Based on the molecular formula, determine whether each of the following is an alkane, alkene, or alkyne. (Assume that the hydrocarbons are noncyclical and there is no more than one multiple bond.)
a. C3H6
b. C6H12
c. H8H18
d. C7H12

Answers

Answer 1

Answer:

C₃H₆ is an alkene

C₆H₁₂ is an alkene

C₈H₁₈ is an alkane

C₇H₁₂ is an alkyne

Explanation:

To determine which of the compound is alkane, alkene, or alkyne,we shall use the general formula of alkane, alkene, and alkyne. This is illustrated below:

General formula for alkane => CₙH₂ₙ₊₂

General formula for alkene => CₙH₂ₙ

General formula for alkyne => CₙH₂ₙ₋₂

For C₃H₆:

n = 3

Alkane => CₙH₂ₙ₊₂ => C₃H₂₍₃₎₊₂ => C₃H₈

Alkene => CₙH₂ₙ => C₃H₂₍₃₎ => C₃H₆

Alkyne => CₙH₂ₙ₋₂ => C₃H₂₍₃₎₋₂ => C₃H₄

Thus, C₃H₆ is an alkene

For C₆H₁₂:

n = 6

Alkane => CₙH₂ₙ₊₂ => C₆H₂₍₆₎₊₂ =>C₆H₁₄

Alkene => CₙH₂ₙ => C₆H₂₍₆₎ => C₆H₁₂

Alkyne => CₙH₂ₙ₋₂ => C₆H₂₍₆₎₋₂ => C₆H₁₀

Thus, C₆H₁₂ is an alkene

For C₈H₁₈:

n = 8

Alkane => CₙH₂ₙ₊₂ => C₈H₂₍₈₎₊₂ => C₈H₁₈

Alkene => CₙH₂ₙ => C₈H₂₍₈₎ => C₈H₁₆

Alkyne => CₙH₂ₙ₋₂ => C₈H₂₍₈₎₋₂ => C₈H₁₄

Thus, C₈H₁₈ is an alkane.

For C₇H₁₂:

n = 7

Alkane => CₙH₂ₙ₊₂ => C₇H₂₍₇₎₊₂ => C₇H₁₆

Alkene => CₙH₂ₙ => C₇H₂₍₇₎ => C₇H₁₄

Alkyne => CₙH₂ₙ₋₂ => C₇H₂₍₇₎₋₂ => C₇H₁₂

Thus, C₇H₁₂ is an alkyne.

SUMMARY:

C₃H₆ is an alkene

C₆H₁₂ is an alkene

C₈H₁₈ is an alkane

C₇H₁₂ is an alkyne


Related Questions

Explain the difference between atom and element

Answers

Answer:

an atom is the smallest part of an element that has the properties of that element

it can't be broken further into smaller substances

an element is the simplest chemical

it consists of one type of atoms

so you can consider atoms as the building block of an element

If the pressure, volume, and temperature of a gas are known, which can most likely be found by using the ideal gas law?
a.the molar amount of the gas
b.the partial pressure of the gas
c.the standard temperature and pressure
d.the molar mass

Answers

Answer:

the moral amount of the gas.

Which of the following is not a natural
way water is stored in the water cycle?
A Stream
B. Pond
C. Iceberg
D. Cup

Answers

Answer:

cup...................

Yes it is definitely D: Cup

help asap pleaseeeeeee

Answers

I believe it is in this order? Not 100% sure on a and b
A.1
B.4
C.5
D.3
E.2

The data below shows the change in concentration of dinitrogen pentoxide over time, at 330 K, according to the following process.
2N2O5(g) = 4NO2(g) + O2
[N2O5] Time (s)
0.100 0.00
0.066 200.00
0.044 400.00
a) Find the rate of disappearance of N2O5 from t=0 s to t=200s
b) Find the rate of appearance of NO2 from t=0 s to t =200s

Answers

Answer: a) [tex]1.7\times 10^{-4}[/tex]

b) [tex]3.4\times 10^{-4}[/tex]

Explanation:

The reaction is :

[tex]2N_2O_5(g)\rightarrow 4NO_2(g)+O_2(g)[/tex]

Rate = Rate of disappearance of [tex]N_2O_5[/tex] = Rate of appearance of [tex]NO_2[/tex]

Rate =  [tex]-\frac{d[N_2O_5]}{2dt}[/tex] = [tex]\frac{d[NO_2]}{4dt}[/tex]

