Charlotte recorded the number of minutes she spent exercising in the past ten days: 9, 9, 5, 2, 7, 1, 14, 3, 5, 6. Find the median of the data.

Answer:

x= 9

Step-by-step explanation:

85 + 2x +2 + {180 -(11x + 6) }=180 (sum of angles in a triangle)

87 + 2x + 180 - 6 -11x = 180

87 -9x - 6 = 0

81 = 9x

x= 9

Answer:

[tex]\huge\boxed{V=44cm^3}[/tex]

Step-by-step explanation:

(look at the picture)

The formula of a volume of a rectangular prism a × b × c:

[tex]V=abc[/tex]

We have two rectangular prisms.

[tex]1:\ 2cm\times2cm\times5cm\\2:\ 2cm\times2cm\times6cm[/tex]

Calculate the volume:

[tex]V_1=2\cdot2\cdot5=20(cm^3)\\\\V_2=2\cdot2\cdot6=24(cm^3)[/tex]

The volume of the irregular figure:

[tex]V_F=V_1+V_2\\\\V_F=20cm^3+24cm^3=44cm^3[/tex]

Answer:

D

hope this helps

have a good day :)

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

"grow or develop in a healthy or vigorous way, especially as the result of a particularly favorable environment."

Answer:

C.

hope this helps

have a good day :)

Step-by-step explanation:

Answer:

Step-by-step explanation:

12 D + M = 3.50

3*12 D +4M = 11.80

the pair of equations are

12 D + M = 3.50

36 D +4M = 11.80

Answer:

I need points lol 2=yx thank you for letting me spam

Answer:

The number is 222

Step-by-step explanation:

The given parameters are;

The method Ashley models the 3 digit number = A mix of six base-ten blocks

The digits of the 3 digit number are equal

Therefore, given that in a 3 digit number, we have, hundreds, 100s, tens, 10s, and units, 1s, we can find the digits as follows;

Let 'x' represent the number of hundreds digits, let 'y' represent the number of tens digits and let 'z' represent the number of units digits, we have;

x = y = z...(1)

x + y + z = 6...(2)

Substituting the value of x = y, and x = z from equation (1), in equation (2), we get;

x + y + z = x + x + x = 6

∴ 3·x = 6

∴ x = 6/3 = 2

x = 2 = y = z

Therefore, the 3-digit numbers xyz = 222

Answer:

area=1÷2×diagonal(H1+H2)

=1÷2×8(2+2)

=16m2

Answer:

16 m squared,

Step-by-step explanation:

Thre are two triangles. triangle area formula = 1/2 bh

plug in numbers but there's another rectangle so times 2

1/2 8*2 = 8*2=16

if correct, please mark brainliest if you feel like it:)

Answer:

Average score per game = 60,000 per game

Step-by-step explanation:

Given:

Points scored in first game = 25,000

Points scored in second game = 125,000

Points scored in third game = 30,000

Find:

Average score per game

Computation:

Average = Sum of observation / Number of observation

So,

Sum of all game = 25,000 + 125,000 + 30,000

Sum of all game = 180,000

Number of games = 3

Average score per game = 180,000 / 3

Average score per game = 60,000 per game

Answer:

2.5%

Step-by-step explanation:

Given data

Profit = Euro 20,000,000

Tax paid= Euro 500,000

The percentage tax paid is

% Tax= Tax paid/Profit*100

% Tax= 500,000/20,000,000*100

% Tax=0.025*100

% Tax=2.5

Hence the percentage tax paid is 2.5%

Answer:

18 = 4(3)+6

12 + 6

Step-by-step explanation:

the answer is 18 = 4(3)+6

because y is 18

Answer:

x=3

Step-by-step explanation:

[tex]18 = 4x + 6[/tex]

subtract 6 on both sides

[tex]12 = 4x[/tex]

divide both sides by 4

[tex]3 = x[/tex]

Answer:

[tex](7y^2x^3)^2[/tex]

Step-by-step explanation:

Find the GCF then factor out all the numbers

Answer:

(x-5i)(x+5i)

Step-by-step explanation:

Given the expression

(x-5i)²

Expand

(x-5i)(x+5i)

= x² - 5ix + 5ix - 25i²

= x² - 25i²

Since i² = -1, hence;

(x-5i)(x+5i) = x² - 25(-1)

(x-5i)(x+5i) = x² + 25

Hence the required expression is (x-5i)(x+5i)

=======================================================

Explanation:

The arc measures shown are 138 and 58. Subtract the arc measures and divide by 2 to get the answer

(138-58)/2 = 80/2 = 40 degrees

The general formula is

(A - B)/2

where A and B are the arc measures. The value of A is always the larger arc measure. This formula works for two secant lines as this diagram shows, and it also works for a secant line and tangent line, and lastly it works if both lines were tangent.

Answer:

answer is 8

Step-by-step explanation:

hope this helps

Answer:

2x²−13x+21

Step-by-step explanation:

Hope this answer helps you :)

Have a great day

Mark brainliest

Hi there! You have to remember these 6 basic Trigonometric Ratios which are:

Back to the question. Assuming that the question asks you to find the cosine, sine, cosecant and secant of angle theta.

