A 50 Q resistor in a circuit has a current flowing through it of 2.0 A. What is
the power dissipated by the resistor? (Use P-OVI = PR=
SA
A. 100 W
B. 200 W
OC. 50 W
OD. 25 W

Answers

Answer 1

Hello!

We can use the following equation for calculating power dissipated by a resistor:
[tex]P = i^2R[/tex]

P = Power (? W)
i = Current through resistor (2.0 A)
R = Resistance of resistor (50Ω)

Plug in the known values and solve.

[tex]P = (2.0^2)(50) = \boxed{\text{ B. }200 W}[/tex]


Related Questions

Which energy transformation occurs when an electrolytic cell is in operation.

Answers

Answer:

An electrolytic cell converts electrical energy into chemical energy.

Explanation:

The amount of energy required to raise the temperature of one gram of water by one celsius degree is called a

Answers

The amount of energy required to raise the temperature of one gram of water by one celsius degree is called a calorie.

How can you define calorie?

In physics, we can define it as a unit of measurement that defines the amount of energy to raise the temperature of 1 gram  of water by 1°C. Each material has its unique calorie, however by definition we use water as it is the lowest of all the elements.

Normally, calorimetry is directly linked with the thermal capacity that an element has to contain heat.

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The centers of two 350 kg spheres are separated by 2.00 m. what is the gravitational force between them?

Answers

The gravitational force between them is 3000 gravity’s

when the formula m*g=F-Fg is used?​

Answers

The formula (ma = F - Fg) is used to determine the net upward force acting on a body.

What is net upward force acting on a body?

The net upward force acting on a body is the resultant or sum of all the upward forces acting on a body at a given time.

ma = F - Fg

where;

F is the applied forceFg is the force of gravityma is the resultant force

Thus, the formula (ma = F - Fg) is used to determine the net upward force acting on a body.

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What happens to the cost of goods when inflation increases?
OA. The cost of goods decreases.
B. The cost of goods increases.
OC. The cost of goods stays the same.
OD. The cost of goods varies.

Answers

Answer:

The answer is B

Explanation:

Generally speaking, a company selling goods during periods of inflation will see an increase in its cost of goods sold.

When inflation increases, the cost of goods increases. The correct option is B.

Generally speaking, inflation raises the price of products sold. The price of producing and purchasing those things rises together with the prices of goods and services owing to inflation.

This can be attributable to elements like escalating manufacturing costs, rising input costs, and shifting dynamics of supply and demand.

As a result, companies might need to modify their pricing plans to take inflation-related cost increases into account, the cost of goods typically increases when inflation occurs.

Thus, the correct option is B.

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An electromagnetic wave has a wavelength of 10 nm. Calculate its frequency and identify to which part of the electromagnetic spectrum the wave belongs.

Answers

The frequency of an electromagnetic wave with wavelength of 10nm will be 3 × 10∧7 Hz and would belong to the X-ray or ultraviolet part of the electromagnetic spectrum due to its wavelength

What is frequency?

Frequency is defined as the number of oscillations of a wave per unit time and is measured in hertz(Hz).

It is also inversely proportional to the wavelength.

How to calculate the frequency

The frequency of an electromagnetic wave can be calculated using the formula;

frequency = velocity of light divided by the wavelength

f = v ÷ λ

Note that the velocity of light = 3 × 10 ∧8 m/s

Wavelength = 10nm

Frequency, f = 3 × 10∧8 ÷ 10 = 3 × 10∧7 Hz

Hence, the frequency of an electromagnetic wave with wavelength of 10nm will be 3 × 10∧7 Hz and would belong to the X-ray or ultraviolet part of the electromagnetic spectrum due to its wavelength.

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please help with this i am not good with this

Answers

Answer:

Ball 3 (tennis ball)

Explanation:

Formula we are using :

acceleration = Force / mass

=============================================================

Ball 1 :

⇒ acceleration = 15 N / 0.5 kg

⇒ acceleration = 30 m/s²

===========================================================

Ball 2 :

⇒ acceleration = 15 N / 4.5 kg

⇒ acceleration = 30/9 m/s²

⇒ acceleration = 10/3 m/s²

⇒ acceleration = 3.33 m/s²

===========================================================

Ball 3 :

⇒ acceleration = 15 N/ 0.05 kg

⇒ acceleration = 300 m/s²

============================================================

On comparing, we see that Ball 3 (tennis ball) has the greatest acceleration.

what are the similarities and differences between how living and non-living things fly.

