The properties of waves are: wavelength, time period.
Sound wave is considered a mechanical wave because it requires medium to travel.
What is mechanical wave?A mechanical wave is one whose energy cannot be transmitted via a vacuum. To transfer their energy from one place to another, mechanical waves need a medium.
A mechanical wave is something like a sound wave. A vacuum can not be traversed by sound waves.
Units of time and space can be used to measure the fundamental characteristics of waves. The length between wave crests, or wavelength (L), and the time it takes a wave to pass a fixed point, or period (T), are two characteristics that can be measured directly.
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39) Three different dynamic carts of different masses are rolled down a ramp. The heaviest one rolls down the ramp the fastest. Before concluding that a more massive cart will roll down a ramp faster, what experiment with these three carts might you want to do
According to the given information the answer is Add masses to each car until they have the same mass, then test the carts again.
What is dynamic carts?Features three low friction ball bearing wheels and matched axles to assure their rolling along a true line without deviation to produce accurate data, and a sturdy steel body to endure rigorous handling. Each cart is around 1.5 kg in weight. The ends of the cart lift above the bed to transport a brick or any other bulk, and the cart bed is covered with a rubber pad. At one end of the cart, there is a clip where a tape can be fastened. Each cart's pins fit into the holes in the others, allowing the mass to be doubled by stacking them.
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The complete question is-
Three different dynamic carts of different masses are rolled down a ramp. The heaviest one rolls down the ramp the fastest. Before concluding that a more massive cart will roll down a ramp faster, what experiment with these three carts might you want to do?
Run an experiment with the ramp at a different angleFind a fourth cart to add to the test, then test againChange the surface of the ramp, then test the carts againAdd masses to each car until they have the same mass, then test the carts againA 3.70 -uF capacitor that is initially uncharged is connected in series with a 6.20 -kohms resistor and an emf source with E=130V negligible internal resistance.
A) Just after the circuit is completed, what is the voltage drop across the capacitor?
B) Just after the circuit is completed, what is the voltage drop across the resistor?
C) Just after the circuit is completed, what is the charge on the capacitor?
D) Just after the circuit is completed, what is the current through the resistor?
E) A long time after the circuit is completed (after many time constants) what is the voltage drop across the capacitor?
F) A long time after the circuit is completed (after many time constants) what is the voltage drop across the resistor?
G) A long time after the circuit is completed (after many time constants) what is the charge on the capacitor?
H) A long time after the circuit is completed (after many time constants) what is the current through the resistor?
A long time after the circuit is completed (after many time constants), the voltage drop across the capacitor is 104.8V, the voltage drop across the resistor is 25.2V, the charge on the capacitor is -7.5μC, and the current through the resistor is 1.6mA.
A) Just after the circuit is completed, the voltage drop across the capacitor is 0V.
B) Just after the circuit is completed, the voltage drop across the resistor is 130V.
C) Just after the circuit is completed, the charge on the capacitor is 0C.
D) Just after the circuit is completed, the current through the resistor is 20.8mA.
E) A long time after the circuit is completed (after many time constants), the voltage drop across the capacitor is 104.8V.
F) A long time after the circuit is completed (after many time constants), the voltage drop across the resistor is 25.2V.
G) A long time after the circuit is completed (after many time constants), the charge on the capacitor is -7.5μC.
H) A long time after the circuit is completed (after many time constants), the current through the resistor is 1.6mA
Just after the circuit is completed, the voltage drop across the capacitor is 0V, the voltage drop across the resistor is 130V, the charge on the capacitor is 0C, and the current through the resistor is 20.8mA. A long time after the circuit is completed (after many time constants), the voltage drop across the capacitor is 104.8V, the voltage drop across the resistor is 25.2V, the charge on the capacitor is -7.5μC, and the current through the resistor is 1.6mA.
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Please help! 50 points.
A student conducts an experiment to test how the temperature affects the amount of salt that can dissolve in water. In the experiment, she uses 150 milliliters of water in each trial and stirs for five minutes each time.
What is the dependent variable in this experiment?
the temperature of the water
the amount of water
the amount of salt
the time stirred
Answer:
i think its time stirred, double check. i hope it helped ;)
Explanation:
There is a bell on top of a tower that is 45 meters high. The bell has a mass of 20 kg. Calculate its potential energy.
