$
Amount Due at Maturity
6,000.00
Discount Rate
3.50%
1. Calculate the bank discount:
2. Calculate the proceeds:
Time
160
Ordinary Interest
360
Required:
Using the information above please answer the following:
Note: Use cells A2 to D3 from the given information to complete this question.

$Amount Due At Maturity6,000.00Discount Rate3.50%1. Calculate The Bank Discount:2. Calculate The Proceeds:Time160Ordinary

Answers

Answer 1

The bank discount is $93.33 and the proceeds are $5,906.67.

What is the discount?

Discount causes the product's selling price to drop, which increases its allure for the consumer. A price reduction has a psychological effect on the buyer, influencing them to make the purchase. The two types of discounts offered are trade discounts and cash discounts.

We have,

Amount Due at Maturity = $6,000

Discount rate = 3.5%

Time = 160 days

Bank Discount = $6,000*3.5%*160/360=$93.33

Proceeds = Maturity value - Bank Discount

= $6,000 - $93.33

= $5,906.67

Therefore, the bank discount is $93.33 and the proceeds are $5,906.67.

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Related Questions

I need help with this please help me

Answers

From the given figure

a) The value of y = 6

b) The length of the line RS = 39 units

The length of the line ST = 38 units

The length of the line RS = 6y + 3

The length of the line ST = 5y + 8

The length of the line RT = 77

From the line we can say that

RT = RS + ST

77 = 6y + 3 + 5y + 8

Add the like terms

11y + 11 = 77

11y = 77 - 11

11y = 66

y = 66/11

y = 6

The value of y = 6

The length of RS = 6y + 3

= 6×6 + 3

= 36 + 3

= 39 units

The length of the line ST = 5y + 8

= 5×6 + 8

= 30 + 8

= 38 units

Hence, from the given figure

a) The value of y = 6

b) The length of the line RS = 39 units

The length of the line ST = 38 units

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Find the cardinal number of a set B={Q,R,S,T,U,V}.

Answers

Answer:

6

Step-by-step explanation:

The cardinal number of a finite set is the number of elements of the set.

cardinal number = 6

15=2m+3
solving two step equations

Answers

Answer:

[tex]m=6[/tex]

Step-by-step explanation:

Start by subtracting 3 from both sides

[tex]15=2m+3\\15-3=2m+3-3\\12=2m[/tex]

Now, divide both sides by 2!

[tex]\frac{12}{2}=\frac{2}{2}m\\ 6=m\\ m=6[/tex]

Answer:

m=6

i think this help you

Which diagram matches the following situation? The function h relates Kami's age in years to her height in inches on her birthday that year.

Answers

The diagram that matches the given situation is as shown below.

The correct answer is an Option C

We know that, in the mapping of functions, we map certain parameters to a set of other parameter functions.

In this question, we have been given the function h relates Kami's age in years to her height in inches on her birthday that year.

It means that her ages would be one-one the left to map her height. that means there were 2 times were despite her age difference, her height remained the same.

From the given options, the correct one that represents the required mapping is:

h(14) = 64

h(15) = 64

Therefore, the diagram that matches the given situation is as shown below.

The correct answer is an Option C

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solve for missing angle 20 degrees + 40 degrees + 39 degrees + x

Answers

The sum of angles at a point is equal 360 degrees and using that, the value of x is 261 degrees.

Angle At a Point

Angles around a point describes the sum of angles that can be arranged together so that they form a full turn. Angles around a point add to 360°.

In this question, when we sum all angles up, it will give us the sum of 360 degrees.

20 + 40 + 39 + x = 360

x + 99 = 360

x = 360 - 99

x = 261

x has a value of 261 degrees.

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<7 and <8 are vertical angles can you shoe me how to draw this please

Answers

Vertical angles are opposite of each othe. Attached is a picture of how it looks:

I hope this helps!

A. x² +5
B. +5X
C.X + 5
D.5X

Answers

The expression that represents the quotient of the given model is x + 5. The correct option is C. x + 5

Determining the expression that represent the quotient of a model

From the question, we are to determine the expression that represent the quotient of the given model

From the given model, we can write that

x | x² + x + x + x + x + x

Dividing by using the long division

  x + 1 + 1 + 1 + 1 + 1      

x | x² + x + x + x + x + x

Thus, the quotient of the expression is

x + 1 + 1 + 1 + 1 + 1

Further simplification,

NOTE: 1 + 1 + 1 + 1 + 1 = 5

Then,

The expression x + 1 + 1 + 1 + 1 + 1  becomes

x + 5

Hence, the expression is x + 5

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if an odd number is added to an even number the result must be

Answers

Answer:

an odd number

Step-by-step explanation:

it always will be an odd number when you add an even and an odd number

it is an odd number.

