Charlie and Daniella each began a fitness programme. On day one, they both ran 500m. On each subsequent day, Charlie ran 100m more than the previous day whereas Daniella increased her distance by 2% of the distance run on the previous day.

(a) Calculate how far Charlie ran on day 20 of his fitness programme. (1) Daniella ran on day 20 of her fitness programme. On day n of the fitness programmes, Daniella runs more than Charlie for the first time.

b) Find the value of n

Answers

Answer 1

Answer:

a) 2400m on the 20th day for Charlie.

1) 728.41m of 20th day for Daniella.

Didn't find n, sorry.

Answer 2

Charlie ran 2400m on day 20 of his fitness program and Daniella ran 728m on day 20 of her fitness program.

It is given that Charlie and Daniella on day one both ran 500m on each subsequent day.

Charlie ran 100m more than the previous day.

Daniella increased her distance by 2% of the distance run on the previous day.

It is required to calculate how far Charlie and Daniella ran on day 20 and the value of n.

What is a sequence?

It is defined as the systematic way of representing the data that follows a certain rule of arithmetic.

Charlie ran 500m on the first day:

[tex]\rm a_1 = 500[/tex]

[tex]\rm a_2 =600[/tex] ( because charlie ran 100m more than the previous day)

It is an arithmetic progression in which the difference between two consecutive terms:

d = 600 - 500 ⇒ 100

and [tex]\rm a_n = a+d(n-1)[/tex]

[tex]\rm a_2_0 = 500+100(20-1)\\\\\rm a_2_0 = 2400m[/tex]( ∵ n = 20 )

Daniella ran 500m on the first day:

[tex]\rm b_1 = 500[/tex]

[tex]\rm b_2 = 500+ 500\times2 \%[/tex]  (because Daniella increased her distance by 2% of the distance run on the previous day)

We can write [tex]\rm n^t^h[/tex] terms:

[tex]\rm b_n= 500(1+2\%)^n^-^1[/tex]

[tex]\rm b_2_0= 500(1+2\%)^2^0^-^1[/tex]

[tex]\rm b_2_0= 500(1+0.02)^1^9\\\\\rm b_2_0 = 500\times 1.02^1^9\\\\\rm b_2_0 = 500\times1.456 \Rightarrow 728.40 \approx 728 m[/tex]

[tex]\rm b_n > a_n[/tex]  (given in the question)

[tex]\rm500(1+2\%)^n^-^1 > 500+100(n-1) \ \ or \\\\\rm500(1+2\%)^n^-^1 > 100n+400[/tex]

The above expression is not true for all the values of 'n' ie. 'n' can not be determined.

Thus, Charlie ran 2400m on day 20 of his fitness program and Daniella ran 728m on day 20 of her fitness programme.

Learn more about the sequence here:

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Answer:

y = 8/5x + (-4) or y = 8/5x -4

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Slope-intercept form is written like this:

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Answer:

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Answers

Amanda family cannot travel more than 244 miles without needing to refill the gas tank.

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Answer:

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Answer:

C. 1

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Divide 4 by 15

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Consider the expression 8ab + 3b + 16 - 4a. (a) How many terms are there? (b) How many factors are in the first term? Identify them. (c) Which term is a constant? pls do this fast

Answers

a. There are 4 terms in the expression

b. There are 3 factors in the first term.

c. The constant is 16.

8ab + 3b + 16 - 4a

A term is any signed number, a variable, or a constant  multiplied by a

variable or variables.

Therefore, the terms are 8ab,  3b,  16, and -4a. The terms are 4 in numbers.

The first term is 8ab .The first term has the factors 8 , a and b. This means the first term have 3 factors.

The term that is a constant is 16

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X^+17x+72=12 factoring quadratic equation

Answers

Answer:

The first term is, x2 its coefficient is 1 .

The middle term is, -17x its coefficient is -17 .

The last term, "the constant", is +60

Step-1 : Multiply the coefficient of the first term by the constant 1 • 60 = 60

Step-2 : Find two factors of 60 whose sum equals the coefficient of the middle term, which is -17 .

