Answer:
I think A= 5M/S is answer
A student squeezes a clothespin 82 times in a minute. Then, using the same hand and the same clothespin, he squeezes the clothespin 68 times in a minute. State one biological reason for the decrease in the number of squeezes during the second trial.
Answer:
The student squeezed the clothespin less the second time because the muscles in his hand began to fatigue
Explanation:
Why does Farm Bureau and other advocacy organization oppose any mandated labeling of biotech crops?
Answer:
I’m. Nog sure
Explanation:
10 POINTS QUESTION: Why both are models for monomers, polymers, and cross-linked polymers
Answer:
Because both monomers and polymers and cross linked polymers are mers with physically properties which is good for applycations
Explanation:
because they are good for using and not using
also, this is a 5 point question, you are not fooling anyone. thx for 5 points tho
A car traveled 1,215 km West from El Paso to Dallas in 13.5 hours. What was its velocity?
A. 90m/s West
B. 90km/h
C. .09km/h West
D. 90km/h West
3. The velocity of sound is 332 m/s. Answer the following questions:
i) What is the minimum and maximum frequency of sound which
is heard to the human ear?
ii) What is the wavelength of the shortest and longest waves heard
to the human ear?
Answer:
20 Hz, 20000 Hz
0.0166 m, 16.6 m
Explanation:
The minimum frequency that a human ear can hear is 20 Hz
The maximum frequency that a human ear can hear is 20000 Hz.
v = Velocity of sound = 332 m/s
Wavelength is given by
[tex]\lambda=\dfrac{v}{f}\\\Rightarrow \lambda=\dfrac{332}{20}\\\Rightarrow \lambda=16.6\ \text{m}[/tex]
The longest wavelength that can be heard by the human ear is 16.6 m
[tex]\lambda=\dfrac{332}{20000}\\\Rightarrow \lambda=0.0166\ \text{m}[/tex]
The shortest wavelength that can be heard by the human ear is 0.0166 m.
A professional golfer walks at an at an average rate of 4.20 meters per second on the golf course. The amount of time required for her to walk from the tee to the green 622 meters away is
Answer:
T try d add b CD c
Explanation:
Cdgffd
When a ball is thrown into the air, it falls back to the round. What
causes this to happen?
The round shape of the ball.
The way the ball is thrown.
The force of air against the ball.
The force of gravity on the ball.
to
+ Previous
Next
Answer:
The force of Gravity on the ball
Explanation:
Gravity of earth pulls the ball back down to the ground.
Which of these statements is FALSE?*
If you find someone's DNA at a crime scene, they are guilty without a doubt
Even identical Twins have different DNA Fingerprints
DNA is individual evidence
When DNA is found, it will not always lead to usable DNA Fingerprint evidence
The middle one please need done by 3
A 5.75 g bullet is fired with a velocity of 1.50 x 102 m/s toward a stationary solid block resting on a frictionless surface. The bullet embeds but the block does not move. 1. What is the change in momentum of the bullet if it embeds in the block? 2. What is the change in momentum of the bullet if it bounces off the block in the opposite direction with a speed of 100 m/s?
Answer:
1. -0.863 kgm/s 2. -1.438 kgm/s
Explanation:
1. What is the change in momentum of the bullet if it embeds in the block?
Since the block does not move, the velocity of the bullet after hitting the block , v is zero. That is v = 0 m/s
Now, the momentum change of the bullet ΔP = m(v - u) where m = mass of block = 5.75 g = 5.75 × 10⁻³ kg, u = initial velocity of bullet = 1.50 × 10² m/s and v = final velocity of bullet after hitting the block = 0 m/s (since it embeds in the block and the block does not move).
So, ΔP = m(v - u)
= 5.75 × 10⁻³ kg(0 m/s - 1.50 × 10² m/s)
= 5.75 × 10⁻³ kg(- 1.50 × 10² m/s)
= -8.625 × 10⁻¹ kgm/s
= -0.8625 kgm/s
≅ -0.863 kgm/s
2. What is the change in momentum of the bullet if it bounces off the block in the opposite direction with a speed of 100 m/s?
