(b)
On what factor does the mechanical advantage of a simple machine depend?
(a) N/m
B.
Very short answer questions,
1.
What is the principle of simple machine?
2.
3.
The efficiency of simple machine is 75%. What does it mean?
4.
S.
What is lever?
In how many classes is lever classified?
Write the name of a simple machine used to change the direction of force.
6.
0
Reliant Science - 9​

Answers

Answer 1

Answer:

B. 1. The factors on which the mechanical advantage depends are the load, the effort, the distance moved by the load and the distance moved by the effort

2. The principle of a simple machine is the conversion of the direction and magnitude of a force input into one or more outputs of a either a different magnitude, or direction or both

3. A 75% efficiency of a simple machine means that the power of the frictional force is one quarter of the power of the input force

4. A lever is a simple machine that consists of a fulcrum over (or under) which a rigid beam can be  applied

5. There are three classes of lever

6. A pulley

Explanation:

B. 1. For simple machines, we have the Ideal Mechanical Advantage, IMA, given as follows;

[tex]IMA = \dfrac{F_r}{F_e} = \dfrac{d_e}{d_r}[/tex]

Where;

[tex]F_r[/tex] = The resistance force (The load)

[tex]F_e[/tex] = The effort force

[tex]d_e[/tex] = The distance moved by the effort

[tex]d_r[/tex] = The distance the load is moved

Therefore, the factors on which the mechanical advantage depends are the load, the effort, the distance moved by the load and the distance moved by the effort

2. The principle of a simple machine is the conversion of the direction and magnitude of a force input into one or more outputs of a either a different magnitude, or direction or both

3. The mechanical efficiency of a simple machine, η, can be expressed as follows;

[tex]\eta =\dfrac{P_{out}}{P_{in}}[/tex]

Where;

[tex]P_{out}[/tex] = The power at output

[tex]P_{in}[/tex] = The input power

[tex]P_{in}[/tex] = [tex]P_{out}[/tex] + [tex]P_{friction}[/tex]

[tex]P_{friction}[/tex] = The frictional force's power

Therefore, an efficiency of 75% means that we have;

[tex]P_{out}[/tex] = η × [tex]P_{in}[/tex] = 0.75 × [tex]P_{in}[/tex] = 0.75·[tex]P_{in}[/tex]

From which we have;

[tex]P_{in}[/tex] = [tex]P_{out}[/tex] + [tex]P_{friction}[/tex] = 0.75·[tex]P_{in}[/tex] + [tex]P_{friction}[/tex]

∴  [tex]P_{friction}[/tex] = [tex]P_{in}[/tex] - 0.75·[tex]P_{in}[/tex] = 0.25·[tex]P_{in}[/tex]

Therefore, 75% efficiency of a simple machine means that the power of the frictional force is 0.25 × (or one quarter of) the power of the input force

4. A lever is a simple machine that consists of a fulcrum over (or under) which a rigid beam can be  applied

5. There are three classes of lever

(a) First class lever (b) Second class lever and (c) Third class lever

6. A pulley

A pulley acts by lifting a load upward from a downward applied force.

Answer 2

Explanation:

B. 1. The factors on which the mechanical advantage depends are the load, the effort, the distance moved by the load and the distance moved by the effort

2. The principle of a simple machine is the conversion of the direction and magnitude of a force input into one or more outputs of a either a different magnitude, or direction or both

3. A 75% efficiency of a simple machine means that the power of the frictional force is one quarter of the power of the input force

4. A lever is a simple machine that consists of a fulcrum over (or under) which a rigid beam can be applied

5. There are three classes of lever

6. A pulley

Explanation:

B. 1. For simple machines, we have the Ideal Mechanical Advantage, IMA, given as follows;

IMA = \dfrac{F_r}{F_e} = \dfrac{d_e}{d_r}IMA=

F

e

F

r

=

d

r

d

e

Where;

