6. If b>6, then 3b + 3 could be
A. 18
B. 19
C. 20
D. 21
E. 22

The rate of change of this simple index over 1 week is - 8.81%

The rate of change is the ratio of the difference in the value of the simple index to the original value of simple index.

Total value of the simple index at day 1 = (8000 x $4.25) + (5000 x $2.90) + (2000 x $6.40) = $61,300

Total value of the simple index at day 8 = (8000 x $3.90) + (5000 x $2.50)+(2000*6.10)  = 55900

the rate of change of this simple index over 1 week

= (55900-61300)/ 61300          * 100 %

= -8.81 %

the rate of change of this simple index over 1 week is - 8.81%

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Using the binomial distribution, it is found that there is a 0.3438 = 34.38% probability that fewer than 3 of them are boys.

The formula is:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

In this problem, the values of the parameters are given as follows:

n = 6, p = 0.5.

The probability that fewer than 3 of them are boys is given by:

[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)[/tex]

In which:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{6,0}.(0.5)^{0}.(0.5)^{6} = 0.0156[/tex]

[tex]P(X = 1) = C_{6,1}.(0.5)^{1}.(0.5)^{5} = 0.0938[/tex]

[tex]P(X = 2) = C_{6,2}.(0.5)^{2}.(0.5)^{4} = 0.2344[/tex]

Then:

[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0156 + 0.0938 + 0.2344 = 0.3438[/tex]

0.3438 = 34.38% probability that fewer than 3 of them are boys.

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Answer:

g(x) = 1/3 • |x|

Step-by-step explanation:

To stretch a parent function, you multiply by whatever you want to stretch it with. If you multiplied by 3, it would be a vertical stretch... if you multiplied by 1/3, it makes it horizontal.

Hope this helps!

Answer:

option c and d are correct

Step-by-step explanation:

if there is only one choosing option you can choose option c

Answer:

2/3(cx+1/2)-1/4=5/2. CX=29/8

Answer:

v = √(LT/m)

Step-by-step explanation:

Given :

Multiply both sides with L :

Divide both sides by m :

Take the square root on each side :

Answer:

[tex]v = \sqrt{ \frac{tl}{m} } [/tex]

Step-by-step explanation:

[tex]t = \frac{mv {}^{2} }{l} \\ making \: v \: the \: subject \\ t \times l = mv {}^{2} \\ dividing \: bothsides \: by \: m \\ \frac{tl}{m} = \frac{mv {}^{2} }{m} \\ v {}^{2} = \frac{tl}{m} \\ finally \\ v = \sqrt{ \frac{tl}{m} } [/tex]

The approximate area that is within range of the motion sensor is 4975 square meters

The figure is not given, however the area of the range can be calculated without the figure.

The given parameters are:

Angle, ⊕ = 135°

Radius, r = 65 meters

The area of the range is calculated using the following sector area

[tex]A = \frac{\theta}{360} * \pi r^2[/tex]

This gives

[tex]A = \frac{135}{360} * 3.14 * 65^2[/tex]

Evaluate

A = 4974.9375

Approximate

A = 4975

Hence, the approximate area that is within range of the motion sensor is 4975 square meters

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Answer:

162.5

Step-by-step explanation:

25=height

13=base

to find the area of a triangle you do (h(b)b)/2

Answer:

I think that the answer is 432.

Step-by-step explanation:

6x2y3.We have x as 6 and y as 2.So we replace them with their numbers.

We'll have 6*6*2*2*3 which will give us 432. I HOPE THIS HELPS.

Answer:

84 circular tiles are needed to make pattern number 20

4(20+1)

Step-by-step explanation:The number of circular tiles is 1 more than the pattern number on each side of the square.

circular tiles = 4(n +1)

Answer:

Step-by-step explanation:

NOTE : we have 6×6=36 possible outcome.

we can resume the set of outcomes in the table below :

Then

the probability that the sum is not divisible

by 2 and not divisible by 4 :

= 18/36

= 1/2

Answer:

goto gauth maths and ask again

Answer:

perpendicular

Step-by-step explanation:

x = -2    is a vertical line at   x   =  -2

y is a horizontal line          the two lines are perpindicular

the lines  x=−2, y=10 are perpendicular to each other.