If it bounces off the block in the opposite direction with a speed of 100 m/s, then its final velocity is v = -100 m/s.
So, our momentum change ΔP' = m(v - u) where m = mass of block = 5.75 g = 5.75 × 10⁻³ kg, u = initial velocity of bullet = 1.50 × 10² m/s and v = final velocity of bullet after hitting the block = -100 m/s = -1 × 10² m/s
So, ΔP = m(v - u)
= 5.75 × 10⁻³ kg(-1 × 10² m/s - 1.50 × 10² m/s)
= 5.75 × 10⁻³ kg(-2.50 × 10² m/s)
= -14.375 × 10⁻¹ kgm/s
= -1.4375 kgm/s
≅ -1.438 kgm/s
Why do we charge a capacitor under a DC voltage source only?
An alien with a mass of 71 kg is floating 670 m from his spaceship's center of mass. His ship's mass is about 500,000 kgWhat is the gravitational attraction between the alien and his ship?
Answer:
5.28 x 10⁻⁹N
Explanation:
Given parameters:
Mass of alien = 71kg
Distance = 670m
Mass of ship = 500000kg
Unknown:
Gravitational attraction = ?
Solution:
The gravitational attraction can be found using the Universal gravitation law proposed by Newton;
Fg = [tex]\frac{G x mass 1 x mass 2}{d^{2} }[/tex]
G is the universal gravitation constant = 6.67 x 10⁻¹¹
d is the distance
Fg is the gravitational attraction
Fg = [tex]\frac{6.67 x 10^{-11} x 71 x 500000 }{670^{2} }[/tex] = 5.28 x 10⁻⁹N
Two spheres have a gravitational force between
them of 45 N. If the distance between the masses
is increased to 4.0 times its original distance, what
is the new force?
Answer:
The new force is 2.8125 N
Explanation:
Newton’s Law of Universal Gravitation
Objects attract each other with a force that is proportional to their masses and inversely proportional to the square of the distance.
[tex]\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}[/tex]
Where:
m1 = mass of object 1
m2 = mass of object 2
r = distance between the objects' center of masses
G = gravitational constant: 6.67\cdot 10^{-11}~Nw*m^2/Kg^2
Suppose two spheres have a gravitational force between them of F = 45 N. Now increase the distance to r'=4r. The new force F' is:
[tex]\displaystyle F'=G{\frac {m_{1}m_{2}}{(4r)^{2}}}[/tex]
[tex]\displaystyle F'=G{\frac {m_{1}m_{2}}{16r^{2}}}[/tex]
[tex]\displaystyle F'=\frac{1}{16}\ G{\frac {m_{1}m_{2}}{r^{2}}}[/tex]
Substituting the original value of the force:
[tex]\displaystyle F'=\frac{1}{16}\ 45 N[/tex]
F' = 2.8125 N
The new force is 2.8125 N
A 200 kg object is initially at rest on a horizontal frictionless surface. At time t = 0 , a horizontal force of 100 N applied to the object for and then removed. Which of the following is correct about object's motion at time t=2 s?
(A) It is at rest.
(B) It is moving with decreasing acceleration.
(C) it is moving with decreasing speed.
(D)it moving at a constant speed.
(E) It is moving with increasing speed
Answer:
b
Explanation:
Charlie wants to build a magnetic levitation train for his younger brother. Charlie has drawn a diagram of his train and has built the train. What should Charlie do next with his design?
A. Test the device, get feedback from other people, and revise the design if needed.
B. Show his design to other people and get feedback before selling his design.
C. Publish his design in a magazine as is and wait for investors.
D. Test the device and sell it to the local veterinarian.
Answer:
B
Explanation:
I can't explain right now, mabe later.
Select ALL of the places you might find DNA evidence.
saliva on gum
blood spatter on the wall
inside a femur bone found in the woods
cells on root of hair found at the scene
Answer:
Inside a femur bone found in the woods,
saliva of gum
A negative charge of 20 x 10-6C and another charge of 15 x 10-6C are separated by as distance of 0.7 m.
