Answer:Position is an object's location in relation to a reference point. Yes. Both objects are one unit away (the same distance), but they occupy different locations in space because they are in different directions.
Explanation: Hope this helps!!
Yes it is possible for two objects be at the same distance from a single point but be in different positions.
We have two objects at the same distance from a single point but are in different positions.
We have to determine whether this statement is true or not.
What is a Reference frame?A reference frame can be considered as the coordinate frame with respect to origin of which the physical quantities such as velocity, displacement , acceleration etc. of any other object in different reference frame is measured.
According to the question -
YES, Two objects can have same distance from a single point or a reference point (say origin) and can be at different positions. For example - Two different points with Position vectors -
P(1) = i + j
P(2) = - i + j
are located. Now, distance of point P(1) from origin will be - [tex]\sqrt{1+1}=\sqrt{2}[/tex] and that of point P(2) from origin will be - [tex]\sqrt{(-1)^{2} +(1)^{2} } =\sqrt{2}[/tex]
Hence, yes it is possible for two objects be at the same distance from a single point but be in different positions.
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There is an attachment. There is an attachment on here.
Answer:
5 i think
Explanation:
Can you please help I’m sorry I promise this is the last time
Answer:
?
Explanation:
if the net force of 15 N is exerted on an encyclopedia to cause it to accelerate at a rate of 5 m/s2. what is the mass of the encyclopedia
Answer:
3 kg
Explanation:
F = ma
(15) = m(5)
m = 3 kg
can somone pls help asap???!!
The correct Answer: would be A B C E
Explanation:
Can i get brainlyest ?
What does the triangle mean in physics?
In physics, the triangle symbol (∆) typically represents a change or difference in a particular quantity.
A triangle is often used to denote the difference between two values of a variable. For example, if we have two values of time, t1 and t2, the change or difference in time can be represented as Δt = t2 - t1, where Δt is the triangle symbol indicating the change in time. Similarly, it can be used to represent differences in other physical quantities such as displacement (∆x), velocity (∆v), or temperature (∆T). The triangle symbol (∆) is a shorthand notation commonly used in physics to indicate changes or differences.
In terms of change in displacement, the triangle symbol (∆) represents the difference between two positions or locations. It indicates the change in the object's position from an initial point to a final point.
For example, if an object initially starts at position x1 and then moves to position x2, the change in displacement (∆x) can be calculated as ∆x = x2 - x1. Here, ∆x represents the difference or change in the object's displacement.
The magnitude of ∆x gives the overall distance traveled by the object, and its sign indicates the direction of the displacement. A positive ∆x signifies a displacement in the positive direction (e.g., to the right or upward), while a negative ∆x represents a displacement in the negative direction (e.g., to the left or downward).
Therefore, The triangle symbol (∆) is commonly used in physics equations to denote changes or differences in various quantities, including displacement, velocity, time, and more. It helps us analyze and quantify the differences between two values of a physical quantity.
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Which could most likely describe the three surfaces?
Surface 1 is ice, Surface 2 is gravel, and Surface 3
is blacktop.
Surface 1 is gravel, Surface 2 is ice, and Surface 3
is blacktop.
Surface 1 is blacktop, Surface 2 is gravel, and
Surface 3 is ice.
Surface 1 is blacktop, Surface 2 is ice, and Surface
3 is gravel.
Answer:
Surface 1 is blacktop, Surface 2 is gravel, and Surface 3 is ice.
Explanation:
Hope this helps! :]
Answer:
C. Surface 1 is blacktop, Surface 2 is gravel, and
Surface 3 is ice.
Explanation:
A waiter applies 10 Newtons of net force to accelerate some meals 2 meters across the dining room. How much work is done on the food during the acceleration ?
Answer:
The answer is 20 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 10 × 2
We have the final answer as
20 JHope this helps you
Answer:
20 i think
Explanation:
17. What is the position of the image formed by the converging lens of focal length of 12cm in
which the image formed is 1.5 times the size of the object and inverted?
A. 30 cm
B. 56 cm
C. 15 cm
D. 20 cm
Answer:
D is the correct answer
A piece of iron of mass 200g and tempreture 300°C is dropped into 1.00 kg of water of tempreture 20°C. Predict the final equilibrium of the water.
Answer:
The final equilibrium T_{f} = 25.7[°C]
Explanation:
In order to solve this problem we must have a clear concept of heat transfer. Heat transfer is defined as the transmission of heat from one body that is at a higher temperature to another at a lower temperature.
