Determine if the triangles can be proved congruent by SSS, SAS, ASA, AAS, or HL.
SSS

The value of x, given the angles next to the triangle, can be found to be 38 °

To find the value of x, you first need to find the value of the other angles in the triangle.

Angles on a horizontal line add up to 180 degrees so the angle to the bottom left is:

= 180 - 134

= 46 °

The angle to the bottom right is:

= 180 - 84

= 96 °

The angles in a triangle add up to 180 ° so the value of x would be:

= 180 - 46 - 96

= 38 °

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On solving the provided question, we can say that by permutation If an ID card has six digits and each digit may only be used once, then 151,200 distinct ID cards can be created.

The permutation of a set in mathematics is essentially the rearranging of its elements if the set is already ordered, or the arrangement of its members in a linear or sequential order. The act of altering the linear order of an ordered set is referred to as a "permutation" in this context. The mathematical calculation of the number of possible arrangements for a given set is known as permutation. Permutation, in its simplest form, refers to the variety of possible arrangements or orders. The placement of the elements matters with permutations. The placement of items in a specific order is known as a permutation. Here, the set's components are sorted in either chronological order or linear order. like in the case of.

There are 6 digits on a card ( 0 - 9 ).

10 * 9 * 8 * 7 * 6 * 5 = 151,200

If an ID card has six digits and each digit may only be used once, then 151,200 distinct ID cards can be created.

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The longest tornado ever recorded spanned 219 miles of land as it swept through many states at a pace of 60 miles per hour.

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By using scale factor formula we can evaluate the measure of side EF.

When a triangle is dilated by scale factors.The base and height change by the scale factor s while the area changes by a factor of s^2. While the scale distances between points dilations do not change angles.Dilation is used to make the objects larger or smaller.

The scale factor can be calculated when the new dimensions and the original dimensions are given. The basic formula to find the scale factor of a figure is Scale factor = Dimension of the new shape ÷ Dimension of the original shape.

From the question ΔE'F'G' is the image formed by the dilation of preimage ΔEFG.

Therefore,

2/3  =[tex]E_{1}[/tex][tex]F_{1}[/tex]/EF

EF=3/2[tex]E_{1}[/tex][tex]F_{1}[/tex]

By substituting any value of F'G' given in the equation we can evaluate the measure of side FG.

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To solve complex fractions there are two methods -

1 - Divide the numerator by the denominator by multiplying the numerator by the reciprocal of the denominator and then simplify further if necessary.

2 - Multiply the numerator and denominator of the overall complex fractions and then simplify further if necessary.

What is a complex fraction?

A rational expression with a fraction in the numerator, denominator, or both is referred to as a complex fraction.

There are two ways to solve a complex fraction -

Method 1 : Take an example - (1/3-1/4)/(1/8+1/2)

Step 1 - If necessary, combine the denominator and numerator into a single fraction.

Add the numerator -

=1/3-1/4

=(4-3)/12

=1/12

Add the denominator -

=1/8+1/2

=(1+4)/8

=5/8

Combine back to form a complex fraction -

=(1/12)/(5/8)

Step 2: Multiply the numerator by the denominator's reciprocal, then divide the result by the denominator.

Step 3: Simplify the rational expression if necessary.

=(1/12)×(8/5)

=8/60

=2/15

Method 2: Take an example - [(2x+1)/(x^2-25)]/[(4x^2-1)/(x-5)]

Step 1 - Divide the LCD of the smaller fractions by the numerator and denominator of the total complex fractions.

(x^2-25)=(x+5)(x-5)

The denominator of the denominator’s fraction  has the following factor -

(x-5)

Using the highest exponent and combining all the other factors, we arrive at the LCD shown below for all the little fractions -

(x+5)(x-5)

By multiplying the LCD by the numerator and denominator -

=[{(2x+1)/(x+5)(x-5)}×(x+5)(x-5)]/[{(2x+1)(2x-1)/(x-5)}×(x+5)(x-5)]

=(2x+1)/(2x+1)(2x-1)(x+5)

Step 2 - Simplify the rational expression if necessary.

=(2x+1)/(2x+1)(2x-1)(x+5)

=1/(2x-1)(x+5)

Therefore, there are two methods to solve complex fractions.

