The quantity of charge on a plastic tube that has been rubbed with animal fur and gained 3. 8 x 10^9 electrons is The quantity of charge on the plastic tube is 3.8 x 10^9 electrons.
The quantity of charge on the plastic tube is 3.8 x 10^9 electrons. To calculate this value, we can use the equation q = n*e, where q is the charge, n is the number of electrons and e is the elementary charge (1.6 x 10^-19 C). Substituting in the values given, we get q = 3.8 x 10^9 * 1.6 x 10^-19 = 6.08 x 10^-10 C. This means that the plastic tube has gained a charge of 6.08 x 10^-10 Coulombs, which is equivalent to 3.8 x 10^9 electrons.
This can be explained by the process of triboelectricity, which is the transfer of electrons between two materials due to rubbing them together. In this case, the animal fur must have had a higher electron affinity than the plastic, which caused electrons to be transferred from the fur to the plastic tube.
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In 1935, a french destroyer , La Terrible , started from rest and accelerates to attain a speed of 93 km/h. Suppose it took 2 minutes for the ship to speed up. Find the ships average acceleration.
According to the given statement The ships average acceleration is 2790 km/hr².
What is an explain acceleration?Rate of change in both speed and direction of motion over time. A point or object going straight forward is accelerated when it accelerates or decelerates. Even though the speed is constant, motion on a circle accelerates because of direction is always shifting
Calculation:We know that from newton's equation,
v² + u² = 2as
S = ut + 0.5 at²
Where, v = final speed
u = initial speed
a = acceleration
S = distance covered
t = time taken
Given, u = 0
So the equations becomes:
v² = 2as
S = 0.5 at²
Using these equations we get:
v² = 2a(0.5)at²
v² = a²t²
v = at
v/t = a
Given, v = 93 km/hr
t = 2 min = 2/60 hr
Putting these values in above equation we get, a = 2790 km/hr²
So, the ships average acceleration is 2790 km/hr²
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A 50.0-kg child stands at the rim of a merry-go-round of radius 2.70 m, rotating with an angular speed of 3.95 rad/s. What minimum coefficient of static friction is required
A 50.0-kg child stands at the rim of a merry-go-round of radius 2.70 m, rotating with an angular speed of 3.95 rad/s. Minimum coefficient of static friction is required 13.56.
To find the minimum coefficient of static friction required, we need to calculate the centrifugal force acting on the child and compare it to the force of friction.
The centrifugal force acting on the child is given by:
= Fc
= m * r * w^2
where
= m
= 50.0 kg (mass of child)
= r
= 2.70 m (radius of the merry-go-round)
= w
= 3.95 rad/s (angular velocity)
So, Fc = 50.0 kg * 2.70 m * (3.95 rad/s)^2
= 6629.775 N
The force of friction acting on the child is given by:
= Ff
= friction coefficient * normal force
where
friction coefficient = minimum coefficient of static friction required (unknown)
= normal force
= m * g
The normal force is equal to the weight of the child, which is
= m * g
= 50.0 kg * 9.8 m/s^2
= 490 N
So, Ff = friction coefficient * 490 N
To find the minimum coefficient of static friction, we need to set Ff equal to Fc and solve for the friction coefficient:
friction coefficient = Ff / N
friction coefficient = 6629.775 N / 490 N
= 13.56
So the minimum coefficient of static friction required is 13.56.
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i need help plssssss
The three key words that have been replaced in the cross - section of a solar panel are:
R - Insulator S - Copper T - BlackThis means that Option A is correct.
What are some parts in a solar panel ?A solar panel, also known as a photovoltaic (PV) panel, is a device that converts sunlight into electricity. It is made up of several different parts that work together to generate electricity. Solar cells are made of silicon and are responsible for converting sunlight into electricity. They are usually arranged in a grid pattern on the panel.
The backsheet is the layer of material that sits on the back of the solar cells. It is responsible for protecting the back of the solar cells from moisture and other environmental factors. It is an insulator and is shown as R.
There are also the copper wires which heat the water and they are painted black as black absorbs heat better. These are labeled S and T respectively.
