Balance the following chemical equation:
CO2 + VH20 - CH1206+ voz
[
~
CO₂+

Balance The Following Chemical Equation:CO2 + VH20 - CH1206+ Voz[~CO+

Answers

Answer 1

Answer:

Explanation:

Start with Carbon and assume we only get 1 sugar molecule from the process.

you have 6 carbons in the sugar on the right, so you need 6 carbons on the left which only come from CO₂

6 CO₂

you have 12 hydrogen atoms in the sugar on the right, so you need 12 hydrogen atoms on the left which only come from H₂O. At 2 hydrogen atoms per water molecule means you need 6 waters.

6 CO₂ + 6 H₂O → 1 C₆H₁₂O₆

you are supplied with 12 oxygen from the CO₂ and 6 oxygen from the H₂O, but you only need 6 oxygen for the sugar. That means there are 12 oxygen remaining which will become 6 O₂ molecules

6 CO₂ + 6 H₂O → 1 C₆H₁₂O₆ + 6 O₂


Related Questions

You apply the same force to two objects. Object 1 has mass M and object 2 has mass 5M. The acceleration of object 2 is

Select one:

a. one-fifth as that of object 1.


b. ten times that of object 1.


c. has no relation to that of object 1.


d. the same as that of object 1.


e. five times that of object 1.

Answers

five times that of object l


I will mark brainlist

If a wave’s amplitude is 2cm, then its height is equal to:



5 cm.



0 cm



4 cm.



2 cm

Answers

Answer:

4 cm

Explanation:

Amplitude is the measure from the MIDLINE to the peak of the wave....so the wave HEIGHT is twice the ampltude

2 x 2 cm = 4 cm

A stone is allowed to fall from the top of the tower 100m high at the same moment another stone is projected vertically upward with a velocity of 25m/s. Where and when will the two cross each other​

Answers

Answer:

both the stone will meet at a distance of 80 m from the top of tower.

Explanation:

let "t" = time after which both stones meet

"S" = distance travelled by the stone dropped from the top of tower

(100-S) = distance travelled by the projected stone.

◆ i) For stone dropped from the top of tower

-S = 0 + 1/2 (-10) t²

or, S = 5t²

◆ ii) For stone projected upward

(100 - S) = 25t + 1/2 (-10) t²

= 25t - 5t²

Adding i) and ii) , We get

100 = 25t

or t = 4 s

Therefore, Two stones will meet after 4 s.

◆ ¡¡¡) Put value of t = 4 s in Equation i) , we get

S = 5 × 16

= 80 m.

Thus , both the stone will meet at a distance of 80 m from the top of tower.

(Hope this helps can I pls have brainlist (crown)☺️)

The octopus’s tentacle keeps _ right after it is bitten off ? a. Moving b. Breathing c. Growing

Answers

Answer:

The answer is A

Explanation:

The octopus’s tentacle keeps moving right after it is bitten off

PLEASE HELP! I USED 100 POINTS!
Complete the sentence.

_____ are cracks in rock layers, and the pressures within the crust can push one of these layers past another.

A. Faults
B. Tectonic plates
C. Stalagmites

Subject: Science

Answers

Answer:

A i think its right im postivite

Answer: A. Faults

Explanation: ;-; its easy because faults are cracks and they can push layers past each other making tectonic plates rub against each other then creating a earthquake

Starting from rest, a racecar moves 112 m in the first 7 s of uniform acceleration. What is the car's acceleration?​

Answers

Answer:

215mph

Explanation:

multiply 112milws by 2 and multiple that by seven, then divide it by two

Calculate the torque produced by a 50.0 N perpendicular force at the end of a 0.300 m long wrench.

Answers

Answer:

Torque = 50N x 0.3m = 15Nm

Explanation:

Torque = Force x length of lever arm. To obtain the torque simply multiply the two given values.

Which statement is true?
O A ball with more kinetic energy rolls farther because it is harder to stop.
A ball at its highest speed demonstrates its greatest potential energy.
When a ball comes to a stop, its kinetic energy is greatest.
A ball with less kinetic energy rolls farther because it is harder to stop.

