Based on this data, what is a reasonable estimate of the probability that the next type of stir fry ordered is shrimp? Choose the best answer. Choose 1 answer: Choose 1 answer:

The answer is 104°.

.. .. ..

Answer:

Step-by-step explanation:

A line is always equal to 180. So if angle POR is 76, you would do 180-76 which equals 104.

Answer:

$62

Step-by-step explanation:

Hello it's $62 because 31 x 2 = 62 and it was half off so that is why its $62

Answer:

The original price is 62 dollars.

Answer:

117π=367.38

Step-by-step explanation:

r=d/2=3

V=πr2h=π·3²·13=117π=367.38

The diagram isn't attached. However, a rated diagram has been found and attached below.

Answer:

0.8611

Step-by-step explanation:

The probability of an event involves taking the ratio of the required measurement and the entire measurement.

Based on information on the attached circle, the shaded region of the circle takes 310° of the entire 360°

Choosing a point at random from which nside the circle ;

P(shaded portion) = shaded section / total measure of circle

P(shaded point) = 310 / 360 = 0.8611

Answer: X=10

Step-by-step explanation:

Answer:

que pasa parsero deja de esta mostrando el manda aquí vale

Answer:

-20 2/5 (2/5 as fraction)

Answer:

√65/2 square units

Step-by-step explanation:

Find the diagram attached

Area of the triangle = 1/2 * base * height

To get the base and height, we will use the distance formula;

Area of the triangle LMN = 1/2 * LM * MN

For MN

Given the coordinate M(3, 2) and N(1, 3)

MN = √(3-2)²+(1-3)²

MN = √1²+(-2)²

MN = √1+4

MN = √5

For LM;

Given the coordinate L(1, -1) and M(3, 2)

LM = √(2-(-1))²+(3-1)²

LM = √(2+1)²+(2)²

LM = √3²+(2)²

LM = √9+4

LM = √13

Area of the triangle LMN = 1/2 * √13 * √5

Area of the triangle LMN = √65/2 square units

Answer:

I think it's c.

Step-by-step explanation:

Answer:

B. √x.

Step-by-step explanation:

That would be B - the square root of x.

Answer:

-33.

Step-by-step explanation:

[12 -5 x 9]

= 12 - 45

= -33.

Answer:

-36

Step-by-step explanation:

[12-45]=3

-33=3

-33-3=-36

Answer:

The domain of √x - 1 is x ≥ 0

Step-by-step explanation:

The function f(x) = √x has real outputs only for x ≥ 0.  The constant -1 is defned for all x.  

The domain of √x - 1 is x ≥ 0.

Answer:

YOU DONT KNOW HOW TO ROUND SMH

Step-by-step explanation:

LEARN KID LEARN CMON ITS EASY

Answer:

No solution

Step-by-step explanation:

Answer:

No solution

Step-by-step explanation: X can only have 1 anser and -1.25 would make it negative.

Answer:

Disjointed

Step-by-step explanation:

Their economy and a lot of structures were destroyed which left them struggling to recover.

Aisha's net balance after writing the check of $100 to five employees will be $260 .

Given, Aisha’s account balance $760.

Now, to get the net balance of account after deductions .

Remaining amount = Original Balance - Payment amount.

Substitute the values,

Remaining amount = $760 - 5 × $100

Remaining amount = $760 - $500

Remaining amount = $260

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Step-by-step explanation:

Since bx can be defined for all real numbers r, the domain of an exponential function is all real numbers. The range of bx is all real numbers greater than 0. ... If b > 1, then f is an increasing function. I.e. f(x) increases in value as x increases.

La respuesta correcta para esta pregunta abierta es la siguiente.

Desafortunadamente, no nos especificas a qué escuela te refieres, ni al lugar, condado, pueblo, región o ciudad. Hay miles de grupos de"5to Grado." ¿A cuál de todos te refieres?

Tampoco especificas si esta es una pregunta de cultura en general, de música, o es algún problema de matemáticas o estadística.

Si fuera de matemáticas, también se te olvidó incluir todos los datos, números y nombres para ayudarte a responder.

Sin embargo, con la idea de ayudarte un poquito, podemos comentarte lo siguiente de manera general.

El tipo de música grupera de banda gusta más entre los alumnos de quinto grado es generalmente la música de banda como la Banda Machos, los Tucanes de Tijuana, La Banda MS, la Banda el Recodo de Cruz Lizárraga, la Banda Mexicana o la Banda Arrolladora. Estas bandas mexicanas son muy populares en México, Centro y Sudamérica y los Estados Unidos.

Answer:

The purpose is to increase the generalizability of the results. By drawing a random sample from a larger population the goal is that the sample will be representative of the larger group and less likely to be subject to bias

Step-by-step explanation:

Answer:

Step-by-step explanation:

The purpose is to increase the generalizability of the results. By drawing a random sample from a larger population the goal is that the sample will be representative of the larger group and less likely to be subject to bias

Answer:

64[tex]\pi[/tex] mm² or approximately 201.06 mm²

Step-by-step explanation:

If the diameter is 16 mm, the radius will be 8 mm.

