Answer:
Where the primate infant did not possess primate hand features, it will not be able to feed itself. For example, a monkey cannot survive without its grasping hands. It uses them to feed itself. So if an infant monkey does not possess the primate hand features, its survival will be greatly hampered.
Explanation:
Ordinarily, primates (including humans) have five fingers on each of their hands and five toes on their feet. Most primate species have fingernails instead of claws, and they have touch-sensitive pads on each of their digits. The hands and feet of all primates are designed for grasping, with the only exceptions being humans. Human beings feature deep perceptions that differentiate them from other primates.
The only step in cellular respiration that produces no energy (ATP) is:
Answer:
Cellular respiration is a metabolic pathway that breaks down glucose and produces ATP. The stages of cellular respiration include glycolysis, pyruvate oxidation, the citric acid or Krebs cycle, and oxidative phosphorylation.
Explanation:
Specialized processes, or changes, that organisms have or make in order to survive in an environment are called A) adaptations B) developments C) evolutions D) growths E) maturations
The answer is adaptation
Why could organisms that use a K-selected life strategy be more at risk when environmental conditions change?
Answer:
K-selection organisms have the maximum chance of surviving in the surrounding where the number of organisms is near the carrying capacity, however, the lack of offspring makes them endangered species.
Explanation:
K-species can give the offspring with the great possibility of surviving until mature.
K-selection is the most frequent in big animals, that have a long life span, and many generations that meet. K-selection organisms give less offspring but with a stronger organism.
However, these organisms are more endangered, as they tend to have fewer offspring, so their populations cannot recover as quickly from disorders such as excessive hunting or fire.
Below is a sequence from a template strand of DNA. Write the sequence of the mRNA that would be transcribed from this. Be sure to label the 3’ and 5’ ends.
DNA:3’ A G G T C T T C A C 5’
mRNA:
Answer:
In the transcription of DNA to mRNA, for the DNA sequence 3'-AGGTCTCAC-5' corresponds to an mRNA sequence 5'-UCCAGAAGUG-3'.
Explanation:
Transcription is the process by which a strand of mRNA, needed to direct protein synthesis in the cytoplasm, is synthesized from a strand of DNA.
The sequence of nucleotides in the RNA chain depends on the sequence of bases in the DNA strand, being placed according to the complementarity of nitrogenous bases, where a purine is complemented with a pyrimidine.
In RNA, the thymine base is replaced by Uracil, the complementary base to adenine of DNA.
ADN mRNA
A U
T A
C G
G C
For this reason:
DNA: 3’ A G G T C T T C A C 5’
mRNA: 5'-U C C A G A A G U G-3'
How does a developing fetus change in the third trimester?
Answer:
hope it helps..
Explanation:
During the third trimester, the fetus continues to grow in size and weight. The lungs are still maturing. The fetus starts to position itself head-down. By the end of the third trimester, the fetus is about 19 to 21 inches long and weighs about 6 to 9 pounds.
When a bee visits a flower for sweet, sweet nectar, the plant's gametes are also spread to anoher plant. What kind of symbiotic relationship is this?
Answer:
Mutualism
Explanation:
Mutualism is a type of symbiotic relationship in which the two species of organisms involved benefit from one another i.e. the actions of one benefits the other.
In this question, a bee is said to visit a flower for sweet nectar, however, in the process of feeding on the flowers nectar, the plant's gametes are also spread to another plant by the bee. This is a type of MUTUALISTIC RELATIONSHIP because the plant is beneficial to the bee by providing food (nectar) while the bee also helps the plant by helping it pollinate.
Where is water stored?
a. clouds
b. the ground
C. animals
d. all of the above
Answer: it’s D all of the above
Explanation:
Just took the test
Which of the following processes play a role in introducing both water and carbon in the earth's cycles? A) photosynthesis and respiration B) condensation and nitrogen fixation C) burning of fossil fuels and forest fires D) desertification and condensation
Answer:
A) photosynthesis and respiration
Explanation:
BEST/FIRST ANSWER GETS BRAINLYEST!!!! PLEASE HELP
Which evidence shows that landmasses had different climates millions of years ago and supports the theory of
continental drift?
Ⓐ coal fields in several continents
Ⓑvolcano formation
Ⓒtropical plant fossils on
ⒹArctic islands
folded mountains in Africa and South America
Non-steroidal anti-inflammatory drugs (NSAIDS) block the actions of the COX enzymes and their production of eicosanoids from ___.
Answer:
Arachidonic acids
Explanation:
Non-steroidal anti-inflammatory drugs (NSAIDs) are drugs used due to their analgesic, anti-inflammatory effects.