Answer:
9000 Joules
Explanation:
Potential energy = mass x acceleration due to gravity x height
mass = 20kg
acceleration due to gravity = 10m/s2
height = 45 meters
20 x 10 x 45 = 9000 Joules
A 5-ft3 rigid tank contains 5 lbm of water at 20 psia. Determine (a) the temperature, (b) the total enthalpy, and (c) the mass of each phase of water
After that, we will calculate the temperature, total enthalpy, and masses of each water phase using the steam table.
What are temps and what is its unit?Given the water's initial mass and pressure, we can determine whether it is superheated or saturated by utilizing a steam table. On a variety of scales, including the Fahrenheit and Celsius systems, temperature is a unit that is used to denote hotness or coolness.
Heat energy will logically go from a hotter (body with a higher temperature) to a colder (body with a lower temperature) according to temperature (one at a lower temperature).
A comparison of a substance's temperature to a set of hot and cold reference values can be used to determine its temperature. The letter "T" stands for "temperature," which is denoted by the SI unit of "°C."
The three scales that are most frequently used to measure temperature are the Celsius scale, the Fahrenheit scale, and the Kelvin scale.
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When charging by induction using grounding, if a negative rod is used, the object will acquire a ______ charge
When a positively charged rod becomes grounded it becomes neutral. The electrons come from the ground to your hand, then from your hand to the rod making the rod become neutral.
What is happening when a negatively charged rod becomes grounded?Both of the charged objects receive the same kind of charge when charging through conduction. Both things acquire a negative charge when a negative object is used to charge a neutral object.
The neutral sphere needs electrons from the negatively charged rod in order to become negative. 3. To demonstrate how charging by contact works, we'll first look at the scenario of charging a neutral needle electroscope with a negatively charged metal spherical.
Understanding the process necessitates an understanding of how like charges resist one another and have a strong desire to spread out as widely as possible in order to lessen their repulsions. The extra electrons in a negatively charged metal sphere repel one another and move as far apart from one another as possible.
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When charging by induction using grounding, if a negative rod is used, the object will acquire a positive charge.
What is charging by induction?A charging technique called induction charging involves charging a thing without actually contacting it to another charged object. The charged particle is held close to an uncharged substance which is conductive also, that is grounded on a neutrally charged material during the charging by induction process.This method of charging involves using a charged object to help a neutral object become charged without actually touching the objects. The neutral or uncharged conductor, which is grounded on a neutrally charged substance, is brought closer to the charged particle. If a charge is transferred between two objects, an oppositely polarized charge will emerge in the uncharged conducting material.
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Dina is observing a sample of copper metal after it was removed from a flame. She noticed that the temperature decreased. What conclusions could she draw from this observation?
a-The average kinetic energy decreased.
b-The average kinetic energy remained the same.
c-The motion of the particles increased.
d-The motion of the particles stayed the same.
Answer:
A. The average kinetic energy decreased.
Explanation:
When an object gains heat, which is a form of energy, the atoms within the object would in turn gain energy in the form of kinetic energy. Similarly, as the temperature of an object decreases, in other words losing heat energy, the atoms within the object would lose kinetic energy as a result.
A weight of 10 N hangs motionless from a spring. The spring is stretched 0.286 m from its original length. What is the force constant for the spring?
a-2.8 N/m
b-22 N/m
c-35 N/m
d-43 N/m
Answer:
C. -35N/m
Explanation:
Using Hooke's Law, we know that the elastic constant of a spring can be found with this formula:
[tex]F=-kx[/tex]
where:
[tex]F[/tex] is the force ( in Newtons)
[tex]k[/tex] is the constant ( in Newtons per meter)
[tex]x[/tex] is the extension ( in meters)
thus, by rearranging the formula we can get:
[tex]k=-\frac{F}{x}[/tex]
[tex]k = -\frac{10}{0.286}[/tex]
[tex]k=-34.96503N/m[/tex]
Rounding off the answer, we get -35N/m
Assuming the acceleration is still -9.81 m/s2, what is the instantaneous velocity of the shuttlecock when it hits the ground
The acceleration is still -9.81 m/s2, and the instantaneous velocity of the shuttlecock when it hits the ground is [tex]V_{int}[/tex] = [tex]\sqrt{U^{2} + 19.6H }[/tex]
Acceleration is determined as the rate of change of velocity of an object with respect to time. Acceleration is represented by the SI unit is meter per second squared (m/[tex]s^{2}[/tex]). Acceleration is denoted by "a".