Use the circle area formula, A = [tex]\pi[/tex]r², where r is the radius. Plug in 8 as r:

A = [tex]\pi[/tex]r²

A = [tex]\pi[/tex](8²)

A = 64[tex]\pi[/tex]

So, the area of the circle is 64[tex]\pi[/tex] mm² or approximately 201.06 mm²

If the diameter of the circle above is 16 mm, what is the area of the circle ?

Diameter of the circle = 16 mm. (Given)

Radius (r) of the circle = 16/2 = 8 mm.

[tex] \bigstar [/tex] To Find the area of the circle.

Since we know,

[tex] \dag [/tex] Area of circle is πr².

So, Area of the circle = 3.14 × (8)²

Area of the circle = 3.14 × 8 × 8

Area of the circle = 200.96 = 201 mm².

Answer:

1.10 2.158 3.157 4.100. 5.32 6. 168 7.99 8.46 9.3

Step-by-step explanation:

Answer:

9, 84, 30, 10, 157, 45, 168, 3, 100, 99

Step-by-step explanation:

Answer: p(1/2)=11/2p(a)=a.

Step-by-step explanation:

Answer:

       2x3 - 5x2 + 2x - 7

 ——————————————————

       x - 2      

Step-by-step explanation:            2x3 - 5x2 + 2x - 7

Simplify   ——————————————————

                 x - 2      

Checking for a perfect cube :

3.1    2x3 - 5x2 + 2x - 7  is not a perfect cube

Trying to factor by pulling out :

3.2      Factoring:  2x3 - 5x2 + 2x - 7

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  2x - 7

Group 2:  2x3 - 5x2

Pull out from each group separately :

Group 1:   (2x - 7) • (1)

Group 2:   (2x - 5) • (x2)

Bad news !! Factoring by pulling out fails :

The groups have no common factor and can not be added up to form a multiplication.

Polynomial Roots Calculator :

3.3    Find roots (zeroes) of :       F(x) = 2x3 - 5x2 + 2x - 7

Polynomial Roots Calculator is a set of methods aimed at finding values of  x  for which   F(x)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  x  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  2  and the Trailing Constant is  -7.

The factor(s) are:

of the Leading Coefficient :  1,2

of the Trailing Constant :  1 ,7

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        -16.00    

     -1       2        -0.50        -9.50    

     -7       1        -7.00        -952.00    

     -7       2        -3.50        -161.00    

     1       1        1.00        -8.00    

     1       2        0.50        -7.00    

     7       1        7.00        448.00    

     7       2        3.50        24.50    

Polynomial Roots Calculator found no rational roots

Polynomial Long Division :

3.4    Polynomial Long Division

Dividing :  2x3 - 5x2 + 2x - 7

                             ("Dividend")

By         :    x - 2    ("Divisor")

dividend     2x3  -  5x2  +  2x  -  7

- divisor  * 2x2     2x3  -  4x2        

remainder      -  x2  +  2x  -  7

- divisor  * -x1      -  x2  +  2x    

remainder              -  7

- divisor  * 0x0                

remainder              -  7

Quotient :  2x2 - x

Remainder :  -7

so x=-7

Answer:

m<1 = 48°

m<2 = 132°

m<3 = 132°

m<5 = 48°

Step-by-step explanation:

Given:

m<4 = 48°

Required:

m<1, m<2, m<3, and m<5

Solution:

m<1 = m<4 (alternate exterior angles are congruent)

m<1 = 48° (substitution)

m<2 = 180° - (m<1) (linear pair theorem)

m<2 = 180° - 48° (substitution)

m<2 = 132°

m<3 = m<2 (alternate interior angles are congruent)

m<3 = 132° (substitution)

m<5 = m<4 (corresponding angles are congruent)

m<5 = 48° (substitution)

Answer: Find the length of A

3) Find the scale factor.

Step-by-step explanation:

Step-by-step explanation:

given

2x + y = 13

turning to y = ax + b we get

y = - 2x + 13

hope it helps :)❤

Given:

The functions are:

[tex]f(x)=2x+1[/tex]

[tex]g(x)=x^2[/tex]

To find:

The value of [tex]fg(3)[/tex].

Solution:

We have,

[tex]f(x)=2x+1[/tex]

[tex]g(x)=x^2[/tex]

Substitute [tex]x=3[/tex] in each function.

[tex]f(3)=2(3)+1[/tex]

[tex]f(3)=6+1[/tex]

[tex]f(3)=7[/tex]

And,

[tex]g(3)=(3)^2[/tex]

[tex]g(3)=9[/tex]

We know that, product of two functions is defined as:

[tex]fg(x)=f(x)\times g(x)[/tex]

Using this rule, we get

[tex]fg(3)=f(3)\times g(3)[/tex]

[tex]fg(3)=7\times 9[/tex]

[tex]fg(3)=63[/tex]

Therefore, the value of [tex]fg(3)[/tex] is 63.

