A 90 kg body is taken to a planet where the acceleration due to
gravity is 2.5 times that of the earth. What is the weight of this body
on the surface of this planet? Take g = 10 m/s?.

Answer:

There are two main ways to determine the age of a rock, these are Relative dating and Absolute dating. Relative dating is used to determine the relative order of past events by comparing the age of one object to another.

Explanation:

Explanation:

rock and fossils are made by layers of dirt, sand,organic matter that has beem compressed over thousands,if not millions of years.

some scientists use this layering to determine how old the earth is.

its kind of like looking at the rings of a tree to see how old it is.

the scientists look at each layer of the rock or fossil and use what they already know about when this type of soil or organic matter existed and try to piece together the past

Answer:

Matter is made of atoms which are in turn made up of protons, nuetrons and electrons. Atoms come together to form molecules which is the building block for all matter.

Explanation:

I feel like this question is like What is the meaning of life. Matter is made up of Matter. i don't know man

Answer:

Because they want attention

Answer:

t = 9.14 s

Explanation:

We first analyze the accelerating motion by applying first equation of motion:

Vf₁ = Vi₁ + a₁t₁

where,

Vf₁ = Final Speed of Car before turning off engine

Vi₁ = Initial Speed of Car = 0 m/s

a₁ = acceleration of car = 25 m/s²

t₁ = time taken in accelerating motion

Therefore,

Vf₁ = 25t₁   ---------- equation (1)

Now, we apply second equation of motion:

s₁ = Vi₁ t₁ + (1/2)a₁t₁²

where,

s₁ = distance covered during accelerating motion

Therefore,

s₁ = (0)t₁ + (1/2)(25)t₁²

s₁ = 12.5 t₁²   ----------- equation (2)

Now, we analyze the decelerating motion by applying first equation of motion:

Vf₂ = Vi₂ + a₂t₂

where,

Vf₂ = Final Speed of Car = 0 m/s

Vi₂ = Initial Speed of Car after turning off engine

a₂ = deceleration of car = - 3 m/s²

t₂ = time taken in decelerating motion

Therefore,

Vi₂ = 3t₂   ---------- equation (3)

Now, we apply second equation of motion:

s₂ = Vi₂ t₂ + (1/2)a₂t₂²

where,

s₂ = distance covered during decelerating motion

Therefore,

s₂ = (Vi₂)t₂ + (1/2)(-3)t₂²

s₂ = Vi₂ t₂ - 1.5 t₂²  

using equation (3):

s₂ = 3 t₂² - 1.5 t₂²

s₂ = 1.5 t₂²   ------------ equation (4)

Now, we know that the Final Velocity of accelerating motion (Vf₁) is equal to the initial velocity of decelerating motion (Vi₂):

Vf₁ = Vi₂

using equation (1) and equation (3):

25 t₁ = 3 t₂

t₁ = 0.12 t₂   ------------ equation (5)

Also, we know that sum of the distances is 200 m:

s₁ + s₂ = 200

using equation (2) and equation (4):

12.5 t₁² + 1.5 t₂² = 200

using equation (5):

12.5 (0.12 t₂²) + 1.5 t₂² = 200

3 t₂² = 200

t₂² = 200/3

t₂ = 8.16 s

substitute this in equation (5):

t₁ = 0.12(8.16 s)

t₁ = 0.97 s

Hence, the minimum time required for this motion is:

t = t₁ + t₂ = 0.97 s + 8.16 s

t = 9.14 s

Answer:

Conduction, convection, and radiation

Explanation:

Conduction is the process in which energy is transferred from a hot body to a cooler body. Convection is a process by which heat is transferred as a result of the movement of heated fluid in the form of air or water. Radiation refers to the transmission of energy through a material medium.

Based on the information provided, a lava lamp could be used to provide an example of conduction, convection, and radiation.

Answer:

Explanation: When you throw a ball up in the air, its direction/velocity on the way up, although it rises up into the air, is actually downward. On its way up, its speed decreases, until it momentarily stops at the very top of the ball s motion. Its acceleration is -9.8 m/s^2 at the very top.

