Consider pure water separated from an aqueous sugar solution by a semipermeable membrane, which allows water to pass freely but not sugar. After some time has passed, the concentration of sugar solution: a. will have decreased b. will be the same on both sides of the membrane c. might have increased or decreased depending on other factors d. will not have changed e. will have increased

Answer:

The activation energy is the amount of energy needed for a chemical reaction to occur.

Answer:

Activation energy, in chemistry, the minimum amount of energy that is required to activate atoms or molecules to a condition in which they can undergo chemical transformation or physical transport.

Answer: Does the animal prey on other animals? Is the animal a carnivore?

Answer: 8%

Explanation:

Can't you just do 4/50= 8%?  If not, just remember that for empirical formula, do percent to grams, and grams to moles, divide by smallest and multiply to whole!

Answer:

See explanation

Explanation:

Hello there!

In this case, since the the concentrations are not given, and not even the Ksp, we can solve this problem by setting up the chemical equation, the equilibrium constant expression and the ICE table only:

[tex]AgCl(s)\rightleftharpoons Ag^+(aq)+Cl^-(aq)[/tex]

Next, the equilibrium expression according to the produced aqueous species as the solid silver chloride is not involved in there:

[tex]Ksp=[Ag^+][Cl^-][/tex]

And therefore, the ICE table, in which x stands for the molar solubility of the silver chloride:

       [tex]\ \ \ \ \ \ \ \ \ \ \ \ \ \ AgCl(s)\rightleftharpoons Ag^+(aq)+Cl^-(aq)[/tex]

I          -                   0             0

C        -                   +x           +x

E        -                    x             x

Which leads to the following modified equilibrium expression:

[tex]Ksp=x^2[/tex]

Unfortunately, values were not given, and they cannot be arbitrarily assigned or assumed.

Regards!

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Answer:

67.91 g of CuCl2; 32.09 g of Cu.

Explanation:

The two masses add to 100.0 g, the initial amount of starting material, demonstrating the law of conservation of matter.

Answer:

5.450 mol Si₃N₄

Explanation:

Step 1: Write the balanced equation

3 Si + 2 N₂ ⇒ Si₃N₄

Step 2: Establish the theoretical molar ratio between the reactants

The theoretical molar ratio of Si to N₂ is 3:2 = 1.5:1.

Step 3: Establish the experimental molar ratio between the reactants

The experimental molar ratio of Si to N₂ is 16.35:11.26 = 1.45:1. Comparing both molar ratios, we can see that Si is the limiting reactant.

Step 4: Calculate the moles of Si₃N₄ produced from 16.35 moles of Si

The molar ratio of Si to Si₃N₄ is 3:1.

16.35 mol Si × 1 mol Si₃N₄/3 mol Si = 5.450 mol Si₃N₄

Answer:

c4 is an explosive..

contains RDX, DOS, DOA, and PIB.

Explanation:

Answer:

a. True

Explanation:

The gases that we study are governed by different laws of physics. Gases behaves according to some given set of laws like the Universal gas laws, Boyles law, Charles law, Gay Lussac's law and many more.

But we do not see a definite pattern or rule when we study solids or liquids. The behavior of the solids and liquids are not described by the set of laws which are applied regardless of the identity of the substance.

Answer:

[tex]P_{H_2}=727mmHg[/tex]

Explanation:

Hello there!

In this case, according to the given data, it is possible to infer that the gas mixture lies on the 15.0 cm-high column of water, so that the total pressure or atmospheric pressure is given by:

[tex]P_{atm}=P_{water}+P_{H_2}[/tex]

Thus, since the atmospheric pressure is 745 mmHg and the vapor pressure of water is 18 mmHg, the pressure of hydrogen turns out to be:

[tex]P_{H_2}=P_{atm}-P_{water}\\\\P_{H_2}=745mmHg-18mmHg\\\\P_{H_2}=727mmHg[/tex]

Best regards!

Answer:

[tex]n_{O_2}=0.866molSO_2\\\\n_{SO_2}=0.577molSO_2[/tex]

Explanation:

Hello there!

In this case, according to the given balanced chemical reaction by which ZnS reacts with O2, it is possible to calculate the moles of the latter that are consumed, not produced, according the 2:3 mole ratio between them and the following stoichiometric set up:

[tex]n_{O_2}=56.25gZnS*\frac{1molZnS}{97.47gZnS}*\frac{3molO_2}{2molZnS} \\\\n_{O_2}=0.866molO_2[/tex]

But also, we can compute the moles of SO2 that are produced via the the 2:2 mole ratio of ZnS to SO2:

[tex]n_{SO_2}=56.25gZnS*\frac{1molZnS}{97.47gZnS}*\frac{2molSO_2}{2molZnS} \\\\n_{SO_2}=0.577molSO_2[/tex]

Regards!