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Answer:

31.25

Step-by-step explanation:

25% * 125 = 25/100 * 125 = 1/4 * 125 = 31.25

When you and your 3 friends decide to split the bill of $36 evenly and you leaving a 12% tip on your part, you pay a total of $13.32.

Therefore the answer is 13.32 dollars.

When you and your 3 friends decide to split the bill evenly, each person is responsible for paying 1/4 of the total bill. The total bill is $36, so each person is responsible for paying

$36 / 4 = $9

You also decided to leave a 12% tip on your part, so you need to calculate 12% of $36. To do this, you can multiply $9 by 0.12

$36 × 0.12 = $4.32  

So, you are responsible for paying $9 + $4.32 = $13.32

So you are responsible for paying $13.32 in total.

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The dimensions of the wood that remains after Tierra finishes making the 21 steps is 1.185 cm by 21.6 cm

In Mathematics, dimensions are referred to as measures of size such as length, width, and height of an object or a shape.

A square has sides of equal dimensions.

A rectangle has length and width as its dimensions that define the area of a rectangle.

Also, dimension is used widely to term the figure as one-dimensional, two-dimensional or three-dimensional.

Wood = 1.5 cm by 30 cm

Each cut = .15 mm by 4 mm

Steps = 21

The remaining dimension is calculated as:

Remaining = 1.5 cm - 21 * .15 mm by 30 cm - 21 * 4 mm

Express mm as cm

Remaining = 1.5 cm - 21 * .015 cm by 30 cm - 21 * 0.4 cm

Evaluate the difference

Remaining = 1.185 cm by 21.6 cm

Hence, the dimensions of the wood that remains after Tierra finishes making the 21 steps is 1.185 cm by 21.6 cm

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The score of Larry is 32 points.

Two algebraic expressions having same value and symbol '=' in between are called as an equation.

Given:

Ervin scores half as many points in a game as Larry.

If Larry scored x points,

then the points of Ervin are x/2 points.

Here, x = 16,

So,

Ervin's points = Larry's points

The equation is,

16 = x/2

x = 16(2)

x = 32 points

Therefore, 32 points are the score of Larry.

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The domain and range of the functions are Domain: (-∞,∞),{x|x∈R} and Range: [4,∞),{y|y≥4}.

The vertex form of a quadratic function is f(x) = a(x - h)² + k, where (h, k) is the vertex of the parabola. The coefficient a determines whether the graph of a quadratic function will open upwards or downwards.

From the graph, vertex is (h, k)=(0, 4) and (x, y)=(2, 0)

Here, y= a(x - h)² + k

0=a(2-0)+4

-4=2a

a=2

Substitute, a=2 and (h, k)=(0, 4) in y= a(x - h)² + k, we get

y=2(x-0)²+4

y=2x²+4

So, f(x)=2x²+4

Find the domain by finding where the function is defined. The range is the set of values that correspond with the domain.

Domain: (-∞,∞),{x|x∈R}

Range: [4,∞),{y|y≥4}

Now,

(a) f(-3)= 2(-3)²+4=18

(b) f(2)= 2(2)²+4=12

(c) f(0)= 2(0)²+4=4

(d) f(3)= 2(3)²+4=18

Therefore, the domain and range of the functions are Domain: (-∞,∞),{x|x∈R} and Range: [4,∞),{y|y≥4}.

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Answer:

-18a^3b^5

Step-by-step explanation:

First do -ab^2*-6ab^2=-6a^2b^4

Then multiply that by 3ab=-18a^3b^5

Answer:

The like terms in this expression are 24a and -8a, and -12b and 12b.

Step-by-step explanation:

The like terms 24a and -8a can be combined by adding the coefficients and the variables, which gives us 24a - 8a = 16a.

The like terms -12b and 12b can be combined by adding the coefficients and the variables, which gives us -12b + 12b = 0.

So the like terms in this expression are 24a, -8a, and -12b, 12b.

The required,
1. figure 1, domain and range are (0, ∞) and {25000, 0}, the graph shows the exponential decay.
2.  figure 2, domain and range are (-∞, ∞) and {0, ∞}, the graph shows the exponential growth.