Answers

Flying animals utilize their wings to create both lift and propulsion by moving them in relation to the body.

What are living and nonliving things?

They both consist of fundamentally simple building blocks. They are composed of substance or mass. Atmospheric and molecular building blocks make up the world.

The differences between how living and non-living things fly;

1. Moving both living and non-living objects consumes energy. Flying animals utilize their wings to create both lift and propulsion by moving them in relation to the body.

In contrast to most air vehicles where the components that generate lift wings and thrust engines or propellers are distinct and the wings stay stationary.

Animal aviators like birds as well as natural parachuters like patagial as well as human inventions like aircraft as well as rockets that can power spacecraft and spaceplanes are just a few examples of the many things that can fly.

Hence there are similarities and differences between how living and non-living things fly.

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11) The total conversion of 2.50 kilogram of the
Sun's mass into energy yields
(1) 9.31 x 102 MeV
(2) 8.38 x 10¹⁹ MeV
(3) 1.41 x 1030 MeV
(4) 2.25 x 10¹7 MeV

Answers

1.41 × 10³⁰ MeV

As we know, E=mc², where E is energy, m is mass and c is the speed of light(i.e. 3×10⁸ m/s).

Given mass = 2.5 kgs

E = (2.5)×(3×10⁸)² J = 22.5×10¹⁶ J

As our answer is in joules so we have to convert it into mega electron volt(MeV)

1 J = 6.242 × 10¹² MeV

⇒ 22.5×10¹⁶ J = 22.5×10¹⁶ × (6.242 × 10¹²) MeV

1.41 × 10³⁰ MeV

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It’s number (3) 1.41

A plastic rod that has been charged negatively touches a neutral metal sphere. What kind of charged particle was transferred between the rod

Answers

Answer:

Negative particles will be transferred to the sphere,

Assuming the sphere is not grounded the sphere will be negatively charged when the plastic rod is withdrawn,

(The sphere can be positively charged by grounding the sphere and bringing the rod close to the sphere and then remove the grounding to the sphere)

Care must be taken in noting if and when the sphere is grounded.

Explain how horizontal motion can be uniform while vertical motion is accelerated.
How will projectile motion be affected when drag due to air resistance is taken into
consideration?

Answers

In projectile motion horizontal motion has zero acceleration and when there is no air resistance acting on the object the motion will be uniform. Motion in the vertical direction is accelerated downwards to to the acceleration due to gravity

Transverse waves are to radio waves as longitudinal waves are to:

1. light waves
2. microwaves
3. ultraviolet waves
4. sound waves

URGENT!!!!

Answers

It’s sound waves
4
D
Answer

4. Sound Waves.

Explanation

The first three options are electromagnetic radiations (including radio waves), which are transverse waves. Sound waves is a longitudinal wave as it oscillates in the direction by which the wave propagates.

During the course of a concert, the temperature of a pipe organ gradually increases. As a result, the frequency of the sound from each pipe will ______ throughout the concert.

Answers

As the temperature increases, frequency of sound from each organ pipe will increase as well.

when we throw an arrow by streching the string of a bow , how does the energy change take place ?​

Answers

when we throw an arrow , we first stretch the string of the bow. while stretching the string of the bow, the work done by us in stretching the bowstring gets stored as potential energy in the bow. This potential energy of the bow is transformed into kinetic energy when the bowstring is released and this gives the momentum and Kinetic energy to the arrow.

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When an arrow is drawn back by a bow, the work done by us in stretching the bowstring gets stored at potential energy in the bow. This potential energy of bow is transformed into kinetic energy when the bowstring is released and this gives kinetic energy to the arrow.

All the best!

A chemical reaction is the only way to separate a(n)

Answers

Answer:

pure substance

Explanation:

yw

A cylinder 15.0 cm in diameter rotates at 1000 rpm. (a) what is its angular velocity in rad/s? (b) what is the tangential velocity of a point on the rim of the cylinder?

Answers

Answer:

(a) Approximately [tex]105\; {\rm rad \cdot s^{-1}}[/tex].

(b) Approximately [tex]15.7\; {\rm m \cdot s^{-1}}[/tex], assuming that this cylinder is rotating along the axis that goes through the center.

Explanation:

The unit [tex]{\rm rpm}[/tex] stands for "revolutions per minute", where each revolution is [tex]2\, \pi[/tex] radians.

