describe how to get started on a formal business document by using word processing software

Answer:

The solution is provided in the explanation section.

Detailed explanation is provided using comments within the code

Explanation:

import java.util.*;

public class Main {

//The Bubble sort method

public static void bb_Sort(int[] arr) {  

   int n = 10; //Length of array  

   int temp = 0; // create a temporal variable  

   for(int i=0; i < n; i++){  

         for(int j=1; j < (n-i); j++){  

           if(arr[j-1] > arr[j]){  

               // The bubble sort algorithm swaps elements  

               temp = arr[j-1];  

               arr[j-1] = arr[j];  

               arr[j] = temp;  

             }  

         }            

         }  

        }

 public static void main(String[] args) {

   //declaring the array of integers

   int [] array = new int[10];

   //Prompt user to add elements into the array

   Scanner in = new Scanner(System.in);

   //Use for loop to receive all 10 elements

   for(int i = 0; i<array.length; i++){

     System.out.println("Enter the next array Element");

     array[i] = in.nextInt();

   }

   //Print the array elements before bubble sort

   System.out.println("The Array before bubble sort");

   System.out.println(Arrays.toString(array));

   //Call bubble sort method

   bb_Sort(array);  

   System.out.println("Array After Bubble Sort");  

   System.out.println(Arrays.toString(array));

 }

}

Answer:

prt scan+Windows logo

In python:

import random

die1 = random.randint(1,6)

die2 = random.randint(1,6)

if die1 + die2 > 8:

   print(f"The sum of the dice is {die1 + die2}")

print("done")

If you need me to change anything, I will. I hope this helps!

Corrected Question

Write a program that reads in 15 numbers in sorted order from the user (i.e. the user enters them in order) and stores them in a 1D array of size 15. Next, prompt the user for a number to search for in the array (i.e. the "target"). Then, print the array. Next, search the array using a linear search – find the target element and printing out the target and its index as well as the entire array

Answer:

The solution is given in the explanation section

See detailed explanation of each step given as comments

Explanation:

import java.util.*;

class Main {

 public static void main(String[] args) {

   //Create the array of 15 elements

   int [] array = new int [15];

   //Create an object of the scanner class to receive user input

   Scanner in = new Scanner(System.in);

   //Prompt user to enter the values in sorted order

   //Using a for loop

   for (int i =0; i<array.length; i++){

         System.out.println("Enter the next element: In SORTED order please!");

         array[i] = in.nextInt();

   }

   System.out.println("All Fifteen element have been entered");

   // Ask the user for an element to be searched for

   //A target element

   System.out.println("Which element do you want to search for in the array");

   //Create the target element

   int target = in.nextInt();

   //Use a for loop to sequentially check each element in the array

   for(int i = 0; i<array.length; i++){

     if(array[i]==target){

       System.out.println(target+" is found at index "+i +" of the array");

     }

   }

       // Printout the entire array

   System.out.println(Arrays.toString(array));

 }

}

Answer:

laptops

Explanation:

B

You can buy new applications at a retail store on DVD for laptops. Thus, option A (laptops) is correct.

A website is an accumulation of internet pages and related items that is posted on at least one server and given an unique domain name. Most blogs focus on a single subject or objective, such as reporting, education, industry, entertaining, or photo sharing.

A raster-based photograph designed for the web and publishing is stored as a JPG file. The JPG format is the default file format for image sensors and is the most widely used picture format on the web because of its universal compatibility and decompression. Portraits in both colour and black and white work brilliantly with them.

Therefore, option A (laptops) is the correct option.

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Answer:

There are three primary components to understanding networks: 1. Physical Connections; 2. Network Operating System; and 3. Application Component. Hope this helps!

Explanation:

Answer:

I hope the above picture may help you.

Answer: not sentence [3:6]

I hope this helps

Explanation:

Answer:

Data bar

Explanation:

The answer to this question is data bar. Through the use of a day bar we are able to see trends in our data. They are very useful when it comes to visualization of values that are In a range of cells. Now if the bar is longer then the value we are visualizing is definitely higher. And if it is shorterr the value is lower. Several applications like excel has programmes that makes use of data bars especially for statistical purposes.