Rate of disappearance of [tex]N_2O_5[/tex] = [tex]\frac{\text {change in concentration}}{time}[/tex] = [tex]\frac{0.100-0.066}{200-0}=1.7\times 10^{-4}[/tex]

a) Rate of disappearance of [tex]N_2O_5[/tex] = [tex]-\frac{d[N_2O_5]}{2dt}[/tex]

Rate of appearance of [tex]NO_2[/tex] = [tex]\frac{d[NO_2]}{4dt}[/tex]

b) Rate of appearance of [tex]NO_2[/tex] =  [tex]\frac{d[NO_2]}{dt}=2\times 1.7\times 10^{-4}}=3.4\times 10^{-4}[/tex]

A) Find the rate of disappearance of [tex]N_2O_5[/tex] from t = 0 s to t = 200s

[tex]Rate = \frac{1}{2}(\frac{-\delta N_2O_5}{\delta t})\\\\Rate = -\frac{1}{2}(\frac{0.066 - 0.100}{200 - 0})\\\\Rate = 8.5*10^{-5}[/tex]

B) Find the rate of appearance of [tex]NO_2[/tex] from t = 0 s to t = 200s

According to rate law,

[tex]\frac{1}{2}(\frac{-\delta N_2O_5}{\delta t}) = \frac{1}{4}(\frac{\delta NO_2}{\delta t})\\\\8.5*10^{-5} = \frac{1}{4}(\frac{\delta NO_2}{\delta t})\\\\\frac{\delta NO_2}{\delta t} = 4 * 8.5*10^{-5}\\\\Rate = 3.4*10^{-4}[/tex]

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5. When an electric current is passed through water during the process of electrolysis, two gases are formed. One gas has a boiling point of -183°C and the other has a boiling point of -253ºC. Was this event a physical
change or a chemical change?
It was a chemical change.
It was both a chemical and physical change
It was a physical change
It could have been either a physical or chemical change.

Answers

Answer:

Change is happening all around us all of the time. Just as chemists have classified elements and compounds, they have also classified types of changes. Changes are classified as either physical or chemical changes. Chemists learn a lot about the nature of matter by studying the changes that matter can undergo. Chemists make a distinction between two different types of changes that they study—physical changes and chemical changes.

At what temperature a gas with volume 175 L at 15 oC and 760mmHg will occupy a volume of 198 L at a pressure 640mmHg?

Answers

Answer:

To calculate the pressure when temperature and volume has changed, we use the equation given by combined gas law. The equation follows:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

T

1

P

1

V

1

=

T

2

P

2

V

2

where,

P_1,V_1\text{ and }T_1P

1

,V

1

and T

1

are the initial pressure, volume and temperature of the gas

P_2,V_2\text{ and }T_2P

2

,V

2

and T

2

are the final pressure, volume and temperature of the gas

We are given:

\begin{gathered}P_1=760mmHg\\V_1=175L\\T_1=15^oC=[15+273]K=288K\\P_2=640mmHg\\V_2=198L\\T_2=?K\end{gathered}

P

1

=760mmHg

V

1

=175L

T

1

=15

o

C=[15+273]K=288K

P

2

=640mmHg

V

2

=198L

T

2

=?K

Putting values in above equation, we get:

\begin{gathered}\frac{760mmHg\times 175L}{288K}=\frac{640mmHg\times 198L}{T_2}\\\\T_2=274K\end{gathered}

288K

760mmHg×175L

=

T

2

640mmHg×198L

T

2

=274K

Hence, the temperature when the volume and pressure has changed is 274 K

Arrange the compounds below in decreasing order of the ionic character of the bonds in them.

a. CsF
b. OF2
c. SrF2
d. F2

Answers

Answer: [tex]CsF[/tex] > [tex]SrF_2[/tex] >  [tex]OF_2[/tex]  > [tex]F_2[/tex]

Explanation:

The percent ionic character is used to determine if a bond is more ionic or covalent. More is the percent ionic character, the more ionic the molecule is. If the electronegativity difference between two elements is higher than 1.7 it will be considered as ionic.

The electronegativity difference for CsF is (3.98-0.79) = 3.19

The electronegativity difference for [tex]OF_2[/tex] is = (3.98-3.44) = 0.54

The electronegativity difference for [tex]SrF_2[/tex] is (3.98-0.95) = 3.0

The electronegativity difference for [tex]F_2[/tex] is  0.