With an angular velocity of [tex]1000\; {\rm rpm}[/tex], this cylinder would turn [tex]1000\times 2\, \pi = 2000\, \pi[/tex] radians every minute ([tex]60\; {\rm s}[/tex]). Thus, the angular velocity of this cylinder would be:

[tex]\begin{aligned} \omega &= \frac{2000\, \pi\; {\rm rad}}{60\; {\rm s}} \\ &\approx 104.720\; {\rm rad \cdot s^{-1}}\end{aligned}[/tex].

A point at the rim of this cylinder would be at a distance of [tex]r = 15.0\; {\rm cm} = 0.150\; {\rm m}[/tex] from the axis of revolution of this cylinder. If the angular velocity of this cylinder is [tex]\omega[/tex], the tangential velocity of this point would be:

[tex]\begin{aligned} v&= \omega\, r \\ &= \frac{2000\, \pi}{60\; {\rm s}} \times 0.150\; {\rm m} \\ &\approx 15.7 \; {\rm m\cdot s^{-1}}\end{aligned}[/tex].

A 20.00 kg lead sphere is hanging from a hook by a thin, massless wire 2.80 m long and is free to swing in a complete circle. Treat the sphere as a point mass. Suddenly it is struck horizontally by a 5.00 kg steel dart that embeds itself in the lead sphere. What must be the minimum initial speed of the dart so that the combination makes a complete circular loop after the collision

Answers

The minimum initial speed of the dart so that the combination makes a complete circular loop after the collision is 58.5 m/s.

Minimum speed for the object not fall out of the circle

The minimum speed if given by tension in the wire;

T + mg = ma

T + mg = m(v²)/R

tension must be zero for the object not fall

0 + mg = mv²/R

v = √(Rg)

Final speed of the two mass after collision

Use the principle of conservation of energy

K.Ef  = K.Ei + P.E

¹/₂mvf² = ¹/₂mv² + mg(2R)

¹/₂vf² = ¹/₂v² + g(2R)

¹/₂vf² = ¹/₂(Rg) + g(2R)

vf² = Rg + 4Rg

vf² = 5Rg

vf = √(5Rg)

vf = √(5 x 2.8 x 9.8)

vf = 11.7 m/s

Initial speed of the dart

Apply principle of conservation of linear momentum for inelastic collision;

5v = vf(20 + 5)

5v = 11.7(25)

5v = 292.5

v = 58.5 m/s

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A 500 N weight is hung at the middle of a rope attached to two buildings at the same level. If the breaks in the tension exceed 1800 N, what is the minimum angle the rope can make with the horizontal?

Answers

Not sure what you mean by "breaks in the tension" but I suspect you mean the rope will come apart if the tension in the rope exceeds 1800 N.

In the free body diagram for the 500 N weight, we have a figure Y with the net force equations

• horizontal net force:

∑ F[hor] = T₁ cos(θ) - T₂ cos(θ) = 0

• vertical net force:

∑ F[ver] = T₁ sin(θ) + T₂ sin(θ) - 500 N = 0

From the first equation, it follows that T₁ = T₂, so I'll denote their magnitude by T alone. From the second equation, we have

2 T sin(θ) = 500 N

and if the maximum permissible tension is T = 1800 N, it follows that

sin(θ) = (500 N) / (3600 N)   ⇒   θ = arcsin(5/36) ≈ 7.9°

is the smallest angle the rope can make with the horizontal.

Which of the following is a good radiator of heat option is (a) a shiny silvered surface option (b) a dull black surface option (c) a white surface option (d) a green coloured surface

Answers

Answer:

option b

Step by step explanation:

a dull black surface is a good radiator of heat

Answer:

option b is the answer

Sean, who has a mass of 65-kg, is out roller blading with friends at a speed of 3 m/s. Not realizing he accidentally let the dog out as he was leaving, Sean finds his 12-kg pup at rest in the middle of the street. Sean gracefully scoops the dog up as he skates down the road and proceeds to carry the pup home. Calculate their final velocity.