Answer:

the clock rate of the first machine need to be 1.7 GHz

Explanation:

Given:

CPI of A = 1.9

CPI of B = 1.1

machine, B executes the same program with 20% less instructions and with a CPI of 1.1 at 800MHz

To find:

In order for the two machines to have the same performance, what does the clock rate of the first machine need to be

Solution:

CPU execution time = Instruction Count * Cycles per Instruction/ clock rate

CPU execution time = (IC * CPI) / clock rate

(IC * CPI) (A) / clock rate(A) =  (IC * CPI)B / clock rate(B)

(IC * 1.9) (A) / clock rate(A) = (IC * (1.1 * (1.0 - 0.20)))(B) / 800 * 10⁶ (B)

Notice that 0.20 is basically from 20% less instructions

(IC * 1.9)  / clock rate = (IC * (1.1 * (1.0 - 0.20))) / 800 * 10⁶

(IC * 1.9)  / clock rate =  (IC*(1.1 * ( 0.8))/800 * 10⁶

(IC * 1.9)  / clock rate =  (IC * 0.88) / 800 * 10⁶

clock rate (A) =  (IC * 1.9) / (IC * 0.88) / 800 * 10⁶

clock rate (A) =  (IC * 1.9) (800 * 10⁶) /  (IC * 0.88)

clock rate (A) = 1.9(800)(1000000)  / 0.88

clock rate (A) =  (1.9)(800000000)  / 0.88

clock rate (A) = 1520000000  / 0.88

clock rate (A) = 1727272727.272727

clock rate (A) = 1.7 GHz

Answer:

7. true

8.B

Hopefully those are correct!

Explanation:

Answer:

a. I think the Aluminum will conduct heat better.

b. I think the Fiberglass will insulate heat better.

Fiberglass is used to insulate most everyday items, so I can be sure that fiberglass can be the best insulator, as for aluminum it conducts heat like you wouldn't believe.

Note: Your answer doesn't have to be right, they just want you to make a prediction about your answer, that means it's alright to guess, also know I didn't guess I am just telling you that you didn't have to ask this question. <3

Answer:

True Just took the test

Explanation:

Answer:

the answer is T or TRUE

Explanation:

Answer:

The program equivalent in C++ is:

#include <cstdio>

#include <cstdlib>

#define SIZE 5

using namespace std;

int main(int argc, char *argv[]) {

int numerator = 25;

int denominator = 10;

FILE * inPut = fopen(argv[1], "r");

FILE * outPut = fopen(argv[2], "w");

float result = (float)numerator/denominator;

fprintf(outPut,"Result is %.2f\n", result);

float arr[SIZE];

for(int i = 0; i < SIZE; i++) {

fscanf(inPut, "%f", &arr[i]);

fprintf(outPut, "%7.4f\n", arr[i]);

}

return 0;

}

Explanation:

See attachment for explanation.

Each line were numbered with equivalent line number in the C program

In python:

for i in range(56, 71):

   print(i, end=" ")

Answer:

for n in range(56,71):

   print(n, end=" ")

Explanation:

Answer:

using a limited access public computer to watch movies

Explanation:

Cause it doesn't involve you performing any illegal actions.

Answer:

C. using a limited access public computer to watch movies

Explanation:

IM A DIFFERENT BREEED!!

PLUS NOTHING ELSE MAKES SENSE LOL!

The ways that technology helps business professionals to be more efficient is that  Business professionals may stay more organized, communicate more effectively, and keep firms secure with the use of technology.

Technology makes it simpler to connect with employees by utilizing e-mail and memos, and it helps keep employee information and corporate paperwork a lot more organized using computers and software.

By streamlining time-consuming procedures, technology also increases office productivity. For instance, using document management software eliminates the need for manual data entry, filing, as well as in file retrieval.

Therefore, one can say that Technology can be used to safeguard private executive decisions, financial data, and other forms of proprietary information that gives a company a competitive edge. Simply simply, technology aids firms in protecting their ideas from rivals.

Learn more about technology from

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Answer:

The correct answer to this question is given below in the explanation section.

Explanation:

in most programming languages, the print() function is used to display a string value to the screen. Because, the print function prints all the string given in it as a parameter.

for example: to print hello world.

we use the function to print hello world as print("hello world").

However, it noted that other options are not correct because the main() function is an entry point of a program and it does not print string value to the screen. while run and show function do not print string value of screen also.

Answer:

in python print()

Answer:

110101 = 53

Hope this helps :)

To help us solve this problem, I've created a simple python program.

print(int("110101", 2))

The program prints 53 to the console.

If you search python ide online and paste that code into the ide and then replace the binary in between the quotes, you can find the value of any binary number you want.

Answer and Explanation:

A. The study by the research team may not reflect the purpose of the research which is to know how much inbound tourism is contributing to the economy. They are sampling the population on their favorite spots to visit( which may be too narrow here) and what their leisure activities are (which are not the only things tourists spend on). Also 10000 residents may be too small as a sample to reflect more accurate study outcome representative of the population.