The function which is in format f(x) =aˣ  where, a is constant and x is variable,  the domain of this exponential function  lies   (-∞, ∞).

As mentioned in the question, the graph of two exponential functions are given, we have to determine the domain and range of both function and justify which graph shows the exponential growth and decay.

1.
A general exponential equation is given as,
y = aˣ
Graph 1, the graph shows the exponential decay because the value of the function is getting decreasing for the domain 0 to ∞. For this domain, the value of the function starts from point A which is at 25000 and ends at point B where y = 0, so the range is {25000, 0}.

Similarly,
Graph 2 shows exponential growth,
Domain and range are (-∞, ∞) and (0, ∞).

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The equivalent form   [tex][latex] {{8}^{\frac{1}{3}}}[/latex][/tex]can be determined where the origin of the numerator of 1.

When rewriting a radical with a fractional exponent, the numerator is the power to which the radicand is increased, and the denominator is the root or index.

The link between [tex][latex] \sqrt[n]{{{a}^{m}}}[/latex]and [latex] {{a}^{\frac{m}{n}}}[/latex][/tex]also applies to rational exponents with a numerator of 1. For instance, the radical [tex][latex] \sqrt[3]{8}[/latex][/tex]

can also be expressed as [tex][latex] \sqrt[3]{{{8}^{1}}}[/latex][/tex].

Since any number retains its value when raised to the first power, [/latex]. Now that you have the equivalent form of [tex][latex] {{8}^{\frac{1}{3}}}[/latex][/tex], you can determine where the origin of the numerator 1.

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Enlargements of the picture or reductions of the image are both types of dilations.

Resizing an item uses a transition called dilation. Dilation is used to enlarge or contract the items. The result of this transformation is a picture with the same shape as the original. However, there is a variation in the shape's size.

A dilation is a transformation that yields a different-sized picture with the same general shape as the original. Enlargements are dilations that result in a bigger picture. Reduction is the name for a dilatation that shrinks the picture. The initial figure is stretched or contracted by a dilatation.

The angles of the dilated picture relative to the pre-image stay constant, which is one of the primary characteristics of dilated images.

Even in the enlarged picture, parallel and perpendicular lines are still discernible.

A dilated image's side's midway matches the pre-exactly. image's

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On solving the provided question, we can say that stabilizing selection type of selection does this demonstrate is shown by frequency distribution.

In order to make the information easier to understand, frequencies are organized into frequency distributions, which are visual displays. The frequencies displayed in a frequency distribution can be absolute or relative, like ratios or percentages. Both a graph and a table of frequencies can be used to represent a frequency distribution. Both the exact number of observations and the proportion of observations falling within each range can be displayed in a frequency distribution. A relative frequency distribution is the name given to the distribution in the latter scenario. The frequency of an observation is the frequency with which it appears in the data. The frequency of the number 9 in the following list of numbers, for instance, is 5. (because it occurs 5 times). 1, 2, 3, 4, 6, 9, 9, 8, 5, 1, 1, 9,

stabilizing selection type of selection does this demonstrate is shown by frequency distribution.

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Complete question: The frequency distribution of birthweights in human infants is bell shaped with most birthweights in the middle of the range of birthweights. What type of selection does this exemplify?

The equation of line passes through the point (2, 3) will be;

⇒ y = 1/2x + 2

And, Graph of this equation of line is shown in figure.

The equation of line in point-slope form passing through the points

(x₁ , y₁) and (x₂, y₂) with slope m is defined as;

⇒ y - y₁ = m (x - x₁)

Where, m = (y₂ - y₁) / (x₂ - x₁)

Given that;

The point on the line are (2, 3).

And, The perpendicular line is,

⇒ y - 4 = - 2 (x + 3)

⇒ y -  4 = - 2x - 6

⇒ y = - 2x - 2

Now,

Since, The equation of line passes through the point (2, 3).

So, We need to find the slope of the line.

Since, The product of slope of the perpendicular line is - 1.