Instantaneous velocity is the rate of change of position for a time interval which is almost zero (very small). The magnitude of the instantaneous velocity is instantaneous speed. It is measured by using SI unit m/s.
Mathematically, the equation for acceleration is:
a = [tex]v\frac{dv}{dt}[/tex]
ah = [tex]v^{2}[/tex] - [tex]u^{2}[/tex]
Where the acceleration is still -9.81 m/s2
Hence, [tex]v^{2}[/tex] - [tex]u^{2}[/tex] = 2 (-9.81) * -H
Therefore, [tex]v_{int}[/tex] = [tex]\sqrt{U^{2} + 19.6H }[/tex]
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How does the flux of light from an isotropic source depend on the distance r from the source?
A. r 2
B. r -2
C. r -1
D. r 1
E. r 1/2
F. none of the above
The flux of light from an isotropic source depend on the distance r from the source by r-2.
What is isotropic source?
An isotropic source is a source of radiation or sound that emits energy in all directions equally. This type of source is usually assumed to have uniform power density in all directions, making it a simplifying assumption when analyzing a system. Examples include a point source in free space, such as a light bulb, or a sound source in a room.
The flux of light from an isotropic source (a source that radiates uniformly in all directions) decreases as the inverse square of the distance from the source. This means that the flux of light from the source decreases according to the equation F = 1/r2, where F is the flux of light, and r is the distance from the source. Therefore, the flux of light from an isotropic source decreases with the distance r from the source according to the equation F = r-2.
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The work W required to lift an object varies jointly with the object's mass m and the height h that the object is lifted. The work required to lift a 120-kilogram object 1.8 meters is 2116.8 joules. Find the amount of work required to lift a 150-kilogram object 1.6 meters.
The work W required to lift an object varies jointly with the object's mass m and the height h that the object is lifted. The work required to lift a 120-kilogram object 1.8 meters is 2116.8 joules is 1,372J.
What does physics mean by a work done?
In physics, the term "work" refers to the measurement of energy transfer that takes place when an item is moved over a distance by an external force, at least a portion of which is applied in the direction of the displacement.
Work done can be computed using the formula:
[tex]w=Fd[/tex]
Where:
W = work (J)
F = Force (N)
d = Distance (d)
Looking at the given, you know that you do not have a value for force, so you will have to solve for it.
[tex]F=Ma[/tex]
Where:
F = Force
m = mass
a = acceleration
Because the object is being lifted, the acceleration will rely on gravity. Acceleration due to gravity is a constant 9.8 m/s^2. Let's list our given first:
F = ?
m = 100kg
a = 9.8m/s^2
Put that into our equation and solve:
[tex]F=mA\\F=100*9.8\\F=980Kg.m/s^{2}[/tex]
Our force is then 980 N.
Now that we have force we can solve for Work. The given for work is as follows:
F= 980N
d = 1.4mPut that into our formula and solve:
[tex]W=Fd[/tex]
[tex]W=(980)*(1.4)\\W=1372[/tex]
The work done is 1,372J.
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A myopic person sees that her eyeglasses perscription is -4.00 D, for eyeglasses positioned 1.75 cm from her eyes. What is her far point?
After solving the problem the person's far point is 25 cm
What is myopic person?
A myopic person is someone who is near sighted and is unable to clearly see objects that are far away. This is caused by the eyeball being too long and the cornea having too much curvature. Light entering the eye is focused in front of the retina rather than directly on it, resulting in blurred vision for distant objects. Myopia is a common eye condition and can usually be corrected with glasses or contact lenses. In more severe cases, laser surgery may be necessary. People with myopia may need to wear their glasses or contact lenses all the time in order to see clearly, but they may be able to take them off when they are close to something they want to see clearly.
The far point is the farthest distance at which a person can see clearly without any corrective lenses.
The formula for calculating far point is 1/f = 1/d + 1/p, where f is the far point, d is the distance from the eye to the lens (1.75 cm in this case), and p is the power of the lens (in diopters) which is -4.00 D.
Plugging the values into the formula yields 1/f = 1/1.75 + 1/-4.00, which simplifies to 1/f = 4.00 - 0.5714. Solving for f gives f = 0.2500, or 25 cm.
Therefore, the person's far point is 25 cm.
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A bicyclist maintains a constant velocity of
4. 0 m/s for a distance of 480 m. How long does it take the bicyclist to travel this distance?
