Answer:
This ability of charged particles to do work is called an electric potential.
Explanation:
When two negative charges are brought close to each other, they also repel. But when a positive and a negative charge are brought close together, they attract each other. When these two opposite charges are combined, they can be used to work. This is why we need a positive (+) and a negative (–) to light a bulb or run any electrical tool, equipment, mobile phone or home appliance.
Potential difference is the difference in the amount of energy that charge carriers have between two points in a circuit. ... The energy is transferred to the electrical components in a circuit when the charge carriers pass through them. We use a voltmeter to measure potential difference (or voltage).
A closed, uninsulated system fitted with movable piston, so no matter is exchanged with the surroundings, was assembled. Introduction of 430 J of heat caused the system to expand, doing 238 J of work against a constant pressure of 101 kPa. What is the value of for this process
Answer: You do not specify what is being asked for. ∆E? ∆H?
∆E = (430 - 238) J = 192 J
∆H = 430 J
Explanation:
If asked for the value of ∆H the answer is simply the change in heat, and in the question, it states introduction of 430 J of heat is causing the system to expand.
Therefore ∆H = 430 J
If asked for ∆E, we know that ∆E = ±q (heat) + work (-P∆V) = ±q + w
The question states that 238 J of work are done AND the system expanded
(work is negative because expansion means work is done BY the system, releasing energy/heat... Conversely, if the system were compressed, work is done ON the system, absorbing heat/energy)
Therefore, ∆E = (430 - 238) J = 192 J
(a) Define the term ginning? (b) Name the simple device used for spinning?
A simple device used for spinning is a hand spindle also known as takli.
hope it helps
If you traveled 50m/s for 60 seconds, how far did you travel? Remember speed=distance/time
Question options:
300 m/s
500 m/s
3,000 m/s
300 km/h
Answer:
3,000 m
Explanation:
speed = distance/time
distance = speed * time
= 50 * 60
= 3000 m
Which term describes energy stored in the bonds between atoms?
A. Nuclear energy
B. Chemical energy
O C. Thermal energy
D. Sound energy
Answer:
B. Chemical energy
Explanation:
chemical energy is the energy stored in the bonds between atoms
What is an involuntary and a voluntary muscle action?
Answer:
Involuntary muscle action are muscles that move WITHOUT conscious control, and voluntary muscle action are muscles that move WITH conscious control.
Explanation:
A example of a involuntary muscle action would be your heart. Your heart is a muscle beats without you thinking about it and is very vital to your body. A example of a voluntary muscle would be the muscles that are attached to your bones and allow you to move your body, and it's voluntary because your body won't move on it's own.
Hope this helps.
Describe what causes the planets to stay in orbit around the Sun
Answer:
Gravitional pull or gravity
Explanation:
Its that simple
A 220g mass is on a frictionless horizontal surface at the end of a spring that has a force constant of 7.0N/m The mass is displaced 5 2m from its equilibrium position and then released to undergo simple harmonic motion.
At what displacement from the equilibrium position is the potential energy equal to kinetic energy?
Answer:
Explanation:
Your numbers seem wonky, so I'll just assume that the initial displacement is a distance A (Amplitude) from the equilibrium position. Spring constant = k
Initial potential energy is
PE = ½kA²
As potential energy and kinetic energy are constantly exchanging in SHM,
the position x where half of the original spring potential exists is found where
½kx² = ½(½kA²)
x² = ½A²
x = (√0.5)A
x ≈ 0.707A
just plug in your actual starting position A
With A = 5.2 cm
x = 3.67695... 3.7 cm
A race car rounding a corner at a constant speed of 200 miles per hour.
Answer:
Yes since it is changing direction
Explanation:
A race car rounding a corner at a constant speed of 200 miles per hour
In 1962 measurements of the magnetic field of a large tornado were made at the Geophysical Observatory in Tulsa, Oklahoma. If the magnitude of the tornado's field was B = 17.50 nT pointing north when the tornado was 9.10 km east of the observatory, what current was carried up or down the funnel of the tornado? Model the vortex as a long, straight wire carrying a current. A (conventional current) flowing ---Direction--- the tornado.
Answer:
796.25 A
Explanation:
B= (μI)/(2πr)
I= (B*2πr)/(μ)
μ= 4π*10^-7
I= ((17.50*10^-9)(2π)(9.10*10^3)) / (4π*10^-7)
= 796.25 A
A (conventional current) flowing "DOWN" the tornado.