Hence, Slope of the given perpendicular line is,

⇒ y = - 2x - 2

m = dy/dx = - 2

m = - 2

So, The slope of line is,

⇒ m₂ = - 1/m

         = 1/2

Thus, The equation of line with slope 1/2 is,

⇒ y - 3 = 1/2 (x - 2)

⇒ y - 3 = 1/2 (x - 2)

⇒ y - 3 = 1/2x - 1

⇒ y = 1/2x - 1 + 3

⇒ y = 1/2x + 2

Therefore, The equation of line passes through the point (2, 3) will be;

⇒ y = 1/2x + 2

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The number of machine fed copies are 25 and the number of hand fed copies are 55. This is solved forming simultaneous equations.

What are simultaneous equations?

Two or more algebraic equations that share variables, such as x and y, are said to be simultaneous equations. Since the equations are solved simultaneously, they are known as simultaneous equations. These equations alone could have an infinite number of solutions.

Given cost per page of machine fed copies = $0.08

          cost per page of hand fed copies = $0.20

Let,

  number of machine fed copies = x

 number of hand fed copies = y

Given the total number of copies = 80

So we can write the equation as

  x + y = 80  ⇒   (1)

It is also given that the total cost of the movie script is $13

So we can the equation as

0.08x + 0.20y = 13 ⇒ (2)

Solving the simultaneous equations (1) and (2)

From (1),

x = 80 - y

Substituting the above in (2)

0.08(80 - y) + 0.20y = 13

0.12y = 6.6

y = 55

x = 80 - 55 = 25

Therefore the number of machine fed copies are 25 and the number of  hand fed copies are 55.

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You can ride in many places, so be sure to look for hazards that could cause injury or other risks while bicycling.

The number of miles you can cycle in a single day is unlimited. It depends on your level of fitness, your exercise regimen, and the distance you cycle. Starting out, 10 kilometres per day is OK.

If you're an experienced cyclist who can pedal 25–30 miles every day, 45 miles is a realistic limit.  You can ride a certain bike trail. By riding a bike to work, you can get in shape. If you've never rode a bike before, start out slowly. If you ride your bike for at least three miles every day, you might be able to travel further.

You may be able to make the most of your speed sensor’s accuracy, depending on how accurate it is. You need to know exactly how much effort you put in during your rides.

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According to the Angle-Angle-Angle (AAA) criterion, "if in two triangles, corresponding angles are equal, then their corresponding sides are in the same ratio (or proportion), and hence the two triangles are identical."

Proof:

Consider two triangles ABC and DEF, such that ∠A = ∠D, ∠B = ∠E, and ∠C = ∠F

Now, cut DP= AB and DQ= AC and join PQ. Hence, we can say that a triangle ABC is congruent to the triangle DPQ.

(i.e) ∆ ABC ≅ ∆ DPQ, which gives ∠B = ∠P = ∠E, and also, the line PQ is parallel to EF.

Therefore, by using the basic proportionality theorem, we can write

DP/PE = DQ/QF.

(i.e) AB/DE = AC/DF. …(1)

Similarly,

AB/DE = BC/EF …(2)

From (1) and (2), we can write:

AB/DE = BC/EF = AC/DF.

Therefore, the two triangles ABC and DEF are similar.

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Answer:

This equation can be used to determine how long the car was traveling at each speed. You can solve for one of the variables by using algebraic techniques. For example, you could subtract 35y from both sides to get:

55x = 200 - 35y

Then divide both sides by 55 to get:

x = (200 - 35y)/55

This equation shows that the value of x (the time spent traveling at 55 mph) is determined by the value of y (the time spent traveling at 35 mph). If you know the value of y, you can use this equation to calculate the value of x.

To find the values of x and y that satisfy the equation, you will need to use additional information. For example, you could set up a system of equations and solve for x and y using techniques such as substitution or elimination.

Step-by-step explanation:

Ken should leave a $3.59 tip.

We will discuss algebra, a branch of mathematics that deals with symbols and the rules for manipulating them, in the context of algebra word problem worksheets.

They represent variables or quantities without set values. Our abilities to construct and solve equations must be combined in order to solve algebraic word problems.

It is crucial to start by converting verbal descriptions into algebraic formulas before tackling word issues.

To find the amount of tip he should give, we note that 15% is equal to 0.15 as a decimal.

