Consider this diagram of quadrilateral ABCD, which is not drawn to scale.
Which two statements must be true based on the information indicated by the diagram?

A. AC=~ BD

B. Triangle ABC =~ Triangle CDA

C.AB =~ DC

D. Angle ABD =~ Angle DBC

Answer:

its 5,1

Step-by-step explanation:

just took the test

Answer:

$50

Step-by-step explanation:

Hello There!

We are given that for 1 hour of work 250 dollars is charged and for 3 hours of work 350 dollars is charged

This could also be represented in two points (1,250) and (3,350)

The question wants us to find the hourly charge rate (slope)

we can easily find the slope ( hourly charge rate ) by using the slope formula

[tex]slope=\frac{y_2-y_1}{x_2-x_1}[/tex]

we have our two points so all we need to do is plug in the values (remember y values go on top and x values go on the bottom.)

[tex]slope=\frac{350-250}{3-1} \\350-250=100\\3-1=2\\slope=\frac{100}{2} or50[/tex]

So we can conclude that the hourly charge rate is $50

Answer:

11.9

Step-by-step explanation:

Use sin

Sin ratio is opposite over hypotenuse

Sin [tex]57^{o}[/tex] = [tex]\frac{10.8}{x}[/tex]

x = [tex]\frac{10.8}{sin57^{o} }[/tex]

x = 11.9

Answer:

8

Step-by-step explanation:

10+8-3+5-12=

Answer:

I think it is positive.

Step-by-step explanation:

Iam soory if Iam wrong.

Answer:

Option (1)

Step-by-step explanation:

By applying tangent rule in ΔABD,

tan(30°) = [tex]\frac{\text{Opposite side}}{\text{Adjacent side}}[/tex]

             = [tex]\frac{AB}{BD}[/tex]

BD = [tex]\frac{AD}{\text{tan}(30)}[/tex]

BD = [tex]\frac{200}{\frac{1}{\sqrt{3} } }[/tex]

BD = 200√3 ft

By applying tangent rule in ΔABC,

tan(60°) = [tex]\frac{AB}{BC}[/tex]

[tex]\sqrt{3}=\frac{200}{BC}[/tex]

BC = [tex]\frac{200}{\sqrt{3}}[/tex]

Since, CD = BD - BC

CD = 200√3 - [tex]\frac{200}{\sqrt{3}}[/tex]

     = 346.41 - 115.47

     = 230.94 ft

     ≈ 230.9 ft

Therefore, Option (1) will be the correct option.

Answer:

230.9 ft

Step-by-step explanation:

person above said it was correct answer

Answer:

P = 8x-28

Step-by-step explanation:

Given that,

Length = (3x-7)

Width = (x-7)

We need to find the perimeter of the rectangle. The formula for the perimeter of a rectangle is given by :

[tex]P=2 (l+b)\\\\P=2(3x-7+x-7)\\\\P=2(4x-14)\\\\P=8x-28[/tex]

So, the perimeter of the rectangle is equal to 8x-28.

Answer:

m=7/36

Step-by-step explanation:

we need two points in order to find the ratio of the change in y and change in x, which is the slope

m=(y-y1)/(x-x1) (you can choose any point as y1 but be careful that you use the corresponding x1 value in the denominator)

m=(11-4)/(17-(-19))

m=7/36

The Wronskian for the set of functions (3[tex]x^2[/tex], [tex]e^x[/tex], x[tex]e^x[/tex]) is W(0) = 1 and the set of functions (3[tex]x^2[/tex], [tex]e^x[/tex], x[tex]e^x[/tex]) are linearly independent.

To find the Wronskian for the set of functions (3[tex]x^2[/tex], [tex]e^x[/tex], x[tex]e^x[/tex]) and determine if they are linearly dependent or independent, we calculate the determinant of the matrix formed by taking the derivatives of these functions and evaluating them at a specific point.