It inhibit cyclooxygenase (COX) enzyme that takes part in the biosynthesis of prostaglandins (PGs) and thromboxane (TX) and the production of eicosanoids.
Eicosanoids are made by the enzymatic or non-enzymatic oxidation of arachidonic acid or from other polyunsaturated fatty acids (PUFAs) that are close to arachidonic acid which are 20 carbon units in length.
They are important cell signaling molecules that inhibit inflammation, allergy, fever,regulate abortion of pregnancy and normal childbirth, regulating cell growth.
Scientists reported that a fungal pathogen, may negatively a!ect the growth of soybeans (Glycine max). Soybean growth decreased during three years of high rainfall, and the soybean roots were poorly developed. Close relatives of R. anaerobis are plant pathogens and grow in the soil. A lectin-like protein was found in the soil around the soybean roots. is protein may have been secreted by the fungus. Lectins induce mitosis in some root apical meristem tissues. In many instances, rapid cell divisions weaken plant tissues.You have been asked to investigate whether the fungal pathogen lectin a!ects the number of cells undergoing mitosis in a di!erent plant, using root tips.• What is your experimental hypothesis? Your null hypothesis? Are these the same?• How would you design an experiment with onion bulbs to test whether lectinsincrease the number of cells in mitosis?• What would you measure, and how would you measure it?• What would be an appropriate control for your experiment?Your teacher will provide you with untreated and lectin-exposed roots. You should be comfortable identifying cells in mitosis or in interphase before you begin examining the chromosome squashes.
Answer:
What is your experimental hypothesis?
Experimental hypothesis: If we introduce lectins into the root systems of plants, then they will cause rapid cell division, mitosis, to begin in the root apical meristem tissues which will weaken plant tissues.
Your null hypothesis?
Null hypothesis: If we introduce lectins into the root systems of plants, then there will be no initiation of mitosis in the root apical meristem tissues and the plants will not weaken as a result.
Are these the same?
These are not the same, the experimental hypothesis states that lectin will have an effect on the rate of cell division within the plants which will cause the plant to be weaker, however, the null hypothesis states that lectin will have no effect on the rate of cell division and therefore will not affect the plants overall strength. The null hypothesis is the opposite of the experimental and we are testing the experimental hypothesis to decide whether to accept or reject the null hypothesis.
How would you design an experiment with onion bulbs to test whether lectins increase the number of cells in mitosis?
Assuming these onion bulbs have roots, we would get multiple untreated onions and isolate them by putting them into a controlled environment within a lab by using soil obtained from a store, steady LED light from the room, watered 2 times a day with 2 cups (480 ml) each time and finally isolated the same lab room. The only testable variable in this experiment will be whether the onions are given the lectin or not. In one group we would have the control group, the water they are given would be purely distilled water, however, in another group we would have the experimental group, which would be treated with water mixed with lectin. We are looking to study if there is a change, more specifically an increase, in the cell division of the onion within the treatment/experimental group.
What would you measure, and how would you measure it?
We would need to observe pictures taken of the onion cells under a microscope in order to count the cells in each phase of mitosis. If more cells are visibly undergoing mitosis, and more are present in the picture (density), then we can know that the lectin is causing an increase in rapid cell division. We will compare the amount of cells in each phase with that of the onion which was used as a control.
What would be an appropriate control for your experiment?
An untreated onion that is given distilled water as a treatment, a placebo, which allows us to compare no treatment to the effects of the treatment in the experimental group.
Explanation: I hope the answers are very thorough :) you're welcome future AP Bio students.
If the experiment goes fine, the roots of Group-1 will more denser than the control group.
Experimental hypothesis:
If we introduce lectins into the root systems of plants, then it will increase , mitosis, which will weaken the plant tissues.
Null hypothesis:
If lectins is introduced into the root of plants, then there is no initiation of mitosis in the root apical meristem and the plants will not weaken.
Experimental hypothesis and Null hypothesis are not the same because both statements are opposite.
The onion bulbs with roots, will be divided into 2 groups
1. Onion bulb's liquid media with lectin.
2.Onion bulb's in water only.
The onion bulbs with water apparatus will use as control. The density of the cell will be measured under the microscope.
Therefore, if the experiment goes fine, the roots of Group-1 will more denser than the control group.
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Which of the following structures would NOT be found in a prokaryotic cell?
DNA
cell membrane
ribosomes
nucleus
What is DNA and what is it for
What jobs do cells have?
Answer: Cells are the basic building blocks of all living things. The human body is composed of trillions of cells. They provide structure for the body, take in nutrients from food, convert those nutrients into energy, and carry out specialized functions.
Explanation:
Create an illustration showing the application of Chargaff’s rule in the structure of DNA.
How are plant cells different from animal cells?
