Batman shoots a grappling hook
34.6 m/s at an 80.2° angle. What is the magnitude only (no direction) of the velocity of the hook 1.09 s later?

(Unit = m/s)

The radius of the hydrogen-atom Bohr orbit shown in the figure is 5.3 nm.

The path that hypothetical electrons take around the nucleus is known as Bohr's orbit.

These orbits are described by Bohr in his hypothesis of the structure of an atom as energy levels or shells where electrons move in a fixed circle around the nucleus.

These orbits resemble solar system orbits, with the exception that they are attracted by electrical forces rather than gravity. The term "ground state" refers to the amount of energy that an electron typically occupies.

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According to the right-hand rule, the magnetic field of the solenoid will be directed towards the left direction.

Right Hand Thumb Rule is the rule which is used If a current carrying conductor is imagined to be held in the right hand direction such that the thumb always points along the direction of the current flow, then the direction of the wrapped fingers in the hand will give the direction of the magnetic field lines of the bar magnet.

By the application of the right-hand rule, the magnetic field of the solenoid will be directed towards the left hand direction.

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To solve this we must be knowing each and every concept related to velocity. Therefore, the amplitude and maximum velocity are 0.23 m and 2.75 m/s respectively.

V is the velocity measurement of an object's rate of motion and direction of motion. As a result, in order to calculate velocity using this definition, we must be familiar with both magnitude and direction.

For example, if an item travels west with 5 meters a second (m/s), its velocity to the west will be 5 m/s. The most frequent and simplest approach to determine velocity is using the formula shown below.

v = √(k / m) ×A

v = velocity of the mass

k= spring constant

m =mass of the object

A= amplitude of the oscillation.

substituting all the given values in the above equation, we get

2.3 m/s = √(200 N/m / 3.00 kg)×A

A = 2.3 m/s / √(200 N/m / 3.00 kg)

    = 0.23 m

v =√(200 N/m / 3.00 kg) ×0.23 m

 = 2.75 m/s

Therefore, the amplitude and maximum velocity are 0.23 m and 2.75 m/s respectively.

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The crate will be under a net force of 95 N. Resolving the force in the x-direction yields the net force on the crate: F = 300 cos 10° - N F= 295.44-196.45, F= 95.

The resistive force of friction (Fr) divided by the normal or perpendicular force (N) pushing the objects together yields the coefficient of friction (fr), which is a numerical value. The formula fr = Fr/N serves as a representation of it.

The friction of a moving item is inversely proportional to the normal force and runs perpendicular to it. The type of surface the thing comes into touch with determines the amount of friction it experiences. As long as there is a point of contact, friction does not depend on the area of contact.

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The statement that best illustrates the application of the principles of behaviorism is -

"A parent is using "time out" as a consequence for bad behavior".

The theory that human and animal behaviour can be explained in terms of conditioning, without appeal to thoughts or feelings, and that some mental conditions are best treated by altering behaviour patterns.

Given are the applications of the principles of behaviorism.

The statement that best illustrates the application of the principles of behaviorism is -

"A parent is using "time out" as a consequence for bad behavior".

Therefore, the statement that best illustrates the application of the principles of behaviorism is -

"A parent is using "time out" as a consequence for bad behavior".

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If an object is working against gravity, that means gravity must have the opposite sign of the object (this is why we see objects slow down at their peak height and return to us if we throw them in the air!). If the object is working with gravity, though, they must both be moving in the same direction, therefore gravitational acceleration would be the same sign as the velocity (positive or negative depending on how you define your axes).

Therefore, your answer should be C. Different sign + or - on the acceleration.

I hope this helps!

Answer:

drops

Explanation:

Ohm's Law states that V=I*R, where V is voltage, I is current and R is resistance. In a series circuit, the voltage drop across each resistor will be directly proportional to the size of the resistor. In a parallel circuit, the voltage drop across each resistor will be the same as the power source

Answer:

To find the distance the vehicle traveled, you will need to find the average speed of the vehicle over the 4.60 seconds and multiply that by the time traveled.

The average speed of the vehicle can be found by adding the initial speed and the final speed, and then dividing by 2: (15.0 + 28.0) / 2 = 21.5 km/h.