Answer:

Explanation:

From the given information:

The energy of photons can be determined by using the formula:

[tex]E = \dfrac{hc}{\lambda}[/tex]

where;

planck's constant (h) = [tex]6.63 \times 10^ {-34}[/tex]

speed oflight (c) = [tex]3.0 \times 10^8 \ m/s[/tex]

wavelength λ = 58.4 nm

[tex]E = \dfrac{6.63 \times 10^{-34} \ J.s \times 3.0 \times 10^8 \ m/s}{58.4 \times 10^{-9 } \ m}[/tex]

[tex]E =0.34 \times 10^{-17} \ J[/tex]

[tex]E = 3.40 \times 10^{-18 } \ J[/tex]

To convert the energy of photon to (eV), we have:

[tex]1 eV = 1.602 \times 10^{-19} \ J[/tex]

Hence

[tex]3.40 \times 10^{-18 } \ J = \dfrac{1 eV}{1.602 \times 10^{-19 } \ J }\times 3.40 \times 10^{-18 } \ J[/tex]

[tex]E = 2.12 \times 10 \ eV[/tex]

E = 21.2 eV

b)

The equation that illustrates the process relating to the first ionization is:

[tex]Hg_{(g)} \to Hg^+ _{(g)} + e^-[/tex]

c)

The 1st ionization energy (I.E) of Hg can be calculated as follows:

Recall that:

I.E  = Initial energy - Kinetic Energy

I₁ (eV) = 21.2 eV - 10.75 eV

I₁ (eV) = 10.45 eV

Since ;

[tex]1 eV = 1.602 \times 10^{-19} \ J[/tex]

∴

[tex]10.45 \ eV = \dfrac{1.602 \times 10^{-19 } \ J }{ 1 \ eV}\times 10.45 \ eV[/tex]

Hence; the 1st ionization energy of Hg atom = [tex]1.67 \times 10^{-18} \ J[/tex]

[tex]1.67 \times 10^{-21} \ kJ[/tex]

Finally;

[tex]I_1 \ of \ the \ Hg (kJ/mol) = \dfrac{1.67 \times 10^{-21 \ kJ} \times 6.02 \times 10^{23} \ Hg \ atom }{1 \ Kg \ atom }[/tex]

[tex]\mathbf{= 1.005 \times 10^3 \ kJ/mol}[/tex]

Answer:

0.500 moles

Explanation:

In order to convert grams of any given substance into moles, we need the substance's molar mass:

We can find the molar masses of each element in the periodic table:

Now we can divide the given mass by the molar mass in order to calculate the number of moles:

Answer:no

Explanation:

Answer:

Scandium is a transition metal

Explanation:

Answer:

Ionization Energy = 9 eV

Explanation:

If we apply the law of conservation of energy to the given situation, we will get the following equation:

[tex]Energy\ of\ Photon = Ionization\ Energy + Kinetic\ Energy\ of\ Electron\\[/tex]

where,

Energy of Photon = 10 eV

Ionization Energy = ?

Kinetic Energy of Electrons = 1 eV

Therefore,

[tex]10\ eV = Ionization\ Energy + 1\ eV\\Ionization\ Energy = 10\ eV - 1\ eV[/tex]

Ionization Energy = 9 eV

Here's the solution,

we know,

potential energy = mgh

where,

So,

=》

[tex]p.e = 0.5 \times 9.8 \times 0.8[/tex]

=》

[tex]p.e = 3.92 \: \: joules[/tex]

Answer:

No, no precipitate is formed.

Explanation:

Hello there!

In this case, since the reaction between ammonium sulfide and aluminum nitrate is:

[tex]3(NH_4)_2S(aq)+2Al(NO_3)_3(aq)\rightarrow Al_2S_3(s)+6NH_4NO_3(aq)[/tex]

In such a way, we can calculate the concentration of aluminum and sulfide ions in the solution as shown below, and considering that the final total volume is 140.00 mL:

[tex][Al^3^+]=\frac{120.00mL*0.0082M}{140.00mL}=0.00703M[/tex]

[tex][S^2^-]=\frac{20.00mL*0.0090M}{140.00mL}=0.00129M[/tex]

In such a way, we can calculate the precipitation quotient by:

[tex]Q=[Al^3^+]^2[S^2^-]^3=(0.00703)^2(0.00129)^3=1.05x10^{-13}[/tex]

Which is smaller than Ksp and meaning that the precipitation does not occur.

Regards!

Answer:

1.0 moles of N2

Explanation:

since

1.0 × avogadro's no# = same answer for SO2 and N2

avogadro's no#= 6.02× 10²³

The number of molecules in 1.0 mole of SO₂ is the same as the number of molecules in (3) 0.25 mole of NO₂.