What is the magnitude of the electrical force between the two charges:
answer to the closest 0.1 N
Answer:
Approximately [tex]5.5\; \rm N[/tex], assuming that the volume of these two charged objects is negligible.
Explanation:
Assume that the dimensions of these two charged objects is much smaller than the distance between them. Hence, Coulomb's Law would give a good estimate of the electrostatic force between these two objects regardless of their exact shapes.
Let [tex]q_1[/tex] and [tex]q_2[/tex] denote the magnitude of two point charges (where the volume of both charged object is negligible.) In this question, [tex]q_1 = 20 \times 10^{-6}\; \rm C[/tex] and [tex]q_2 = 15 \times 10^{-6}\; \rm C[/tex].
Let [tex]r[/tex] denote the distance between these two point charges. In this question, [tex]r = 0.7\; \rm m[/tex].
Let [tex]k[/tex] denote the Coulomb constant. In standard units, [tex]k \approx 8.98755\times 10^{9}\; \rm kg \cdot m^{3}\cdot s^{-2}\cdot C^{-2}[/tex].
By Coulomb's Law, the magnitude of electrostatic force (electric force) between these two point charges would be:
[tex]\begin{aligned}F &= \frac{k \cdot q_1 \cdot q_2}{r^{2}}\end{aligned}[/tex].
Substitute in the values and evaluate:
[tex]\begin{aligned}F &= \frac{k \cdot q_1 \cdot q_2}{r^{2}}\\ &\approx 8.98755 \times 10^{9}\; \rm kg \cdot m^{3}\cdot s^{-2}\cdot C^{-2} \\ &\quad \times 20\times 10^{-6}\; \rm C\\ &\quad \times 15\times 10^{-6}\; \rm C \\ &\quad \times \frac{1}{{(0.7\; \rm m)}^{2}}\\ &\approx 5.5\; \rm N \end{aligned}[/tex].
A force of 2 kN is applied to an object to make it move 3.6 m in the direction of the force. Select the correct value of work done on the object.
Answers to choose from:
1.8J
7200J
7.2J
555.6J
Answer:
W= F × d
W= 2kn × 3.6
W= 7.2 J
Work is measured in Joules!
A banana has a mass of 1.4 kg. What is its weight, in Newtons?
Answer
given :
m=1.4 kg
r/q = N
N = m(9.8)
= 1.4 kg(9.8)
= 13.72 Newton
Answer:
9.8066500286389 N
Explanation:
Skater A bumps into another skater, Skater B. Skater B is stationary.
The skaters move off together in a straight line.
Explain what happens to the velocity of each of the skaters.
Use the idea of conservation of momentum.
From the principle of the conservation of energy, the velocity of the moving skater would be transferred to the stationary skater.
What is the conservation of energy?We know that according to the principle of the conservation of energy, energy can neither be created nor destroyed but we can be able to convert the energy from one form to the other. Given the fact that the energy of the object can be converted, we can also look at the collision as being an inelastic Collison.
Let us recall that a collsion is said to be in elastic if the momemtum and thge kinetic energy of the colliding particles is not conserved. The simple implication of this is that the objects would stick together and then move at a common velocity after the collision must have taken place in the system.
Learn more about energy conservation:https://brainly.com/question/13949051
#SPJ1
A truck with a mass of 5000 kg and transfers 800,000 newtons(N) of force when it hits a wall. What was the acceleration of the truck?
a. 160 m/s
b. 160 km/hr
c. 160 m/s2
d. 160 miles/hr
Name the type of reproduction process as shown in Fig 1 and Fig 2. State one point of difference between the two
Figure 1= binary fission in amoeba
figure 2= budding in yeast
difference
1.Parent divides to form two daughter cells and itself gets disappeared in binary fission but in budding , a bud gets matured and detaches from the parent
HELP I GIVE YOU BRAIN!!!!