Which of the following could be used as a statement in a two-column proof?

Answers

A statement of given information can be used in a two column proof

What is two column proof ?Among the many methods available to mathematicians are proofs, or logical arguments, that begin with premises and reach conclusions through the presentation of facts. The proof is hard to write because you have to put each part in the correct order.While paragraphs and flow charts are enough to outline the various steps, nothing beats a two-column proof for purity and clarity. A two-column proof uses a table to represent a logical argument and assigns a task to each column.The two columns then work in lockstep, leading the reader from the premise to the conclusion. Paragraph proofs tell a story by chronologically listing each fact and reason. This means you have to be very organized and have to rewrite paragraphs over and over until you get it right. Flowchart proofs can be difficult to follow, but at least they provide a clean separation between mathematics and reasoningIn light of the question -

The two-column proof is summarized in the statement and reason columns, and each statement must have a verified reason. Two-column proof reasons are usually given information, vocabulary definitions, hypotheses, and previously proven theorems.

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Out of 45 times at bat, Raul got 27 hits. Write the decimal that represents the times Raul didn't
get a hit.

Answers

Answer:

0.6

Step-by-step explanation:

A biologist is studying a particular species of flower. She writes the following equation to
show the length of the flower petal f(w), in cm, after w weeks:
f(w) = 3(1.03)
Part A (3pts): Complete
the table using the
function.
0
1
2
3
4
5
f(w)
Part B (1pt) Highlight the data
needed to solve this from the
table in Part A.
(2pts): What is an average
rate of change of the function
f(w) when w = 2 to
w = 5?
Rate of change formula =
y₂-y₁
x₂-x
3.03
Part C (2pts): What does the y-intercept of
the graph of the function f(w) represent?
(Circle the correct answer.)
a.) initial length of the petal
b.) length of the petal after w weeks
c.) time it took for the flower to stop growing
d.) percentage of growth each week
Part D (2pts): At the end of the study the
length of the petal was 3.48 cm. What is a
reasonable domain to plot the growth
function?
Sws

Answers

A. The lengths of the flower petals corresponding to the weeks 0, 1, 2, 3, 4, and 5 are 0, 3.09, 6.18, 9.27, 12.36, and 15.45, respectively.

B. The average rate of change of the function f(w) from week two to week five is 3.09.

C. The y-intercept of the function f(w) represents the initial length of the petal.

D. The reasonable domain to plot the growth function is week 0 to week 2.

The length of the flower petal and the weeks passed are denoted by f(w) and w. The equation of the function is given below.

f(w) = 3(1.03)w

The simplified function is f(w) = 3.09w.

The rate of change of the function from weeks 2 to 5 is calculated below.

R = [f(5) - f(2)]/(5 - 2)

R = [3.09*5 - 3.09*2]/3

R = 3.09*(5 - 2)/3

R = 3.09

The length of the flower petal at the end of the study was 3.48 cm. The length lies between the week 0 and the week 2.

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The curve with equation y = x³ +3 has two tangents parallel to the line with equation
y = 12x-1. Find the co-ordinates of the two points.

Answers

Answer:

  (-2, -5), (2, 11)

Step-by-step explanation:

You want the coordinates of the points on the curve y = x³ +3 where the tangent lines are parallel to y = 12x -1.

Slope

The slope of the tangent line is the x-coefficient in its equation: 12.

The slope of the curve is given by its derivative:

  y' = 3x²

We want the x-values where the slope is 12. These are the solutions to ...

  12 = 3x²

  4 = x² . . . . . . . . . . divide by 3

  x = ±√4 = ±2 . . . . . take the square root

Coordinates

The coordinates of the points with x = ±2 are ...

  y = (±2)³ +3 = ±8 +3 = {-5, 11}

The tangent points are (-2, -5) and (5, 11).

__

Additional comment

The attached graphs and table show the solutions to y'=0 and the corresponding point locations. It also shows the tangent line equations (in point-slope form).