The Wronskian is a determinant that helps determine if a set of functions is linearly dependent or independent.

For the given set of functions (3[tex]x^2[/tex], [tex]e^x[/tex], x[tex]e^x[/tex]), we need to calculate the Wronskian.

First, we take the derivatives of the functions:

f₁(x) = 3[tex]x^2[/tex]

f₂(x) = [tex]e^x[/tex]

f₃(x) = x[tex]e^x[/tex]

Taking the first derivatives, we get:

f₁'(x) = 6x

f₂'(x) = [tex]e^x[/tex]

f₃'(x) = [tex]e^x[/tex] + x[tex]e^x[/tex]

Next, we form a matrix with these derivatives:

| 6x [tex]e^x[/tex] [tex]e^x[/tex] + x[tex]e^x[/tex] |

To calculate the Wronskian, we evaluate this matrix at a specific point, let's say x = 0, and take the determinant:

W(0) = | 6(0) [tex]e^0[/tex] [tex]e^0[/tex] + 0[tex]e^0[/tex] |

| 0 1 1 |

| 1 1 1 |

Simplifying, we find:

W(0) = | 0 1 1 |

| 1 1 1 |

| 1 1 1 |

Calculating the determinant, we have:

W(0) = (0)(1)(1) + (1)(1)(1) + (1)(1)(1) - (1)(1)(1) - (1)(1)(0) - (1)(1)(1) = 1

Since the Wronskian is non-zero (W(0) ≠ 0), the set of functions (3[tex]x^2[/tex], [tex]e^x[/tex], x[tex]e^x[/tex]) are linearly independent.

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Answer:2,6

Step-by-step explanation:Edge2021

Answer

2,6

Step-by-step explanation:

The solutions to the differential equation y' = 2y are y = 0 and y = 2x. The solution y = 0 represents a constant function. The solution y = 2x represents a family of exponential functions.

The given differential equation is y' = 2y, where y' represents the derivative of y with respect to x. To solve this equation, we can separate variables by moving all terms involving y to one side and terms involving x to the other side:

dy/y = 2dx

Next, we integrate both sides of the equation. The integral of dy/y is ln|y|, and the integral of 2dx is 2x:

ln|y| = 2x + C

Here, C is the constant of integration. To simplify the equation, we can rewrite it as:

|y| = e^(2x + C)

Since e^(2x + C) is always positive, we can remove the absolute value sign:

y = ±e^(2x + C)

Now, let's consider the two cases separately.

Case 1: y = 0

If y = 0, then the exponential term becomes e^C, which is a constant. This implies that y remains zero for all values of x. Therefore, y = 0 is a solution to the differential equation.

Case 2: y ≠ 0

If y ≠ 0, we can rewrite the solution as:

y = ±e^C * e^(2x)

Since e^C is a constant, we can replace it with another constant, let's call it K:

y = ±K * e^(2x)

Here, ±K represents a family of exponential functions that grow or decay exponentially with a rate proportional to 2. Each value of K corresponds to a different solution to the differential equation.

In summary, the solutions to the differential equation y' = 2y are y = 0 and y = ±K * e^(2x), where K is a constant. The solution y = 0 represents a constant function, while y = ±K * e^(2x) represents a family of exponential functions.

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Answer:

4. 50

5. 35

6. 45

7. 30

8. No mode

9. 42

10. 22, 25, 45, 73, 80

11. 15, 25, 30, 48, 50

12. 58

13. 35

14. 51

15. 24

16. 22.13

17. 10.22

18. Iffy's team had a lower performance than Kaiya's team. Iffy's team collected an average of 35 cans, whereas, Kaiya's team collected an average of 50 cans!! Kaiya's team also had very versatile and active players who were able to collect more, individually, unlike Iffy's team.