Velocity: _ m/s

Answers

Answer:

2.53m/s

Explanation:

Initial momentum in a system= Final momentum in a system

65kg*3m/s+12kg*0m/s=(65kg+12kg)*v

195kgm/s=77kg*v

v=2.53m/s

At 6: 00 am, a motorbike set off from town A to town B at a speed of 40km/h. At the same time, a car set off from town B to town A at a speed of 60km/h. What time did they meet

Answers

Answer:

One would need to know how far apart the towns are:

T = SA / 40      time it takes for first cyclist to travel S1

T = SB / 60       time it takes for cyclist B to travel distance S2

SA + SB = S     the distance between the towns

SB = 60 / 40 SA = 1.5 SA

SA + 1.5 SA = S

S = 2.5 SA where cyclist travels distance SA

The time will depend on the separation of the towns.

What is the energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b?
1.
8.42 ev
2.
5.74 ev
3
3.06 ev
4.
2.68 ev

Answers

The energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b is 3.06 eV.

Change in energy level of the electron

When photons jump from a higher energy level to a lower level, they emit or radiate energy.

The change in energy level of the electrons is calculated as follows;

ΔE = Eb - Ef

ΔE = -2.68 eV - (-5.74 eV)

ΔE = 3.06 eV

Thus, the energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b is 3.06 eV.

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The arrows in the diagram show the direction of the magnetic fields of the atoms that make up an object. Which sentence best describes the object? A. The object is made of nonmagnetic material. B. The material of the object can attract a magnet. C. The object is weakly magnetic. OD. The material of the object can be magnetized.​

Answers

Option D, the sentence that best describes the object is the material of the object can be magnetized.​

Atoms of magnetic material

The direction of the magnetic fields of the atoms that make up an object is always aligned towards the north pole or south of the material.

Objects that are made of unmagnetised  materials such iron, cobalt and nickel are attracted to either pole of a magnet, but not repelled.

The diagram given shows unmagnetised material, and hence the material of the object can be magnetized.​

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Sound travels at a rate of 340 m/s in all directions through air. Matt rings a very loud bell at one location, and Steve hears it some time later at his location 450 meters to the south. How long did it take the sound to travel from the bell to Steve's location?

Answers

Answer:

110 m/s

Explanation:

because if you subtract 450 from 340 you get 110

Drag the tiles to the correct boxes to complete the pairs.
Identify the type of potential energy described.

Answers

Plants have more food is the chemical energy.

Two north magnetic poles have been brought together is the magnetic energy.

A person has walked to the top of hill posses gravitational potential energy.

A balloon has gained negative charged after being rubbed with a wool cloth is the electric energy.

A spring has been compressed inside a toy.

What is energy?

Energy is the ability to do work.

There are different kind of energies like kinetic energy, potential energy, gravitational energy, heat energy, elastic energy, chemical energy, etc.

Thus, the statement are connected to the correct type of potential energies.

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When vehicle wheels are about to lock, the ABS senses the impending lock up and prevents this from occurring. a) True b) False 2 Question 2 Electronic stability control reduces the risk of rollover crashes, such as are common with SUVs. a) True b) False 3 Question 3 _______________have the ability to control wheel lock on all four tires. a) Four-wheel anti-lock brakes b) Rear-wheel anti-lock brakes c) All anti-lock brakes d) None of the above 4 Question 4 _______________is a technology that works to help maintain vehicle control and steering capability in the event of a skid. a) Parking/emergency brake b) Service brakes c) Anti-lock Braking system d) None of the above 5 Question 5 ___________ reduce the impact forces of a crash exerted upon a vehicle's occupants by allowing parts of the front of the vehicle to crush at varying rates. a) Electronic Stability Control b) Anti-lock Braking Systems c) Crumple Zones d) Traction Control Systems 6 Question 6 The Traction Control System (TCS) is designed to help maintain traction on a vehicle in hazardous conditions or situations. a) True b) False 7 Question 7 A driver operating a vehicle with traction control should brake for the feature to activate. a) True b) False 8 Question 8 Air bags in trucks or other vehicles that do not have a rear seat will have an on/off switch that can be activated for children under age 12. a) True b) False 9 Question 9 All vehicles are equipped with Anti-lock Braking Systems. a) True b) False 10 Question 10 Airbags may deploy in the _______ of the passenger or driver, or from the ____of the vehicle.

Answers

The answers to the questions are:

True TrueFour-wheel anti-lock brakesAnti-lock braking systemCrumple zonesTrue FalseTruefalseFront, sides

What is ABS?

ABS is known as an Anti-lock braking systems (ABS) that act in the capacity of steering one in times in emergencies by bringing back traction to one's tires.

