengthened through a thermal or chemical treatment. Tempering not only strengthens the glass but also changes its breakage pattern, causing it to shatter into small pieces instead of large sharp angles, reducing the chance of injury. It is best used for applications where the fire will not be near the glass, as constant temperatures of 500 degrees or more will cause it to weaken and shatter.
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If the distance and time of an object are given, and I need to find speed, I will *
1.add the distance and time
2.divide the distance and time
3.multiply the distance and time
Answer:
2. divide the distance and time
speed=distance÷time
if 6.75g of oxide of lead was reduced to 6.12g of metal, calculate the empirical formula of the oxide
the Ability of water to pass through layers of soil and rock is....
1. impermeable
2. permeability
3. gradient
4. porosity
What kind of bond is formed between a metal and a metal
O All of the above
O lonic bond
O Metallic bond
O Covalent bond
Answer:
metallic bond
Explanation: