Chemistry work here. Please help as soon as possible. I have allot of questions that needs to be answered. Can someone do it for me?

Answer:

Here you can use the Clausis Clayperon equation: ln P1/P2=-Ea/R-(1/T1 - 1/T2)

where P1 is the pressure at standard condition: 760 mm Hg

P2 is the variable we need to solve

Ea is the activation energy, which in this case is delta H vaporisation: 56.9 kJ/mol

R is the gas constant 8.314 J/mol or 8.314 J/mol /1000 to convert to kJ

T1 is the normal boiling point 356.7 C, but converted to Kelvin: 629.85K

T2 is room temperature 25 C, but converted to Kelvin: 298.15 K

Once you plug everything in, you should get 4.29*10^-3 mmHg

Explanation:

We are given:

The force applied on the poor hamster (F) = 12 N

Acceleration of the poor Hamster (a) = 8 m/s²

Solving for the mass of the Poor Hamster:

From newton's second equation of motion, we know that:

F = ma

replacing the given values

12 = 8 * m

m = 12/8 kg

m = 3/2 kg

The poor Hamster weighs 3/2 kg

Answer:

0.758 V.

Explanation:

Hello!

In this case, case when we include the effect of concentration on an electrochemical cell, we need to consider the Nerst equation at 25 °C:

[tex]E=E\°-\frac{0.0591}{n} log(Q)[/tex]

Whereas n stands for the number of moles of transferred electrons and Q the reaction quotient relating the concentration of the oxidized species over the concentration of the reduced species. In such a way, we can write the undergoing half-reactions in the cell, considering the iron's one is reversed because it has the most positive standard potential so it tends to reduction:

[tex]Fe^{2+}+2e^-\rightarrow Fe^0\ \ \ E\°=0.440V\\\\Ni^0\rightarrow Ni^{2+}+2e^-\ \ \ E\°=-0.250V[/tex]

It means that the concentration of the oxidized species is 0.002 M (that of nickel), that of the reduced species is 0.40 M and there are two moles of transferred electrons; therefore, the generated potential turns out:

[tex]E=(0.440V+0.250V)-\frac{0.0591}{2} log(\frac{0.002M}{0.40M} )\\\\E=0.758V[/tex]

Beat regards!

Answer:

D-when the aim is to show electron distributions in shells

Explanation:

Answer:

D on edge 2021

Answer:

yes it should react yoyoyoyoyo

Answer:

is there an all of them are true option cause it should be that

Explanation:

your answer to your question is all of the above

Answer:

the moon gets infront of the sun

Answer:

A solar eclipse happens when the moon moves in front of the Sun as seen from a location on Earth. During a solar eclipse, it gets dimer and dimmer outside as more and more of the Sun is covered by the Moon. During a total eclipse, the entire Sun is covered for a few minutes and it becomes very dark outside. The temperature outside also drops.

Answer:

39.099 amu

Explanation:

saw this on quizlet no cap sorry im 3 weeks late

Answer:

Electron microscopes differ from light microscopes in that they produce an image of a specimen by using a beam of electrons rather than a beam of light. Electrons have much a shorter wavelength than visible light, and this allows electron microscopes to produce higher-resolution images than standard light microscopes.

Explanation:

Answer:

the answer is D. extraction through fracking can contaminate groundwater

The disadvantage of natural gas has been the contaminating groundwater due to fracking. Thus, option D is correct.

Natural gas has been the stored fossil energy that has been found buried deep inside the earth. The gas has consisted of a varying quantity of compounds with a maximum proportion of methane.

Natural gas has been nonrenewable, causing pollution with the burning. The release of greenhouse gases with the burning of natural gas results in affecting the environment.

Although there has been the presence of various extraction methods, natural gas results in contaminating groundwater due to fracking. Thus, option D is correct.

For more information about natural gas, refer to the link:

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Answer:

salt.

Explanation:

Mark me as brainliest

Answer:

element,compound

Explanation:

im petty sure this is the anwser

Answer: D

Explanation:

Answer:

λ = 4.5×10⁻³⁴ m

Explanation:

Given data:

Energy of photon = 4.42×10⁸ J

Wavelength of photon = ?

Solution:

Formula:

E = hc/λ

speed of light = c = 3×10⁸ m/s

planck's constant = h = 6.63×10⁻³⁴ Js

Now we will put the values in formula.