Answers

Answer:

c when a ball stop it's kinetic enegy is the greatest

When a ball comes to a stop, its kinetic energy is greatest is true.

What are the types of energy ?

The energy is the ability to do work or produce action and / or movement and manifests itself in many different ways, such as body movement, heat, electricity, etc.

The various types of energy include Kinetic energy which is associated with the movement of bodies and the  Potential energy is  stored by virtue of a body's position  also called gravitational potential energy.

Thermal Energy  can be referred as the energy  associated with the kinetic energy of the molecules that make up an element, it can be manifested if there is a temperature difference between two bodies.

Chemical energy released or formed from chemical reactions, Solar energy from sunlight. This form of energy is used to generate electricity through photovoltaic plates, for example.

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the push up is dynamic or static​

Answers

Answer:

Dynamic exercises

Explanation:

During the experiment it is determined that, as the cart rolls between two points on the track, the work done on the cart by the hanging masses and other forces present is 0.91 J. At the initial time of observation the cart moves with speed 0.61 m/s. Determine the speed at the second point of observation. The mass of the cart is 0.80 Kg.

Answers

Answer:

Explanation:

If the work done on the cart is NET work

Then the work will result in an increase in kinetic energy

KE₀ + W = KE₁

½mv₀² + W = ½mv₁²

½(0.80)(0.61²) + 0.91 = ½(0.80)v₁²

v₁ = 1.626991...

v₁ = 1.6 m/s

The speed of the cart at the second point of observation is equal to 1.62 m/s.

What is the work done?

Work can be demonstrated as the energy utilized when a force is exerted to make an object move through a particular displacement. Work done by this force is calculated from the product of the magnitude of the exerted force (F) and the distance (d) covered by the body

W= F.d

Where 'F' is the exerted force and 'd' is the displacement and W is work done.

Work and energy have a direct relationship with each other. Work done by an object can be expressed as a change in kinetic energy:

[tex]W =\frac{1}{2}mv_2^2- \frac{1}{2}mv_1^2[/tex]

Where m is the mass of the object, v₂ is the final velocity (m/s), and v₁ is the initial velocity (m/s).

Given, the work done by the cart, W = 0.91 J

The mass of the cart, m = 0.80 Kg

The speed of the cart at the first point, v₁ = 0.61 m/s

[tex]0.91 =\frac{1}{2}\times 0.80 \times v_2^2- \frac{1}{2}0.80 \times (0.61)^2[/tex]

0.40 v₂² = 1.06

v₂² = 2.65

v₂ = 1.62 m/s

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Alicia is naturally rather shy and is graduating from college. She will need to find a job, so she is starting to go on job websites and work on her
resume. She knows she should network, but it sounds a little intimidating. What is the BEST advice for Alicia?
ОА. If she is not comfortable networking, she will never find a job.
ОВ. The majority of jobs are found through networking, so she should really try it.
OC. Networking is overrated, so she can skip that part of the job search process.
OD If she is naturally shy, she probably has really poor social skills and should work on that.

Answers

Answer:

OB and i have no reasoning

calculate 18% of 2758 correct to 4 significant figure​

Answers

Answer:

......the answer is 496.4

what is translator disadvantage?​

Answers

Machine translators:

Level of accuracy can be very low.

Accuracy is also very inconsistent across different languages.

Machines can't translate context.

Mistakes are sometimes costly.

Sometimes translation simply doesn't work.

Human translators:

Turnaround time is longer.

Translators rarely work for free.

Unless you use a translation agency, with access to thousands of translators, you're limited to the languages any one translator can work with.

why is cooking faster with a pressure cooker. plz help me I beg​

Answers

Explanation:

The same thing happened in pressure cooker but the temperature inside is most higher.

hope you like my answer

thank you

Because cooking reactions speed up at a higher temperature also the boiling temperature of water increases and hence, the food cooks faster.

source:

https://www.vedantu.com/question-answer/a-pressure-cooker-reduces-cooking-time-for-food-class-9-chemistry-cbse-5feaba32e9fb3d3419e4a61a

calculate the change in gravitational potential energy when a 10kg object falls from 6m on earth