23.95 * 0.15= 3.5925≈3.59 (approximately)

Therefore, Ken should leave a $3.59 tip.

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The number √2 is called an irrational number because the value of √2 = 1.41421356... and the the value is non terminating and non repeating .

What are Irrational Numbers ?

The Numbers whose vales are Non Repeating and Non Terminating are called as Irrational Numbers ,

also the numbers that cannot be expressed on the form of [tex]\frac{p}{q}[/tex] are called as Irrational Numbers .

the number is given as √2 ;

we know that the values of √2 is = 1.41421356... ,

we see that the the value is non terminating and the numbers after decimal point are non repeating ,

Therefore  , the number √2 is an irrational number .

The given question is incomplete , the complete question is

Why the number √2 is called a Irrational Number ?

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Answer:

Step-by-step explanation:80085

Answer:

Graph 1: No

Graph 2: No

Graph 3: No

Graph 4: Yes

Graph 5: No

Graph 6: Yes

Step-by-step explanation: To figure out whether a graph is a function, you need to give each graph a Vertical Line Test. All you need to do is see if more than one point is on the same line whenever a vertical line is placed. If there is more than one point on any vertical line that you drew, it's not a function.

Hope this helps! :)

Answer:

[tex]x=\dfrac{\log 6}{\log 23}[/tex]

Step-by-step explanation:

Given exponential equation:

[tex]23^x=6[/tex]

[tex]\textsf{Apply the log law}: \quad a^c=b \iff \log_ab=c[/tex]

[tex]\implies\log_{23}6=x[/tex]

[tex]\textsf{Given change of base formula}: \quad \log_by=\dfrac{\log y}{\log b}}[/tex]

Apply the given change of base formula:

[tex]\implies x=\dfrac{\log 6}{\log 23}[/tex]

The nature of roots of quadratic equation x² = -2x + 1 is real and distinct.

The standard form of a quadratic equation is:

ax² + bx + c = 0

The discriminant is defined as:

D = b² - 4ac

Using  the value of discriminant, we can determine the nature of roots of a quadratic equation.

If:

D > 0, the quadratic equation has two distinct real roots or the roots are real and distinct.

D = 0, the quadratic equation has 1 real equal roots or the roots are unique

D < 0, the quadratic equation has complex conjugate roots or the roots are imaginary.

In this case, the quadratic equation is:

x² = -2x + 1

transform it into the standard form:

x² + 2x - 1 = 0

Calculate the discriminant:

D = 2²  - 4 (-1) = 8

Since D > 0, the roots are two distinct real roots.

Your question is incomplete, but most probably your question was:

What is the nature of roots of quadratic equation x² = -2x + 1?

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â' in mathematics refers to the hexadecimal representation of the number 10.

In machine code and assembly programming languages, hexadecimal is widely utilised. It is frequently used to refer to memory addresses. It can be used to represent numbers kept in a CPU's registers or in main memory, as well as during the debugging phase of designing a computer programme.

Although there are six more digits to consider, counting in hex is very similar to counting in decimal. When a digit position exceeds "F," you roll that place over to "0" and increase the digit to the left by 1. And once you've reached 1F16, move on to 2016 and keep churning the right-most

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Therefore, there are 12 bandages in 2 boxes, which is the answer to the unitary method presented problem.

The term "unitary" refers to a single or separate unit or variable . As a result, this strategy's objective is to establish values in terms of a single unit. For instance, if a car travels 44 kilometres on two litres of gas, the unitary technique can be used to determine how many kilometers it will drive on one.

Here,

Given: Each box of bandages has three packs, with two bandages in each pack.

Now, determine how many bandages there are in two boxes.

Therefore, we solve using the unitary method:

One pack contains two bandages.

In 3 packs, there are therefore = 2*2 = 6 bandages.

One box contains three packs as stated.

Consequently, we multiply 2 by 6 to obtain the bandages in 2 boxes:

=> 2 * 6 = 12

Therefore, there are 12 bandages in 2 boxes, which is the answer to the unitary method's presented problem.

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Answer:

2(3n^2-4) and 6n^2-8

Step-by-step explanation:

There are two different answers but try at least both of them.