HELP ME PLEASE!!!?!!!!!?!!!?!!!!0.0

Answers

Answer:

wean positive realtionship

Maria is applying for a summer job. Six employees who do various jobs at the company earn $8.00, $8.50, $9.00, $9.50, $10.00, and $23.50 per hour. In the interview, the boss tells Maria that the median of the hourly wages is $9.25. Is the boss’s statement misleading? Why or why not?

Answers

Answer:

Boss's statement is not misleading.

Explanation:

To find the median, we need to find the middle number.

8.00, 8.50, 9.00, 9.50, 10.00, 23.50

9.00 and 9.50 are in the middle.

And in the middle of those two is 9.25.

Solve the linear programming problem.

Answers

On the coordinate (0,7) the value of P is maximum 280.

What is a Linear Inequality?

In mathematics, inequality denotes a mathematical expression in which neither side is equal. In Math, an inequality occurs when a connection produces a non-equal comparison between two expressions or two integers.

Solution:

First of all to solve the Linear Inequality we need to plot the graph of the given equations.

Kindly find the attached graph

To maximise the equation P = 30x + 40y

we need to find the corner values of x and y.

According to the graph, the corner values of (x,y) are

(5,0), (3,4) and (0,7)

putting the values in the equation P = 30x + 40y

at x = 5 and y = 0

P = 150

at x = 3 and y = 4

P = 250

at x = 0 and y = 7

P = 280

So, on the cordinate (0,7) the value of P is maximum i.e. 280.

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The physical plant at the main campus of a large state university recieves daily requests to replace
florecent lightbulbs. The distribution of the number of daily requests is bell-shaped and has a mean
of 36 and a standard deviation of 4. Using the 68-95-99.7 rule, what is the approximate percentage
of lightbulb replacement requests numbering between 32 and 36?
Do not enter the percent symbol.
%6
ans =
> Next Question

Answers

The percentage of lightbulb replacement requests numbering between 32 and 36 is 34

According to the question,

The distribution of the number of daily request is bell-shapes means Number of daily request follows Normal distribution

Mean of normal distribution : μ = 36

Standard deviation : σ = 4

Let the lightbulb replacement requests number be "x"

So, the probability of lightbulb replacement requests numbering between 32 and 36 = P(32 < x <36)

below 36 i.e. mean of normal

32 = 36 - 4 is probability between one standard deviation and below mean

Percentage between mean ± standard deviation is always 68%

so , percentage of lightbulb replacement requests numbering between 32 and 36 will be half of 68% as mean + standard deviation is excluded

= 68/2

= 34

Hence , 34 percentage of lightbulb replacement requests numbering between 32 and 36.

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Find a formula for the polynomial of least degree that is graphed below Its x-intercepts are 0 and -3, and the graph goes through the point (-1,4).

Answers

Answer: y=-2x²-6x

Step-by-step explanation:

Its x-intercepts are 0 and -3, and the graph goes through the point (-1,4)

Hence we have three coordinates of the equation y=ax²+bx+c    (1):

                                    (0,0)   (-3,0)   (-1,4)

Let's substitute these coordinates into formula (1):

[tex]0=a(0)^2+b(0)+c\\0=a(-3)^2+b(-3)+c\\4=a(-1)^2+b(-1)+c\\\\0=0+0+c\\0=9a-3b+c\\4=a-b+c\\\\0=c\\0=9a-3b+0\\0=a-b+0\\\\c=0\\9a-3b=0\ \ (1)\\a-b=4\ \ \ \ \ (2)\\\\c=0\\\\[/tex]

Divide both parts of the equation (1) by 3 and multiply both parts of the equation (2) by -1: :

[tex]3a-b=0\\-a+b=-4\\\\[/tex]

Sum these equations:

[tex]2a=-4[/tex]

Divide both parts of the equation by 2:

[tex]a=-2[/tex]

We substitute the value of a=-2 into equation (2):

[tex]-2-b=4\\[/tex]

Divide both parts of the equation by -1:

[tex]2+b=-4\\\\2+b-2=-4-2\\\\b=-6[/tex]

[tex]Thus, \\\\y=-2x^2-6x+0\\\\y=-2x^2-6x[/tex]

find the value of x.....