Two vectors P=40m/s and q=60mls are perpendicular to each other. Calculate the resultant force and the angle resultant make with either vectors
This question involves the concepts of the rectangular components of the vector and the resultant of the vectors.
The magnitude of the resultant force is "72.11 N", and it makes an angle of "33.7°" from one of the vectors.
The rectangular components of a vector are those components that have a right angle between them. The resultant of two rectangular components of a vector can be found using the following formula:
[tex]F = \sqrt{F_1^2+F_2^2}[/tex]
where,
F = resultant force = ?
F₁ = First component of force = 40 N
F₂ = Second component of force = 60 N
Correction: The unit in question is given as m/s, while the unit of force is N. Hence, N is taken here.
Therefore,
[tex]F = \sqrt{(40\ N)^2+(60\ N)^2}[/tex]
F = 72.11 N
The following formula can be used to find the angle of resultant from 60N vector:
[tex]\theta = tan^{-1}(\frac{40\ N}{60\ N})\\\\[/tex]
θ = 33.7°
Learn more about rectangular components of a vector here:
https://brainly.com/question/14793638?referrer=searchResults
The attached picture shows the resultant calculation for the rectangular components of a vector.
Which of the following formulas describes the change in momentum of an
object?
A. change in momentum = force x time over which force is applied
B. change in momentum = acceleration distance over which
acceleration is applied
C. change in momentum = force x distance over which force is
applied
O D. change in momentum = acceleration time over which
acceleration is applied
What was the initial speed of a car if its speed is 40 m/s after 5 seconds of
accelerating at 4 m/s27
A. 10 m/s
B. 60 m/s
C. 20 m/s
D. 25 m/s
Reset Selection
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Answer:
[tex]\boxed {\boxed {\sf C. \ 20 \ m/s }}[/tex]
Explanation:
We are asked to find the initial speed of a car.
We are given the final speed, the time, and the acceleration, so we will use the following kinematic equation:
[tex]v_f=v_i+at[/tex]
We know the final speed is 40 meters per second, the acceleration is 4 meters per second squared, and the time is 5 seconds.
[tex]v_f[/tex]= 40 m/s t= 5 s a= 4 m/s²Substitute the values into the formula.
[tex]40 \ m/s = v_i+(4 \ m/s^2 * 5 \ s)[/tex]
Multiply inside the parentheses.
[tex]40 \ m/s =v_i+ 20 \ m/s[/tex]
We are solving for the initial speed, so we must isolate the variable [tex]v_i[/tex].
20 meters per second is being added to [tex]v_i[/tex]. The inverse operation of addition is subtraction. Subtract 20 m/s from both sides of the equation.
[tex]40 \ m/s - 20 \ m/s = v_i + 20 \ m/s - 20 \ m/s[/tex]
[tex]40 \ m/s - 20 m/ s = v_i[/tex]
[tex]20 \ m/s=v_i[/tex]
The initial speed of the car is 20 meters per second and choice C is correct.
When converted to a household measurement, 9 kilograms is approximately equal to a
Answer:
D) 19.8 lbs
Explanation:
1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.
1kg is also equal to 2.205 lbs. 9*2.205=19.8416
9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system
a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.
This leaves us with 19.8 lbs
hola buen día por favor alguien me puede ayudar por favor1. Dos cargas puntuales q1=+4μC y q2=+ 6μC están separadas por 10 cm. Una carga
puntual
q3=+2μC se coloca a medio camino entre q1 y q2. Encuentra la magnitud y la dirección de la
fuerza resultante sobre q3. Asuma que q1 está a la izquierda de q3 y q2 a la derecha de q3.
Revisa el ejemplo de la clase del tema 6. Además, recuerda que las fuerzas no siempre actúan
en la misma dirección.
2. Se coloca una carga puntual de 4 μC en un punto P (x = 0.2 m, y = 0.4 m). ¿Cuál es el campo
eléctrico E debido a esta carga en el origen del plano cartesiano? Hint: asume un plano
cartesiano y dibuja el campo eléctrico que se busca. Además, recuerda el teorema de
Pitágoras.