The distance traveled can be found by multiplying the average speed by the time traveled: 21.5 km/h * 4.60 s = 98.7 km.

So, the vehicle will have traveled 98.7 km.

Explanation:

If heat is transferred between these objects via conduction, both arrows will point towards the cold.

Heat energy is transferred through the mechanism of conduction when nearby atoms or molecules collide. In solids and liquids, where particles are more closely spaced, conduction happens more easily than in gases, where particles are more widely spaced. Heat transfers through solid materials via conduction. The roof, walls, and windows of your house all carry heat on hot days.

The act of heating a skillet on a stovetop is a typical illustration of conduction. The surface of the pan receives heat directly from the burner. The amount of kinetic energy that the particles in a sample of matter have converted to heat is measured by temperature. Conduction mostly comes in two flavors. Steady-state conduction is what they are. temporary conduction.

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The initial horizontal velocity of the football if a player kicks a football from ground level with a velocity of 27/ms at an angle of 30 degrees above the horizontal is 23.662 m/s.

To find the initial horizontal velocity (Vx) of the football, you can use the horizontal component of the velocity vector. The horizontal component of velocity is found by multiplying the velocity by the cosine of the angle of launch.

[tex]V_{x}[/tex] = V × cos(angle)

where V is the initial velocity, the angle is the angle of launch (in this case, 30 degrees), and cos is the cosine function.

So, in this case, the initial horizontal velocity of the football would be:

[tex]V_{x}[/tex] = 27 m/s × cos(30)

[tex]V_{x}[/tex] = 27 m/s × 0.866

[tex]V_{x}[/tex] = 23.662 m/s

So the initial horizontal velocity of the football, which moves in the x-direction, is approximately 23.662 m/s.

This means the football will move 23.662 m/s in x direction initially and if no air resistance acts upon the football, it will move at the same velocity in x direction throughout the motion.

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Thus the electric field at the fourth corner of the square of side L is E4 = kQ.[2/a² + 1/a√2].

Electric field strength is a quantitative expression of the intensity of an electric field in an electric circuit at a particular location and time. The standard unit of the electric field strength is the volt per meter (V/m or V·m⁻¹). An electric field strength of 1 V/m represents a potential difference of about 1V between the two points which are separated by 1 meter distance.

We are given that:

Number of point charges = 3

Here, we shall use the superposition principle to calculate the net electric field at the fourth point, so

E4 = E1 + E2 + E3

E4 = kQ/a² + kQ/√(2a²) + kQ/a²

E4 = kQ [1/a² + 1/√(2a²) + 1/a²]

Thus the electric field at the fourth corner is  E4 = kQ [2/a² + 1/a√2].

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Answer:

70.56 J

Explanation:

The increase in potential energy of the ball can be calculated using the formula:

PE = mgh

where:

PE is the increase in potential energy

m is the mass of the ball (6 kg)

g is the acceleration of gravity (9.8 m/s²)

h is the height the ball is lifted (1.2 m)

Substituting in the values, we get:

PE = (6 kg)(9.8 m/s²)(1.2 m)

This simplifies to:

PE = 70.56 J

So the increase in the ball's potential energy is 70.56 J.

A pitcher throws a baseball towards a batter at 30m/s. The batter swings his bat and hits the baseball, then there is a transfer of energy in this situation : c) Yes, because the force from the bat changes the motion of the ball.

Although baseball may appear hard and solid, it actually behaves much like a rubber ball. In the fraction of a second that ball collides with the swinging bat, ball compresses as the energy of motion goes into deforming the ball and transforms it into an elastic potential energy.

The collision of baseball with bat is elastic and the collision between baseball and glove is nearly inelastic.

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Answer:

Choice A. gamma rays

Explanation:

To find the horizontal and vertical components of the tension force in para sailing, we can use the basic trigonometric ratios of sine, cosine and tangent.

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The law of motion that accounts for an apple accelerating as it falls from a tree is the law of gravity, specifically Newton's Second Law of Motion.

