Create a class named Invoicing that includes three overloaded computeInvoice() methods for a book store: see pages 196 for examples… The 8% tax should be defined as a constant.
1. When computeInvoice() receives a single parameter, it represents the price of one book ordered. Add 8% tax and display the total due.
2. When computeInvoice() receives two parameters, they represent the price of a book and the quantity ordered. Multiply the two values, add 8% tax, and display the total due.
3. When computeInvoice() receives three parameters, they represent the price of a book, the quantity ordered, and a coupon value. Multiply the quantity and price, reduce the result by the coupon value, and then add 8% tax and display the total due.
Create a driver class named TestInvoice with a main() method that tests all three overloaded methods using the following data: Price $24.95 Price, $17.50, quantity 4, Price $10.00, quantity 6, coupon $20.00 Output printed to Eclipse Console:
Price $26.95
Price $76.95
Price $43.20

Answer:

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

              //print the header

              System.out.println("**************************************");

              System.out.println("*                                    *");

              System.out.println("*                                    *");

              System.out.println("*   Gas-N-Clean Service Station      *");

              System.out.println("*                                    *");

              System.out.println("*   March 2, 2004                    *");

              System.out.println("*                                    *");

              System.out.println("**************************************");

               //set the constant values for gasoline

               final double REGULAR_GASOLINE = 2.89;

               final double PLUS_GASOLINE = 3.09;

               final double SUPER_GASOLINE = 3.39;

              // initialize the variables as 0

              double gasolinePrice = 0, gasolineCost = 0, carWashCost = 0, totalCost = 0;

               Scanner input = new Scanner(System.in);

               //ask the user to enter the gallons, gas type and car wash choice

               System.out.print("Enter number of gallons ");

               double gasolinePurchase = input.nextDouble();

               System.out.print("Enter gas type (R, P, S, or N) ");

               char gasType = input.next().charAt(0);

               System.out.print("Enter Y or N for car wash ");

               char carWashChoice = input.next().charAt(0);

               //check the gas type. Depending on the choice set the gasolinePrice from the corresponding constant value

              if(gasType == 'R')

                  gasolinePrice = REGULAR_GASOLINE;

              else if(gasType == 'P')

                  gasolinePrice = PLUS_GASOLINE;

              else if(gasType == 'S')

                  gasolinePrice = SUPER_GASOLINE;

                //calculate the gasolineCost

                gasolineCost = gasolinePurchase * gasolinePrice;

               //check the carWashChoice. If it is yes and gasolineCost is greater than 10, set the carWashCost as 1.25. Otherwise, set the carWashCost as 3.00

               if(carWashChoice == 'Y'){    

                   if(gasolineCost >= 10)

                       carWashCost = 1.25;

                   else

                       carWashCost = 3.00;

               }

              //calculate the total cost, add gasolineCost and carWashCost

              totalCost = gasolineCost + carWashCost;

               //print the values in required format

              System.out.println("Amount Gasoline purchases " + gasolinePurchase);

              System.out.println("Gallons Price per gallons $ " + gasolinePrice);

              System.out.printf("Total gasoline cost $ %.2f\n", gasolineCost);

              System.out.println("Car wash cost $ " + carWashCost);

              System.out.printf("Total due $ %.2f\n", totalCost);

               System.out.println("Thank you for stopping\nPlease come again \nRemember to buckle up and drive safely");

}  

}

Explanation:

*The code is in Java.

Please see the comments in the code for explanation

Answer:

The answer to this question is given below in the explanation section.

Explanation:

The correct answer to this question is online decision support system. Because the decision support systems process the data, evaluate and predict the decision, and helps the decision-makers,  and offer real time information immediately in making the decision in an organization. So the correct answer to this question is the decision supports system.

Why other options are not correct

Because the transaction processing system can only process the transaction and have not the capability to make the decision for the future. Office support processing system support office work, while the batch processing system process the task into the batch without user involvement.   however, online executive processing does not make decisions and offer timely information to decision-makers in an organization.

Answer:

The answer is C Natural selection

Explanation:

Natural selection is the differential survival and reproduction of individuals due to differences in phenotype. It is a key mechanism of evolution, the change in the heritable traits characteristic of a population over generations

According to Darwin’s theory of evolution, differences between species may be a result of  Natural selection. Thus the correct option is C.

According to Darwin, all species descended from a single ancestor, species can change through time, and new species can arise from existing ones which makes them interconnected with common traits.

Natural selection of traits in a species that would help the species in its survival is the process that drives diversification, the evolutionary process through which new biological species form.

Natural selection is the evolutionary mechanism stating that with many resources available in nature, creatures with genetically inherited features that promote survival and reproduction will typically produce more offspring than their conspecific competitors.

Therefore, option C is appropriate.

Learn more about  Darwin’s theory of evolution, here:

https://brainly.com/question/25718754

#SPJ6

Answer:

The answer to this question is given below in the explanation section.

Explanation:

The correct answer to this question is the Bar graph.

Because we use this chart type to visually compare values across a few categories when the charts show duration or when the category text is long.

However, we can present information similarly in the bar graph and in column charts, but if you want to create a chart with the horizontal bar then you must use the Bar graph. In an Excel sheet, you can easily draw a bar graph and can format the bar graph into a 2-d bar and 3-d bar chart.

A column chart is used to compare values across a few categories. You can present values in columns and into vertical bars.

A line graph chart is used to show trends over months, years, and decades, etc.

Pie Chart is used to show a proportion of a whole. You can use the Pie chart when the total of your numbers is 100%.

Answer:

Bar graph option A

Explanation:

I did the test

Answer:

def __str__(self):

       return ('Year: %d, VIN: %s' %(self.year_made, self.car_vin))

Explanation:

Here you go! This should do it.

The program gives an implementation of the car record class which displays the model year and registration number of a car. The program written in python 3 goes thus :

class CarRecord :

#initialize a class named carRecord

def __init__(self):

#define the init method of the class

self.year_made = 0

#year car was made is initialized to 0 (integer)

self.car_vin = ' '

#vehicle registration is an empty string

def __str__(self):

#define an str method

return f"Year:{self.year_made}, VIN:{self.car_vin}"

#returns formatted display of the year and VIN number

my_car = CarRecord()

#creates an instance of the carRecord class

my_car.year_made = int(input())

#prompts user for the model year of the car

my_car.car_vin = input()

#prompts user for the model Vin number

print(my_car)

# display the details

A sample run of the program is given

Learn more :https://brainly.com/question/20504501

Answer:

Sentence: Jack or Peggy Zale must fix quickly the fax.

Correct: Either Jack or Peggy Zale must quickly fix the fax.

There are 2 errors in these sentence construction. In stating two persons as an option we must use the word "either" to indicate that you only have two choose from the two of them. The word "

Explanation:

The correct sentence would be "either Jake or Peggy Zale must quickly fix the fax".

In the question construction, there is a conjunction and misarrangement error.

In conclusion, the word " "either Jake or Peggy Zale must quickly fix the fax" is correct

Read more about conjunction

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You could try something likes this.

lst = []

n = int(input("Number of elements: ))

for i in range(0, n):

element = int(input("Element: "))

lst.append(element)

Answer:

To create a pivot table, select the columns to pivot and click on the insert option, click on the pivot table option and select the data columns for the pivot, verify the table range, select the location for the pivot and click ok. To format a column, select the columns and click the number option on the home tab, select the currency option and click on the number of decimal places

Explanation:

Microsoft Excel is a great tool for data analysis and visualization. It has several mathematical, engineering, statistical, and graphical tools for working with data.

A pivot-table is an essential tool for describing and comparing data of different types.