2. A flawed sample which is a sampling error would not represent the population as the results from sample would contradict population results

Answer:

The answer to this question is given below in the explanation section

Explanation:

The correct option for this question is Animation tab.

Animation tab in PowerPoint ribbon is a unique tab that is not found in other office applications such as in word, excel, outlook, publisher etc.

Because in PowerPoint you can use animation to make your slides animated and all animation can be managed and animation-related settings, you can find in the animation tab.

However, other tabs such as Home, Insert, and View are common in all office applications.

Answer:

Follows are the code to this question:

def weeklypay(hour_rate,hour ):#defining a method weeklypay that accepts two parameters

   pay=hour_rate* hour#defining variable pay that calculate payable amount

   return pay#return pay value

hour_rate=float(input("Enter your hour rate $: "))#defining variable hour_rate that accepts rate vlue

hour=int(input("Enter total hours: "))#defining hour variable that accepts hour value

print('The total amount you will get $: ',weeklypay(hour_rate,hour))#call method and print return value

Output:

Enter your hour rate $: 300

Enter total hours: 3

The total amount you will get $:  900.0

Explanation:

In the above-given code, a method "weeklypay" is declared, which holds two value "hour_rate and hour" in its parameter, inside a method a "pay" variable is declared, that calculate the total payable amount of the given inputs and return its value.

In the next step, the above variable is used to input the value from the user-end and uses the print method to call the "weeklypay" method and print its return value.

Answer:

I've implemented this program using python

userinput = int(input("Length: "))

mylist = []

mylist.append(userinput)

for i in range(1,userinput+1):

   userinp = int(input("Input: "))

   mylist.append(userinp)

smallval = mylist[1]

for i in range(1,len(mylist)):

   if smallval > mylist[i]:

       smallval = mylist[i]

for i in range(1,len(mylist)):

   mylist[i] = mylist[i] - smallval

for i in range(1,len(mylist)):

   print(mylist[i],end=' ')

Explanation:

I've added the full source program as an attachment where I used comments to explain difficult lines

The program written in python 3 deducts the least from a list of user given integers and prints the output. The program goes thus :

len_input = int(input())

#the number of inputs the user wishes to supply

vals = []

#initialize an empty list to accept the inputs

for i in range(1, len_input +1):

#use a loop to accept the user inputs

num = int(input())

#allow users to take in the inputs

vals.append(num)

#append each value to the list

least =min(vals)

#using the min function, obtain the lowest value from the list

output_vals = []

#initialize an empty list to hold the normalized values

for i in range(len_input):

#loop using a for loop

diff = vals[i] - least

#deduct the minimum value from each element in the list

output_vals.append(diff)

#append the values to the new list.

print(output_vals)

#display the output

A sample run of the program and the script is attached.

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Answer:

You could have a bug, virus, or you might have been hacked the most I can tell you is try to contact a technician to check it and try to help you. It could also be a problem with your internet, maybe you hit your computer against something and it broke something inside, or it could be a technical glitch. I hop this helps! Good Luck fixing your computer!

Answer:

Modify

If scores[index] > highest then highest = scores[index]

End Of highest

Name = students[index]

End For Display

to

If scores[index] > highest then highest = scores[index]

Name = students[index]

End Of highest

End For Display

Explanation:

In the code, you posted the code segment that gets the name of the student with the highest score is outside the if condition that determines the highest.

To make correction, we only need to bring this code segment into the loop.

See Answer

Answer:

See solution below

See comments for explanations

Explanation:

import java.util.*;

class Main {

 public static void main(String[] args) {

   //PrompT the User to enter a String

   System.out.println("Enter a sentence or phrase: ");

   //Receiving the string entered with the Scanner Object

   Scanner input = new Scanner (System.in);

   String string_input = input.nextLine();

   //Print out string entered by user

   System.out.println("You entered: "+string_input);

   //Call the first method (GetNumOfCharacters)

   System.out.println("Number of characters: "+ GetNumOfCharacters(string_input));

   //Call the second method (OutputWithoutWhitespace)

   System.out.println("String with no whitespace: "+OutputWithoutWhitespace(string_input));

   }

 //Create the method GetNumOfCharacters

   public static int GetNumOfCharacters (String word) {

   //Variable to hold number of characters

   int noOfCharactersCount = 0;

   //Use a for loop to iterate the entire string

   for(int i = 0; i< word.length(); i++){

     //Increase th number of characters each time

     noOfCharactersCount++;

   }

   return noOfCharactersCount;

 }

 //Creating the OutputWithoutWhitespace() method

 //This method will remove all tabs and spaces from the original string

 public static String OutputWithoutWhitespace(String word){

   //Use the replaceAll all method of strings to replace all whitespaces

   String stringWithoutWhiteSpace = word.replaceAll(" ","");

   return stringWithoutWhiteSpace;