Newton's Second Law of Motion states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. In the case of an apple falling from a tree, the net force acting on it is the gravitational force pulling it toward the Earth. The acceleration of the apple is therefore determined by the strength of this gravitational force and the mass of the apple.

As the apple falls from the tree, it accelerates toward the ground due to the gravitational force acting on it. The faster the apple falls, the greater its acceleration. This acceleration is commonly referred to as acceleration due to gravity, which is a constant value of 9.81 m/s^2 near the surface of the Earth.

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The acceleration of the snowboarder is 0.466 m/s².

Acceleration is the rate of change of velocity.

To calculate the acceleration of the snowboarder, we use the formula below.

Formula:

Where:

From the question,

Given:

Susbtitute these values into equation 1

Hence, the acceleration is 0.466 m/s².

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Expansion of universe is not a hypothetical one but the universe is expanding in the sense increase distance over the space and dark matter.

The increase in distance over time between any two particular gravitationally unbound regions of the observable universe is known as the universe's expansion. 

As a result, the size of space itself expands intrinsically. It is not necessary for space to exist outside of the cosmos or for it to extend into anything.

The metric changes in scale rather than space or the things in space moving in the conventional sense. Objects move farther apart from one another at ever-increasing speeds as the spatial component of the universe's spacetime metric scales up.

Any viewer in the cosmos would see that all of space appears to be expanding, except for the galaxies receding with a speed proportional to the distance from the observer.

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True. The majority of space lawyers concur that the line dividing airspace from outer space is located halfway between the altitude at which airplanes fly and the orbital altitude of satellites.

They serve a variety of functions, including that of the Satellite Navigation System, amateur radio, television transmission, and weather forecasting. In order to conduct study and acquire data, they also employ telescopes to view outward somewhere at solar system.

Over 99% of Americans have access to satellite internet, along with most other (but certainly not all) rural residents. You do not need to have a home internet connection because the broadband signal is transmitted from satellites.

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(a) The kinetic energy of the ball just before it hits the ground is 78.4 J.

(b) The kinetic energy of the ball at a height of 1.2 m is 31.36 J.

The kinetic energy of the ball just before it hits the ground is calculated as follows;

K.E ( bottom) = P.E (top)

P.E (top) = mgh

where;

P.E (top) = 4 x 9.8 x 2

P.E (top) = 78.4 J

The change in the potential energy of the ball during its motion is calculated as follows;

ΔU = P.Ef - P.E i

where;

ΔU = 0 J - 78.4 J

ΔU = -78.4 J

The kinetic energy of the ball at a height of 1.2 m is the change in the potential energy of the ball and it is calculated as follows;

K.E = -ΔU

K.E = -mg (hf - hi)

K.E = (4 x 9.8)(2m - 1.2 m)

K.E = 31.36 J

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The resultant (x,y) coordinate of vector B is  (- 5, 3) and that of A is (9,3). Then, the sum of x components of vector A and B is 4.

Vectors are physical quantities having both magnitude and direction. For example force, velocity, displacement etc .are vector quantities. Coordinates are used to describe the position of these vectors.

The coordinates of tail of  the vector A is (0, 0) and the head is (9,3)

Then the coordinate of A is (9 -0, 3-0) = (9,3)

Similarly, the tail coordinate of B is (9,3) and head is (4,6). The coordinates of B vector is (4-9, 6-3) = (-5, 3)

Now the sum of x components of A and B is = - 5 + 9 = 4.

Therefore, option b is correct.

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The bullet stops moving on hitting on a surface. Hence, the impulse here is equal to the momentum. Therefore, the mass of the bullet is 0.1 Kg.

Impulse in physics is the change in momentum. It is the product of the force and change in time.

hence, impulse = f. dt

When the bullet is travelling with  a velocity of 500 m/s it has a momentum. When it brought to rest, momentum become zero. Thus, the momentum is equal to the impulse here.

Therefore, f.dt = m. v

f.dt = 50 N s

v = 500 m/s

m = 50 N s/500 m/s = 0.1 Kg

Therefore, the mass of the bullet is 0.1 Kg.