3. Una carga puntual q = 25μC está ubicada en el centro de una esfera de radio R = 25 cm, el
campo eléctrico generado a esta distancia debido a esa carga es E=3.6 x 10^6 N/C. Se quita de
la superficie una sección circular con radio r = 5 cm. Encuentre el flujo eléctrico que pasa por
esta sección. Hint: solo quieres saber el flujo eléctrico sobre el área de la superficie que se
aisló, por lo que es importante recordar cómo se obtiene el área de un círculo.
4. En cierta región al norte del planeta tierra, existe un campo eléctrico uniforme, la dirección
del campo eléctrico es hacía el centro del planeta y según se sabe, tiene un valor de 1000 N/C.
Encuentra el cambio de la energía potencia eléctrica de una partícula que tiene una carga de
-1.6 x10 -19 C. Considera que la partícula se suelta en un punto A y llega hasta un punto B que
está a 50 m del punto A.
5. Dos cargas q1 = −2 μC y q2 = + 2 μC se fijan en sus posiciones y se separan por una distancia d
= 10 cm. ¿Cuál es el potencial eléctrico en el origen debido a estas dos cargas?
Answer:
vfyugpuvfhvjvfhuvihfiurj
Explanation:
vfehgwfljhgiurnjfkfjhk
An 80 kg box is accelerated to the right at a rate of 3 m/s2. What is the applied force?
As we know,
F= ma
Here,
applied force(f)= mass × acceleration
=80kg×3m/s2
=240kgm/s2
=240N
Am I correct? Plz answer ASAP! I will give brainilest:D (Science)
Answer:
I would agree with your selection.
Explanation:
A box is 30 cm wide, 40 cm long and 25 cm high. Calculate the volume of the box in cubic centimeter.
A) 3,000
B) 30,000
C) 15,000
D) 1,200
Answer:
The correct answer would be A: 3,000.
Explanation:
To find the volume of a box, you have to do l * w * h. You multiply 30, 40, and 25 which gives you an answer of 3,000 cubic centimeters.
Una masa de aire de 20g absorbe 780 cal. Teniendo en cuenta que su temperatura inicial es de 30°C. Calcular la
temperatura que alcanzo al absorber el calor. Ce:0,24 cal/g °C
Answer:
sorry I don't know the answer
What will be the current through a resistance of 50Ω if the applied voltage across the resistance is 117V?
Formulas: V=IR, I=V/R, R=V/I
Note: No need to write the unit of your answer.
2.34 A
Explanation:
[tex]V = IR \Rightarrow I = \dfrac{V}{R} = \dfrac{117\:\text{V}}{50\:Ω} = 2.34\:\text{A}[/tex]
how can I become a good science student ?
Answer:
Study hard , focus on your studies and alyways ask questions .
Study, revise, write notes, listen in class, don't let yourself be distracted by others, and do the work in class...maybe join stem or science club if you wanna
Hope this helped you- have a good day bro cya)
I NEED A 100% ACCURATE ANSWER FOR THIS QUESTION ASAP NO LINKS !!!
What describes the pressure in a contained fluid?
1: unknown as long as the fluid is contained
2: the same throughout the fluid
3: higher in some places and lower in other places
Answer:
3) higher in some places nd lower In other places
Explanation:
The pressure in a fluid is given by the law
p = p0 + pgh
where
p0 is the atmospheric pressure
p is the fluid's density
g is the acceleration of gravity
h is the depth at which the pressure is calculated
As we see, the pressure depends on the value of h (depth): therefore, points which are located at more depth experience a larger pressure than points located near the fluid's surface.
What is 1/3 a millisecond in seconds (decimal form)? (0._ s)
Answer:
I don't know
Explanation:
plz
plz mark me as brainlist
the electrical energy used to pump the water up to a mountain lake is 1.2 x 10 to the power 12 J only 6.2 x 10 to the power 11 J of electrical energy is generated when the water is released calculate the efficiency of this energy storage scheme
Answer:
Explanation:
ake is 1.2 x 10^12 J. Only 6.2 x 10^11 J of electrical energy is generated when the water is released. Calculate the efficiency of this energy
A trouble-making youth is standing on a bridge, and wants to drop a water balloon on an unsuspecting passerby. A man is jogging on a path below the bridge with a constant speed of 4.2 m/s. The bridge is 11.6 m above the ground. If the balloon is to land right at the jogger's feet, at what horizontal distance x from the bridge should he be when the youth drops the balloon?