Option (3) is correct.

Avogadro's number, approximately 6.022 x 10²³, represents the number of molecules or atoms in one mole of any substance. In this case, 1.0 mole of SO₂ contains the same number of molecules as any other substance with 1.0 mole, such as 1.0 mole of N₂ or 2.0 moles of Ne.

However, when comparing different moles of substances, we can use the concept of stoichiometry and molar ratios to determine the number of molecules. Given that 1 mole of SO₂ is equivalent to 1 mole of NO₂, 0.25 mole of NO₂ would also contain the same number of molecules as 1 mole of SO₂. Therefore, the number of molecules in 1.0 mole of SO₂ is the same as the number of molecules in 0.25 mole of NO₂.

To learn more about number of molecule here

https://brainly.com/question/32364567

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Answer:

Pressure Affects the Boiling Point

Atmospheric pressure influences the boiling point of water. When atmospheric pressure increases, the boiling point becomes higher, and when atmospheric pressure decreases (as it does when elevation increases), the boiling point becomes lower.

Explanation:

i think it will help you

Answer:

2.0kg

Explanation:

The mass of 7 red apples in kilograms is to be considered as the 1.16 kilograms.

Since the mass of a dozen apples is 2 kg.

we know that

1 dozen is 12 units

So the mass of 12 apples = 2kg

So mass of 1 apple = 2/12 = 1/6  kg

Now the mass of 7 apple is to be  

= 7/6 kg

= 1.16 kg

hence, The mass of 7 red apples in kilograms is to be considered as the 1.16 kilograms.

Learn more about mass here: https://brainly.com/question/24701836

Answer:

84672 J

Explanation:

From the question given above, the following data were obtained:

Height (h) = 72 m

Combined mass (m) = 120 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Energy (E) =?

We can obtain the energy by using the following formula:

E = mgh

Where

E => is the energy.

g => is the acceleration due to gravity

m => is the mass.

h => is the height.

E = 120 × 9.8 × 72

E = 84672 J

Thus, the energy is 84672 J

Answer:

Oxygen cycle, along with the carbon cycle and nitrogen cycle plays an essential role in the existence of life on the earth. The oxygen cycle is a biological process which helps in maintaining the oxygen level by moving through three main spheres of the earth which are:

Explanation:

The atmosphere is the layer of gases presents above the earth’s surface. The sum of Earth’s ecosystems makes a biosphere. Lithosphere is the solid outer section along with the earth’s crust and it is the largest reservoir of oxygen.

Answer:

Oxygen cycle, circulation of oxygen in various forms through nature. ... Free in the air and dissolved in water, oxygen is second only to nitrogen in abundance among uncombined elements in the atmosphere. Plants and animals use oxygen to respire and return it to the air and water as carbon dioxide (CO2).

Explanation:

Solution :

According to Chick's law

[tex]$\frac{N_t}{N_0}=e^{-k'C^n t}$[/tex]

where, t = contact time

            c = concentration of disinfectant

            k' = lethality coefficient = 4.71

            n = dilution coefficient = 1

            4 log removal = % removal = 99.99

[tex]$\frac{N_t}{N_0}=\frac{\text{bacteria remaining}}{\text{bacteria initailly present}}$[/tex]

      = 1 - R

      = 1 - 0.9999

Now for plug flow reactor contact time,

[tex]$\tau =\frac{V}{Q} =\frac{75000}{40 \times 10^6}$[/tex]

          = 0.01875 days

          = 27 minutes

For CSTR, [tex]$\tau =\frac{V}{Q} =\frac{150000}{40 \times 10^6}$[/tex]

                             [tex]$=3.75 \times 10^{-3}$[/tex] days

                            = 5.4 minute

There are 3 reactors, hence total contact time = 3 x 5.4

                                                                            = 16.2 minute

Or [tex]$\frac{N_t}{N_0}=e^{-k'C^n t}$[/tex]

or [tex]$(1-0.9999)=e^{-4.71 \times C \times t}$[/tex]

∴ C x t = 1.955

For PFR, [tex]$t_1 = 27 $[/tex] min

∴ C [tex]$=\frac{1.955}{27}$[/tex] = 0.072 mg/L

For CSIR, [tex]$t_2=16.2$[/tex] min

[tex]$C=\frac{1.955}{16.2} = 0.1206$[/tex] mg/L

∴ Chlorine required for PFR in kg/day

[tex]$=\frac{0.072 \times 40 \times 10^6 \times 3.785}{10^6}$[/tex]      (1 gallon = 3.785 L)

= 18.25 kg/day

Therefore we should go for PFR system.