What is a linear equation?

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

Here, The given equations are :

x=−2 and y=10

First, consider x = -2 equation :

equation x = -2 is a vertical line, parallel to x = 0 line and perpendicular to line y = 0.

Consider second line y = 10 :

line y = 10 is horizontal line and is parallel to line y = 0 and is perpendicular to line x = 0.

Therefore, the lines  x=−2, y=10 are perpendicular to each other.

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Equation of the function: f(x) = 4 sin (x/2) + 6.

The term sinusoidal is used to describe a curve, referred to as a sine wave or a sinusoid, that exhibits smooth, periodic oscillation. It is named based on the function y=sin(x).

Given: max value= 6, min value= -2, y-intercept= 6.

As, standard form f(x) = A sin (ωx +φ) + k,

where A is the amplitude, ω is the angular velocity with ω=2πf.

Now,

A = |6- (-2)/2|

A = |6 +2/2| = 8/2

A = 4

Also, ω:

The period of a sinusoidal is T = 1/f

so, f = 1 / T

ω = 2πf

ω = 2π ( 1/T) with T = 4π

ω = 2π (1/(4π) = 2π (2)

ω = 1/2

The y-intercept k = 6

So, equation with values A =4, ω = 1/2, k = 6, φ = 0.

f(x) = A f(x)

f(x) = A sin (ωx +φ) + k

f(x) = 4 sin (x/2) + 6.

Hence, equation of the function f(x) = 4 sin (x/2) + 6.

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Answer:

2,160 ÷ 36 = 60

Step-by-step explanation:

The division problem that this area model represents is,

2,160 ÷ 36 = 60

Answer:

See below

Step-by-step explanation:

You will just need to use your protractor to measure the given angles..

  Here is some gross guesses  starting with top row

      45     120   100  25   90   80  135  120 °

Answer: 10

Step-by-step explanation:

By the geometric mean theorem, if we let the length of the altitude to the hypotenuse be [tex]y[/tex], this means that [tex]y^{2}=84 \longrightarrow y=\sqrt{84}[/tex].

So, by the Pythagorean theorem, [tex]x=\sqrt{(\sqrt{84})^{2}+4^{2}}=\boxed{10}[/tex]

To Find = Diameter, Area

Solution :

Diameter = 2 × Radius

Diameter = 2 × 6cm

Diameter = 12 cm

Area = 2πr

[tex]area \: = 2 \times \frac{22}{7} \times 6cm[/tex]

[tex]area \: = \frac{264}{7} [/tex]

[tex]area \: = 37.7 \: cm[/tex]

2. Given : Diameter = 8 DM

( 1dm = 10 cm

8dm = 8 × 10 = 80cm )

To find : Radius , area

Solution :

[tex]raduis \: = \frac{1}{2} \times diameter[/tex]

[tex]radius \: = \frac{1}{2} \times 80cm[/tex]

[tex]radius \: = 40 \: cm \: or \: 4dm[/tex]

Area = 2πr

[tex]area \: = 2 \times \frac{22}{7} \times 40[/tex]

[tex]area \: = \frac{1760}{7} [/tex]

[tex]area \: = 251.4cm \: \: \: or \: 25.14dm[/tex]

3. Given : Radius = 2.5m

To find : Diameter , Area

Solution :

Diameter = 2 × radius

Diameter = 2 × 2.5m

Diameter = 5m

Area = 2πr

Area = 2 × 22/7 × 5m

Area = 220/7

Area = 31.4m

Answer:

\begin{gathered}\\1) \: \: \underline{ \sf{ Alternate \: interior \: angles \: \: : }}\\\end{gathered}

1)

Alternateinteriorangles:

\begin{gathered} \sf \implies \: 2\: \: and \: \: 7\\\end{gathered}

⟹2and7

\begin{gathered} \sf \implies \: 6\: \: and \: \: 3\\\\\end{gathered}

⟹6and3

\begin{gathered}\\2) \: \: \underline{ \sf{ Alternate \: interior \: angles \: \: : }}\\\\\end{gathered}