Answer:
Explanation:
Time needed for a balloon to drop from vertical rest a distance of 11.6 m
t = √(2h/g) = √(2(11.6)/9.8) = 1.538618
d = vt = 4.2(1.538618) = 6.462197...
d = 6.5 m
Horizontal distance x = 6.5 m from the bridge he should be when the youth drops the balloon with velocity 4.2 m/s.
What is velocity?When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.
Uniform motion an object is said to have uniform motion when object cover equal distance in equal interval of time within exact fixed direction. For a body in uniform motion, the magnitude of its velocity remains constant over time.
Given in the question time needed for a balloon to drop from vertical rest a distance of 11.6 m
t = √(2h/g) = √(2(11.6)/9.8) = 1.538618
d = vt = 4.2(1.538618) = 6.462197...
d = 6.5 m
Horizontal distance x = 6.5 m from the bridge he should be when the youth drops the balloon with velocity 4.2 m/s.
To learn more about velocity refer the link:
brainly.com/question/18084516
#SPJ2
Which of the following statement describes a nonpolar molecule
Answer:
?
Explanation:
what are the statements
A car with a mass of 1500 kg is pulled by a rope that is horizontal to the ground. The tension in the rope is 2000 N and a friction force of 350 N opposes the car's motion. What is the magnitude of the car's acceleration?
Answer:
Explanation:
Assuming the ground is level as well.
F = ma
a = F/m
a = (2000 - 350) / 1500
a = 1.1 m/s²
The acceleration of the car is 1.1 m/s².
To calculate the magnitude of the acceleration of the car, we use the formula below.
F-F' = ma................ Equation 1Where:
F = Tension in the ropeF' = Friction forcem = mass of the cara = acceleration of the carMake a the subject of the equation
a = (F-F')/m................. Equation 2From the equation,
Given:
F = 2000 NF' = 350 Nm = 1500 kgSubstitute these values into equation 2
a = (2000-350)/1500a = 1650/1500a = 1.1 m/s²Hence, the acceleration of the car is 1.1 m/s².
Learn more about acceleration here: https://brainly.com/question/605631
I need help ASAP please.....
A student is asked to calculate the centripetal acceleration of a hummingbird that makes a complete circle in 0.43 seconds. If the circle has a radius of 0.25 m, what is
the correct setup for determining the centripetal acceleration of the hummingbird?
(3.65m/s)2/0.25m
(3.65m/s)2-0.43
O (0.435)2 / 25m
O (0.432.25m
The centripetal acceleration of the hummingbird is [tex]\frac{(3.65)^2}{0.25} = 53.29 \ m/s^2[/tex]
The given parameters;
time of motion of the hummingbird, t = 0.43 sradius of the circle, r = 0.25 mnumber of revolution of the hummingbird = 1 rev per 0.43 sThe angular speed of the hummingbird is calculated as follows;
[tex]\omega = \frac{1 \ rev}{0.43 \ s} \times \frac{2\pi \ rad}{1 \ rev} =14.61 \ rad/s[/tex]
The linear speed of the hummingbird is calculated as follows;
v = ωr
v = 14.61 x 0.25
v = 3.65 m/s
The centripetal acceleration of the hummingbird is calculated as follows;
[tex]a_c = \frac{v^2}{r} \\\\a_c = \frac{(3.65)^2}{0.25} \\\\a_c = 53.29\ m/s^2[/tex]
Thus, the centripetal acceleration of the hummingbird is [tex]\frac{(3.65)^2}{0.25} = 53.29 \ m/s^2[/tex]
Learn more here:https://brainly.com/question/11700262
Ex 2) A cannon ball is shot straight up into the air with an initial velocity of 25 m/s[Up).
What is the maximum height of the cannonball?
Explanation:
The final velocity at the cannon ball's maximum height is zero ([tex]v_y = 0[/tex]). We can use the equation
[tex]v_y^2 = 0 = v_{0y}^2 - 2gy_{max}[/tex]
[tex]\Rightarrow y_{max} = \dfrac{v_{0y}^2}{2g}[/tex]
[tex]y_{max} = \dfrac{(25\:\text{m/s})^2}{2(9.8\:\text{m/s}^2)}[/tex]
[tex]\:\:\:\:\:\:\:=31.9\:\text{m}[/tex]
how long untill the semester is done