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A new way of "multiplying" two vectors is introduced in this chapter. What is it called? Select one: O a. The tensor product. O b. The angular product. Oc. The scalar product. O d. The dot product. O e. The cross product.
The correct option is option e) cross product
The cross-product is a new way of "multiplying" two vectors. It results in a new vector that is perpendicular to both the original vectors and its magnitude is given by the area of the parallelogram formed by the two original vectors.
In three-dimensional space, cross-product is a binary operation on two vectors. It yields a vector perpendicular to both vectors. a b represents the vector product of two vectors, a and b. Its resulting vector is parallel to a and b. Cross goods are another name for vector products.
The cross-product has four basic applications:
calculating the angle () between two vectorsdetermining a vector normal to a planecalculating the moment of a force about a pointcalculating the moment of a force about a line.Read more about Cross-Product from:
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Mess Me and You will have nonsense Explain how this riddle relates to mutation in DNA
Deoxyribonucleic acid is a polymer composed of two polynucleotide chains that coil around each other to form a double helix.
What makes a nonsense mutation nonsense?
A nonsense mutation occurs in the DNA when a sequence changes itself and gives rise to a stop codon rather than a codon specifying an amino acid. The presence of the new stop codon results in the production of a shortened protein that is non-functional.
A nonsense mutation is also known as base substitution which results in a stop codon in such a position from where there was not one before, which causes the premature termination of protein synthesis and, more than likely, a complete loss of function in the finished protein.
So we can conclude that a nonsense mutation always causes a loss of amino acids.
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In the video, Dr. Hewitt lifts a bowling ball on a rope to his teeth, then lets go, the ball swings away and returns. What happens the first time Dr. Hewitt lifts the bowling ball near his teeth and lets go?
answer choices
O The ball returns to Dr. Hewitt, stopping almost exactly at the point where it was released.
O The ball leaves Dr. Hewitt and returns to him, going past the point where it was released.
O The ball leaves Dr. Hewitt and returns to him, stopping short of the point where it was released.
Option 1 is correct choice, The ball returns to Dr. Hewitt, stopping almost exactly at the point where it was released.
Potential energy becomes kinetic energy when a stationary item begins to move. When an item in motion stops moving, its kinetic energy transforms into potential energy.
Here, the energy input from the push is transforming into kinetic energy, which would be later transformed into even more potential energy than the ball had at the beginning of the motion.
The component of swinging is called kinetic energy, and it is the speed at which the ball runs back and forth. The most powerful aspect of swinging is potential energy. The ball achieves more potential energy the higher you go on the swing, so When it comes back to Dr. Hewitt, the ball stops almost exactly where it started.
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Stephen has to drive 8 miles south and 3 miles east to get to work.What is his distance and displacement?
Since the displacement is a vector quantity, the distance is 11 miles while displacement is 8.5 miles
What is Displacement ?Displacement is a distance travelled in a specific direction. Distance is a scalar quantity while displacement is a vector quantity.
Given that Stephen has to drive 8 miles south and 3 miles east to get to work.
His distance will be 8 miles + 3 miles = 11 miles
While his displacement can be calculated by using Pythagoras theorem. That is,
Displacement D = √(8² + 3²)
D = √(64 + 9)
D = √73
D = 8.5 miles
Therefore, his distance is 11 miles and his displacement is 8.5 miles.
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A 65.6 kg ice skater moving to the right with a velocity of 2.65 m/s throws a 0.142 kg snowball to the right with a velocity of 32.7 m/s relative to the ground. What is the velocity of the ice skater after throwing the snowball
The velocity of the ice skater after throwing the snowball is 0.08m/s.
Given data as per the question is,
Mass of ice skater= 65.6kg
Velocity 1= 2.65m/s
Mass of the Snowball= 0.142kg
Velocity 2= 25.2m/s
Conditions before snowball is thrown:
Total mass of skater + snowball = 65.6+ 0.142 = 65.742kg
Total Momentum of skater + snowball = mv = 65.6 x 2.65 = 173.84 kgm/s
Conditions after snowball is thrown:
Let's call the velocity of the skater V.