Answer:

x = 3, JL = 17, MN = 13

Step-by-step explanation:

Given 2 intersecting chords in a circle , then

The product of the parts of one chord is equal to the product of the parts of the other chord, that is

14x = 7 × 6 = 42 ( divide both sides by 14 )

x = 3

Then

JL = x + 14 = 3 + 14 = 17

MN = 6 + 7 = 13

The correct letter that match each summation expression are;

[tex]\displaystyle \sum\limits_{i=1}^n[/tex] is equal to c

[tex]\displaystyle {\sum\limits_{i=1}^n i}[/tex] is equal to b

[tex]\displaystyle \sum_{i=1}^n c[/tex] is equal to d

[tex]\displaystyle\sum_{i=1}^n i^3[/tex] is equal to e

[tex]\displaystyle \sum\limits_{i=1}^n i^2[/tex]is equal to a

The summation expression indicates the sum of all values of a series of a function within a specified limit of values.

The equation for the sum of a constant c and the ith term of an of a sequence of numbers is equivalent to the product of the constant and the sum of the terms of the sequence as follows;

[tex]\sum\limits_{i=1} ^n {c\cdot a_i} = c\cdot \sum\limits_{i=1} ^n {a_i}[/tex] the correct option is c

The sum of ith terms from i = 1 to i = n is an arithmetic series with the formula;

Sₙ = (n/2)·[2·a + (n - 1)·d]

Where; a = The first term = 1

d = The common difference = 1

Therefore;

Sₙ = (n/2)·[2 + (n - 1)] = n + n·(n - 1)/2 = (2·n + n² - n)/2

(2·n + n² - n)/2 = (n² + n)/2 = n·(n + 1)/2

Therefore;

[tex]\sum\limits_{i=1}^n i = \dfrac{n\cdot (n + 1)}{2}[/tex] The correct option is b

The sum of n number of a constant, c is c·n, therefore;

[tex]\sum\limits_{i = 1}^n c = c\cdot n[/tex] The correct option is d

[tex]\sum\limits_{i=1}^n [(1 + i)^3-i^3[/tex] = (2³ - 1³) + (3³ - 2³) + ... + ((n + 1)³ - n³) = (n + 1)³ - 1³

(n + 1)³ - 1³ = n³ + 3·n² + 3·n

[tex]\sum\limits_{i=1}^n [(1 + i)^3-i^3[/tex] = n³ + 3·n² + 3·n

However, we get;'

[tex]\sum\limits_{i=1}^n [(1 + i)^3-i^3[/tex] = [tex]\sum\limits_{i=1}^n [ i^3 + 3\cdot i^2 + 3\cdot i+ 1-i^3][/tex]

[tex]\sum\limits_{i=1}^n [ i^3 + 3\cdot i^2 + 3\cdot i+ 1-i^3][/tex] = [tex]\sum\limits_{i=1}^n [ 3\cdot i^2 + 3\cdot i+ 1][/tex] = 3·S₂ + 3·S₁ + n

Where;

[tex]S_2 = \sum\limits_{i=1}^n i^2[/tex]

[tex]S_1 = \sum\limits_{i=1}^n i[/tex] = n·(n + 1)/2

[tex]\sum\limits_{i=1}^n [ 3\cdot i^2 + 3\cdot i+ 1][/tex] = n³ + 3·n² + 3·n = 3·S₂ + 3·S₁ + n

3·S₂ = n³ + 3·n² + 3·n - (3·S₁ + n) = n³ + 3·n² + 3·n - (3·(n·(n + 1)/2) + n)

n³ + 3·n² + 3·n - (3·(n·(n + 1)/2) + n) = n³ + 3·n²/2 + n/2

3·S₂ = n³ + 3·n²/2 + n/2

S₂ = n³/3 + 3·n²/6 + n/6 = (2·n³ + 3·n² + n)/6

S₂ = (2·n³ + 3·n² + n)/6 = n·(2·n² + 3·n + 1)/6

S₂ = n·(2·n² + 3·n + 1)/6 = n·(2·n + 1)·(n + 1)/6

S₂ = n·(2·n + 1)·(n + 1)/6

[tex]S_2 = \sum\limits_{i=1}^n i^2 = \dfrac{n\cdot (2\cdot n + 1)\cdot (n + 1)}{6}[/tex] The correct option is; a

(n + 1)⁴ - n⁴ = 4·n³ + 6·n² + 4·n + 1

Therefore;

(n + 1)⁴ - 1⁴ = 4·S₃ + 6·S₂ + 4·S₁ + n

4·S₃ = (n + 1)⁴ - 1⁴ - (6·S₂ + 4·S₁ + n)

(n + 1)⁴ - 1⁴- (6·(n·(2·n + 1)·(n + 2)/6) + 4·(n·(n + 1)/2) + n) = (n + 1)·(3·n² - n + 1)

4·S₃ = n²·(n + 1)²

S₃ = n²·(n + 1)²/4

[tex]S_3 = \sum\limits_{i=1}^n i^3 = \dfrac{n^2\cdot (n+1)^2}{4}[/tex] The correct option is e

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