Step-by-step explanation:

y=0.5x+2

y=4

4=0.5x+2

-2        -2

2=0.5x

/0.5 /0.5

4=x

---

hope it helps

Answer:

[tex]x[/tex] = 4

Step-by-step explanation:

If [tex]y[/tex] = 4 then it would look like:

[tex]y[/tex] = .5[tex]x[/tex] + 2

Since .5 is 0.5, Half of 4 equal 2, PLUS the other 2 making it 4!!

The function f(x) = (x + 7)^2 is one-to-one and non-decreasing for any domain on the real numbers. The inverse of f(x) restricted to this domain is y = √x - 7.

To find a domain on which the function f(x) = (x + 7)^2 is one-to-one and non-decreasing, we need to determine where the function is strictly increasing or non-decreasing and has a one-to-one correspondence.

First, let's examine the graph of f(x) = (x + 7)^2 to understand its behavior. The function is a parabola that opens upward, centered at x = -7, and the vertex is the lowest point on the graph.

Since the vertex is the lowest point and the parabola opens upward, the function is non-decreasing for all x-values. Therefore, the function is non-decreasing over its entire domain.

To find a domain on which the function is one-to-one, we observe that the function is not symmetric about the y-axis. Hence, the domain can be any subset of the real numbers.

Now, let's find the inverse of f(x) restricted to this domain. Since f(x) is non-decreasing, the inverse will also be non-decreasing. The inverse function can be found by interchanging the roles of x and y in the original equation and solving for y.

Let's proceed with finding the inverse:

Start with the equation f(x) = (x + 7)^2.

Interchange x and y: x = (y + 7)^2.

Solve for y:

Take the square root of both sides: √x = y + 7.

Subtract 7 from both sides: y = √x - 7.

The inverse function of f(x) restricted to any domain on which it is one-to-one and non-decreasing is given by y = √x - 7.

Note that the domain can be any subset of the non-negative real numbers, since the square root function is defined only for non-negative values.

In summary, the function f(x) = (x + 7)^2 is one-to-one and non-decreasing for any domain on the real numbers. The inverse of f(x) restricted to this domain is y = √x - 7.

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Answer: False

Step-by-step explanation:

Answer:

hi

Step-by-step explanation:

i think 10 in

hope it helps

Answer:

10

Step-by-step explanation:

The triangles are the same size, and if you look at the picture, you can see that MN and QR are the same, making QR 10 in.

Answer:

$57.289

Step-by-step explanation:

18% of 48.55

48.55 × 18 ÷ 100

= 8.739

48.55 + 8.739

=$57.289

Answer:

0.8

Step-by-step explanation:

got it right on edg

Answer:

5/7

Step-by-step explanation:

Answer:

90,000

Step-by-step explanation:

10^4=10,000.

2*10,000=20,000

7*10,000=70,000

20,000+70,000=90,000

1. Perimeter is 3 + 3 +3 +4 +5 = 18 feet

 Area = 3*3 = 9, 1/2*3*4 = 6, 9 + 6 =15 square feet

2. perimeter = 2.5 +2.5+ 2.5+2.5+0.5+0.5 = 11 meters

  Area = 3*.5 = 1.5, 3*2=6,  6+1.5 = 7.5 square meters

3. perimeter = 3.14*2*3 = 18.84 +8 = 26.8 inches

  Area = 6*4 = 24 + 3.14*3^2 = 28.26 = 28.26 +24 = 52.3 inches  

4. surface area = 2*π*6*20+2*π*6^2= 980.2 yards

Volume = π*6^2*20 = 2261.9 cubic yards

5.surface area = 2*(9*7+2*2+2*9) = 190 cm

Volume = 2*7*9 = 126 cubic cm

6. surface area = 2*(11*11+11*11+11*11) = 726 mm

 Volume = 11 *11*11 = 1331 cubic cm

Answer:

330

Step-by-step explanation:

Answer:

335.5

Step-by-step explanation:

Answer:

Step-by-step explanation:

the equation in the point slope form is

and reducing the equation (slope-intercept form)

Step-by-step explanation:

first we calculate the slope of the line with the formula:

where  is a point where the line passes, and  is another point where the line passes.