Answer:

-9.8 m/s^v2

Explanation:

When you throw a ball up in the air, its direction/velocity on the way up, although it rises up into the air, is actually downward. On its way up, its speed decreases, until it momentarily stops at the very top of the ball s motion. Its acceleration is -9.8 m/s^2 at the very top.

Answer:

D) miu = 0.17

Explanation:

To be able to solve this problem we must perform a sum of forces in the direction of the movement. This sum of forces must be equal to zero, since the block moves at a constant speed, therefore there is no acceleration.

The friction force is defined as the product of the normal force by the coefficient of friction.

[tex]f=miu*N[/tex]

where:

f = friction force = 50 [N]

miu = friction coefficient

N = normal force [N]

Now the normal force is defined as the force with equal magnitude to the weight of the block but acting in the opposite direction.

[tex]N=300[N][/tex]

Now replacing:

[tex]miu=f/N\\miu=50/300\\miu = 0.166\\ or 0.17[/tex]

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 0.25 × 4000

We have the final answer as

Hope this helps you

Answer:

lol bruhh wat a question

We donot feel any of this motion because these speed are constant. The spining and orbital speed of earth stay the same so we don't feel any acceleration or deceleration. You can only feel motin if your speed change.

Hope it's Help!

Given :

A 2450 kg stunt airplane accelerates from 120 m/s to 162 m/s in 2.10 s.

If the airplane is putting out an average force of [tex]5.8810\times 10^4 \ N[/tex].

To Find :

The average friction force exerted on the airplane by the air.

Solution :

Acceleration is given by :

[tex]a = \dfrac{162-120}{2.10}\ m/s^2\\\\a = 20 \ m/s^2[/tex]

Now, force equation is given by :

[tex]F - F_{friction} = ma\\\\F_{friction} = F-ma\\\\F_{friction} = 58810 - (2450\times 20 )\\\\F_{friction} = 9810\ N[/tex]

Therefore, frictional force exerted in the airplane by the air is 9810 N.

Answer:

for number 1 i got 100

Explanation:

Answer:

false

Explanation i have none

Answer:

B. The magnetic field of the magnets causes a mechanical force to

act on the electric charges within the moving loop of wire.

The magnetic field of the magnets causes a mechanical force to

act on the electric charges within the moving loop of the wire causes an electric current to flow in the loop of wire that turns between an electric generator's two permanent magnets, therefore the correct option is B.

A magnetic field could be understood as an area around a magnet, magnetic material, or an electric charge in which magnetic force is exerted. The SI unit of the magnetic field is tesla.

the magnetic field can also be generated as the magnetic effect of electric current for example when current is flown through an electrical wire there is the generation of the magnetic field around the conducting wire

For a simple bar magnet, N-pole and S-pole are the points on a magnet that have the strongest magnetic field. The magnetic field originates from the north pole and terminates in the south pole of a magnet.

The magnetic field of the magnets causes a mechanical force to act on the electric charges within the moving loop of the wire responsible for the electric current to flow in the loop of wire that turns between an

electric generator's two permanent magnets.

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Answer:

xaubUajnaai ajn AJ au aun a

Explanation:

ahayba uabah an aj

Answer:

[tex]\huge\boxed{\sf a_{c} = 15.6\ m/s^2}[/tex]

Explanation:

Given Data:

Radius = r = 40 m

Speed = v = 25 m/s

Required:

Centripetal Acceleration = [tex]\sf a_{c}[/tex] = ?

Formula:

[tex]\sf a_{c} = \frac{v^2 }{r}[/tex]

Solution:

[tex]\sf a_{c} = \frac{v^2}{r} \\\\a_{c} = \frac{(25)^2}{40} \\\\a_{c} = \frac{625}{40} \\\\a_{c} = 15.6 m/s^2\\\\\rule[225]{225}{2}[/tex]

Hope this helped!

Answer:

divide 10 by 50.