That is to say for this case the heat is transferred from the iron to the water, the temperature of the water will increase, while the temperature of the iron will decrease. At the end of the process a thermal balance is found, i.e. the temperature of iron and water will be equal.
The temperature of thermal equilibrium will be T_f.
The heat absorbed by water will be equal to the heat rejected by Iron.
[tex]Q_{iron} = Q_{water}[/tex]
Heat transfer can be found by means of the following equation.
[tex]Q_{iron}=m*C_{piron}*(T_{i}-T_{f})[/tex]
where:
Qiron = Iron heat transfer [kJ]
m = iron mass = 200 [g] = 0.2 [kg]
T_i = Initial temperature of the iron = 300 [°C]
T_f = final temperature [°C]
[tex]Q_{water}=m*C_{pwater}*(T_{f}-T_{iwater})[/tex]
Cp_iron = 437 [J/kg*°C]
Cp_water = 4200 [J/kg*°C]
[tex]0.2*437*(300-T_{f})=1*4200*(T_{f}-20)\\26220-87.4*T_{f}=4200*T_{f}-84000\\26220+84000=4200*T_{f}+87.4*T_{f}\\110220 = 4287.4*T_{f}\\T_{f}=25.7[C][/tex]
The ball in this activity could reach much greater speeds if not for the loss of energy in many different transformations. There is one major energy loss that is causing the ball to move more slowly, what is that energy? What force is acting upon the ball to create this loss of energy?
Please help quick!
Answer:
friction acts upon the ball when it is sliding down the slide and this action creates thermal energy
A swimmer jumps from a diving board into a pool. What would a graph of the swimmer's potential energy and total mechanical energy look like?(1 point)
Potential energy would increase, while total mechanical energy would remain constant.
Potential energy would remain constant, while total mechanical energy would increase.
Potential energy would decrease, while total mechanical energy would remain constant.
Potential energy would remain constant, while total mechanical energy would decrease.
Answer: Potential energy would decrease, while total mechanical energy would remain constant.
Explanation: I did the test and this was right.
The graph should represent the third option.
Potential energy & mechanical energy:The graph for the potential energy of the swimmer and the mechanical energy should be that there is a reduction of the potential energy and the mechanical energy should remain the same.
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Desde un rascacielos de 300 m de altura se lanza un objeto con una velocidad inicial de 50 m/s. Calcula el tiempo que transcurre hasta que llega al suelo y con qué velocidad llega en cada uno de los casos: a) Si se lanza verticalmente hacia arriba. b) Si se lanza verticalmente hacia abajo. c) Si se lanza horizontalmente (En este caso calcular también la distancia al edificio cuando llega al suelo) d) Si se lanza con un ángulo de 30o (Calcular también distancia al edificio)
Answer:
a) t = 14.2 s , v = -92 m / s , b) v = - 59.16 m / s , t = 0.916 s
c) t = 7.75 s , x = 387.5 m
d) t = 10.64 s , x = 463.9 m , v = 92.2 m / s
Explanation:
This is an exercise in kinematics, suppose we take the upward direction as positive
a) is thrown up vertically.
Let's use the equation
y = y₀ + v₀ t - ½ g t²
When reaching the ground y = 0, the initial height is y₀ = 300 m and the initial velocity is v₀ = + 50m / s, to simplify we use g = 10 m /s² as the value of the acceleration of gravity, for a more exact calculation we can must use 9.80 m /s²
0 = y₀ + v₀t - ½ g t²
½ 10 t² - 50 t - 300 = 0
Let's solve the quadratic equation
t² - 10 t - 60 = 0
t = [10 ±√ (10² + 4 60)] / 2
t = [10 ± 18.4] / 2
t₁ = 14.2 s
t₂ = -4.2 s
since time must be a positive quantity, the correctors result t = 14.2 s
the speed at this point is
v = v₀ - g t
v = 50 - 10 14.2
v = -92 m / s
the sign indicates that the body is going down
b) in this case the initial velocity is vo = -50 m / s
let's calculate the velocity on the ground
v² = v₀² - 2g (y-y₀)
v² = 50 2 - 2 10 ((0- 300)
v² = 3500
v = + - 59.16 m / s
as the body is going down the correct sign is the negative
v = - 59.16 m / s
the time it takes to arrive is
v = v₀ - g t
t = (v₀ - v) / g
t = (-50 + 59.16) / 10
t = 0.916 s
c) the velocity is horizontal (vox = 50 m / s), this implies that the vertical velocity is zero voy = 0
y = y₀ + v₀ t - ½ g t²
0 = 300 + 0 - ½ 10 t²
t = √ (2 300/10)
t = 7.75 s
the horizontal displacement at this time is
x = v₀ₓ t
x = 50 7.75
x = 387.5 m
d) as it is thrown with an angle let's find each component of the velocities
v₀ₓ = v₀ cos 30
[tex]v_{oy}[/tex] = v₀ sin 30
v₀ₓ = 50 cos 30 = 43.3 m / s
v_{oy} = 50 sin 30 = 25 m / s
we look for the time of descent
y = y₀ + v_{oy} t - ½ g t²
0 = y₀ + v_{oy} t - ½ g t²
0 = 300 + 25 t - ½ 10 t²
t² - 5t - 60 = 0
we solve the second degree equation
t = [5 ±√ (5² + 4 60)] / 2
t = [5 ± 16.28] / 2
t₁ = 10.64 s
t₂ = -5.64 s
since the time must be positive the result is t = 10.64 s
the range on the x axis is
x = v₀ₓ t
x = 43.6 10.64
x = 463.9 m
the ground speed is
v_{y} = [tex]v_{oy}[/tex] - g t
v_{y} = 25 - 10 10.64
v_{y} = -81.4 m / s
speed is
v = √ (v₀ₓ² + v_{y}²)
v = √ (43.3² + 81.4²)
v = 92.2 m / s
wassup people of this wor;d
What is the normal force acting on the 7.50 kg box shown?