F_rF

r

= The resistance force (The load)

F_eF

e

= The effort force

d_ed

e

= The distance moved by the effort

d_rd

r

= The distance the load is moved

Therefore, the factors on which the mechanical advantage depends are the load, the effort, the distance moved by the load and the distance moved by the effort

2. The principle of a simple machine is the conversion of the direction and magnitude of a force input into one or more outputs of a either a different magnitude, or direction or both

3. The mechanical efficiency of a simple machine, η, can be expressed as follows;

\eta =\dfrac{P_{out}}{P_{in}}η=

P

in

P

out

Where;

P_{out}P

out

= The power at output

P_{in}P

in

= The input power

P_{in}P

in

= P_{out}P

out

+ P_{friction}P

friction

P_{friction}P

friction

= The frictional force's power

Therefore, an efficiency of 75% means that we have;

P_{out}P

out

= η × P_{in}P

in

= 0.75 × P_{in}P

in

= 0.75·P_{in}P

in

From which we have;

P_{in}P

in

= P_{out}P

out

+ P_{friction}P

friction

= 0.75·P_{in}P

in

+ P_{friction}P

friction

∴ P_{friction}P

friction

= P_{in}P

in

- 0.75·P_{in}P

in

= 0.25·P_{in}P

in

Therefore, 75% efficiency of a simple machine means that the power of the frictional force is 0.25 × (or one quarter of) the power of the input force

4. A lever is a simple machine that consists of a fulcrum over (or under) which a rigid beam can be applied

5. There are three classes of lever

(a) First class lever (b) Second class lever and (c) Third class lever

6. A pulley

A pulley acts by lifting a load upward from a downward applied force.


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Answers

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Answers

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Answers

Answer:

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Answers

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Answers

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Answers

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Answers

Answer:

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Explanation:

Given parameters:

Height of the building  = 30m

Initial velocity  = 12m/s

Unknown:

Final velocity  = ?

Solution:

We apply one of the kinematics equation to solve this problem:

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They did a flu shot from McKinnon at 45° to the horizontal with an initial speed of 25 m/s and that is positioned at a horizontal distance of 50 m from the canyon from which it is shot how long does it take the daredevil to travel the 50 m horizontally

Answers

Answer:

The time taken for the daredevil to travel the 50 m horizontally is 2.83 s.

Explanation:

Given;

angle of projection, θ = 45°

initial speed of the projectile, u = 25 m/s

horizontal distance traveled by the projectile, x = 50 m

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[tex]t =\frac{X}{u_x}[/tex]

where;

[tex]u_x[/tex] is the horizontal component of the velocity = uCosθ

[tex]t =\frac{X}{u Cos \ \theta} \\\\t =\frac{50}{25 \times Cos(45)} \\\\t= \frac{50}{17.678} \\\\t = 2.83 \ s[/tex]

Therefore, the time taken for the daredevil to travel the 50 m horizontally is 2.83 s.

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Answers

Answer:

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Son po siya ni Seema

A 3.0 g bullet traveling at a speed of 400 m/s enters a tree and exits the other side with a speed of 200 m/s. Where did the bullet's lost KE go, and what was the energy transferred?

Answers

Answer:

1800J

Explanation:

Step one:

given data

mass of bullet m= 3g= 0.03kg

initial velocity u = 400m/s

final velocity v= 200 m/s

Step two:

1.The bullet's lost kinetic energy went inside the tree.

2. The energy transferred is computed as

= initial KE- KE final

Initial KE= 1/2mu^2

Initial KE= 1/2*0.03*400^2

Initial KE= 1/2*0.03*160000

Initial KE= 1/2*4800

Initial KE= 2400J

KE final= 1/2mv^2

KE final= 1/2*0.03*200^2

KE final= 1/2*0.03*40000

KE final= 1/2*1200

KE final= 600J

KE transferred = 2400-600

KE transferred= 1800J

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