What we have now are:

Looks like we are missing the hypotenuse. Do you remember the Pythagorean Theorem? Recall it!

Define that c-term is the hypotenuse. a-term and b-term can be defined as adjacent or opposite

Since we know the value of adjacent and opposite, we can use the formula to find the hypotenuse.

Thus, the hypotenuse is:

[tex] \large \boxed{c = 2 \sqrt{61} }[/tex]

Now that we know all lengths of the triangle, we can find the ratio. Recall Trigonometric Ratio above! Therefore, the answers are:

Questions can be asked through comment.

Furthermore, we can use Trigonometric Identity to find the hypotenuse instead of Pythagorean Theorem.

Hope this helps, and Happy Learning! :)

Answer:

[tex] \sin(c) = \frac{ab}{ac} \\ \sin(c) = \frac{36}{45} \\ \sin(c) = \ \frac{4}{5} [/tex]

Answer:

44.4

Step-by-step explanation:

sin(40)= x/69

x=69(sin40)

x= 44.4

Answer:

Length of hypotenuse is 13 unit or 5 unit

Step-by-step explanation:

Find;

Length of hypotenuse

Computation;

Assume;

Length of hypotenuse = h

Length of longer leg = h - 1

Length of shorter leg = h - 1 - 7

Using Pythagorean theorem

hypotenuse² = longer leg² + shorter leg²  

h² = (h - 1)² + (h - 1 - 7)²  

h² = (h - 1)² + (h - 8)²  

h² = h² - 2h + 1 + h² - 16h + 64  

h² = 2h² - 18h + 65

h² - 18h + 65 = 0

h² - 13h - 5h + 65 = 0

h(h - 13) -5(h - 13)

(h - 13)(h - 5)

So,

Length of hypotenuse is 13 unit or 5 unit

Answer:

Area of composite figure = 623.25 cm²

Step-by-step explanation:

Given:

Equal side of triangle = 39 cm

Diameter of semi-circle = 30 cm

Base of triangle = 30 cm

Find;

Area of composite figure

Computation:

Radius of triangle = 30 / 2

Radius of triangle = 15 cm

Height of triangle = √39² - 15²

Height of triangle = √1,521 - 225

Height of triangle = 36 cm

Area of composite figure = Area of semi-circle + Area of triangle

Area of composite figure = [πr² / 2] + [(1/2)(b)(h)]

Area of composite figure = [(3.14)(15)² / 2] + [(1/2)(15)(36)]

Area of composite figure = [(3.14)(225) / 2] + [(15)(18)]

Area of composite figure = [706.5 / 2] + [270]

Area of composite figure = 353.25 + 270

Area of composite figure = 623.25 cm²

Answer:

would you still like me to help you with this problem?

Answer:

5) [tex]x=3,-1[/tex]

6) [tex]r=-6,-4[/tex]

7) [tex]p=2,3[/tex]

8) [tex]n=-4,8[/tex]

Step-by-step explanation:

5) [tex](x-3)(x+1)=0[/tex]

   [tex](3-3)(-1+1)=0[/tex] substitute x for a number that will make the statement true.

6) [tex](r+6)(r+4)=0[/tex]

   [tex](-6+6)(-4+4)=0[/tex] substitute r for a number that will make the statement true.

7) [tex](p-2)(p-3)=0[/tex]

   [tex](2-2)(3-3)=0[/tex]  substitute p for a number that will make the statement true.

8) [tex](n+4)(n-8)=0[/tex]

   [tex](-4+4)(8-8)=0[/tex] substitute n for a number that will make the statement true.

Answer: [tex]20\ \text{unit}\times 10\ \text{unit}[/tex]

Step-by-step explanation:

Given

A studio apartment has a floor that measures [tex]120\ ft \times 60\ ft[/tex]

Scale used is 1 unit:6 feet i.e 6 feet of actual floor is considered 1 unit in drawing

The dimension of scale drawing is [tex]\frac{1}{6}[/tex] of actual

Dimensions are

[tex]\Rightarrow \dfrac{120}{6}\times \dfrac{60}{6}\\\\\Rightarrow 20\ \text{unit}\times 10\ \text{unit}[/tex]

Answer:

y - 1 = 3/2(x - 4)

Step-by-step explanation:

plug in the given(known) x and y coordinates into the point-slope form:

=> y - 1 = 3/2(x - 4)

Answer:

120 in³

Step-by-step explanation:

10 x 4 x 3 = 120

Answer:

you will pay back $4,984 in total and you will owe 984 in interest alone just in case you need that too.

Answer:

Step-by-step explanation:

[tex]\sqrt{3[/tex] *2[tex]\sqrt{30[/tex]

2[tex]\sqrt{30*3}[/tex]

2[tex]\sqrt{3*3*2*5}[/tex]

2*3[tex]\sqrt{2*5}[/tex]

6[tex]\sqrt{10}[/tex]