(they convert sunlight into energy, they take in material through their cell membrane, or they use energy to grow and reproduce)??
Answer:
one has a cell wall and tge other doesnt
What would be the best diet to your knowledge?
Describe the difference between normal vision and colorblindness. Do individuals with red/green colorblindness have difficulty seeing at night? Why or why not?
Answer:
Color vision is possible due to photoreceptors in the retina of the eye known as cones. These cones have light-sensitive pigments that enable us to recognize color. Found in the macula (the central part of the retina), each cone is sensitive to either red, green or blue light (long, medium or short wavelengths). The cones recognize these lights based on their wavelengths. Normally, the pigments inside the cones register different colors and send that information through the optic nerve to the brain. This enables us to distinguish countless shades of color. But if the cones don't have one or more light-sensitive pigments, they will be unable to see all colors.
Most people with color vision deficiency can see colors. The most common form of color deficiency is red-green. This does not mean that people with this deficiency cannot see these colors altogether, they simply have a harder time differentiating between them, which can depend on the darkness or lightness of the colors.
Another form of color deficiency is blue-yellow. This is a rarer and more severe form of color vision loss than just red-green deficiency because people with blue-yellow deficiency frequently have red-green blindness, too. In both cases, people with color-vision deficiency often see neutral or gray areas where color should appear.
People who are totally color deficient, a condition called achromatopsia, can only see things as black and white or in shades of gray. Color vision deficiency can range from mild to severe, depending on the cause. It affects both eyes if it is inherited and usually just one if it is caused by injury or illness.
Explanation:
Brainliest please?
One student filled three-fourths of a flask with water and closed its mouth with a rubber stopper. He put a glass tube through the hole in the rubber stopper. The flask was heated on a Bunsen burner. After some time the boiling water was forced up through the glass tube as shown below. (1 point)
Image of a flask sitting on a Bunsen burner, the flask is 3/4 filled with water, the flask is closed with a rubber stopper that has a glass tube through it, water is rising to approximately 1/3 of the glass tube.
The student's experiment demonstrates the formation of
wells
caves
geysers
sinkholes
Answer: It's geysers
Answer:
geysers is correctamungo
Explanation:
Have an AWESOME day!
What are the differences and similarity between action potential and graded potential?
Help please
Answer:
Depending on the stimulus, graded potentials can be depolarizing or hyperpolarizing. Action potentials always lead to depolarization of membrane and reversal of the membrane potential. Amplitude is proportional to the strength of the stimulus. ... Duration of graded potentials may be a few milliseconds to seconds.
Explanation:
6 Infer Why do you think loess can be carried further
than sand?
Answer:
During deflation,wind removes the top layer of fine sediment or soil. ... Loess can be carried further than sand because loess weighs less than sand so wind can pick loess up easier.
Identify the control group for the rat experiments described in the Paralytic Shellfish Poisoning Scenario.
Answer:
This question is incomplete
Explanation:
This question is incomplete. However, the control group of an experiment is the group in which every other group of the experiment is firstly compared with. This is because control groups are usually not administered with any form of treatment. Thus, the control group of the experiment/scenario referred to in the question will be the group that did not receive any form of treatment and was probably given water or placebo.
What are these species BowHead and Omura a type of
Answer:
The bowhead whale (Balaena mysticetus) belongs to the Balaenidae family and is the only living representative of the Balaena genus. The Omura whale (Balaenoptera omurai) had been defined as a new species in 2003 and quickly thereafter as an ancient basal lineage to a clade of Bryde / ein whale.
Please help if u know the water cycle part2.
Answer:
3. Cohesion and 4. transpiration
Explanation:
Cohesion is water to water, adhesion is water to substance and surface tension is the ability of water to shrink into the minimum area it receives.
A scientist is using a species of green algae to study the electron transport chain in photosynthesis. He uses a laser to inactivate all of chlorophyll A in the algae but leaves chlorophyll B intact (case 1). In a separate experiment, the scientist applies a chemical to the algae that inhibit PS I but do not affect PS II (case 2).
Which of the following results is expected?
A)in case 1, only PS I completely loses function; in case 2, no proton gradient is produced.
B)In case 1, only PS I completely loses function; in case 2, a proton gradient is still produced.
C)In case 1, both PS I and PS II completely lose function; in case 2, no proton gradient is produced.
D)In case 1, both PS I and PS II completely lose function; in case 2, a proton gradient is still produced.
Answer:
D) In case 1, both PS I and PS II completely lose function; in case 2, a proton gradient is still produced.
Explanation:
The light dependent reaction of photosynthesis, which produces the ATP and NADPH needed in the light independent stage of the process, includes complexes of proteins and pigments called PHOTOSYSTEMS. These photosystems (I and II) are key to the functionality of the light dependent reactions in the thylakoid.