 }

}

Answer:  

Here is the C++ program:  

#include <iostream>   //to use input output functions    

using namespace std;   //to identify objects cin cout    

int main() {   //start of main method    

int red,green,blue,smallest;   //declare variables to store integer values of red,green, blue and to store the smallest value    

cout<<"Enter value for red: ";  //prompts user to enter value for red    

cin>>red;  //reads value for red from user    

cout<<"Enter value for green: ";  //prompts user to enter value for green  

cin>>green; //reads value for green from user    

cout<<"Enter value for blue: "; //prompts user to enter value for blue    

cin>>blue;   //reads value for blue from user    

//computes the smallest value  

if(red<green && red<blue) //if red value is less than green and blue values    

smallest=red;   //red is the smallest so assign value of red to smallest    

else if(green<blue)   //if green value is less than blue value    

smallest=green; //green is the smallest so assign value of green to smallest  

else //this means blue is the smallest    

smallest=blue;  //assign value of blue to smallest    

//removes gray part by subtracting smallest from rgb  

red=red-smallest; //subtract smallest from red    

green=green-smallest; //subtract smallest from green    

blue=blue-smallest; //subtract smallest from blue    

cout<<"red after removing gray part: "<<red<<endl;  //displays amount of red after removing gray    

cout<<"green after removing gray part: "<<green<<endl; //displays amount of green after removing gray  

cout<<"blue after removing gray part: "<<blue<<endl;  } //displays amount of blue after removing gray  

Explanation:  

I will explain the program using an example.    

Lets say user enter 130 as value for red, 50 for green and 130 for blue. So  

red = 130    

green = 50

blue = 130  

First if condition if(red<green && red<blue)   checks if value of red is less than green and blue. Since red=130 so this condition evaluate to false and the program moves to the else if part else if(green<blue) which checks if green is less than blue. This condition evaluates to true as green=50 and blue = 130 so green is less than blue. Hence the body of this else if executes which has the statement: smallest=green;  so the smallest it set to green value.    

smallest = 50    

Now the statement: red=red-smallest; becomes:    

red = 130 - 50    

red = 80    

the statement: green=green-smallest;  becomes:    

green = 50 - 50    

green = 0    

the statement: blue=blue-smallest; becomes:    

blue = 130 - 50    

blue = 80    

So the output of the entire program is:    

red after removing gray part: 80                                                                                                 green after removing gray part: 0                                                                                                blue after removing gray part: 80    

The screenshot of the program along with its output is attached.

Answer:

The answer to this question is given below in the explanation section.

Explanation:

The solution to this question is given in the attached word file.  

Answer:

Open your python console and execute the following .py code

Explanation:

Code bellow:

#include <iostream>

#include <iomanip>

#include <string>

using namespace std;

void inputInfo(string*, int*, int);

double mathAvr(int*, int);

void printInfo(string*, int*, int, double);

int main()

{

   double avg;  

   int n;  

   string *names;  

   int *scores;  

   char ch;

   do

   {

       cout << "\n contestants quantity: ";

       cin >> n;

       names = new string[n];

       scores = new int[n];

       inputInfo(names, scores, n);

       avg = mathAvr(scores, n);

       printInfo(names, scores, n, avg);

       delete [] names;

       delete [] scores;

       cout << "\n again? (Y/N): ";

       cin >> ch;

   }while(ch=='Y' || ch=='y');

   cout << "\n\n";

   return 0;

}

void inputInfo(string *names, int *scores, int n)

{

   int i;

   for(i=0; i<n; i++)

   {

       cout << "\n\n Name of the participant: ";

       cin >> *(names+i);

       do

       {

           cout << "\n score " << *(names+i) << " (0-100): ";

           cin >> *(scores+i);

       }while(*(scores+i) < 0 || *(scores+i) > 100);

   }

}

double mathAvr(int *scores, int n)

{

   int i, sum=0;

   double avg;

   for(i=0; i<n; i++)

   {

       sum += *(scores+i);

   }

   avg = sum / (double)n;

   return avg;

}

void printInfo(string *names, int *scores, int n, double avg)

{

   int i;

   cout << "\n\n " << left << setw(20) << "Participant name" << left << setw(6) << "Score" << " \n";

   for(i=0; i<n; i++)

   {

       cout << "\n " << left << setw(20) << *(names+i) << left << setw(6) << *(scores+i);

   }

   cout << fixed << setprecision(2);

   cout << "\n\n Average: " << avg << " \n\n";

}