4.42×10⁸ J = 6.63×10⁻³⁴ Js ×  3×10⁸ m/s  / λ

λ =   6.63×10⁻³⁴ Js ×  3×10⁸ m/s /  4.42×10⁸ J

λ = 19.89×10⁻²⁶ Jm /  4.42×10⁸ J

λ = 4.5×10⁻³⁴ m

Water is oxidized and reduced at both electrodes

Electrolysis utilizes electrical energy to carry out non-spontaneous redox reactions. The ions in the solution flowed by an electric current will move toward the electrode opposite the charge.

The negative ions from the solution will move towards the positive electrode, and release electrons around the positive electrode (oxidation occurs) and electrons flow to the negative pole

While around the negative electrode electron binding occurs and a reduction reaction occurs

the reaction at the cathode:

1. the reduced active metal is water, other than that the metal will be reduced

2. H⁺ of the acid will be reduced

For reactions in anode:

1. if the electrodes are not inert then the metal is oxidized

2. If inert then:

a. OH⁻ from the base will be oxidized

b. The halogen metal will oxidize

2H₂O(l)+2e⁻⇒ H₂(g)+2OH⁻(aq)

2H₂O(l)⇒4H⁺(aq)+O₂(g)+4e⁻

Answer:proton,neutrons,and electrons.

Explanation:

Answer:

Common water treatment processes such as flocculation, sedimentation, filtration and disinfection are employed to remove general impurities such as floating and suspended matters, colloidal particles, dissolved organic matter and destruction of disease-causing microorganisms (pathogens).

Explanation:

Answer:

See explanation

Explanation:

In SF4, the lone pair is placed at an equatorial position. One needs to consider the A-B interactions (axial-equatorial) as well as the B-B (equatorial-equatorial) interactions.

The lone pair occupies an equatorial site to minimize repulsion and maximize the space between electron pairs. Remember that equatorial bonds(Xeq-E-Xeq) are at an angle of 120 degrees while axial bonds(Xax-E-Xeq) lie at an angle of 90 degrees.

It should be noted that in the molecule SF4, the lone pair is placed at an equatorial position.

From the complete question, it's important to consider the axial-equatorial interactions as well as the equatorial-equatorial which is the B-B interactions.

Furthermore, the lone pair occupies an equatorial site that is vital in minimizing repulsion as well as maximizing the space that's between the electron pairs.

In conclusion, the lone pair is placed at an equatorial position.

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Answer:

Use a glass testtube

Insert a 1-hole stopper in which you insert a glass tube (use a bit of glycerine around the bottom end which makes it slip easier into the stopper)

Fill the testtube with colored water

Place rubber stopper

Make sure there are no air bubbles and that the column in the glass tube is low, as indicated

Place testtube assembly into water which you will heat (hot plate)

Observations

You will observe that the water column in the glass tube moves up as the temperature of the water in the testtube increases. With a 20 mL testtube, and a temperature change from 20 degrees C to 80 degrees C, you should get something like 15-20 cm of change in height.

What do YOU observe?

How do YOU explain your observation?

What is happening there?

Explanation

The water in the testtube expands as it is heated. There is only one direction to expand in, the glass tube. This glass tube is narrow so that a small change in volume will result in a considerable change in height; your signal is amplified.

This is the same phenomenon as in thermometers with a glass bulb on the lower end. Thermometers use a variety of liquids including alcohol (expands more than water) and mercury (is dangerous when spilled).

Explanation:

hope this helps

Answer:

Experiment 1:

What happens to the water in the small tube as the water in the test tube absorbs heat?

Answer: As the water in the test tube absorbs heat the water in the small tube continues to rise

Why do you think a small tube was used to observe the expansion of water?

Answer: The small tube was used to observe the expansion of water to show a visible change that could also be measure with a ruler

Experiment 2:

Compare the circumference of the balloon before and after freezing. What is the percent increase in this measurement?

Answer: The circumference of the balloon increased after it was put in the freezer. The measurement increased by about 5%, it started at 39.5cm then increased to 41.5cm

According to the data, an increase in temperature caused the water molecules to expand because it gained energy which caused it to move more rapidly ultimately resulting in an increase of volume of water. In addition, when being froze water expands making it less dense than the water from which it freezes, causing the volume to also increase. The difficulty I faced in this experiment is pinpointing the exact change in the waters expansion. Two real world issues are when icebergs float as a result of water freezing resulting in expansion, another one is the warming of Earth due to the heat-trapping from greenhouse gases. This heat is absorbed by oceans and seas causing the temperature to rise and the water to expand.

Explanation:

If the partial pressure of hydrogen in the mixture is 75 torr, the total pressure of the mixture is 100 torr.