Answers

Answer:

Below

Step-by-step explanation:

All of the angles labeled sum up to a right angle = 90 °

x+4     +      x+4        +  x+4      = 90

3x + 12 = 90

3x = 78

x = 26°

Answer:

x = 26

Step-by-step explanation:

from the diagram

∠ BFC + ∠ CFD + ∠ DFE = ∠ BFE , that is

x + 4 + x + 4 + x + 4 = 90

3x + 12 = 90 ( subtract 12 from both sides )

3x = 78 ( divide both sides by 3 )

x = 26

(a - 2b)3 when a = 3 and b = -1/2

Answers

0 I do know this because I don’t know just doing this to get points

Answer:

64

Step-by-step explanation:

Substitute the values so (3-2(-1/2))3

Then distribute so (3-(-1))3

Add since it's a double negative to get (4)3

And 4 cubed is 64

The equity sections for Atticus Group at the beginning of the year (January 1) and end of the year (December 31) follow.



Stockholders’ Equity (January 1)

Common stock—$4 par value, 100,000 shares authorized, 35,000 shares issued and outstanding $ 140,000

Paid-in capital in excess of par value, common stock 100,000

Retained earnings 360,000

Total stockholders’ equity $ 600,000



Stockholders’ Equity (December 31)

Common stock—$4 par value, 100,000 shares authorized, 41,000 shares issued, 5,000 shares in treasury $ 164,000

Paid-in capital in excess of par value, common stock 148,000

Retained earnings ($50,000 restricted by treasury stock) 440,000

752,000

Less cost of treasury stock (50,000)

Total stockholders’ equity $ 702,000


The following transactions and events affected its equity during the year.



January 5 Declared a $0.50 per share cash dividend, date of record January 10.

March 20 Purchased treasury stock for cash.

April 5 Declared a $0.50 per share cash dividend, date of record April 10.

July 5 Declared a $0.50 per share cash dividend, date of record July 10.

July 31 Declared a 20% stock dividend when the stock’s market value was $12 per share.

August 14 Issued the stock dividend that was declared on July 31.

October 5 Declared a $0.50 per share cash dividend, date of record October 10.



3. What is the amount of retained earnings transferred to paid-in capital accounts (capitalized) for the stock dividend?

4. What is the per share cost of the treasury stock purchased? (Round your answer to 2 decimal places.)

5. How much net income did the company earn this year?

Answers

3. The amount of retained earnings transferred to the paid-in capital accounts (capitalized) for the stock dividend is $72,000.

4. The per-share cost of the treasury stock purchased is $10.

5. The net income earned by the Atticus Group this year was $217,500.

How are stock dividends capitalized?

Stock dividends do not affect the cash account, unlike cash dividends.

Instead, the deduction is made from the retained earnings.

When the stock dividends are distributed, they are capitalized to the paid-in capital accounts (common stock and additional paid-in capital).

Transaction Analysis:

January 5 Dividend $17,500 Dividends Payable $17,500 (35,000 x $0.50)

Retained Earnings $17,500 Dividend $17,500

March 20 Treasury Stock $20,000 Paid-in Capital in Excess $30,000 Cash $50,000 ($50,000/5,000)

April 5 Dividend $15,000 Dividends Payable $15,000 (30,000 x $0.50)

Retained Earnings $15,000 Dividend $15,000

July 5 Dividend $15,000 Dividends Payable $15,000 (30,000 x $0.50)

Retained Earnings $15,000 Dividend $15,000

July 31 Stock Dividend $72,000 Dividends Issuable $72,000 (30,000 x 20% x $12)

Retained Earnings $72,000 Stock Dividend $72,000

August 14 Dividends Issuable $72,000 Common Stock $24,000 Paid-in Capital in excess of par value $48,000

October 5 Dividend $18,000 Dividends Payable $18,000 (36,000 x $0.50)

Retained Earnings $18,000 Dividend $18,000

5) Retained earnings

Ending balance  $440,000

Add:

Dividend $17,500

Dividends $15,000

Dividends $15,000

Dividends $72,000

Dividends $18,000 $137,500

Less Beginning balance $360,000

Net income = $217,500

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In a town 100 people need 700 liters of water to drink everyday at a festival time how many liters of water do they need to drink with their 30 guest

Answers

Answer: 210 liters

Step-by-step explanation:

Find the y-coordinate of the y-intercept of the polynomial function defined below.

f(x) = (x + 6) (5x² + 2)(x − 3)

Answers

The y-coordinate of the y-intercept of the polynomial function is -36.

Given:

polynomial function defined below.

f(x) = (x + 6) (5x² + 2)(x − 3)

To find y intercept put x = 0 in the function.

y = (0+6)(5*0^2+2)(0-3)

= 6*(5*0+2)*(-3)

= 6*(0+2)(-3)

= 6*2*(-3)

= 12(-3)

= -36

Therefore The y-coordinate of the y-intercept of the polynomial function is -36.

