(a) The absorbance of mixture at 400 nm was 0.40.
Using the standard curve, calculate the
concentration of haemoglobin in g/dl for this female
patient.

Answer:

i don't understand the question

Explanation:

Answer:

V₂ = 22.84 L

Explanation:

Given data:

Initial volume = 20.0 L

Initial pressure = 1.50 atm

Initial temperature = 23 °C (23 +273 = 296 K)

Final temperature = 271°C (271+273 = 544 K)

Final pressure = 3.50 atm

Final volume = ?

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 1.50 atm × 29.0L ×544 K / 296 K × 3.50 atm

V₂ = 23664 atm .L. K / 1036 atm.K

V₂ = 22.84 L

Answer:

The cell potential = +0.03 V

Explanation:

The half reactions for the cells are given below:

Oxidation half reaction (anode):   Zn(s) ----> Zn²⁺(aq) + 2e⁻

Reduction half reaction (cathode):  Zn²⁺(aq) + 2e⁻ -----> Zn(s)

To calculate cell potential of the cell, we use the equation given by Nernst, which is given as: Ecell = E°cell - (0.0591/n) log Q

where  Q = Concentration of dilute solution/Concentration of concentrated solution = 0.01/0.1

n = number of moles of electrons transferred = 2

Since, the cell is a concentration cell, E°cell = 0

therefore, the Nernst equation becomes, Ecell = - (0.0591/n) log Q

substituting the values;

Ecell = - (0.0591/2) log (0.01/0.10)

Ecell = +0.03 V

Therefore, the cell potential = +0.03 V

The question is incomplete, the complete question is;

In the Energy and Specific Heat lab, you measure the temperature change of water to study the specific heat of a metal. What statement explains the relationship between the water and the metal you are studying? Select one: O The heat lost by the metal plus the heat gained by the water equals 100. O The temperature change of the metal is equal to the temperature change of the water. O The heat lost by the metal is equal to the heat gained by the water. The initial temperature of the metal equals the initial temperature of the water

Answer:

The heat lost by the metal is equal to the heat gained by the water.

Explanation:

When the piece of metal is put into water, heat is lost by the metal and gained by the water.

Recall that energy is conserved hence heat lost by metal must be equal to heat gained by water.

Thus, the relationship between the metal under study and the water is that the metal looses heat to the water and heat lost by metal is equal to heat gained by water.

The statement that explains the relationship that lies between the water and the metal you are studying is that  the heat lost by the metal is equal to the heat gained by the water.

The following information should be considered:

Therefore we can conclude that the statement that explains the relationship that lies between the water and the metal you are studying is that  the heat lost by the metal is equal to the heat gained by the water.

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Answer:

hope it's correct.

Explanation:

element is nickel.

Answer:

4,2,3,1

Explanation:

Answer:

C.

Explanation:

They will need to know the influence of gravitational force on objects because gravity can affect an objects weight.

Answer:

The answer is "[tex]\bold{1.39 \ mg}[/tex]".

Explanation:

Please find the complete question in the attached file.

Total Moles of [tex]Mg_2^{+}[/tex] = moles of [tex]MgSO_4[/tex]

                                 [tex]= \frac{mass}{molar \ mass \ of MgSO_4}\\\\= \frac{0.450}{120.37}\\\\ = 0.0037385 \ mol[/tex]

[tex]Mg_2^{+} + EDTA4^{-} \longrightarrow Mg(EDTA)2^{-}[/tex]

EDTA mol in 37.6 mL of solution = 50.0 mL of [tex]Mg2^{+}[/tex]

                                                      [tex]= \frac{50.0}{500} \times[/tex] total moles of [tex]Mg2^{+}[/tex]

                                                      [tex]= \frac{50.0}{500} \times 0.0037385\\\\= 3.7385 \times 10^{(-4)} \ mol\\[/tex]

[tex]Ca2^{+} + EDTA4^{-} \longrightarrow Ca(EDTA)2^{-}[/tex]

[tex]CaCO_3 Moles = Ca2^{+} Moles =[/tex] EDTA moles in a solution of 1.40 mL

                      [tex]= \frac{1.40}{37.6} \times 37.6 \ mL[/tex] the solution of EDTA moles.