The steps to follow in order to produce a Pivot table would be as mentioned below:

Learn more about 'Pivot Table' here:

brainly.com/question/13298479

Answer:

Explanation:

The range() function is a built-in function in the Python programming language. In the following code, we will use this function to iterate over all the positions in the array called user_names and add them to the list g. (assuming that is what was meant by modifying the list g)

for i in range( len(user_names) ):

   g.append(user_names[i])

This simple 2 line code should do what you are asking for.

In python:

print("This weekend will be nice.")

I hope this helps!

Answer:

The answer is below

Explanation:

Adjacency list is a technique in a computer science that is used for representing graph. It deals with a gathering of unorganized lists utilized to illustrate a limited graph. In this method, each list depicts the group of data of a peak in the graph

Adjacency List are most preferred to Adjacency Matrix in some cases which are:

1.  When the graph to is required to be sparsely.

2.  For iterability, Adjacent List is more preferable

Answer:

mobile computing system

Explanation:

Answer:

mobile computing system... C

Answer:

Throughout the interpretation section elsewhere here, the explanation of the problem is summarized.

Explanation:

since this has already been answered, who is your favorite SMP character?

mines Wilbur/ Ghostbur

some people will disagree with me but jshlatt is one of my favorite characters on the dream smp . But my all time favorite characters is ALL of Wilbur's characters

Answer:

To use cout statements, you must include the iostream file in your program.

Answer:

Choose file>import>import library

Explanation:

because it is the process to add images to your library

Answer:

Well, First of all, use Linear

Explanation:

My sis always tries to explain it to me even though I know already, I can get her to give you so much explanations XD

I have the Longest explanation possible but it won't let me say it after 20 min of writing

Answer:

C and G

Explanation:

In C language, the asterisks, ' * ', and the ampersand, ' & ', are used to create pointers and references to pointers respectively. The asterisks are used with unique identifiers to declare a pointer to a variable location in memory, while the ampersand is always placed before a variable name as an r_value to the pointer declared.

Answer:

Follows are the code to this question:

def build_word_counter(string):#defining a method build_word_counter that accepts string as a parameter  

   d = dict()#defining d variable as a dictionary

   for x in string:#defining for loop that use string

       x = x.lower()#Use lower method  

       if not d.get(x):#defining if block that holds value in d variable

           d[x] = 1#use dictionary to hold value in 1

       else:#defining else block

           d[x] += 1#use dictionary to increment value by 1

   return d#return dictionary

print(build_word_counter(["Like","like","LIKE"]))#use print method to call method

def build_letter_distribution(string):#defining a method build_letter_distribution that accepts string variable

   d = dict()#defining d variable as a dictionary

   for i in string:#defining for loop to count string value

       for j in i:#defining for loop to hold string as number

           if not d.get(j):#defining if block that doesn't get value in dictionary  

               d[j] = 1#hold value in dictionary  

           else:#defining else block

               d[j] += 1#use dictionary to increment the dictionary value

   return d#return dictionary

print(build_letter_distribution(["Like","test","abcdEFG"]))#use print method to return its value

Output:

please find the attached file.

Explanation:

In the first program a method, "build_word_counter" is defined that accepts a string variable in its parameter, and inside the method, a dictionary variable "d" is defined that uses the for loop to hold string value and convert all value into lower case.

In the next step, a conditional statement is used that holds value in the dictionary and count its word value.

In the second program a method, "build_letter_distribution" is defined that holds string variable in its parameter, and inside the method, a dictionary variable "d" is defined that uses the two for loop and in if the block, it holds value in the dictionary and returns its value, and use print method to print its return its value.

Answer:

Using three or more vanishing points within a work to create the illusion of space on a two-dimensional surface.