Answers

Answer:

600

Explanation:

GPE=mgh (mass*gravitational force*height)

m=10 kg

g=10

h=6m

10*10*6= 600 Joules

g A 150-kg object and a 450-kg object are separated by 4.90 m. (a) Find the magnitude of the net gravitational force exerted by these objects on a 39.0-kg object placed midway between them. 130000000000 Incorrect: Your answer is incorrect. Draw a picture of the three objects, including the forces exerted on the third. N (b) At what position (other than an infinitely remote one) can the 39.0-kg object be placed so as to experience a net force of zero from the other two objects

Answers

Answer:

BBbbb

Explanation:

B is the correct answer:))))

A object travels at constant negative acceleration. What does the graph of the object's velocity as a fun
(1 point)
O a curved line increasing from left to right
O a straight line with negative slope
O a straight line with positive slope
O a curved line decreasing from left to right

Answers

Constant = straight line
“Travels at constant negative acc.”
Which is negative slope

Solution: B. Straight line w/ neg. slope

Your in an escape room. Only its real and your oxygen runs out in 3 minutes unless you solve this problem, The problem :a ball is thrown and travels 30 inches before bouncing, It bounces and travels 50% of the distance traveled. It continues to do this until coming to rest. What is the total distance traveled by ball? Also it's cold and dark and you have no phone nor anyone to ask. You have no ball

Answers

60 inches

because if 30=50% then 60=100% so its 60 inches

The sum of the series allows to find the result for the total distance that the ball bounces is:

            total distance = 59.52 in

A series is a set of things or numbers related by a specific operation.

They indicate that the ball falls from an initial height y₀ = 30 in. and it bounces 50% of the height and the process is repeated until it stops, see attached.

Let's build a table to observe the sequence.

drop   height    rebound

   1        30          15

   2       15            7.5

   3        7.5         3.75

If we call the first term y₀  

The first bounce can be found.

                             y₁ = [tex]\frac{y_o}{2}[/tex]

The second bounces.

                             [tex]y_2 = \frac{y_1}{2} \\y_2 = \frac{y_o}{4}[/tex]

The third bounce.

                             [tex]y_3 = \frac{y_2}{2} \\y_3 = \frac{y_0}{ 8}[/tex]

By observing this table we can construct a series of the form

 

      Total distance = [tex]y_o \ ( 1 + \frac{1}{2} + \frac{1}{4}+ \frac{1}{8} + ... +\frac{1}{2n} )[/tex]

The sum of the serie has a result of

        sum  = 127/64 = 1,984

Let's calculate

     distance total  = 30 1,984

     Distance total = 59.52 cm

In conclusion, using the sum of the series we can find the result for the total distance that the ball bounces is:

            total distance = 59.52 in

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when a torque is acting on a fly wheel the angular velocity of the fly wheel changes from 10rad/sec to 25rad/sec in 5sec.what will be the magnitudes of the angular acceleration of the fly wheel?​

Answers

Hello!

We can use the following angular kinematic equation to solve:

α = Δω/Δt, or (ωf-ωi)/t

Plug in the given values:

α = (25 - 10)/5 = 15/5 = 3 rad/sec²

a process generates 250 watts of useful energy and 600 watts of waste energy. WhT is the efficiency of the process?
O29percent
O2.4percent
O42 percent
O71percent

Answers

The efficiency of the process is 42%

From the question given above, the following data were obtained:

Useful energy = 250 watt

Wasteful energy = 600 watt

Efficiency =?

The efficiency of the process can be obtained as illustrated below:

[tex]efficiency \: = \frac{useful \: energy}{wasteful \: energy} \times 100 \\ \\ efficiency \: = \frac{250}{600} \times 100 \\ [/tex]

Efficiency = 42%

Therefore, the efficiency of the process is 42%

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Answer:

Its actually 29%

Explanation:

Took the Test

A. A small, closed chamber of gas is heated. When the gas in the
chamber expands, it does 5 J of work on a piston. The gas has
an initial energy of 8 J and a final energy of 30 J. Considering
the equation for the first law of thermodynamics (AU = Q + W.
does the work done in this scenario have a positive or negative
value? Explain.
B. How much heat is added to the gas in the chamber?