The answer would be 31 N. This is because Fn = 7.5*9.8*sin(25).
At which temperature could air hold the most water vapor?
O A. 24°C (75°F)
B. 2°C (36°F)
C. 35°C (95°F)
O D. 13°C (55°F)
SUBMIT
Explanation:
35 maybe hope it's right
Katie and Mark sit next to one another in class. She has a mass of 40 kg and his mass is 65 kg.
If they are 0.5 meters apart, what is the gravitational force between Mark and Katie?
Explain the difference between mass and weight and
how they are measured.
Answer:
Mass is a measure of how much force it will take to change that path. Mass depends on how much matter – atoms and so on – there is in an object; more mass means more inertia, as there is more to get moving. ... Weight, on the other hand, is a measure of the amount of downwards force that gravity exerts on an object
Two forces of magnitude 40N and 70N acts on an object calculate and write the resultant force acting on the object and the resultant a
direction of force when both the force act in opposite direction
A) 70N in the direction of lesser force
B) 110N,opposite direction
C) 30N,in the direction of the greater force
D) 30N in the direction of lesser force
Explanation:
Required Answer70N-40N=30N
30N in lesser forceHELP MEH QUICK PLEASE
Which of the following is a source of direct current (D/C)? *
A) a radio wave
B) a wall socket
C) a generator
D) a battery
Answer:
D) a Battery
Explanation:
The best real-life example of direct current is a battery. Batteries have positive and negative terminals on a battery, the electrons in the wires will begin to flow to produce a current.
An applied force is a force that is applied to an object by a person or another object.
True or False
Answer:
true
Explanation:
Analyze why force pairs do not cancel each other
Answer:
Action and reaction forces don't cancel each other out because they act on separate objects.
Explanation:
Action and reaction forces are always equal in magnitude, so it's not possible to exert more force on an object than it can exert back.
Why is my life like this
Answer:
stop it get some help
:)
Explanation:
Answer:
My life be like oooh ahhh ooh ah
What reaction/soccur between an acid and base.
Answer:
neutralization reaction
Explanation:
The reaction of an acid with a base is called a neutralization reaction.
es una reacción química que ocurre entre un ácido y una base produciendo sal y agua. ... Se mezcla un ácido fuerte con una base fuerte: Cuando esto sucede, la especie que quedará en disolución será la que esté en mayor cantidad respecto de la otra.
How far did the football player run if it took them 30 s running at 25m/s?
Answer:
[tex]\boxed {\boxed {\sf 750 \ meters}}[/tex]
Explanation:
Distance can be found by multiplying the speed by the time.
[tex]d=s*t[/tex]
The speed is 25 meters per second. The time is 30 seconds.
[tex]s=25 \ m/s \\t= 30 \ s[/tex]
Substitute the values into the formula.
[tex]d=25 \ m/s * 30 \ s[/tex]
Multiply. Note the seconds, or "s" will cancel each other out.
[tex]d= 25 \ m * 30[/tex]
[tex]d= 750 \ m[/tex]
The football player ran 750 meters.
1. A ball is thrown straight up.if the launch velocity is 15 m/s, at what velocity will the ball return to the thrower's hand?
2. A boat moves across a river going 18 m/s. At the same time there is a current flowing at a right angle to the boat at 6 m/s. What is the resulting velocity of the boat?