A8s
B 120s C 476s D 1920s
The bicyclist will need to ride for a total time of 120 seconds in order to cover 480 meters of distance at a constant velocity of 4.0 meters per second.
In this scenario, we are provided with:
The distance of the ride is 480 meters.
The velocity is four meters per second
In order to calculate the time, we can use the following formula:
Time = Distance : Velocity
= 480 meters : 4.0 meters per second
= 120 seconds
Therefore, the amount of time a cyclist needs to travel would be 120 seconds.
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01) When operating a simple machine an effort of 60N is used to lift the load of 240 N. Find the mechanical advantage.
02) When operating the same machine the effort arm moves 4m while load moves 1m. Find velocity ratio
03) In the same machine find work input.
04) In the same machine find work output.
05) Find the efficiency of this simple machine.
Useless answers will be reported!
Answer:
1 MA= load/effort
MA= 240/60
MA=4
2.VR=Distance moved by effort/ Distance moved by Load
VR=4/1
= 4
5. Efficiency= MA/VR
4/4*100/1
=100%
The sum of kinetic energy and potential energy
of the particles in a material is blank
The sum of kinetic energy and potential energy of the particles in a material is known as mechanical energy.
What is Kinetic energy?The energy that an object has as a result of motion is known as kinetic energy. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes.
What is potential energy?Due to its position, an object has the ability to store energy. For instance, when a demolition machine's heavy ball is held in an elevated position, it is storing energy. Potential energy is the name for this positional energy that has been stored. Similar to how a drawn bow can store energy due to its posture, There is no energy in the bow while it is in its normal position, or when not drawn. The bow can yet store energy when its position is changed from its normal equilibrium position because of its position. Potential energy is the name for this positional energy that has been stored. Potential energy is the energy of position that a thing has stored inside it.
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What does an increases in concentration do to a material?
Answer:
it will increase the frequency of collisions between the two reactants
Explanation:
mark brainliest?
Is there any difference between antimatter, dark matter, dark energy, and degenerate matter?
Yes. Antimatter, dark matter, dark energy, and degenerate matter are all distinct entities that actually exist in our universe, despite their names sounding hazy and almost fictitious.
Is there a distinction between dark energy and dark matter?Dark energy and dark matter are not the same, despite the name. The only difference is that both are invisible. Galaxies are pushed apart by dark energy, while dark matter holds them together.
Which of the three kinds of dark matter exists?Candidates for dark matter can be either baryonic or non-baryonic, or a combination of the two. Most of the time, the non-baryonic forms fall into two categories: Hot Dark Matter (HDM) and Cold Dark Matter (CDM).
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Write a complete scientific explanation to account for why the heavier ball caused more flour to spread out
When a ball moves with faster velocity, then a greater impulse force is Imparted that causes more flour to spread out.
The momentum of a system remains constant unless the system is acted on by an external force in which case the acceleration of center of mass satisfies. The force on a system of particles is the external force because the internal force is zero.
The external force is equal to the change in momentum of the system and is proportional to the acceleration of the center of mass. For a fixed choice of system, if there are no external forces acting on the system then the momentum of the system is constant is constant.
The external force may be zero in one direction but not others. The component of the system momentum is constant in the direction that the external force is zero. The component of system momentum is not constant in a direction in which external force is not zero.
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A worker uses a pulley (Links to an external site.) system to raise a 225 N carton 16.5 m. A force of 129 N is exerted and the rope is pulled 33.0 m. What is the IMA of the system
Answer: 1.74
Explanation: “How do you calculate the mechanical advantage of a block and tackle pulley?To calculate the mechanical advantage, we can either divide the weight of the object being lifted by the force required to lift it or we can divide the amount of rope we have to pull by the distance the object moves."If we use the rope method the mech advantage is 33.0/16.5 = 2 now if we use the forces MA = 225/129 =1.74 <==== this is not equal to '2' as we first found due to energy being lost to friction/deformation of rope etc. SO I would say the truemechanical advantage = 1.74 Efficiency = 1.74/2 = 87%
A Shuttle astronaut is sent to repair a defective relay in a 600. 00- kg satellite that is traveling in space at 17 00. 0 m/s * a * w * a * y Suppose the astronaut and his Manned Maneuvering Unit ( MMU) have a mass of 400. 00 kg and travel at 17 010. 0 m/s toward the satelliteWhat is the combined velocity when the astronaut grabs hold of the satellite?