Since we have the following points:

(8, -2)

(5,5)

we conclude that

now we substitute this values to find the slope:

to find the equation now that we know the slope we use the point-slope equation:

and we subtitute the slope and the values of  and :

we reduce this equation:

the equation in the point slope form is

and reducing the equation (slope-intercept form)

Answer:

135

Step-by-step explanation:

The sequence are:

a, 2a, 4a, 8a, 16a.....

the total value of the first three terms is 63

That is,

a + 2a + 4a = 63

7a = 63

a = 63/7

a = 9

work out the total value of the first four terms

First four terms are: a, 2a, 4a, 8a

Where,

First term, a = 9

Second term, 2a = 2*9 = 18

Third term, 4a = 4*9 = 36

Fourth term, 8a = 8*9 = 72

The total value of the first four terms = 9 + 18 + 36 + 72

= 135

The total value of the first four terms = 135

None of the given options is the answer.

To calculate the probability of decay for substance A over the next 70 years, we need to consider the decay rate of 0.03 percent per year.

The decay rate of 0.03 percent per year can be converted to a decimal by dividing it by 100: 0.03 / 100 = 0.0003.

The probability of an atom decaying in a given year is equal to the decay rate, which is 0.0003.

To calculate the probability of an atom not decaying in a given year, we subtract the decay rate from 1: 1 - 0.0003 = 0.9997.

The probability of an atom not decaying over the next 70 years can be calculated by multiplying the probability of not decaying in each year together: (0.9997)^70 ≈ 0.9704.

Therefore, the probability of an atom decaying in the next 70 years is equal to 1 minus the probability of not decaying: 1 - 0.9704 ≈ 0.0296.

So, the probability that an atom of substance A chosen at random will decay in the next 70 years is approximately 0.0296 or 2.96%.

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(a) E and F are not mutually exclusive due to the overlapping value of 8. So the answer is No or option A.

(b) F and G are mutually exclusive since they have no common outcomes. So the answer is No or option A.

a) E and F are not mutually exclusive. To be mutually exclusive, two events cannot occur simultaneously. In this case, both E and F have an overlapping value of 8. The interval (8,9) is included in both E and F, indicating that there is a common outcome (8) between the two events.

Therefore, E and F are not mutually exclusive.

b) F and G are mutually exclusive. In order for two events to be mutually exclusive, they must have no common outcomes. Looking at the intervals (7,8) and (4,6,9), there is no overlapping value between F and G. F includes the value 7, which is not present in G, and G includes the values 4, 6, and 9, which are not present in F.

Therefore, there are no common outcomes between F and G, making them mutually exclusive.

In summary, E and F are not mutually exclusive due to the overlapping value of 8, while F and G are mutually exclusive since they have no common outcomes.

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The student's suggested algorithm for subtracting numbers is incorrect. The algorithm produces the correct result in this specific case (72 - 38), but it does not work consistently for all subtraction problems.

The student's algorithm suggests subtracting the ones digit first and then subtracting the tens digit. While this approach may give the correct answer in some cases, it does not work for all subtraction problems. Subtraction is an operation where we need to consider the place value of the digits being subtracted.

In the case of 72 - 38, the student's algorithm produces the correct result of 34. However, if we apply the same procedure to a different subtraction problem, such as 43 - 29, we would get an incorrect result of 14 instead of the correct answer, 14. The student's algorithm fails to consider borrowing or regrouping when subtracting digits from different place values.

As a teacher, it is important to guide the student in understanding the standard algorithm for subtraction, which involves subtracting digits starting from the rightmost place value and borrowing when necessary. By teaching the correct procedure, students can consistently obtain accurate results for subtraction problems. It is crucial to explain the limitations of the student's suggested algorithm and emphasize the importance of understanding and applying the appropriate method for subtracting numbers.

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