2)

Alternateinteriorangles:

\begin{gathered} \sf \implies \: 1\: \: and \: \: 8\\\end{gathered}

⟹1and8

\begin{gathered} \sf \implies \: 5\: \: and \: \: 4\\\\\end{gathered}

⟹5and4

\begin{gathered}\\3) \: \: \underline{ \sf{ Corresponding \: angles \: \: : }}\\\end{gathered}

3)

Correspondingangles:

\begin{gathered} \sf \implies \: 3\: \: and \: \: 1\\\end{gathered}

⟹3and1

\begin{gathered} \sf \implies \: 5\: \: and \: \: 7\\\end{gathered}

⟹5and7

\begin{gathered} \sf \implies \: 4\: \: and \: \: 2\\\end{gathered}

⟹4and2

\begin{gathered} \sf \implies \: 6\: \: and \: \: 8\\\\\end{gathered}

⟹6and8

\begin{gathered}\\4) \: \: \underline{ \sf{ Consecutive\: Interior \: angles \: \: : }}\\\end{gathered}

4)

ConsecutiveInteriorangles:

\begin{gathered} \sf \implies \: 2\: \: and \: \: 3\\\end{gathered}

⟹2and3

\begin{gathered} \sf \implies \: 6\: \: and \: \: 7\\\\\end{gathered}

⟹6and7

\begin{gathered}\\5) \: \: \underline{ \sf{ Consecutive\: Exterior \: angles \: \: : }}\\\end{gathered}

5)

ConsecutiveExteriorangles:

\begin{gathered} \sf \implies \: 1\: \: and \: \: 4\\\end{gathered}

⟹1and4

\begin{gathered} \sf \implies \: 5\: \: and \: \: 8\\\\\end{gathered}

⟹5and8

Answer:

A- 17/24 sugar all together

B- yes the bowl would be big enough because when you add all the ingredients together it equals 3 5/24 and it's less than 3 1/2.

Answer:

-204kk+3+32k/4k

Hope this helps!!

The option first is correct because  y= 2√x and y= √2x have same domain which is x ≥ 0.

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have a function:

y= 2√x

From the above function the domain should be:

x ≥ 0 (because square root of negative values does not exist)

The function:

y = √(2x)

2x ≥ 0

x ≥ 0

Thus, the option first is correct because  y= 2√x and y= √2x have same domain which is x ≥ 0.

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Answer:

Total, 2 milkshakes, and 3 cokes would cost $12.50

Step-by-step explanation:

The cokes cost $11.50 and the milkshakes $10.00

The rule for construction of Inscribed equilateral triangle

Means if marks are from 1 to 6 then

Or

Now

Here the rest two segments are

Answer:

FB and DB

Step-by-step explanation:

got it right on the test

Answer:

area = 62ft

Step-by-step explanation

so you section the polygon into a big rectangle and 2 small rectangles

the area of the small rectangle will be 2ft x 3ft which will be 6 ft, and as there are 2 of them the area of it will be 12ft

the area of the big rectangle will be 10ft x 5ft, as 8ft - 3ft is 5ft so 5x10=50ft

now add the areas you got, 50+12 which is 62ft

hope this helps:)

Based on the table, a conclusion which can be drawn about f(x) and g(x) is that: B. the functions f(x) and g(x) are reflections over the y-axis.

In Mathematics, two functions are considered to be reflections over the y-axis under the following condition:

If, f(-x) = g(x).

Evaluating the given functions, we have:

f(x) = 2ˣ

f(-x) = 2⁻ˣ = ½ˣ = g(x).

Similarly, two functions are considered to be reflections over the x-axis under the following condition:

If, -f(x) = g(x).

Evaluating the given functions, we have:

f(x) = 2ˣ

-f(x) = -2ˣ ≠ g(x).

Therefore, we can logically conclude that the two functions f(x) and g(x) are considered to be reflections over the y-axis but not the x-axis.

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