A Shuttle astronaut is sent to repair a defective relay in a 600. 00- kg satellite that is traveling in space. The combined velocity when the astronaut grabs hold of the satellite is 17,004.4 m/s.
The combined velocity of the astronaut and the satellite when the astronaut grabs hold of the satellite is the relative velocity between the two objects. The relative velocity can be calculated using the principle of conservation of momentum. The principle states that the total momentum of an isolated system remains constant if no external forces act on it.
The initial momentum of the satellite is
= (600.00 kg) * (17,000.0 m/s)
= 10,200,000 kg*m/s
The initial momentum of the astronaut and the MMU is
= (400.00 kg) * (17,010.0 m/s)
= 6,804,400 kg*m/s
The final momentum of the combined system is
= (600.00 kg + 400.00 kg) * v,
where v is the final velocity of the combined system.
The conservation of momentum equation:
=> initial momentum = final momentum
= 10,200,000 kgm/s + 6,804,400 kgm/s
= (1000 kg) * v
= v
= (10,200,000 + 6,804,400) / 1000
= v
= 17,004.4 m/s
So, the combined velocity of the astronaut and the satellite when the astronaut grabs hold of the satellite is 17,004.4 m/s.
It's important to note that the relative velocity is the same in both directions, this is a vector quantity and direction is important.
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If 230 g of water is heated from 24°C to 100°C, how much energy would have been consumed?
Answer:
i believe it would be 64 kJ
Explanation:
What linear speed must an Earth satellite have to be in a circular orbit at an altitude of 204 km above Earth's surface
According to the question linear speed must an Earth satellite have to be in a circular orbit at an altitude of 204 km above Earth's surface is 30.682× [tex]10^{10}[/tex].
What does orbit mean?Astronomically speaking, an orbit is the curved path—typically elliptical—that a planet, satellite, comet, etc. takes when it revolves around another celestial body as a result of gravitation.
By Newton's second law
GMm/[tex]r^{2}[/tex] m[tex]v^{2}[/tex] /r.
Since the radius of Earth is 6.37 × [tex]10^{6}[/tex] m,
the orbit radius is r=(6.37×[tex]10^{6}[/tex] m+204×[tex]10^{3}[/tex] m)=1.3×[tex]10^{3}[/tex] m.
The solution for v is
v= [tex]\sqrt{\frac{GM}{r} }[/tex] = (6.67×[tex]10^{-11}[/tex]× 5.98×[tex]10^{24}[/tex]/1.3×[tex]10^{3}[/tex])^1/2
⇒ v= 30.682× [tex]10^{10}[/tex]
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Can you help me please for exercise 2.
In the film Alone on Mars, Mark Watney faints in the rocket responsible for bringing him back to the ship
major. His colleague comments: “He has just taken 13 g, give him two minutes”. Before
going on an expedition, astronauts are prepared to undergo strong accelerations, commonly
quantified in g. On Earth, when a rocket "goes up to 1 g", it means that its speed increases by 10
meters per second, in one second.
The positions successively occupied by Mark have been represented. The duration separating
each position is equal to 0.50 seconds.
+M.
1) Calculate the values of the speeds vo
and go.
2) Prove that the variation of the
speed between times t. and t4 is:
AV = VA - VO = 260 m.s-1
3) What is the time interval At
separating position to and tA?
4) The acceleration 'a' is given by the
formula a = :
If, calculate the acceleration of
Mark between the M. and MA positions
Compare this acceleration with the
g-value. The sentence "He has just
take 13 g»>, it seems to you
correct?
Exercise 3: movement of the Moon (5
pt)
The Moon, the only natural satellite of the
Earth, is in orbit around it
for billions of years. Four
times smaller than the Earth, it puts.
The velocity, time and acceleration motion of Mark Watney rocket as he moves from M₀ to M₄ is described as follows;
1) v₀ = initial velocity = u
v₄ = u + 260 m/s
2) Δv = u + 260 m/s - u = 260 m/s
3) Δt = 2 seconds
4) Mark's acceleration is 13·g
What is motion under acceleration?Acceleration is the rate of change of velocity. Motion under a constant acceleration is one in which the velocity of the object changes as time changes.