Thus decreasing order of  ionic character of the bonds is CsF >  [tex]SrF_2[/tex] >  [tex]OF_2[/tex]  > [tex]F_2[/tex]

If the wavelength of red light is 650 x 10^-9 meters (or 6.50x10^-7m) and the speed of light (c) is 3.00 x 10^8 m/s , what is its frequency in Hz?(1/sec = Hz) , and c = (wavelength x frequency)

Answers

Answer:

f = 4.6 × 10¹⁴ Hz

Explanation:

Given data:

Wavelength  of light = 6.50x10^-7m

Speed of light = 3.00 x 10^8 m/s

Frequency of light = ?

Solution:

Formula:

Speed of radiation = frequency × wavelength

by putting values,

3×10⁸ m/s  =  f × 6.50x10^-7m

f  =  3×10⁸ m/s   /  6.50x10^-7m

f  =  0.46 × 10¹⁵ s⁻¹

f = 0.46 × 10¹⁵ Hz

f = 4.6 × 10¹⁴ Hz

Atoms have _______ different subatomic particles.
A. 7
B. 5
C. 3
D. None of the above

Answers

Answer:

C. 3

Explanation:

I hope my answer will be useful

6- A favorable condition for two elements to form an ionic bond is?
a- both should be electronegative
b- one should have low electron affinity and the other low ionization energy.
C- one should have high electron affinity and the other low ionization energy.
d- both should be highly electronegative​

Answers

Answer: C- one should have high electron affinity and the other low ionization energy.

Explanation:

Ionization energy is the energy required to remove the electron from an isolated gaseous atom.

Electron affinity is the tendency of an isolated atom to attrcat the electrons towards itsellf.

An ionic bond is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element or the metal and it can donate electron easily if it has low ionization energy.

The element which accepts the electrons is known as electronegative element or non metal and it can easily accept the electron if it has high electron affinity.

Write electron configuration
1s
2s
2p
3s
3p
4s
3d
4p
5s
4d

Answers

Answer:

Here:

Explanation:

Determine the number of electrons in the atom from its atomic number. (See Below.)

Add electrons to the sublevels in the correct order of filling.

Add two electrons to each s sublevel, 6 to each p sublevel, 10 to each d sublevel, and 14 to each f sublevel.

To check your complete electron configuration, look to see whether the location of the last electron added corresponds to the element’s position on the periodic table.

Predicting the Order of Filling of the Orbitals

There are three ways to predict the order of filling of the orbitals. Probably the least reliable method is to memorize the following list (even though it shows the order of filling of all the orbitals necessary for describing the ground state electron configurations of all of the known elements).

1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p 6s 4f 5d 6p 7s 5f 6d 7p

Instead of relying on memorization, you can use the memory aid shown below to remind you of the correct order of filling of the sublevels. The following steps explain how to write it and use it yourself.

Write the possible sublevels for each energy level in organized rows and columns like the image below. To do this, you need to remember that there is one sublevel on the first principal energy level, two on the second, three on the third, etc. Every principal energy level has an s orbital. The second principal energy and all higher energy levels have a p sublevel. The d sublevels start on the third principal energy level, the f sublevels start on the fourth principal energy level, etc.

Draw arrows like those you see below .

Starting with the top arrow, follow the arrows one by one in the direction they point, listing the sublevels as you pass through them.

The sublevels that are not needed for describing the known elements are enclosed in parentheses below .

Image of the memory aid that allows you to determine the order of filling for the sublevels

We can also use the block organization of the periodic table, as shown below, to remind us of the order in which sublevels are filled. To do this, we move through the elements in the order of increasing atomic number, listing new sublevels as we come to them. The type of sublevel (s, p, d, or f ) is determined from the block in which the atomic number is found. The number for the principal energy level (for example, the 3 in 3p) is determined from the row in which the element is found and the knowledge that the s sublevels start on the first principal energy level, the p sublevels start on the second principal energy level, the d sublevels start on the third principal energy level, and the f sublevels start on the fourth principal energy level.

We know that the first two electrons added to an atom go to the 1s sublevel.

Atomic numbers 3 and 4 are in the second row of the s block (look for them in the bottom half of in image below), signifying that the 3rd and 4th electrons are in the 2s sublevel.

Atomic numbers 5 through 10 are in the first row of the p block, and the p sublevels start on the second energy level. Therefore, the 5th through 10th electrons go into the 2p sublevel.