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A camp counselor and four campers are to be seated along a picnic bench. In how many ways can this be done if the counselor must be seated in the fourth and a camper who has a tendency to engage in food fights must sit to the​ counselor's immediate ​?

Answers

Answer: 6 ways

Step-by-step explanation:

Is 49 prime or composite?

Can Mario organize his marbles into aqual piles?

Answers

The number 49 is a composite number because it has more than two factors.

What is a prime number?

A prime number is a natural number greater than one that cannot be calculated as the product of two smaller natural numbers. A composite number is a natural number greater than one that is not prime. 5 is prime, for example, because the only ways to write it as a product, 1 5 or 5 1, involve 5 itself.

Numbers with more than two factors are known as composite numbers. Non-prime numbers are composite numbers because they can be divided by more than two numbers.

A positive integer is a composite number. which is not the case (i.e., which has factors other than 1 and itself). The first few composite numbers (sometimes abbreviated as "composites") are 4, 6, 8, 9, 10, 12, 14, 15, and 16.

A composite number is one that can be formed by multiplying two smaller positive integers. It is a positive integer with at least one divisor other than 1 and itself. Every positive integer is either composite, prime, or the unit 1, so composite numbers are those that are neither prime nor a unit.

In this case, the factor of 49 are 1, 7 and 49. Therefore, it's a composite number.

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Piece of rope is 24 1/2 feet long how many 1/4 foot sections will there be?

Answers

By taking a quotient between the lengths, we will see that 98 pieces of 1/4 foot can be made.

How many 1/4 foot sections are in the piece of rope?

We know that the total length of the rope is (24 + 1/2) ft, to see how many pieces of 1/4 feet we can take from that rope, we need to take the quotient between the total length and the length of the pieces.

It gives:

Q = (24 + 1/2)ft/(1/4)ft = 4*(24 + 1/2)

Q = 4*24 + 4*(1/2)

Q = 96 + 4/2

Q = 96 + 2 = 98

So 98 pieces of 1/4 foot can be made.

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A single serving of hot chocolate requires 0.75 cups of milk. Nina used 7 cups of milk to make hot chocolate for her 9 friends. Did she make enough for each friend to get a serving of hot chocolate?

Answers

Yes, 0.75 x 9 = 6 cups.

Answer:

nik

Step-by-step explanation:

HELP NOW
Which variables would the scatter plot at the right be most likely to represent?

A.The number of people at a concert and the total concession sales


B.The number of guests at a hotel and the total water consumption


C.The number of siblings a person has and the person's GPA


D.The total number of miles driven and the total gallons of gas used

Answers

The answer should be C

My reasoning is that the scatter plot has no set direction and the number of siblings has no relationship to someone’s GPA.

The sum of two numbers is 12. The difference of the two numbers is 6. What are the two numbers?

Answers

Answer:

3 and 9

Step-by-step explanation:

x+y=12

y-x=6

y-x=6

 +x.  +x

y=6+x

x+(6+x)=12

6+2x=12

-6.    -6

2x=6

/2. /2

x=3

3+y=12

-3.  -3

y=9

Hopes this helps please mark brainliest

dentify on which quadratic function is positive.

Y = 2x^2 - 17x + 30

Identify on which quadratic function is negative.

Y = - x^2 - 6x - 8

A explanation on the answers would be appreciated!

(Lots of points!)

Answers

Step-by-step explanation:

Let us identify which quadratic function is positive. Yeah, let's start.

Y = [tex]{ \red{ \sf{2 {x}^{2} - 17x + 30}}}[/tex]

By using factorisation method,

[tex]{ \red{ \sf{2 {x}^{2} - 12x - 5x + 30}}}[/tex]

Take common factors

[tex]{ \red{ \sf{2x(x - 6) - 5(x - 6)}}}[/tex]

[tex]{ \red{ \sf{(2x - 5)}}} \: \: \: \: \: \: \: || \: \: \: \: \: { \red{ \sf{(x - 6)}}}[/tex]

[tex]{ \red{ \sf{2x - 5 = 0}}} \: \: || \: \: { \red{ \sf{x - 6 = 0}}}[/tex]

[tex]{ \red{ \sf{2x = 5}}} \: \: \: \: \: \: \: \: \: || \: \: \: \: { \red{ \boxed{ \green{ \sf{x = 6}}}}}[/tex]