The scale of the graph is 5 units = 46 meters
The distance between M₀ and M₄ = 25.5 units
1 unit = 46/5 meters/unit
25.5 units = (46/5) m/unit × 25.5 units = 234.6 meters
The time between M₀ and M₄ = 0.5 s × 4 = 2 s
= 25.5 unit × 0.5 s/unit = 12.75 s
The speed at M₄, v₄ =
The location of M₀ = 0
The location of M₄ =
The values of the speeds are;
The distance be
1) The time at M₀, t₀ = 0
The time at t₄ = 2 s
The speed, v = u + a·t
Where;
u = The initial velocity of the rocket
a = The acceleration = 13·g = 13 × 10 m/s² = 130 m/s²
The speed at v₀ = u + 130 m/s² × 0 s = u
The speed at v₄ = u + 130 m/s² × 2 s = 260 m/s2) The variation of the speed between v₄ and v₀, Δv, is found as follows;
Δv = v₄ - v₀
Therefore;
Δv = 260 m/s - 0 m/s = 260 m/s3) The number of change in position from M₀ to M₄ is found as follows;
M₀ to M₁M₁ to M₂M₂ to M₃M₃ to M₄The number of 0.5 seconds between M₀ and M₄ = 4
The time difference between t₀ and t₄ is therefore;
Δt = t₄ - t₀ = 2 seconds4) The formula for the acceleration is; [tex]a = \dfrac{\Delta v}{\Delta t}[/tex]
Therefore, the acceleration between positions M₀ and M₄ is found as follows;
The speed at M₀ = u
Speed at M₄ = u + 260 m/s
t₄ - t₀ = 2 seconds
[tex]a = \dfrac{u+260 \, m/s - u}{2\, s} = 130\, m/s^2[/tex]
The value of the acceleration due to gravity, g ≈ 10 m/s²
Therefore, a = 13·g
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What is the equation for torque used for lever arm and F for force?
The required equation for torque used for lever arm r and F for force is given as τ = |r| |F| sinθ.
A simple way to calculate the magnitude of the torque is to first determine the lever arm and then multiply by the times of applied force.
The lever arm is described as the perpendicular distance from axis of rotation to the line of action of force.
The equation used to calculate torque is , τ = r × F = |r| |F| sinθ
where,
r is the magnitude of lever arm
F is the magnitude of force vector
θ is the angle between lever arm and force vectors
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In the above situation, what is the net torque on wire 2 due to wire 1?
a. Up b. Down
c. Into the screen d. Out of the screen e. Zero
In the above situation the net torque on wire 2 due to wire 1 is Zero.
Which way is the force acting on the wire?Fleming's left-hand rule identifies the force's direction on a current-carrying wire when it is placed in a magnetic field. It always runs counter to how the magnetic field and electric current are moving.
Directional torque: what is it?Torque is a vector quantity by definition. The direction is determined as part of the torque computation. The direction is parallel to both the force and the radius from the axis. It is customary to choose it along the rotational axis in the right-hand rule direction.
When rotating clockwise, is torque negative?a force that is applied that results in a positive counterclockwise torque A negative torque rotates an object in a clockwise direction.
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CAN SOMEONE PLEASE ANSWER THESE 4 QUESTIONS I WILL NEED IT IN A FEW HOURS , YOU WILL GET BRAINLIEST!!
1.) Compare reflection and refraction. How are they similar and how are they different?
2.) In your own words, describe how ray diagrams can be used to describe if light rays are being reflected or refracted.
3.) What is the formula for the Law of Reflection? Define the variables and explain what it tells us about the motion of light.
4.) What is the formula for Snell's? Define the variables and explain what it tells us about the motion of light.
Answer:
1.)Reflection is the act of light reflecting back when it hits a medium on a plane. Refraction is the process by which light shifts its path as it travels through a material, causing the light to bend. Thus, this is the key difference between reflection and refraction. This phenomenon usually occurs in mirrors.
2.)ray diagrams are a visual representation of the propagation of light. They can help us to understand and visualise multiple situations, such as light being reflected off of a mirror or changing its direction while moving through a lens.
3.)Reflection: The process of sending back the light rays which fall on polished surface is called reflection of light.
Laws of reflection:
(i) The angle of reflection is always equal to the angle of incidence.
(ii) The incident rays, reflected rays and the normal, all lie in the same plane.
4.)Snell’s law formula is expressed as: μ= sin i/sin r
, where i is the angle of refraction, r is the angle of refraction and μ is known as the refractive index of the second medium with respect to the first medium.
Severity and determinants of stunting in children under age 2 years in Odisha (India): A tribal v/s non-tribal analysis
In the past eight years, there has been a 3% annual drop in the prevalence of stunting among Indian tribal children under the age of five.