Answer: The trip took 40 minutes average speed should be 1 mph
Explanation: It takes aprox 12 mins to reach 20km and the trip took 40 mins. This is obviously above what it should be. Not sure if I'm 100% correct
please answerrr asapp tyty Laura goes for cycle from her house to the post office 4km away how long did it take for Laura to reach the post office
Answer:
See the answer below
Explanation:
The time Laura took to reach the post office would depend on the speed of cycling.
We know that;
speed = [tex]\frac{distance}{time}[/tex]
hence,
time = [tex]\frac{distance}{speed}[/tex]
Since the distance from Laura's house to the post office is 4 km, the equation becomes;
time = [tex]\frac{4}{speed}[/tex]
Just ensure that the speed is in km per hour, minute, or seconds in order to obtain the time in hours, minutes, or seconds respectively.
The diagram shows a wave traveling through a medium.
Identify point B.
amplitude
crest
trough
wavelength
The point B represent the crest of the wave. The crest is the peak of the wave. While the trough is the lowest.
What is wavelength?The distance between two successive troughs or crests is known as the wavelength.
The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.
The point B represent the crest of the wave. The crest is the peak of the wave. While the trough is the lowest.
Hence, option B is correct.
To learn more about the wavelength, refer to the link;
brainly.com/question/7143261
#SPJ2
What is catching a pass in football called
1.Reception
2.mossed
3.Grab
4.odel Beckham
What type of wave did you create when you pushed your arm back and forth?
plz help
Answer: It is a transverse wave ^^
Explanation:
if a 2kg ball has and initial velocity of
4 m/s and is kicked and accelerated to
10 m/s in one second, what is the force that was applied to the ball? Rember that acceleration is the change in velocity/ change in time
please help me asap
Answer:
[tex]\boxed {\boxed {\sf 12 \ Newtons }}[/tex]
Explanation:
Force is equal to the product of mass and acceleration.
[tex]F=m*a[/tex]
We know the mass, but not the acceleration. Therefore, we must calculate it before we can calculate force.
1. Calculate Acceleration
Acceleration is the change in velocity over the change in time.
[tex]a=\frac{V_f-V_i}{t}[/tex]
The final velocity is 10 meters per second and the initial velocity is 4 meters per second. The time is 1 second.
[tex]V_f=10 \ m/s \\V_i= 4 \ m/s \\t= 1 \ s[/tex]
Substitute the values into the formula.
[tex]a=\frac{10 \ m/s-4 \ m/s }{1 \ s}[/tex]
Solve the numerator.
[tex]a=\frac{6 \ m/s}{1 \ s }[/tex]
Divide.
[tex]a= 6 \ m/s/s=6 \ m/s^2[/tex]
2. Calculate Force
Now we know the acceleration and the mass.
[tex]m= 2 \ kg \\a= 6 \ m/s^2[/tex]
Substitute the values into the fore formula.
[tex]F= 2 \ kg * 6 \ m/s^2[/tex]
Multiply.
[tex]F= 12 \ kg*m/s^2[/tex]
1 kilogram meter per square second is equal to 1 Newton. Our answer of 12 kg*m/s² is equal to 12 Newtons[tex]F= 12 \ N[/tex]
The force applies to the ball was 12 Newtons.
I have a 3 cc piece of aluminum with a density of steel with a mass of 24.0 g. I cut it into 2 equal pieces. How has the density of the steel pieces changed
Answer:
What happens to the density of an object if the object is cut in half? ... The density remains the same because cutting the object in half will divide the mass & volume by the same amount. Also, the density of a substance remains the same no matter what size it is.
Explanation:
What happens to the density of an object if the object is cut in half? ... The density remains the same because cutting the object in half will divide the mass & volume by the same amount. Also, the density of a substance remains the same no matter what size it is.
Which idea did Ptolemy's model use to explain why the planets appeared to move backward as they moved in their orbits? The planets spun in epicycles. The planets rotated on their axes. The planets revolved around the Sun. The planets were made of different materials.
Answer:
The planets spun in epicycles.
Explanation:
The planets were not simply attached to a mystical sphere (“deferent”) but they were actually attached to a mini-sphere (“epicycle”) which rotated on the larger one.
Answer:A
Explanation: