Can someone help me with these problems and explain them as well please

Answer:

[tex]17 \le t \le 28[/tex]

Step-by-step explanation:

Given

[tex]t = 22\frac{1}{2}[/tex] --- average time

[tex]\triangle t = 5\frac{1}{2}[/tex] --- the variation

Required

The inequality to represent the scenario

To do this, we simply add and subtract the variation from the average time.

i.e.

[tex]t \± \triangle t[/tex]

So, the inequality is:

[tex]22\frac{1}{2} - 5\frac{1}{2} \le t \le 22\frac{1}{2} + 5\frac{1}{2}[/tex]

Solve:

[tex]17 \le t \le 28[/tex]

Answer:

Step-by-step explanation:

Step 1:  Find slope of Linear function A

[tex]slope = \frac{y_2 - y_1}{x_2-x_1} = \frac{-5--1}{-4--2} = \frac{-5 +1}{-4+2} = \frac{-4}{-2} = 2[/tex]

Step 2 : Find slope of B

Since they are perpendicular to each other, product of their slope = -1

That is,

   [tex]m_A \times m_B = - 1\\2 \times m_B = -1\\\\slope, m_B = \frac{-1}{2}[/tex]

Given the function passes through (4, -6)

Equation of the linear function :

                                         [tex]x_3 = 4 \ , \ y_3 = -6\\\\(y - y_3) = m_B (x - x_3)\\\\(y - -6) = -\frac{1}{2} (x - 4)\\\\y + 6 = -\frac{1}{2}x + 2\\\\y = -\frac{1}{2}x + 2 - 6 \\\\y = -\frac{1}{2}x -4[/tex]

Part B

Linear Function is parallel to B

Therefore the slope of B and slope of C are the same. And the equation will be of the form :

                   [tex]y = -\frac{1}{2} x + C[/tex]

Answer:  D

Step-by-step explanation:

We're given a point (a,b) that happens to be on the unit circle, a²+b²=1, so a is the cosine of the angle θ and b is its sine.

Answer:

option 4

Step-by-step explanation:

Answer:

[tex]\sqrt{53}[/tex]

Step-by-step explanation:

Answer:

A = 5

B = -13

C = 7

Step-by-step explanation:

The general formula of quadratic equation is ax^2+bx+c.

Answer:

BC = 8 cm

Step-by-step explanation:

tan(x) = sin(x)/cos(x)

sin(x) is the opposite side of the angle x.

cos(x) is the side with a right angle to sin(x).

2 = 12/EC

EC = 12/2 = 6 cm

=>

CD = ED - EC = 10 - 6 = 4 cm

now, the same tan(x) relation had to be true for BCD.

tan(x) = BC/CD

2 = BC/4

BC = 8 cm

Answer:

8

Step-by-step explanation:

Range is found by taking the largest number and subtracting the smallest number

The largest number is 9

The smallest number is 1

9-1 =8

The range is 8

Answer:

8

Step-by-step explanation:

Range = highest value - lowest value

Range = 9 - 1

Range = 8

Answer:

Step-by-step explanation:

let -2/3 be the rational number and 9 be the positive real number

according to the given of indices this tis can be written as

[tex]9^{-2/3}[/tex]

[tex](3)^{2*-2/3}[/tex]

[tex]3^{-4/3}[/tex]

1/3^4/3

Answer:

7 groups

Step-by-step explanation:

1 hour = 60 minutes

3/4 of an hour = 3/4(60) = 45 minutes

therefore, 1 3/4 hours is 105 minutes

105 divided by 15 is 7

Answer: 3/4

Step-by-step explanation:

Did the test

The required multiplicative rate in the given function is 3 / 4. Option B is correct.

The function which is in format f(x) =a^x  where a is constant and x is variable,  the domain of this exponential function lies   (-∞, ∞).

Here,
From the table of the exponential functions,
The multiplicative factor is given as,
K = y₂/y₁
K =  [9 / 8] / [3/2]
K = 3 / 4

Thus, the required multiplicative rate in the given function is 3 / 4. Option B is correct.

learn more about exponential function here:

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the answer is 165 I think because I didn't understand the question

Answer:

y=-1

Step-by-step explanation:

y=-1 just shows the y value which means its just a horizontal line which is parallel to the x axis.

Answer:

yes

Step-by-step explanation:

Answer:

angle x= 60

so it is in the ratio 1:2:√3

√3x=3

ie.x=√3/3

adjacent side=x=√3/4

Step-by-step explanation:

everything can be found in the picture

Answer:

if your in high school why you need the answer

Step-by-step explanation:

t f

hi i am a boy that does math at school

Answer:

using pythagoras theorem

hyp 2=opp 2+adj 2

=( √6)(√6)+(√7)(√7)

hyp 2=13

hyp=√13

Given:

A right angle triangle with legs [tex]\sqrt{6}[/tex] cm and [tex]\sqrt{7}[/tex] cm. The length of the hypotenuse is x.