Explanation:

Because its time over speed 10/50

5 meter/ second

I think it's helpful

follow me and don't forget to Mark me as brainlist please

Explanation:

F=MA

F=1500 * 2

F=3000N

Answer:

6.18 m/s

Explanation:

Given that a ferry approaches shore, moving north with a speed of 6.1 m/s relative to the dock. A person on the ferry walks from one side of the ferry to the other, moving east with a speed of 1.0 m/s relative to the ferry Part. What is the speed of the person relative to the dock?

The speed of the person can be calculated by using pythagorean theorem.

Let the speed of the person = S

S^2 = 6.1^2 + 1^2

S^2 = 38.21

S = sqrt ( 38.21)

S = 6.18 m/s

Therefore, the speed of the person relative to the dock is 6.18 m/s

Answer:

B

Explanation:

I just took the test and got 100%

Answer:

Based off the word "conserved" I would say

A. Conservation of Momentum.

Explanation:

Answer:

A.) Conservation of Momentum

Answer:

I think it will be b. solar

Hope I can help.

Answer:

Explanation:

its b

Spreading my love to everyone, <3

Answer:

I would add a higher center of gravity, and make the car shaped in a way where wind could hit it, and the wind won't affect the car's movement whatsoever.

Explanation:

A higher center of gravity ensures that your car will take less effects from the wind, and the shape would make it barely noticeable.

It is simpler to maintain your balance the lower your center of gravity is. You can lean over more if you're sitting down than if you're standing. You can lean further to one side or the other when your center of gravity is low.

From a handling perspective, lower is better since it lessens weight transfer during cornering and braking and lessens the tendency to roll over.

For safe handling, the height of the vehicle's center of gravity is crucial. You are more likely to go over if your center of gravity is high, like in the case of having large or stacked-high cargo on top.

It is especially hazardous when driving around curves or when swerving to avoid hazards.

Increase the center of gravity of the vehicle and shape it so that it can be hit by wind without the wind having any impact on how the vehicle moves.

Therefore, Your car will be less affected by the wind if it has a higher center of gravity, and the shape would barely be evident.

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Answer:

[tex]\huge\boxed{\sf Speed = 2 \ m/s}[/tex]

Explanation:

Given:

Time = t = 45 seconds

Distance = S = 90 meters

Required:

Speed = v = ?

Formula:

v = S / t

Solution:

v = 90 / 45

Speed = 2 m/s

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

Answer:

Explanation:

a)

Firstly to calculate the total mass of the can before the metal was lowered we need to add the mass of the eureka can and the mass of the water in the can. We don't know the mass of the water but we can easily find if we know the volume of the can. In order to calculate the volume we would have to multiply the area of the cross section by the height. So we do the following.

100[tex]cm^{2}[/tex] x 10cm = 1000[tex]cm^{3}[/tex]

Now in order to find the mass that water has in this case we have to multiply the water's density by the volume, and so we get....

[tex]\frac{1g}{cm^{3} }[/tex] x 1000[tex]cm^{3}[/tex] = 1000g or 1kg

Knowing this, we now can calculate the total mass of the can before the metal was lowered, by adding the mass of the water to the mass of the can. So we get....

1000g + 100g = 1100g or 1.1kg

b)

The volume of the water that over flowed will be equal to the volume of the metal piece (since when we add the metal piece, the metal piece will force out the same volume of water as itself, to understand this more deeply you can read the about "Archimedes principle"). Knowing this we just have to calculate the volume of the metal piece an that will be the answer. So this time in order to find volume we will have to divide the total mass of the metal piece by its density. So we get....

20g ÷ [tex]\frac{8g}{cm^{3} }[/tex] = 2.5 [tex]cm^{3}[/tex]

c)

Now to find out the total mass of the can after the metal piece was lowered we would have to add the mass of the can itself, mass of the water inside the can, and the mass of the metal piece. We know the mass of the can, and the metal piece but we don't know the mass of the water because when we lowered the metal piece some of the water overflowed, and as a result the mass of the water changed. So now we just have to find the mass of the water in the can keeping in mind the fact that 2.5[tex]cm^{3}[/tex] overflowed. So now we the same process as in number a) just with a few adjustments.