Answers

A.

The work has a negative value.

Since the gas in the chamber expands, it increases in volume and does positive work on the piston since the change in volume is positive.

Work, W = pΔV. Since the gas expands, ΔV > 0. So, W > 0. Thus Work done by the gas is positive.

Since in ΔU = Q + W, W here is work done by the surroundings, W is negative since it is the opposite of the work done on the surroundings by the gas..

So, the work has a negative value.

B.

The heat added to the gas chamber is 17 J

From the first law of thermodynamics, ΔU = Q + W where ΔU = internal energy change = U₂ - U₁ where U₁ = initial energy = 8 J and U₂ = final energy = 30 J, Q = heat added to the gas chamber and W = work on piston = - 5 J

ΔU = Q + W

U₂ - U₁  = Q + W

30 J - 8 J = Q + (-5 J)

22 J = Q - 5 J

Q = 22 J + 5 J

Q = 27 J

The heat added to the gas chamber is 27 J.

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PLEASE HELP DUE TODAY
When same vectors are in the same direction they add. When same vectors are in opposite directions, they

a, also add
b, subtract
c, multiply
d, divide

Answers

Answer:

The answer is a (also add)

what are the greenhouse gasses in the earth that are primarily responsible for the greenhouse effect on Earth

Answers

Answer:

Water Vapour, Carbon dioxide, methane,nitrous oxide,ozone.

What is Motion ????? ​

Answers

Answer:

the action or process of moving or being moved.

Explanation:

which an object changes its position over time

A baseball is hit with a speed of 30.0 m/s at an angle of 47.0 ∘ . It lands on the flat roof of a 11.0 m -tall nearby building. If the ball was hit when it was 1.4 m above the ground, what horizontal distance does it travel before it lands on the building?

Answers

Answer:

500m/s

Explanation:

ma thii nay pathe me thuda dase dangur ni puthar

500m/s
This might help u
Pls mark me as a brainlist

question below................

Answers

Answer:

do your work why you in class and you would know

Explanation:

A rod of length 0.82 m, rotating with an angular speed, 4.2 rad/s, about axes that pass perpendicularly through one end, has a mass of 0.63 kg, which is distributed uniformly along its length. Find the kinetic energies of the rod.

Answers

Hi there!

[tex]\large\boxed{KE =1.245 J}}[/tex]

The equation of angular kinetic energy is:

[tex]KE = \frac{1}{2}Iw^2[/tex]

Where:

I = moment of inertia (kgm²/s)

ω = angular speed (rad/sec)

A rod rotated about one of its endpoints has a standard moment of inertia of 1/3mR², so:

[tex]KE = \frac{1}{2}(\frac{1}{3}mL^2w^2)[/tex]

[tex]KE = \frac{1}{6}mL^2w^2[/tex]

Plug in the given values:

[tex]KE = \frac{1}{6}(0.63)(0.82^2)(4.2^2) = 1.245 J[/tex]

a police finds skid marks 60m long on a highway showing where a car made an emergency stop. assuming that the acceleration was -10m/s2. how fast was the car going and did it exceed the sooed limit of 80km/h?​

Answers

the answer is 029 and 177 hours later i’m going on my grandma to

Answer:

029 and 177

simple luv:)

Explanation:

Given that T= [L] * [m] Y [Lt-2]Z
Find

1) Y

2)X

3)Z

Answers

Answer:

2

Explanation:

please mark me as brainlist i need it so sorry

Over a period of 3 seconds, a speedboat accelerates uniformly from 20 m/s
to 50 m/s. What is the acceleration of the speedboat relative to the shore?

Answers

The acceleration of the speedboat relative to the shore is 10m/s²

Acceleration is the change in velocity of an object with respect to time. Mathematically;

Acceleration = change in velocity/Time

Change in velocity = 50 - 20

Change in velocity = 30m/s

Time = 3secs

Substitute into the formula to have:

acceleration = 30/3

acceleration = 10m/s²

Hence the acceleration of the speedboat relative to the shore is 10m/s²

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