Answer:
1) The velocity of the ball return to the thrower's hand is -15 meters per second.
2) The resulting velocity of the boat is [tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex].
Explanation:
1) Let suppose that ball experiments a free fall, that is an uniform accelerated motion, in which effects from gravity and Earth's rotation can be neglected. The velocity of the ball is represented by the following equations of motion:
Position
[tex]v_{o}\cdot t -\frac{1}{2}\cdot g\cdot t^{2} = 0[/tex]
[tex]t\cdot \left(v_{o}-\frac{1}{2}\cdot g\cdot t \right) = 0[/tex] (1)
Velocity
[tex]v = v_{o}-g\cdot t[/tex] (2)
Where:
[tex]t[/tex] - Time, measured in seconds.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]v_{o}[/tex] - Initial velocity of the ball, measured in meters per second.
[tex]v[/tex] - Final velocity of the ball, measured in meters per second.
From (1), we get the time when the ball returns to the thrower's hand:
[tex]v_{o}-\frac{1}{2}\cdot g\cdot t = 0[/tex]
[tex]t = \frac{2\cdot v_{o}}{g}[/tex]
And then we apply this result in (2):
[tex]v = v_{o}-g\cdot \left(\frac{2\cdot v_{o}}{g} \right)[/tex]
[tex]v = -v_{o}[/tex] (3)
Then, the velocity of the ball return to the thrower's hand is -15 meters per second.
2) The resulting velocity of the boat ([tex]\vec v_{B}[/tex]) is represented by the vectorial sum of the velocity of the boat relative to the river ([tex]\vec v_{B/R}[/tex]) and the velocity of the river ([tex]\vec v_{R}[/tex]), both measured in meters per second, that is:
[tex]\vec v_{B} = \vec v_{R}+\vec {v}_{B/R}[/tex] (4)
If we know that [tex]\vec v_{R} = 6\,\hat{i}\,\left[\frac{m}{s} \right][/tex] and [tex]\vec v_{B/R} = 18\,\hat{j}\,\left[\frac{m}{s} \right][/tex], then the resulting velocity of the boat is:
[tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex]
The resulting velocity of the boat is [tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex].
What made "Lunar Orbit Rendezvous" such an attractive method to get to the Moon that it was selected by NASA in July, 1962
Answer:
I don't know the answer
Helppppppppppp I’ll give brainliest
Answer:
[tex] \boxed{(i).... 40cm}\\ \boxed{(ii).... 18cm}\\ \boxed{(iii).... 7.5N
}\\ [/tex]
Explanation:
[tex](i).... \\ the \: weight \: of \: the \: rod \: acts \: at \: the \: center \\ which \: is \: the \: half \: of \: 80cm = 40cm \\ (ii).... \\ let \: the \: distance \: be \: \boxed{d}...then \: 22 + d = 40 \\ d = 40 - 22 = 18cm \\ (iii).... \\let \: the \: weight \: of \: the \: metal \: rod \: be \: \boxed{ w} \\ taking \: the \: moment \: about \: the \: string \to \\ 15 \times (22 - 13) = 18w \\ 18w = (9)(15) \\ 2w = 15 \\ w = 7.5N[/tex]
♨Rage♨
Uniform Circular Motion: You need to design a wheel for testing purposes such that its rim will have an acceleration of 1.5 g when the rim is moving at 37 m/s while spinning. What should be the diameter of this wheel?
Answer:
We want to have an acceleration of:
A = 1.5*g = 1.5*9.8m/s^2 = 14.7 m/s^2
When the rim is moving at 37m/s while spinning.
Now, in circular motion we have two accelerations.
Tangential acceleration, that is the one related to the change of speed, as we have a speed of 37m/s, we can assume that is constant, then the tangential acceleration is zero.
Centripetal acceleration, is the one related to the change in direction, is perpendicular to the velocity vector and is the one that allows the circular motion.
I suppose that in this problem we want to have a centripetal acceleration of 14.7m/s^2
The equation for the centripetal acceleration is:
Ac = v^2/r
Where v = velocity and r = radius.
then we must solve:
14.7m/s^2 = (37m/s)^2/r
r = (37m/s)^2/14.7m/s^2 = 93.13 m
A kangaroo hopped at 22 meters per second, saw a skunk and then
hopped at 52 meters per second. This is an example of which of the
following?
Acceleration
Velocity
Speed
motion graphs
Answer:
this is an example of acceleration
What is the life cycle of our sun?
Answer:
the sun is currently a mian sequence star
and will remain so for another 4-5 billion