Atomic numbers 11 and 12 are in the third row of the s block, so the 11th and 12th electrons go into the 3s sublevel.

Because atomic numbers 13 through 18 are in the p block, we know they go into a p sublevel. Because the p sublevels begin on the second principal energy level and atomic numbers 13 through l8 are in the second row of the p block, the 13th through 18th electrons must go into the 3p sublevel.

The position of atomic numbers 19 and 20 in the fourth row of the s block and the position of atomic numbers 21 through 30 in the first row of the d block show that the 4s sublevel fills before the 3d sublevel.

Moving through the periodic table in this fashion produces the following order of sublevels up through 6s:

1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p 6s

Notice that atomic numbers 57 through 70 on the periodic table below are in the 4f portion of the table. It is a common mistake to forget that the 4f sublevel is filled after the 6s sublevel and before the 5d sublevel. In order to make the overall shape of the table more compact and convenient to display, scientists have adopted the convention of removing the elements with atomic number 57 through 70 and 89 through 102 (the latter being the 5f portion of the table) from their natural position between the s and d blocks and placing them at the bottom of the table. Electrons go into the 5f sublevel after the 7s sublevel and before the 6d sublevel. The second periodic table below shows how the blocks on the periodic table would fit together if the inner transition metals­—the f block—were left in their natural position.

Uranium (VIII) Sulfide formula

Answers

Answer:

US₂

Explanation:

Uranium sulfide (US₂)

Uranium atomic symbol = U

Sulfur atomic symbol = S

Uranium valency = +4

Sulfur valency = -2

So;

Uranium sulfide (US₂)

If you have moles and want to convert to liters, which conversion factor would you use

Answers

Answer:

When converting from liters to moles or moles to liters, you will use the equality 1 mole=22.4 L for a gas at STP.

If you have moles and want to convert to (Volume) liters, 1 mole = 22.4 L is the conversion factor that can be used.

The area that any three-dimensional solid occupies is known as its volume. These solids can take the form of a cube, cuboid, cone, cylinder, or sphere. Various forms have various volumes. We have studied the several solids and forms that are specified in three dimensions, such as cubes, cuboids, cylinders, cones, etc., in 3D geometry. We will discover how we can determine the volume for each of these shapes. One mole of any gas have 22.4 L at STP.

1 mole = 22.4 L

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A student sets up the following equation to convert a measurement.
(The ? stands for a number the student is
going to calculate.)
Fill in the missing part of this equation.
Note: your answer should be in the form of one or more fractions multiplied together.
gcm
3 kg.m
-2.9 x 10
0x0
.
X Х
5

Answers

Answer:

9 . this was not able the first one. it has to go on, I will not sure about

In the reaction shown below, cobalt ...
Co(s) + Ni (C2H302)2(aq) → Co(C2H302)2(aq) + Ni(s)

A) gains electrons and is reduced
B) loses electrons and is oxidised
C) loses electrons and is reduced
D) gains electrons and is oxidised

Answers

B) loses electrons and is oxidised

Its oxidation number is 0 in Co(s) and +2 in Co(C2H302)2(aq), hence it gets oxidised

In the reaction as mentioned below:-

[tex]Co(s) + Ni(C2H302)2aq -- > Co(C2H3O2)2aq + Ni(s)[/tex]

As shown in reaction cobalt losses elections so the reaction is oxidised.  Thus, option b is correct.

What is oxidation?

Oxidation is a type of reaction in which loss of electrons and gain of protons is takes place during a reaction by molecules, atom or ion. Oxidation takes place when the oxidation state of a molecule, atoms or ion is increased.

The opposite reaction is called as reduction in which gains of electron and loss of protons is takes place . In reduction reaction the oxidation state of molecules, atoms or ion is decreased.

Oxygen has been added to a compound as an older method of oxidation.  Although oxygen is typically added to a compound in compliance with the loss of electrons requirements and the oxidation state increase.

Therefore, we can say that in the reaction

[tex]Co(s) + Ni(C2H302)2aq -- > Co(C2H3O2)2aq + Ni(s)[/tex]

As shown in reaction cobalt losses elections so the reaction is oxidised.  Thus, option b is correct.

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If the density of a certain oil is 0.8gcm3. What is the mass of 10 cm3 sample of this oil?
report your answer with one significant figure.

