Answer:
8
8
8
8 8
8 8 8
-------------------
1 0 0 0
Step-by-step explanation:
Assume the sample is a random sample from a distribution that is reasonably normally distributed and we are doing inference for a sample mean. Find endpoints of a t-distribution with 0.005 beyond them in each tail if the sample has size n
Answer:
The correct answer is "2.660".
Step-by-step explanation:
Given that,
Sample size,
n = 61
t-distribution with,
t = 0.005
Now,
The degree of freedom will be:
= [tex]n-1[/tex]
= [tex]61-1[/tex]
= [tex]60[/tex]
hence,
⇒ [tex]t,df=t_{0.005}, 60[/tex]
[tex]=2.660[/tex]
Drag each pair of rates to the correct location on the table.
Identify the pairs of rates as equivalent or not equivalent.
and and and and and 10 and
PLS PLS PLSS HELP ME OUT
Answer:
36/6 and 6/1 is equivalent
20/5 and 3/1 is not equivalent
18/3 and 9/1 is not equivalent
35/7 and 5/1 is equivalent
32/4 and 8/1 is equivalent
100/10 and 5/1 is not equivalent.
Step-by-step explanation:
36 divided by 6 is 6.
20 divided by 5 is 4.
18 divided by 3 is 6.
35 divers by 7 is 5.
32 divided by 4 is 8.
100 divided by 10 is 10.
Can someone help me find the equivalent expressions to the picture below? I’m having trouble
Answer:
Options (1), (2), (3) and (7)
Step-by-step explanation:
Given expression is [tex]\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}[/tex].
Now we will solve this expression with the help of law of exponents.
[tex]\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}[/tex]
[tex]=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}[/tex]
[tex]=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}[/tex]
[tex]=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}[/tex]
[tex]=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}[/tex]
[tex]=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}[/tex]
[tex]=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }[/tex] [Option 2]
[tex]2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2[/tex] [Option 1]
[tex]2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2[/tex]
[tex]=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }[/tex]
[tex]=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }[/tex] [Option 3]
[tex]2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }[/tex]
[tex]=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}[/tex] [Option 7]
Therefore, Options (1), (2), (3) and (7) are the correct options.
2x -20 = -30
What is x?
Help me plsssssssssss
Which expression can be used to determine the length of segment ZY?
On a coordinate plane, triangle X Y Z has points (3, 1), (3, 4), (negative 5, 1).
Answer:
The length of segment ZY is of [tex]\sqrt{73}[/tex] units.
Step-by-step explanation:
Distance between two points:
Suppose that we have two points, [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]. The distance between them is given by:
[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
In this question:
Point Z has coordinates (-5,1)
Pount Y has coordinates (3,4).
The length of segment ZY is the distance between points Z and Y. Thus
[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]D = \sqrt{(-5-3)^2+(1-4)^2}[/tex]
[tex]D = \sqrt{8^2+3^2}[/tex]
[tex]D = \sqrt{73}[/tex]
The length of segment ZY is of [tex]\sqrt{73}[/tex] units.
r − ns × 12
for n = 2, r = 9, and s = 3.
Answer:
-63
Step-by-step explanation:
9 - (2×3) × 12
9 - (6 × 12)
9 - 72
= -63
Answer:
-63
Step-by-step explanation:
r − ns × 12
Let n = 2, r = 9, and s = 3
9 - (2)*3 * 12
Multiply first
9 - 72
-63
Amie collects data on the fuel efficiency, in miles per gallon, and the mass, in kilograms, of
several different cars. She creates a scatter plot and determines that the line of the best fit for
the scatter plot has the equation y = 43.28 -0.011x, where y is the fuel efficiency, in miles per
gallon, and x is the mass, in kilograms. Based on this model, which of the following statements
is true?