                      [tex]= \frac{1.40}{37.6} \times 3.7385 \times 10^{(-4)} \\\\= 1.392 \times 10^{(-5)}\ mol\\\\[/tex]

Mass of [tex]CaCO_3 =[/tex]mole[tex]\times[/tex] the molar mass of [tex]CaCO_3[/tex]

                            [tex]= 1.392 \times 10^{(-5)} \times 100.09\\\\= 0.00139 \ g\\\\ = 1.39 \ mg[/tex]

Answer:

a) When air inside the tires gets colder, it shrinks, so the tires seem flat, even though they haven't lost any air.

b) When the air inside the soda can gets hot, the molecules of gas move faster, exerting more and more and more pressure, eventually exploding the soda can.

c) When the nalgene is cooled, the air pressure inside will lower; the volume of the nalgene will stay the same, though, because the nalgene is a rigid container.

Answer:

Sodium hydroxide reacts with iron(III) chloride to produce iron(III) hydroxide and sodium chloride.

Hope this helps plz hit the crown :D

Answer:

Mega = 10^6

Milli = 10^-3

Explanation:

Mega is whatever times 10 to 6th power.

Milli is whatever times 10 to the -3rd power.

Answer: 51.9961 g/mol, don't know if it helps :)

Explanation:

Answer:

Chromium is a steel-gray, lustrous, hard metal that takes a high polish, is fusible with difficulty, and is resistant to corrosion and tarnishing.

The most common oxidation states of chromium are +2, +3, and +6, with +3 being the most stable. +4 and +5 are relatively rare. Chromium compounds of oxidation state 6 are powerful oxidants.ion:

Answer:

Of the main group elements, fluorine has the highest electronegativity (EN = 4.0) and cesium the lowest (EN = 0.79). This indicates that fluorine has a high tendency to gain electrons from other elements with lower electronegativities.

Explanation:

Answer:

Creativity leads scientists to design new methods to test their hypotheses.

Creativity permits scientists to think of new questions to investigate.

Explanation:

A scientist must be very creative and must be a critical thinker.

Creativity is the ability of someone to use imaginations to solve a problem.

Answer:

B and D

Explanation:

Answer:

z = 2s

Explanation:

This is the only info given.

Answer:

I THINK it's D, I could be incorrect, however.

Explanation:

C3H8O, as it is flammable, and thus I wouldn't imagine it being a product of combustion. I could be incorrect, so take my answer with a grain of salt.

Answer:

1.45 Atmospheres = 146.92125 Kilopascals, or about 146.9 Kilopascals

Explanation:

1 Atmosphere = 101.325 Kilopascals, so 101.325 Kilopascals x 1.45 Atmospheres = 146.92125 Kilopascals.

Using the conversion table, the pressure of the compressed gas at 1.45 atm when converted to kilopascal becomes 146.92 kPa.

Atm is the standard atmosphere which is a unit of pressure.

From conversion table

1 atm atmospheric pressure is equivalent to 101.325 kPa ( kilopascal ).

Now, the pressure of the compressed gas at 1.45 atm will be;

P = 1.45 × 101.325 kPa

P = 146.92 kPa

Therefore, the pressure of the compressed gas at 1.45 atm when converted to kilopascal using the conversion table becomes 146.92 kPa.

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Answer:

If you're talking about Solid, Liquid, and Gas the answer would be... well I'm not gonna give this to you straiight away but, here's a game! It has at least 5 letters in it...It has the letter I in it, It has a S in it Hope you got the answer! ✨Brainliest pwease!

Answer:

1+1=2 Unless this is a trick question. Then it's most likely 11.

Explanation:

1 + 1 = 2

thxs for the points realy tho thxs

Given :

A seawater sample contains 2.7 mg chlorophyll m⁻³.

To Find :

What is the chlorophyll concentration in units of mg L⁻¹.

Solution :

We know, 1 m³ = 1000 L .

So, 1 m⁻³ = 10⁻³ L⁻¹

Concentration is :

[tex]c = 2.7\ mg\ m^{-3}\\\\c = 2.7\times 10^{-3}\times \ mg\ L^{-1}\\\\c = 0.0027 \ mg\ L^{-1}\\\\c = 2.7\ \mu g \ L^{-1}[/tex]

Therefore, the chlorophyll concentration in units of mg L⁻¹ is [tex]2.7\ \mu g \ L^{-1}[/tex].

Hence, this is the required solution.

Answer:

D. when the number of moles of acid is exactly equal to the number of moles of base.

Explanation:

Regarding options A. and E., pKa and pKb would only be taken into consideration if the titrations were of weak acids and bases. However it is possible to have a titration of monoprotic acids and bases with strong acids and bases.

Another way of looking at the answer is identifying which one best describes the equivalence point.

Answer:

:)

Explanation:

Petroleum gas is mainly C3 and C4 based (propane and butane), whilst natural gas is predominantly C1 and C2 (methane and ethane). Petroleum gas is generally produced via the cracking of naphtha, which is one of the components separated during crude oil refining.