Answers

Taking into account the definition of density, the mass of the sample of oil with a volume of 10 cm³ and a density of 0.8 [tex]\frac{g}{cm^{3} }[/tex]  is 8 grams.

Definition of density

Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.

In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.

Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

[tex]density=\frac{mass}{volume}[/tex]

From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.

Mass of the sample of oil

In this case, you know that:

Density= 0.8 [tex]\frac{g}{cm^{3} }[/tex]Volume= 10 cm³

Replacing in the definition of density:

[tex]0.8 \frac{g}{cm^{3} } =\frac{mass}{10 cm^{3} }[/tex]

Solving:

mass=  0.8 [tex]\frac{g}{cm^{3} }[/tex] × 10 cm³

mass= 8 g

In summary, the mass of the sample of oil with a volume of 10 cm³ and a density of 0.8 [tex]\frac{g}{cm^{3} }[/tex]  is 8 grams.

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How did Wilma contribute to change in America

Answers

Answer:

She overcame her disabilities to compete in the 1956 Summer Olympic Games, and in 1960, she became the first American woman to win three gold medals in track and field at a single Olympics. Later in life, she formed the Wilma Rudolph Foundation to promote amateur athletics.

Explanation:

Need help asap!

1. Given that the electronegativity of sulfur (S) is 2.5 and that of silicon (Si) is 1.8, which of the following best describes the chemical bonding in silicon monosulfide (SiS)?
A. ionic: transfer of electrons from silicon to sulfur
B. nonpolar covalent: equal sharing of electrons between silicon and sulfur
C. polar covalent: electrons shared between silicon and sulfur but attracted more to the sulfur
D. polar covalent: electrons shared between silicon and sulfur but attracted more to the silicon

2. Which of the following is a molecular compound?

A. Mg3N2
B. NH3
C. AlCl3
D. LiBr

3. Potassium (K) reacts with a certain nonmetallic element (Z) to form a compound with the general formula KZ; where element Z is a diatomic gas at room temperature. What is element Z?

A. Oxygen
B. Fluorine
C. Nitrogen
D. Hydrogen

Answers

Answer: 1.  C. polar covalent: electrons shared between silicon and sulfur but attracted more to the sulfur

2. B)  [tex]NH_3[/tex]

3. B) Fluorine

Explanation:

1. A polar covalent bond is defined as the bond which is formed when there is a difference of electronegativities between the atoms.

Electronegativity difference = electronegativity of sulphur- electronegativity of silicon = 2.5 -1.8 = 0.7

Thus as electronegativity difference is less than 1.7 , the cond is polar covalent and as electronegativity of sulphur is more , the electrons will be more towards sulphur.

2. A molecular compound is usually composed of two or more nonmetal elements. Example: [tex]NH_3[/tex]

Ionic compound is formed by the transfer of electrons from metals to non metals. Example: [tex]Mg_3N_2[/tex] , [tex]AlCl_3[/tex] and [tex]LiBr[/tex]

3.  For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

Here K is having an oxidation state of +1 and as the compound formed is KZ, the oxidation state of non metallic element Z should be -1. Thus the element Z is flourine which exists as diatomic gas [tex]F_2[/tex]

how long does crushed candy dissolve in a warm water​

Answers

Answer:

Because of reaction between solid and liquid

Answer:

shouldn't take that long i would say from 30 to 40 minutes bc its melting in warm water its turning from a solid to a liquid.

Explanation:

(2)
3.
How would you calculate the change in entropy when the pressure of a perfect gas is
changed isothermally from P; to Pr​

Answers

How would you calculate the change in entropy when the pressure of a perfect gas is changed isothermally from P_i to P_f

Answer:

ΔS = nRIn(P_i/P_f)

Explanation:

Formula for entropy change is;

ΔS = nC_p•In(T_f/T_i) + nRIn(P_i/P_f)

Since the pressure of the perfect gas is changed isothermally, it means that temperature remains the same and as such T_f = T_i

Thus, we now have;

ΔS = nC_p•In(1) + nRIn(P_i/P_f)

In(1) = 0

Thus;

ΔS = nRIn(P_i/P_f)


why do liquids fill the bottom of a container ​

Answers

Answer:

Liquids take the shape of their containers because they are stuck together enough to not go flying off like gases but not so tightly that they stay in a stiff shape like solids do.

Explanation:

Hope this helps you! ^^

The specific heat capacity of methane gas is 2.20 J/g-K. How many joules of heat are needed to raise the
temperature of 5.00 g of methane from LaTeX: 36.0^\circ C36.0 ∘ C to LaTeX: 75.0^\circ C75.0 ∘ C?