O For every 100-kilogram increase in mass, the fuel efficiency of car decreases by about 0.4 miles
per gallon
O For every 100-kilogram increase in mass, the fuel efficiency of car increases by about 1.1 miles
per gallon
O For every 100-kilogram increase in mass, the fuel efficiency of car decreases by about 1.1 miles
per gallon
O For every 100-kilogram increase in mass, the fuel efficiency of car increases by about 0.4 miles
per gallon
Answer:
For every 100-kilogram increase in mass, the fuel efficiency of car decreases by about 1.1 miles per gallon.
Step-by-step explanation:
Fuel efficiency after x kg in mass:
y = 43.28 -0.011x
Thus, the slope is of -0.011 per x kg.
Increase of 100:
When x = 100, as the slope is negative, the efficiency will decay by:
-0.011*100 = -1.1
Decay of 1.1 miles per gallon, so the answer is:
For every 100-kilogram increase in mass, the fuel efficiency of car decreases by about 1.1 miles per gallon.
Igor is in high school and got a part time job with every paycheck he has decide 10%will go to short term savings 20%to long term savings and the rest he will use for his current expenses and spending .
Find the distance between the points (6,5) and (4,-2). use of the graph is optional
Answer ? Anyone
Answer:
√53
Step-by-step explanation:
Distance between two points =
√(4−6)^2+(−2−5)^2
√(−2)^2+(−7)^2
= √4+49
=√53
= 7.2801
Hope this helps uwu
9514 1404 393
Answer:
option 2: √53
Step-by-step explanation:
The distance formula is useful for this:
d = √((x2 -x1)² +(y2 -y1)²)
d = √((4-6)² +(-2-5)²) = √((-2)² +(-7)²) = √(4+49)
d = √53
The distance between the given points is √53.
3x+2y=4 and -2x+2y=24
Answer:
1x= 28
y= v7vub8b9nf7v6v
a farmer employs 12 men to harvest his crops.they take 9 boys to do the job.if he had employed 8 men,how ling would it have taken.
Answer:
it needs more information
Demonstrate 528 divide by 4 using 10 blocks and the scaffolding method
Describe the shape that would result from a horizontal slice of the figure below.
PLEASE ANSWER FAST ILL MARK BRAINLEIST.!!!
Answer:
A triangular prism and a trapezoidal prism, if I understand the question
Step-by-step explanation:
There wound be a trapezoid and a triangle if you cut it horizontally. If you mean vertically, it would be a right triangular prism
what is the common difference of the following sequence? 4.3,5,7,9,11___
5.16,19,22,25__
Answer:
Step-by-step explanation:
4). Given sequence → 3, 5, 7, 9, 11........
Common difference of an arithmetic sequence is defined by,
Common difference = Successive term - previous term
= 2nd term - 1st term
= 5 - 3
= 2
5). Given sequence → 16, 19, 22, 25........
Common difference of an arithmetic sequence = Second term - first term
= 19 - 16
= 3
I am trying to graph y=2x-7
Step-by-step explanation:
The given equation is :
y = 2x-7
We will first find the points,
x 0 , , 3.5, 1 , 2 , 3
y -7 , 0, -5, -3, -1
The graph of the above equation is as follows :
It is a linear equation.
Write down the name of each of these shapes
A)
B)
C)
D)
Answer:
a - Right angled triangle
b - Parallelogram
c - Square
d - kite
Step-by-step explanation:
Hope this helps
Goodluck
These are the names of each of these shapes;
1. Right-angled triangle
2. Parallelogram
3. Square
4. kite
What is the right angle triangle?A right-angled triangle is a triangle, that has one of its interior angles equal to 90 degrees or anyone angle is a right angle.
A parallelogram is a quadrilateral with two pairs of parallel sides.
The opposite sides of a parallelogram are equal in length and the opposite angles are equal in measure.
A square is a four-sided polygon that has all sides equal in length and the measure of the angles is 90 degrees.
A kite is a quadrilateral whose four sides can be grouped into two pairs of equal-length sides that are adjacent to each other.
These are the names of each of these shapes;
1. Right-angled triangle
2. Parallelogram
3. Square
4. kite
Learn more about parallelogram here;
https://brainly.com/question/12906753
#SPJ2
Please help.