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The full load primary current of a 230/115V, 2kVA transformer can be calculated using the formula:

I_primary = (2kVA * 1000 VA/kVA) / (230V)

I_primary = 8.7V

The full load secondary current of the transformer can be calculated using the formula:

I_secondary = (2kVA * 1000 VA/kVA) / (115V)

I_secondary = 17.4V

Therefore, the full-load primary current of the transformer is approximately 8.7V, and the full-load secondary current is approximately 17.4V. It is important to note that these values are based on the assumption that the transformer is operating at its full load capacity. If the transformer is operating at a lower load, the primary and secondary currents will be correspondingly lower.

It is a “new moon” (the Moon is totally dark in the sky). The gravitational force between the Earth and the Moon is:

Generally, The gravitational force between two objects is given by the equation:

force = G * (mass1 * mass2) / distance^2

Where G is the gravitational constant (6.67 x 10^-11 N*(m/kg)^2), mass1 and mass2 are the masses of the two objects, and distance is the distance between the two objects.

The mass of the Earth is 5.972 x 10^24 kg, the mass of the Moon is 7.347 x 10^22 kg, and the mass of the Sun is 1.989 x 10^30 kg. The average distance between the Earth and the Moon is 384,400 km, and the average distance between the Earth and the Sun is 149.6 million km.

The gravitational force between the Earth and the Moon is:

force = (G * (mass of Earth) * (mass of Moon)) / (distance between Earth and Moon)^2 force

= (6.67 x 10^-11 N*(m/kg)^2) * (5.972 x 10^24 kg) * (7.347 x 10^22 kg) / (384400 x 10^3 m)^2 force

= 2.9 x 10^20 N

The gravitational force between the Earth and the Sun is:

force = (G * (mass of Earth) * (mass of Sun)) / (distance between Earth and Sun)^2 force

= (6.67 x 10^-11 N*(m/kg)^2) * (5.972 x 10^24 kg) * (1.989 x 10^30 kg) / (149.6 x 10^9 m)^2 force

= 3.5 x 10^22 N

To find the net gravitational force on the Earth from the Sun and Moon combined, we add the two forces we found above.

Net force = 2.9 x 10^20 N + 3.5 x 10^22 N

= 3.5 x 10^22 N

When it is a Full Moon the distance is the same 384,400 km

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Answer:

4 rad/s

Explanation:

The angular velocity is velocity over time:

[tex]\displaystyle{\omega = \dfrac{v}{r}}[/tex]

We know that the velocity is 20 m/s and the radius is half of diameter which is 10m/2 = 5 m. Hence, substitute in the formula:

[tex]\displaystyle{\omega = \dfrac{20 \: \text{m/s}}{5 \: \text{m}}}\\\\\displaystyle{\omega = 4 \: \text{rad/s}}[/tex]

Therefore, the angular velocity is 4 rad/s

The potential energy of a rock of mass 500 g, held at a height of 2 m above ground is 9.8J.

The formula for the gravitational potential energy of an object is:

PE = mgh

where m is the mass of the object, g is the acceleration due to gravity (approximately 9.8 m/s^2 on the Earth's surface), and h is the height of the object above the reference point.

So, in this case, we can plug in the given values to find the potential energy of the rock:

PE = (500 g) x (9.8 m/s^2) x (2 m)

The weight of the rock is m*g = 500 g * 9.8 m/s^2 = 4.9 N

Therefore,

PE = 4.9 N x 2 m = 9.8 J

Therefore, the potential energy of a rock of mass 500 g, held at a height of 2 m above ground is 9.8J.

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Answer:

70.56 J

Explanation:

Gravitational Potential Energy= mass×gravitational pull× height

= 6×9.8×1.2= 70.56 J

The things that I will need to survive the layer of the earth called the mesosphere would be thick clothings.

The five(5) layers of the earth include the following such as:

The Mesosphere is one of the layers of the earth that is found directly above the stratosphere and then below the thermosphere.

The characteristics of the mesosphere is that the temperature rises due to reduced absorption of solar radiation and increased cooling by CO2 radiative emissions.

Therefore, for an individual to survive and live effectively at the Mesosphere layer of the earth, such needs thick clothings.

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