To determine the predictors of stunting and severe stunting among tribal children, as well as to suggest potential policy and program implications, cross-sectional data from 1000 children (287 tribal and 713 non-tribal) aged 0-23 months from Odisha's Rapid Survey of Children (RSOC, 2014) were analyzed. The findings indicate that birth order and maternal illiteracy are significant predictors of childhood stunting, and that maternal age at marriage and at birth was less than 18 years old and less than 20 years old, respectively, for severe stunting. Basic factors such as poverty and maternal ages of 20 years at the time of the first birth and 18 years at marriage were found to predict severe stunting in tribal children.
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A 1070-kg car starts from rest at the bottom of a drive way and has a speed of 3.00 m/s at a point where the drive way has risen a vertical height of 0.600 m. Friction and the drive force produced by the engine are the only two nonconservative forces present. Friction does -2870 J of work. How much work does the engine do
In the question the only nonconservative forces in play are friction and the engine's motive force. Work done by friction is -2870 J. The work done by the engine is 1285 J.
The work done by an engine can be determined by the change in kinetic energy of the car. The work-energy principle states that the net work done on an object is equal to its change in kinetic energy. The initial kinetic energy of the car is 0 J (at rest) and the final kinetic energy of the car is 1/2mv^2, where m is the mass of the car and v is its final speed. The work done by the engine is equal to the change in kinetic energy of the car, which is the final kinetic energy minus the initial kinetic energy.Work_engine = change in kinetic energy = (1/2)mv^2 - 0
Work_engine = (1/2)(1070)(3)^2 = 4155 J. The work done by friction is -2870 J, which is negative because it is opposing the motion of the car. The net work done by nonconservative forces is the sum of the work done by the engine and the work done by friction. Net work = Work_engine + Work_friction = 4155 J + (-2870 J) = 1285 J. Therefore, the work done by the engine is 1285 J.
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writing connection science Alfred Wegener never convinced the scientific community that continents move on earths surface. Imagine you could send a message to the past. Explain to Wegener in a letter the evidence that he was missing and the theory of plate tectonics.
The letter explaining to Wegener the evidence that he was missing and the theory of plate tectonics is written below:
Letter on the theory of plate tectonicsDear Alfred Wegener,
I am writing to you from the future to tell you that your theory of continental drift has been proven to be true. However, I understand that during your lifetime, you were not able to convince the scientific community of the validity of your ideas. I want to share with you some of the evidence that was discovered after your time that helped to solidify the theory of plate tectonics.
Firstly, the discovery of the mid-Atlantic Ridge in the 1920s provided evidence for the existence of a divergent boundary. This underwater mountain range, which runs down the center of the Atlantic Ocean, is evidence of the separation of the North American and Eurasian plates. Another key piece of evidence is the matching of rock formations and fossil records on opposite sides of the ocean.
Furthermore, the study of earthquakes and volcanoes also helped to support the theory of plate tectonics. The locations of earthquakes and volcanoes corresponded with plate boundaries, and the movement of these plates could explain their occurrence.
In conclusion, I hope this letter has helped to provide you with some of the evidence that was missing during your lifetime and helped to solidify the theory of plate tectonics. Your contributions to the field of geology were crucial in helping scientists to understand the movement of the Earth's crust.
Yours Sincerely,
John Philips
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The upper and lower fixed points of a mercury thermometer corresponds to 9.00mV and 16.50mV on the thermocouple thermometer. The temperature of a warm iron giving a reading of 11.21mV to the nearest whole number is.
To find the temperature of the warm iron, we first need to convert the reading on the thermocouple thermometer to a temperature value. To do this, we will use the formula:
Temperature = (Reading - Lower Fixed Point) / (Upper Fixed Point - Lower Fixed Point) * (Upper Temperature - Lower Temperature) + Lower Temperature
In this case, the lower fixed point is 9.00mV and the upper fixed point is 16.50mV. We also know that the lower temperature is 0°C (the freezing point of water) and the upper temperature is 100°C (the boiling point of water). So, we can plug in these values:
Temperature = (11.21mV - 9.00mV) / (16.50mV - 9.00mV) * (100°C - 0°C) + 0°C
Simplifying, we get:
Temperature = (2.21mV / 7.50mV) * 100°C
And further simplifying, we get:
Temperature = 0.2907 x 100°C
So, the temperature of the warm iron is approximately 29.07°C to the nearest whole number.
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