The major pigment present in both photosystems is CHLOROPHYLL A, which absorbs light energy and transfers electrons to the reaction center. Chlorophyll B is only an accessory pigment meaning it can be done without. Hence, if all of the chlorophyll A is inactivated in the algae but leaves chlorophyll B intact as in case 1, both PS I and PS II will lose their function because Chlorophyll A is the major pigment that absorbs light energy in both photosystems.
In case 2, if PS I is inhibited and PS II is unaffected, a PROTON GRADIENT WILL STILL BE PRODUCED because the splitting of water into protons (H+) and electrons (e-) occurs in PSII. Hence, H+ ions can still be pumped into the inner membrane of the thylakoid in order to build a proton gradient even without the occurrence of PS I.
In crime scene, as investigator you saw an alleged almost dried semen in the bedsheets at the crime scene. How will you collect the specimen?
Answer:
an investigator will often use a black light to scan an area for traces of bodily fluids left at the crime scene. if there’s a substance that resembles semen or blood, they will often times apply a spray if it is dry and use a cotton swab to collect it in a vial to test back at the lab for dna evidence.
Explanation:
3. Which of the following is not true of meiosis?
A. O involves DNA replication
B. O provides genetic variation
C. O occurs in reproductive cells
D. O prevents genetic variation
Answer:
D prevents genetic variation
8. Which organisms act as a bridge between the nitrogen in the atmosphere and the nitrogen on land?
Answer:
Well, Bacteria plays a key role in the nitrogen cycle, but also some species of nitrogen-fixing bacteria are free-living in soil or water, while others are beneficial symbionts that live inside of plants.
Explanation:
Bacteria act as a bridge between the nitrogen in the atmosphere and the nitrogen on land.
• Nitrogen moves into the living world with the help of microbes, that is, bacteria. The bacteria transform atmospheric nitrogen, that is, N2 into usable biological forms by the process of nitrogen fixation.
• Some nitrogen-fixing bacteria are free-living in water or soil, while some are beneficial symbionts, which reside within the plants.
• The nitrogen-fixing bacteria capture the atmospheric nitrogen by transforming it to NH3 that can be taken by the plants and are utilized to produce organic molecules.
• The nitrogenous molecules are passed onto animals when they consume plants. These gets incorporated within the body of the animal and are excreted in the form of urea in urine.
Thus, bacteria act as a bridge between the nitrogen in the atmosphere and the nitrogen on land.
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In the experiment determining the parental genotype of plant seedlings from a monohybrid cross, if the dominant color was green (C) and the recessive color was white (c), what would the parental genotype have been if plate 1 only contained white seedlings instead of all green
Answer:
cc × cc
Explanation:
This question involves a single gene coding for plant seedling. The green allele (C) is dominant over the white allele (c). This means that the green allele will mask the phenotypic expression of the white allele in a heterozygous state (Cc).
In this experiment where plate 1 only contained white seedlings instead of all green, this illustrates that all the offsprings were recessive. This is because the parental genotypes were both recessive for the color trait i.e. cc.
Note that, the recessive trait can only be expressed when the recessive alleles are present in a gene. Therefore, the parental genotype would have been cc × cc, in order to give rise to all offsprings with the recessive trait (white colour).
Place the following statements in the correct order as they occur in DNA replication. (5A)
1. Appropriate free nucleotides are added to the complementary DNA
strands.
2. DNA unwinds.
3. DNA coils up.
4. The hydrogen bonds are broken between the nitrogenous bases.
Answer: The answer is C.
Explanation: I jus got done taking the test. Also remember the first start is breakin through and tearing apart the hydrogen base bonds, then they’re glued so they do not coil back up.
The correct order of replication are DNA unwinds then the The hydrogen bonds are broken between the nitrogenous bases, and Appropriate free nucleotides are added to the complementary DNA strands. DNA coils up.
What is DNA replication?DNA replication is the process through which cells make copies of the genome's DNA. A cell must first copy (or duplicate) its entire genome before it can divide, ensuring that each daughter cell has a complete genome upon division.
One of DNA's most astounding tricks is likely DNA replication. If you stop to think about it, every cell has all the DNA required to create every other cell.
Therefore, DNA is a molecule that can be copied to create almost exact duplicates of itself. Considering that there are almost three billion base pairs in DNA that need to be copied, this is even more astounding. DNA polymerases, which are molecules dedicated solely to copying DNA, are also used in replication.
Therefore, The correct order of replication are DNA unwinds then the The hydrogen bonds are broken between the nitrogenous bases, and Appropriate free nucleotides are added to the complementary DNA strands. DNA coils up.
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