[tex]{ \red{ \sf{{ \frac{ \cancel2}{ \cancel2}x}}}} = { \red{ \sf{ \frac{5}{2}}}}[/tex]

[tex]{ \red{ \boxed{ \green{ \sf{x = \frac{5}{2}}}}}} [/tex]

____________________________________

Y = [tex]{ \blue{ \sf {{ - x}^{2} - 6x - 8}}}[/tex]

By using factorisation method,

[tex]{ \blue{ \sf{ - {x}^{2} - 2x - 4x - 8}}}[/tex]

Take common factors

[tex]{ \blue{ \sf{ - x(x + 2) - 4(x + 2)}}}[/tex]

[tex]{ \blue{ \sf{( - x - 4)}}} \: \: \: \: \: || \: \: \: \: \: { \blue{ \sf{(x + 2)}}}[/tex]

[tex]{ \blue{ \sf{- x - 4 = 0}}} \: \: \: \: \: || \: \: \: \: \: { \blue{ \sf{x + 2 = 0}}}[/tex]

[tex]{ \blue{ \boxed{ \green{ \sf{x = -4}}}}} \: \: \: \: \: || \: \: \: \: \: { \blue{ \boxed{ \green{ \sf{x = -2}}}}}[/tex]

Hence, the first quadratic function is positive and second quadratic function is negative.

Answer:

[tex]\textsf{$y = 2x^2 - 17x + 30$: \quad $\left(-\infty, \dfrac{5}{2}\right) \cup (6, \infty)$}[/tex]

[tex]\textsf{$y = - x^2 - 6x - 8$: \quad $\left(-\infty, -4\right) \cup (-2, \infty)$}[/tex]

Step-by-step explanation:

A function is positive when it is above the x-axis, and negative when it is below the x-axis.

---------------------------------------------------------------------------------

Given quadratic equation:

[tex]y = 2x^2 - 17x + 30[/tex]

Factor the equation:

[tex]\implies y = 2x^2 - 17x + 30[/tex]

[tex]\implies y = 2x^2 - 5x-12x + 30[/tex]

[tex]\implies y=x(2x-5)-6(2x-5)[/tex]

[tex]\implies y=(x-6)(2x-5)[/tex]

The x-intercepts of the parabola are when y = 0.

To find the x-intercepts, set each factor equal to zero and solve for x:

[tex]\implies x-6=0 \implies x=6[/tex]

[tex]\implies 2x-5=0 \implies x=\dfrac{5}{2}[/tex]

Therefore, the x-intercepts are x = ⁵/₂ and x = 6.

The leading coefficient of the given function is positive, so the parabola opens upwards.  

The function is positive when it is above the x-axis.

Therefore, the function is positive for the values of x less than the smallest x-intercept and more than the largest x-intercept:

[tex]\textsf{Solution: \quad $x < \dfrac{5}{2}$ \;and \;$x > 6$}[/tex][tex]\textsf{Interval notation: \quad $\left(-\infty, \dfrac{5}{2}\right) \cup (6, \infty)$}[/tex]

---------------------------------------------------------------------------------

Given quadratic equation:

[tex]y = - x^2 - 6x - 8[/tex]

Factor the equation:

[tex]\implies y = - x^2 - 6x - 8[/tex]

[tex]\implies y = -(x^2 +6x +8)[/tex]

[tex]\implies y = -(x^2 +4x +2x+8)[/tex]

[tex]\implies y = -((x(x+4)+2(x+4))[/tex]

[tex]\implies y = -(x+4)(x+2)[/tex]

The x-intercepts of the parabola are when y = 0.

To find the x-intercepts, set each factor equal to zero and solve for x:

[tex]\implies x+4=0 \implies x=-4[/tex]

[tex]\implies x+2=0 \implies x=-2[/tex]

Therefore, the x-intercepts are x = -4 and x = -2.

The leading coefficient of the given function is negative, so the parabola opens downwards.  

The function is negative when it is below the x-axis.

Therefore, the function is negative for the values of x less than the smallest x-intercept and more than the largest x-intercept:

[tex]\textsf{Solution: \quad $x < -4$ \;and \;$x > -2$}[/tex][tex]\textsf{Interval notation: \quad $\left(-\infty, -4\right) \cup (-2, \infty)$}[/tex]

See picture-multiple choice.

Answers

A, f(x) is the line making x the axis
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