[tex]\frac{1g}{cm^{3} }[/tex] x (1000[tex]cm^{3}[/tex] - 2.5[tex]cm^{3}[/tex]) = 997.5g

So now that we know the mass of the water in the can after we added the metal piece we can add all the three masses together (the mass of the can. the mass of the water, and the mass of the metal piece) and get the answer.

100g + 997.5g + 20g = 1117.5g or 1.1175kg

Answer:

2,3,1

Explanation:

There are 3 laws of Kepler.

First law = The path of each planet around the sun is an ellipse with the sun at one focus.

Second law =  As a planet moves in its orbit, a line from the sun to the planet sweeps out equal areas in equal times.

Third law = The ratio of the squares of the periods of any two planets revolving around the sun is equal to the ratio of the cubes of their average distance from the sun.

Hence, the correct order for Kepler's law is: 2,3,1

Answer:

the correct one is B,   θ  =  [tex]\frac{1}{4\pi }[/tex]  w t    [rev]

Explanation:

This is a rotational kinematics exercise

        w = w₀ + α t

        w² = w₀² + 2 α θ

indicate that part of rest whereby the initial angular velocity is zero

        w = α t       -> α = w/t

        w² = 2 α θ

we substitute

        w² = 2 (w / t) θ

         w = 2 θ / t

        θ = w t / 2

This angle is given in radians, let's reduce to revolutions = 2π rad = 1 rev

        θ = w t / 2 rad (1 rev / 2π rad)

        θ  =  [tex]\frac{1}{4\pi }[/tex]  w t    [rev]

when checking the answers, the correct one is B, even though he has some mistakes in his writing

Answer:

Similarities between magnetic fields and electric fields: ... Magnetic fields are associated with two magnetic poles, north and south, although they are also produced by charges (but moving charges). Like poles repel; unlike poles attract. Electric field points in the direction of the force experienced by a positive charge ...

Explanation:

copied and pasted from google. I copied and pasted your question into google and got this exact answer

Here is another thing from the same website just not shortened:

Similarities between magnetic fields and electric fields:

- Electric fields are produced by two kinds of charges, positive and negative. Magnetic fields are associated with two magnetic poles, north and south, although they are also produced by charges (but moving charges).

- Like poles repel; unlike poles attract

- Electric field points in the direction of the force experienced by a positive charge. Magnetic field points in the direction of the force experienced by a north pole.

Differences between magnetic fields and electric fields:

- Positive and negative charges can exist separately. North and south poles always come together. Single magnetic poles, known as magnetic monopoles, have been proposed theoretically, but a magnetic monopole has never been observed.

- Electric field lines have definite starting and ending points. Magnetic field lines are continuous loops. Outside a magnet the field is directed from the north pole to the south pole. Inside a magnet the field runs from south to north.

Similarities between magnetic fields and electric fields Magnetic fields are associated with two magnetic poles, north and south, Electric field points in the direction of the force experienced by a positive charge.

Similarities between magnetic fields and electric fields:

Electric fields are produced by two kinds of charges, positive and negative. Magnetic fields are associated with two magnetic poles, north and south, although they are also produced by charges.

Electric field points in the direction of the force experienced by a positive charge. Magnetic field points in the direction of the force experienced by a north pole.

Differences between magnetic fields and electric fields:

Positive and negative charges can exist separately. North and south poles always come together. Single magnetic poles are known as magnetic monopoles.

Electric field lines have definite starting and ending points. Magnetic field lines are continuous loops. Outside a magnet, the field is directed from the north pole to the south pole. Inside a magnet, the field runs from south to north.

Therefore, Similarities between magnetic fields and electric fields Magnetic fields are associated with two magnetic poles, north and south, Electric field points in the direction of the force experienced by a positive charge.

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