Petroleum is C3 or C4 (propane and butane) while Natural Gas is C1 and C2. (methane and ethane)

Petroleum is also produced differently then Natural Gas.

"Petroleum gas is generally produced via the cracking of naphtha, which is one of the components separated during crude oil refining." - socratic.org

Answer:

Mercury Chloride

Explanation:

Trust me, this answer is correct.

Answer:

goes deep into the ground and pollutes the groundwater.

Answer:

True (see detailed explanation).

Explanation:

Hello!

In this case, since insecticides are substances that keep crops from insects that can eat or damage them, it has been acknowledged they are important for the agricultural industry and therefore the citizens sustainability.  

However, since insecticides have really complex chemical structures, they are unlikely or sluggishly decomposed by the humans and other animals' cells, which can lead to irreversible genetic damage, cancer and other serious diseases; therefore, when they are used incorrectly, say higher amounts than necessary, spread on crops that are not significantly affected by insects or by any other reason, they are very likely to be damaging for us, animals and in general the environment.

Best regards!

Answer:

Half-life = 3 minutes

Explanation:

Using the radioactive decay equation we can solve for reaction constant, k. And by using:

K = ln2 / Half-life

We can find half-life of polonium-218

Radioactive decay:

Ln[A] = -kt + ln [A]₀

Where:

[A] could be taken as mass of polonium after t time: 1.0mg

k is Reaction constant, our incognite

t are 12 min

[A]₀ initial amount of polonium-218: 16mg

Ln[A] = -kt + ln [A]₀

Ln[1.0mg] = -k*12min + ln [16mg]

-2.7726 = - k*12min

k = 0.231min⁻¹

Half-life = ln 2 / 0.231min⁻¹

Answer:

34672.96 s

Explanation:

m = Mass of copper = 6.32 g

M = Molar mass of copper = 63.5 g/mol

F = Faraday constant = 96500 C/mol

The electrode equation would be

[tex]Cu^{2+}(aq)+2e^{-}=Cu(s)[/tex]

Number of electrons = 2 = e

I = Current = 0.554 A

t = Time taken

Charge would be

[tex]Q=\dfrac{m}{M}eF\\\RightarrowQ=\dfrac{6.32}{63.5}\times 2\times 96500\\\Rightarrow Q=19208.82\ \text{C}[/tex]

Charge is given by

[tex]Q=It\\\Rightarrow t=\dfrac{Q}{I}\\\Rightarrow t=\dfrac{19208.82}{0.554}\\\Rightarrow t=34672.96\ \text{s}[/tex]

Time taken to deposit the copper is 34672.96 s.

Answer:

5.74 L O₂

General Formulas and Concepts:

Chemistry - Gas Laws

Explanation:

Step 1: Define

RxN:   2HgO (s) → 2Hg (s) + O₂ (g)

Given:   111 g HgO

Step 2: Identify Conversions

STP

Molar Mass of Hg - 200.59 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of HgO - 200.59 + 16.00 = 216.59 g/mol

Step 3: Stoichiometry

[tex]111 \ g \ HgO(\frac{1 \ mol \ HgO}{216.59 \ g \ HgO} )(\frac{1 \ mol \ O_2}{2 \ mol \ HgO} )(\frac{22.4 \ L \ O_2}{1 \ mol \ O_2} )[/tex] = 5.73988 L O₂

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

5.73988 L O₂ ≈ 5.74 L O₂

Answer:

H3PO4 + 3NaOH ==> Na3PO4 + 3H2O

The balanced equation for the given reaction is [tex]3NaOH+H_3PO_4---- > Na_3PO_4+3H_2O[/tex]

A chemical reaction in which an acid and a base react quantitatively with each other is known as neutralization.

In a water reaction, neutralization means that there is no excess of hydrogen or hydroxide ions in the solution.

A neutralization reaction occurs when an acid and a base react to form water and a salt through the combination of H+ ions and OH- ions. The pH of neutralization of a strong acid and a strong base is 7.

Three moles of sodium hydroxide are required for one mole of phosphoric acid. The balanced equation tells us the following: 1 mol of H3PO4 reacts with 3 mol of NaOH.

It can be written as

[tex]3NaOH+H_3PO_4---- > Na_3PO_4+3H_2O[/tex]

Thus, this is the balanced equation for the given neutralizing reaction.

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Answer:

The emmision of ionizing radiation or particles caused by the spontaneous disintegration of atomic nuclei

or

the giving off of rays of energy or particles by the breaking apart of atoms of certain elements