-60 + -1 = -61

-30 + -2 = -32

-20 + -3 = -23

-15 + -4 = -19

-12 + -5 = -17 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -12 and -5

x2 - 12x - 5x - 60

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x-12)

Add up the last 2 terms, pulling out common factors :

5 • (x-12)

Step-5 : Add up the four terms of step 4 :

(x-5) • (x-12)

Which is the desired factorization

Equation at the end of step

1

:

(x - 5) • (x - 12) = 0

STEP

2

:

Theory - Roots of a product

2.1 A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

In other words, we are going to solve as many equations as there are terms in the product

Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation:

2.2 Solve : x-5 = 0

Add 5 to both sides of the equation :

x = 5

Solving a Single Variable Equation:

2.3 Solve : x-12 = 0

Add 12 to both sides of the equation :

x = 12

Supplement : Solving Quadratic Equation Directly

Solving x2-17x+60 = 0 directly

Earlier we factored this polynomial by splitting the middle term. let us now solve the equation by Completing The Square and by using the Quadratic Formula

Parabola, Finding the Vertex:

3.1 Find the Vertex of y = x2-17x+60

For any parabola,Ax2+Bx+C,the x -coordinate of the vertex is given by -B/(2A) . In our case the x coordinate is 8.5000

Plugging into the parabola formula 8.5000 for x we can calculate the y -coordinate :

y = 1.0 * 8.50 * 8.50 - 17.0 * 8.50 + 60.0

or y = -12.250

Parabola, Graphing Vertex and X-Intercepts :

Root plot for : y = x2-17x+60

Axis of Symmetry (dashed) {x}={ 8.50}

Vertex at {x,y} = { 8.50,-12.25}

x -Intercepts (Roots) :

Root 1 at {x,y} = { 5.00, 0.00}

Root 2 at {x,y} = {12.00, 0.00}

Solve Quadratic Equation by Completing The Square

3.2 Solving x2-17x+60 = 0 by Completing The Square .

Subtract 60 from both side of the equation :

x2-17x = -60

Now the clever bit: Take the coefficient of x , which is 17 , divide by two, giving 17/2 , and finally square it giving 289/4

Add 289/4 to both sides of the equation :

On the right hand side we have :

-60 + 289/4 or, (-60/1)+(289/4)

The common denominator of the two fractions is 4 Adding (-240/4)+(289/4) gives 49/4

So adding to both sides we finally get :

x2-17x+(289/4) = 49/4

Adding 289/4 has completed the left hand side into a perfect square :

x2-17x+(289/4) =

(x-(17/2)) • (x-(17/2)) =

(x-(17/2))2

Things which are equal to the same thing are also equal to one another. Since

x2-17x+(289/4) = 49/4 and

x2-17x+(289/4) = (x-(17/2))2

then, according to the law of transitivity,

(x-(17/2))2 = 49/4

We'll refer to this Equation as Eq. #3.2.1

The Square Root Principle says that When two things are equal, their square roots are equal.

Note that the square root of

(x-(17/2))2 is

(x-(17/2))2/2 =

(x-(17/2))1 =

x-(17/2)

Now, applying the Square Root Principle to Eq. #3.2.1 we get:

x-(17/2) = √ 49/4

Add 17/2 to both sides to obtain:

x = 17/2 + √ 49/4

Since a square root has two values, one positive and the other negative

x2 - 17x + 60 = 0

has two solutions:

x = 17/2 + √ 49/4

or

x = 17/2 - √ 49/4

Note that √ 49/4 can be written as

√ 49 / √ 4 which is 7 / 2

Solve Quadratic Equation using the Quadratic Formula

3.3 Solving x2-17x+60 = 0 by the Quadratic Formula .

According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :

- B ± √ B2-4AC

x = ————————

2A

In our case, A = 1

B = -17

C = 60

Accordingly, B2 - 4AC =

289 - 240 =

49

Applying the quadratic formula :

17 ± √ 49

x = —————

2

Can √ 49 be simplified ?

Yes! The prime factorization of 49 is

7•7

To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).

√ 49 = √ 7•7 =

± 7 • √ 1 =

± 7

So now we are looking at:

x = ( 17 ± 7) / 2

Two real solutions:

x =(17+√49)/2=(17+7)/2= 12.000

or:

x =(17-√49)/2=(17-7)/2= 5.000

Two solutions were found :

x = 12

x = 5

Step-by-step explanation:

please mark my answer in brainlist

Which expression represents the number of thirds in 1

Answers

Answer:

A third is written as ¹/₃

Step-by-step explanation:

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Answers

Answer:

y=-x-2

Step-by-step explanation:

The slope is negative 1 and the y intercept is -2

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Subtract 2 from both sides:

3x = 2x +5

Subtract 2x from both sides:

x = 5

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