60
41
49
30
Answer: [tex]30^{\circ}[/tex]
Step-by-step explanation:
[tex]\cos x=\frac{13}{15}\\\\x=\cos^{-1} \left(\frac{13}{15} \right)\\\\x \approx 30^{\circ}[/tex]
ASAP PLZ PLZ PLZ PLZZZZZZ
Answer:x=( y-p-mq)/m
Step-by-step explanation:
y-p=m(x-q)
x-q= y-p/m
x=y-p/m=q= y-p+mq/m
x= y-p+mq/m
If x = 35°, which two lines can be proven parallel?
a)n and o
b)l and m
c)n and l
d)m and o
Answer:
a) n and o
Step-by-step explanation:
by the concept of corresponding angles, angles that are equal when a line intersects 2 parallel lines .
l is the line that intersects n and o, and since x = 35, theyre corresponding angles resulting in n and o being parallel
Answer:
a) n and o
Step-by-step explanation:
Corresponding angles
Simplify the following expression.
29.718 - 29.63
Answer:
0.088 is the answer...
a musician believes that listening to classical music affects mood determine if two-tailed or one-tailed
Answer:
I think one tailed correct me if im wrong
help me :) which this question plzzzz !!
I believe its <ABF =<EDJ
Solve the system of equations Y=-2x+5 and y=x^2+3x+9
I think
x= -4, -1 and y=13, 8
(-4, 13) and (-1, 8)
Verify each trigonometric equation by substituting identities to match the right hand side of the equation to the left hand side of the equation.
cot x sec4x = cot x + 2 tan x + tan3x
(sin x)(tan x cos x - cot x cos x) = 1 - 2 cos2x
1 + sec2x sin2x = sec2x
sine of x divided by one minus cosine of x + sine of x divided by one minus cosine of x = 2 csc x
- tan2x + sec2x = 1
Answer:
Step-by-step explanation:
1)
[tex]cot x sec^4 x = cotx + 2tanx + tan^3 x[/tex]
[tex]RHS =[/tex]
[tex]=\frac{cosx}{sinx} + 2 \frac{sinx }{cosx} + \frac{sin^3x }{cos^3x}\\\\[/tex]
[tex]= \frac{cosx(cos^3x) + 2sinx(sinx \ cos^2x ) + sin^3x(sinx)}{sinx \ cos^3x}\\\\[/tex] [tex][\ taking LCM \ ][/tex]
[tex]=\frac{cos^4x + 2sin^2xcos^2x +sin^4x }{sinx cos^3x}[/tex]
[tex]= \frac{(sin^2 x + cos^2x)^2 }{sin x \ cos^3 x}[/tex] [tex][ \ a^4 + 2a^2b^2 + b^4 = (a^2 + b^2 ) ^2 \ ][/tex]
[tex]= \frac{1}{sinx \ cos^3 x}\\\\= \frac{1 \times cosx}{sinx \times cos^3x \times cosx}[/tex] [tex][ \ multiplying\ and \ dividing \ by \ cosx \ ][/tex]
[tex]= \frac{cosx}{sinx} \times \frac{1}{cos^4x}\\\\=cot x \ sec^4 x[/tex]
[tex]= LHS[/tex]
2)
[tex]sin x \ ( tanx \ cosx - cotx \ cosx) = 1 - 2cos^2x[/tex]
[tex]LHS =[/tex]
[tex]=sinx( [ \frac{sinx}{cosx} \times cosx)] - [ \frac{cosx}{sinx}\times cosx] )\\\\= sinx (sinx - \frac{cos^2x}{sinx})\\\\=sin^2x - cos^2 x\\\\=(1 - cos^2x ) -cos^2 x[/tex] [tex][ \ sin^2x = 1 -cos^2 x \ ][/tex]
[tex]= 1 -cos^2x - cos^2 x \\\\= 1 - 2cos^2x \\\\=RHS[/tex]
3)
[tex]1 + sec^2x \ sin^2x = sec^2 x[/tex]