Explanation:

Answer:

que pinga this is a hw website not snap

Explanation:

The code .cpp is available bellow

#include<iostream>

using namespace std;

//declaring variables

void merge(int* ip, int sz, int* opt, bool opt_asc); //merging

int* mergesort(int* ip, int sz);

void mergesort(int *ip, int sz, int* opt, bool opt_asc);

void merge(int* ip, int sz, int* opt, bool opt_asc)

{

  int s1 = 0;

  int mid_sz = sz / 2;

  int s2 = mid_sz;

  int e2 = sz;

  int s3 = 0;

  int end3 = sz;

  int i, j;

  if (opt_asc==true)

  {

      i = s1;

      j = e2 - 1;

      while (i < mid_sz && j >= s2)

      {

          if (*(ip + i) > *(ip + j))

          {

              *(opt + s3) = *(ip + j);

              s3++;

              j--;

          }

          else if (*(ip + i) <= *(ip + j))

          {

              *(opt + s3) = *(ip + i);

              s3++;

              i++;

          }

      }

      if (i != mid_sz)

      {

          while (i < mid_sz)

          {

              *(opt + s3) = *(ip + i);

              s3++;

              i++;

          }

      }

      if (j >= s2)

      {

          while (j >= s2)

          {

              *(opt + s3) = *(ip + j);

              s3++;

              j--;

          }

      }

  }

  else

  {

      i = mid_sz - 1;

      j = s2;

      while (i >= s1 && j <e2)

      {

          if (*(ip + i) > *(ip + j))

          {

              *(opt + s3) = *(ip + i);

              s3++;

              i--;

          }

          else if (*(ip + i) <= *(ip + j))

          {

              *(opt + s3) = *(ip + j);

              s3++;

              j++;

          }

      }

      if (i >= s1)

      {

          while (i >= s1)

          {

              *(opt + s3) = *(ip + i);

              s3++;

              i--;

          }

      }

      if (j != e2)

      {

          while (j < e2)

          {

              *(opt + s3) = *(ip + j);

              s3++;

              j++;

          }

      }

  }

  for (i = 0; i < sz; i++)

      *(ip + i) = *(opt + i);

}

int* mergesort(int* ip, int sz)

{

  int* opt = new int[sz];

  mergesort(ip, sz, opt, true);

  return opt;

}

void mergesort(int *ip, int sz, int* opt, bool opt_asc)

{

  if (sz > 1)

  {

      int q = sz / 2;

      mergesort(ip, sz / 2, opt, true);

      mergesort(ip + sz / 2, sz - sz / 2, opt + sz / 2, false);

      merge(ip, sz, opt, opt_asc);

  }

}

int main()

{

  int arr1[12] = { 5, 6, 9, 8,25,36, 3, 2, 5, 16, 87, 12 };

  int arr2[14] = { 2, 3, 4, 5, 1, 20,15,30, 2, 3, 4, 6, 9,12 };

  int arr3[10] = { 10, 9, 8, 7, 6, 5, 4, 3, 2, 1 };

  int *opt;

  cout << "Arays after sorting:\n";

  cout << "Array 1 : ";

  opt = mergesort(arr1, 12);

  for (int i = 0; i < 12; i++)

      cout << opt[i] << " ";

  cout << endl;

  cout << "Array 2 : ";

  opt = mergesort(arr2, 14);

  for (int i = 0; i < 14; i++)

      cout << opt[i] << " ";

  cout << endl;

  cout << "Array 3 : ";

  opt = mergesort(arr3, 10);

  for (int i = 0; i < 10; i++)

      cout << opt[i] << " ";

  cout << endl;

  return 0;

}

Answer:

a task and a calendar entry

Explanation:

ITS RIGHT

Answer:

its A) a task and a calendar entry

Explanation:

correct on e2020

Answer:

speed and storage

Explanation:

The pros and cons of both are mainly in regards to speed and storage. Due to linked lists elements being connected to one another it requires that each previous element be accessed in order to arrive at a specific element. This makes it much slower than an array-based implementation where any element can be quickly accessed easily due to it having a specific location. This brings us to the other aspect which is memory. Since Arrays are saved as a single block, where each element has a specific location this takes much more space in the RAM as opposed to a linked implementation which is stored randomly and as indexes of the array itself.

Array Implementation:

Linked Implementation

Answer:

Colunm Chart

Explanation:

Trust me

Answer:

four

Explanation:

quad means four so it runs four times faster