Partial pressure is the notional pressure present in every gas.

Given,

The mole fraction of helium is 0.750.

The partial pressure of hydrogen in the mixture is 75 torr

The mole fraction of hydrogen is

To find the total pressure

By Roult's law

Partial pressures divided by mole fraction

75 / 0.750 = 100 torr

Thus, the correct option is a, 100 torr.

Learn more about pressure, here:

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Answer:

True

Explanation:

Answer:

1. employment   2. mining process  3. pollution

Explanation:

I took the assignment, it is 100% correct. : )

Answer:

B

Explanation:

increased pollution

Answer:

70.98% is the mass percentage of bromine in the original compound

Explanation:

First, we need to convert mass of AgBr to moles with its molar mass (AgBr: 187.77g/mol). Moles of AgBr = Moles of Br. With molar mass of Br-: 79.904g/mol we can find mass of bromide and mass percentage as follows:

0.7514g AgBr * (1mol / 187.77g) = 0.00400 moles AgBr = Moles of Br-

0.00400 moles Br- * (79.904g / mol) = 0.320g Br- in the sample

Mass percentage is:

0.320g Br- / 0.4505g sample * 100

Answer:

Linear molecule is a molecule in which atoms are deployed in a straight line (under 180° angle). Molecules with an linear electron pair geometries have sp hybridization at the central atom. An example of linear electron pair and molecular geometry are carbon dioxide (O=C=O) and beryllium hydride BeH2.

Explanation:

Answer:

1.12 x 10²³atoms of F

Explanation:

Number of MgF₂ atoms = 5.6 x 10²² molecules;

 The unknown here is the number of Fluorine atoms found in the compound.

In MgF₂,

     1 mole of MgF₂ contains 2 moles of F;

From the given number of molecules we can also say that, MgF₂ contains 5.6 x 10²²atoms;

           1 mole of MgF₂ contains 2 moles of F;

    5.6 x 10²²atoms of MgF₂ will contain 2 x   5.6 x 10²² = 1.12 x 10²³atoms of F

The number of atoms of Flourine found in 5.6x10^/²² molecules of MgF2 is; 1.12 x 10²³atoms of F

Number of MgF₂ atoms as given = 5.6 x 10²² molecules;

We are required to determine the number of Fluorine atoms found in the compound.

In MgF₂,

As given, MgF₂ contains 5.6 x 10²²atoms;

Hence, 5.6 x 10²²atoms of MgF₂ will contain 2 x 5.6 x 10²² = 1.12 x 10²³atoms of Flourine.

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Answer:

Adding Neutrons

General Formulas and Concepts:

Chemistry - Atomic Structure

Explanation:

We know that adding Protons to any atom will change its chemical properties and make it a different element.

We also know that adding Electrons to any atom will simply only change its overall charge.

Isotopes are formed by adding neutrons to the nucleus. It will be the same element but it would have a different mass and amount of neutrons.

Answer:

Baking a cake requires heat to be applied to the batter in order for it to cook and chemically change into cake. The energy or heat applied is absorbed by the ingredients, so this represents an endothermic reaction.

Explanation:

Answer:

Sample Response: Baking a cake requires heat to be applied to the batter in order for it to cook and chemically change into cake. The energy or heat applied is absorbed by the ingredients, so this represents an endothermic reaction.

Explanation:

on edge

Answer:

V₂ = 1750 mL

Explanation:

Given data:

Initial volume = 750 mL

Initial pressure = 840 mmHg

Final pressure = 360 mmHg

Final volume = ?

Solution:

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

840 mmHg × 750 mL = 360 mmHg × V₂

V₂ = 630,000 mmHg.mL/360 mmHg

V₂ = 1750 mL

A. 3 purple and 1 white. :)

answer on EDGE2020. took/taking the exam.

Purple flowers are dominant over white flowers. The parent generation includes two heterozygous parents. The possible phenotypes of these parents’ offspring are 3 purple and 1 white. Therefore, option A is correct.

A person's genotype is their unique DNA sequence. This term is used to refer to the two alleles that a person inherited for a specific gene. A patient's clinical presentation is the detectable expression of this genotype.

We have three phenotypic classes with one locus and additive effects: AA, Aa, and aa.

Height, wing length, and hair color are all phenotypes. Phenotypes also include observable characteristics that can be measured in the lab, such as hormone levels or blood cell counts.

Purple flowers outnumber white flowers. There are two heterozygous parents in the parent generation. These parents' offspring could have three purple phenotypes and one white phenotype.

Thus, option A is correct.

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