[tex]LHS =[/tex]
[tex]= 1 +sec^2x \sin^2x \\\\= 1 + (\frac{1}{cos^2x} \times sin^2x )\\\\= 1 + \frac{sin^2 x}{cos^2x}\\\\= 1 + tan^2x \\\\= sec^2 x\\\\=RHS[/tex]
4)
[tex]\frac{sinx}{1 -cosx} + \frac{sinx}{1+cosx} = 2 \ cosec x[/tex]
[tex]LHS =[/tex]
[tex]=\frac{sinx}{1 -cosx} + \frac{sinx}{1+cosx} \\\\= \frac{sinx(1 +cosx)}{(1-cosx)(1+cosx)} + \frac{sinx(1-cox)}{(1+cosx)(1-cosx)}\\\\= \frac{sinx +sinx\ cosx}{(1 - cos^2x)} + \frac{sinx - sinx \ cosx}{1 - cos^2x}\\\\=\frac{sinx + sinx \ cosx + sinx - sinx \ cosx}{1 - cos^2x}\\\\=\frac{2sinx}{sin^2x}\\\\=\frac{2}{sinx}\\\\=2 cosec\ x\\\\=RHS[/tex]
5)
[tex]- tan^2 + sec^2 x = 1\\\\[/tex]
[tex]sin^2 x + cos^2 x = 1\\\\\frac{sin^2x }{cos^2x} + \frac{cos^2x}{cos^x} = \frac{1}{cos^2x}\\\\tan^2x + 1 = sec^2x \\\\1 = sec^2 - tan^2x \\\\-tan^2x + sec^2 x = 1[/tex]
NEED HELP ON THIS ASAP PLZ!!
Answer:
x = 9.7
Step-by-step explanation:
tan θ = opposite side / adjacent side
tan 37° = x / 13
multiply 13 on each side
13 × tan 37° = 13 × x /13
13 × tan 37° = x
Rewrite
x = 13 × tan 37°
multiply, we get
x = 13 × 0.75355..
x = 9.79620265
Round nearest tenth = 9.7
Can someone please help ASAP!!
Step-by-step explanation:
you need to find:
uw:
uv:
vw= 8(already known)
Measure of W= 35
Measure of u= 90
measure of v= 180-90+35= 55
finding uv:
sin(35)= uv/8
0.57=uv/8
4.56=uv
finding uw:
sin(55)= uw/8
0.82= uw/8
6.56= uw
Ryder is building a workbench.
The top of the workbench is a rectangular piece of plywood that is 6.25 feet long and 1.83 feet wide.
Part A
Round the length and width to the nearest whole number.
Then estimate the perimeter of the workbench.
Which of the following equations models this estimate of the perimeter?
A. 6 + 6 + 2 + 2 = 16
B. 6 × 2 = 12
C. 7 + 7 + 2 + 2 = 18
D. 7 × 2 = 14
Part B
Round the length and width to the nearest tenth.
Then estimate the perimeter of the workbench.
Which of the following equations models this estimate of the perimeter?
A. 6.2 + 6.2 + 1.8 + 1.8 = 16
B. 6.2 × 1.8 = 11.16
C. 6.3 + 6.3 + 1.8 + 1.8 = 16.2
D. 6.3 × 1.8 = 11.34
Find the center and foci of the ellipse:
16x2 + 25y2 – 64x – 50y - 311 = 0
Answer:
You should first make sure you explain what exactly is the question, before delete others answers.♀️♀️
Step-by-step explanation:
NO LINKS!!!
What is the volume of this solid?
220 cubic units.
Answer:
Solution given:
for small cylinder
r=1
and for large cylinder
R=5+1=6
height for both [h]=2
Now
Volume of solid=πR²h-πr²h=πh(R²-r²)
=3.14*2(6²-1²)=219.8 =220 units ³.
Small cylinder is r=1
Large cylinder is R= 5+1 =6
Height (h) =2
Volume of solid,
→ πR²h-πr²h
→ πh(R²-r²)
→ 3.14 × 2(6²-1²)
→ 219.8
→ 220 cubic units