Note that it often helps to hinder  wheels from locking up and helping the driver to be able to steer to safety.

When vehicle wheels are about to lock, the ABS senses the impending lock up and prevents this from occurring is true as that is its function.

Note that Electronic stability helps to control helps to the risk of rollover crashes, such as are common with SUVs.

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Can someone tell me what to tick and why for sentences 3 and 5 please

I will give brainliest to whoever answers correct

Answers

Measured in joules - Thermal energy

Measured with a thermometer - Temperature

Does not depend on how much material there is - Thermal energy

Measured in degrees Celsius - Temperature

Increases if you heat something for longer - Thermal energy

10. In Freudian theory, which one of the following is an example of a Thanatos instinct, which includes aggression, trauma, and risky behaviors?
A. going to school.
B. seeking nourishment.
C. joining a basketball club.
D. substance abuse.

Answers

D substance abuse :) hope this helps

In Freudian theory, substance abuse is one of the following an example of a Thanatos instinct, It includes aggression, trauma, and risky behaviors, Therefore the correct answer is option D

What is the Freudian theory?

The psychoanalytic approach to adult personality development is built on the theories of Sigmund Freud. His beliefs addressed four topics: level of consciousness, personality structure, and stages of psychosexual development. These personality qualities interact to create anxiety, which needs to be controlled via a range of defense mechanisms. These strategies mask the true, anxiety-related causes of one's conduct.

Freud's theories also have limited applicability to the fields of gerontology and geriatric medicine because they postulate that personality development related to his stages of psychosexual development essentially ends in adolescence.

Thus, Substance abuse is one of the Thanatos instincts, which also include aggression, trauma, and risky behavior, according to Freudian theory. Option D is the correct answer.

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Help meeee is for tomorrow, plssss!!!
2) For the association of resistors below:
a) The equivalent resistor between A and B.
b) The total electric current that runs through the circuit, knowing that the electrical voltage between terminals A and B is valid 21 V(volts).
c) The value of the electric current passing through the resistor of 1.0 Ohm.
d) The power dissipated through the 8.0 Ohm resistor.

Answers

(a) The equivalent resistance of the circuit is 0.52 ohms.

(b) The total electric current that runs through the circuit is 40.38 A.

(c) The value of the electric current passing through the resistor of 1.0 Ohm is 21 A.

(d) The power dissipated through the 8.0 Ohm resistor is 55.13 W.

Equivalent resistance of the circuit

The equivalent resistance of the circuit is calculated as follows;

1/R = 1/(1 + 1) + 1/(2 + 2 + 2) + 1/(6) + 1/(2) + 1/8 + 1/8 + 1/6 + 1/6

1/R = 1/2 + 1/6 + 1/6 + 1/2 + 1/8 + 1/8 + 1/6 + 1/6

1/R = 1 + 2/3 + 1/4

1/R = 23/12

R = 12/23

R = 0.52 ohms

Total current through the circuit

V = IR

I = V/R

I = 21/0.52

I = 40.38 A

Current through 1 ohm resistor

V = IR

I = V/R

I = 21/1

I = 21 A

Power dissipated through 8 ohm resistor

P = V²/R

P = (21)²/8

P = 55.13 W

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A child jumps from a moving sled with a speed of 2.2 m/s and in the
direction opposite the sled's motion. The sled continues to move in the forward direction, but with a new speed of 5.5 m/s. If the child has a mass of 38 kg and the sled has a mass 68 kg, what is the initial velocity of the sled?

Answers

The initial velocity of the sled will be 7.34 m/sec. V is the initial velocity of the sled.

What is the law of conservation of momentum?

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

The given data in the problem is;

(m₁)  mass of child = 38 kg

(u₁) is the initial velocity child = 2.2 m/s

(m₂) is the mass of sled = 68 kg

(u₂) is the initial velocity of sled = ?

(v) is the velocity after collision = 5.5 m/s

According to the law of conservation of momentum;

Momentum before collision =Momentum after collision

[tex]\rm m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\(38 \times 2.2) + (68 \times V) = 5.5 \times (38+68) \\\\ 83.6 + 68V = 5.5 \times 106 \\\\ 83.6 + 68V =583 \\\\ \rm 68\ V= 583 -83.6 \\\\ \rm 68 \ V= 499.4\\\\ V= 7.34 \ m/sec[/tex]

Hence,the initial velocity of the sled will be 7.34 m/sec.

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