To find:

The value of x.

Solution:

Pythagoras theorem: In a right angle triangle,

[tex]Hypotenuse^2=Base^2+Perpendicular^2[/tex]

Using the Pythagoras theorem, we get

[tex]x^2=(\sqrt{7})^2+(\sqrt{6})^2[/tex]

[tex]x^2=7+6[/tex]

[tex]x^2=13[/tex]

Taking square root on both sides, we get

[tex]x=\sqrt{13}[/tex]                  [Because side length is always positive]

The measure of hypotenuse is [tex]\sqrt{13}[/tex] cm.

Therefore, the correct option is B.

Answer:

63/10,  6.396,  6.99,  7 4/11

Step-by-step explanation:

Convert all to fraction or decimal

Step-by-step explanation:

you tu tubless

ar vi ing

..............

Answer:

i don't know

Step-by-step explanation:

fffgg

Answer:

-10<x<6

Step-by-step explanation:

Find where x starts and where x ends

Answer:

c

Step-by-step explanation:

used socratic

Answer:

Step-by-step explanation:

Compare the given y = x - 7 to the general slope-intercept formula

                                 y = mx + b

Here the slope is 1 and the y-intercept, b, is -7.

Answer:

Step-by-step explanation:

Slope - y intercept form : y = mx +c

y = x - 7

m = 1

c = -7

Answer:

A. 7986.45

[tex] \frac{4}{3} \pir3[/tex]

i think b. not sure sorry if im wrong

Answer:

The given parameters of the study are;

The number of people in the sample, n = 200

The p-value = 0.013

The average increase between fall and spring semester = $0.35

Therefore, we have;

Given that the p-value is less than 0.05, we reject the null hypothesis, and that there is significant statistical evidence to suggest that there is a difference between the fall and spring semester tuition at universities across the U.S.

Step-by-step explanation:

The result of the test hypothesis is incorrect or should be rejected.

Researchers frequently use P-values to determine if a trend they've seen is statistically significant. The p-value of a statistical test is small enough to reject the null hypothesis of the test, which is referred to as statistical significance.

The likelihood that the null hypothesis is true is P > 0.05. The likelihood that the alternative hypothesis is correct is (1-P) the P-value. The test hypothesis is incorrect or should be rejected if the test result is statistically significant (P≤0.05). There was no effect if the P-value was bigger than 0.05.

We reject the null hypothesis since the p-value is less than 0.05, and there is strong statistical evidence to imply that there is a difference between autumn and spring semester tuition at institutions across the United States.

Hence, the result of the test hypothesis is incorrect or should be rejected.

Learn more about P-Value:

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A + B are correct

via a p e x

The correct statements are A and B

'A triangle in which one of the interior angles is 90° is called a right-angled triangle. The longest side of the right triangle, which is also the side opposite the right angle, is the hypotenuse and the two arms of the right angle are the height and the base.'

According to the given problem,

cos(A−B) = cosAcosB + sinAsinB .

Let A=90∘, B = a

Therefore.

cos(90∘−a) = cos90∘cosa + sin90∘sina.

Here, we have,

cos90∘ = 0, sin90∘ = 1.

cos(90∘−a) = sina

Now, we know,

sin∅ = [tex]\frac{Perpendicular}{Hypotenuse}[/tex]

cos∅ = [tex]\frac{Base}{Hypotenuse}[/tex]

For ∠BAC,

cosA = [tex]\frac{AB}{AC}[/tex]

For ∠ACB,

sinC =  [tex]\frac{AB}{AC}[/tex]

Hence, we can conclude, A and B are the true statements for the given right-angled triangle.

Learn more about right-angled triangle here:

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Answer:

Hi, there for x it will be x=−2y+6

But if your solving for y it will be [tex]y=-\frac{1}{2}x+3[/tex]

Hope this Helps :)

Step-by-step explanation:

Let's solve for x.

2x+4y=12

Step 1: Add -4y to both sides.

2x+4y+−4y=12+−4y

2x=−4y+12

Step 2: Divide both sides by 2.

[tex]\frac{2x}{2}=\frac{-4y+12}{2}[/tex]

x=−2y+6

2.

Let's solve for y.

2x+4y=12

Step 1: Add -2x to both sides.

2x+4y+−2x=12+−2x

4y=−2x+12

Step 2: Divide both sides by 4

[tex]\frac{4y}{4} =\frac{-2x+12}{4}[/tex]

[tex]y=-\frac{1}{2} x+3[/tex]