Answers

Heat needed to raise the temperature : Q = 3432 J

Further explanation

Given

c = The specific heat capacity = 2.20 J/g-K

m = mass = 5 g

Δt = Temperature difference = 75-36 =39 °C=312 K

Required

Heat needed

Solution

Heat can be formulated

Q = m.c.Δt

Input the values :

Q = 5 g x 2.2 J/g-K x 312 K

Q = 3432 J

Copper metal reacts with silver nitrate to produce silver metal and copper (II) nitrate.
the correct equation for this reaction is:
A: Cu + SiN—> Si + Cu2N

B: 2Cu + AgNO3–> Ag +
Cu(NO3)2

C: Cu + 2 AgNO3–> Ag + Cu(NO3)2

D:Cu + AgNO3–> Ag + CuNO3

Answers

Answer:

Cu    +    2AgNO₃  →   2Ag    +    Cu(NO₃)₂

Explanation:

The reactants are:

         Copper metal  = Cu

         Silver nitrate  = AgNO₃

The products are:

          Silver metal  = Ag

           Copper (II) nitrate  = Cu(NO₃)₂

So, the reaction equation is given as;

      Cu    +    2AgNO₃  →   2Ag    +    Cu(NO₃)₂

This is a single displacement reaction

HELP ASAP!

Which data value is most likely to be an error in the data shown?
A. The .64 in trial 2
B. The 6.4 in trial 1
O C. The 1.7 in trial 1
D. The 6.3 in trial 3

Answers

Answer:

0.64 in trial 2

Explanation:

Which of the following would be the best thing to do to reverse the impact humans have had on the enviroment?

A. Change the way we approch science

B. Stop growing as a population

C. Change our resource use habits

D. Stop using technology

Which one is the right one? think 40 points for answer : )

Answers

Answer:

I think its C

Explanation:

but don't trust me 2 much

The environment provides a vast array of materials and services that people use to live. Often these resources have competing uses and values.  In order to conserve environment change our resource use habits. The correct option is C.

What are environmental resources?

An environmental resource is any material, service, or information from the environment that is valuable to society. This can refer to anything that people find useful in their environs, or surroundings. Food from plants and animals, wood for cooking, heating, and building, metals, coal , and oil are all environmental resources.

Clean land, air, and water are environmental resources, as are the abilities of land, air, and water to absorb society's waste products. Heat from the sun, transportation and recreation in lakes, rivers, and oceans, a beautiful view, or the discovery of a new species are all environmental resources.

Thus the correct option is C.

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please complete work

Calculate the molar mass of ammonium salfate:(NH4)2SO4

Answers

Answer:

132.14 g/mol

Explanation:

Will mark brainliest!!!! 15 pts!!!!Please solve these equations

Answers

2 K3PO4 + 3 BaCl2 = 6 KCl + Ba3(PO4)2
reaction type: double replacement

2 Al(OH)3 + 3 H2SO4 = Al2(SO4)3 + 6 H2O
reaction type: double replacement

2 HCl + K2CO3 = 2 KCl + H2O + CO2
i think there are two reactions here, so double replacement and decomposition

2 AgNO3 + Na2CO3 = Ag2CO3 + 2 NaNO3
reaction type: double replacement

2 Al2O3 = 4 Al + 3 O2
reaction type: decomposition

An alkene reacts with a strong protic acid to form a carbocation. In Part 1 draw the curved arrow notation for the reaction between an alkene and HBr. However, an alkene will react with a halogen electrophile to form a cyclic intermediate. In Part 2 draw the curved arrow notation for the reaction between an alkene and Br2.

Answers

Answer:

See explanation and image attached

Explanation:

Now, we have chosen the alkene 1-propene in our example.

In the first reaction of  1-propene  with HBr, the reaction proceeds by ionic mechanism leading to the formation of 2-bromo propane.

In the second reaction of  1-propene  with the bromine molecule, the first step is the formation of the brominium cation which is a cyclic intermidiate followed by the addition of Br^- yielding the 1,2- dibromopropane product

Which of the following is an example of chemical weathering?

plant roots splitting rocks
acid dissolving limestone
water breaking rocks
wind breaking down rock

Answers

Answer:

Estoy deprimido y odio la vida. Así que sí

Acid dissolveing???????
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