Total momentum = momentum of skater + momentum of snowball
=65.6V + (4.6434)
= 65.6V + 4.6434
173.84 = 65.6V+4.6434
173.84- 4.6434= 65.6V
169.19=65.6 V
V= 175.156/69.22
V = 2.57m/s
The total momentum after catching the snowball is mV or:
(65.6 + 0.142) x V
So:
4.6434= 65.742V
V= 5.544/69.22
V=0.08m/s
The velocity of the ice skater after throwing the snowball is 0.08m/s
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replace the force system acting on the post by a resultant force and couple moment at point o
By replacing the force system acting on the post with a resultant force and a couple of moments at point o we get total momentum of 1478.85 ft-lb.
As per the figure we have 3 forces: At the top 300lb left side 150lnb and at the middle 200lb.
first, we have to break down the forces into x and y components.
Now calculating each force separately:
∑Fₓ=300lb+cos 30°-150×4/3+200
=259.81-120+200
∑Fₓ=339.81lb.
Now, calculate the sum of y components.
∑Fy=300 sin 30°+150×3/5
∑Fy=300 sin 30°+90
∑Fy=240lb
Now we have to x and y components by these values we can find the actual force.
|F|=√Fx²+Fy²
|F|=√(339.81)²+(240)² α=tan⁻¹(∑Fₓ/∑Fy)
|F|=√115470.83+57600 α=tan⁻¹(339.81/240)
|F|=√173070 α=35.23°
|F|=416.02 and 35.23°
the sum of moments at O
∑Mo=-Fx₃×2+Fx₂×4-Fx₁×6
∑Mo=-200(2)+4/5 150*4-3000cos30°(6)
∑Mo=-400+480-277.65
=1478.85ftlb
∑Mo=1478.85ftlb
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two students are sitting next to each other on chairs with wheels. They push each other and separate in opposite directions. The student with a mass of 48 kg moves to the left with a velocity of 1.8 m/s. How fast and in what direction does the other student with a 59-kg mass move?
The student with a 59-kg mass moves to the right with a velocity of 1.46 m/s.
What is law of conservation of momentum?According to the law of conservation of momentum, The overall momentum of two or more bodies acting on one another in an isolated system stays constant unless an external force is introduced.
The student with a mass of 48 kg moves to the left with a velocity of 1.8 m/s.
Let the student with a mass of 59 kg moves to the left with a velocity of v m/s.
As no external force applied,
48 kg × 1.8 m/s + 59 kg × v = 0
v = - 1.8 × (48/59) m/s
= - 1.46 m/s.
Hence, the velocity of the second bay is 1.46 m/s in right direct.
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A unitormly dense, spherical
planet has a mass of 4×1026 kg, as well
as a radius of 53,000 km. It also
happens to also be hollow in the
following way shown. What is the
magnitude of the gravitational field of
the planet at the point P, in N/kg?
Round your answer to two decimal
places.
The magnitude of the gravitational field of the planet depends on its mass and distance from the object being affected by it.
What is Gravitational field?
Gravitational field is a region of space where a mass or object experiences a force of gravity. It is caused by the presence of a massive object, such as a planet or star, which exerts a gravitational pull on other objects within its vicinity. The strength of the gravitational field is determined by the mass of the object and its distance from other objects.
The gravitational field of the planet at Point P can be calculated by using the equation,
g = G*M/r2
where G is the gravitational constant (6.67 x 10-11 Nm2/kg2), M is the mass of the planet (4 x 1026 kg), and r is the distance from the center of the planet to Point P (53,000 km).
Plugging in the values,
g = (6.67 x 10-11 Nm2/kg2) x (4 x 1026 kg) / (53,000 km)2
g = (6.67 x 10-11 Nm2/kg2) x (4 x 1026 kg) / (2.8409 x 1012 m2)
g = (6.67 x 10-11 Nm2/kg2) x (14.1636 x 1015 kg)
g = 9.5 x 10-5 N/kg
Therefore, the magnitude of the gravitational field of the planet at Point P is 9.50 x 10-5 N/kg.
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. Two spherical objects have masses of 8,000 kg and 5.0 kg. Their centers are separated by a distance
of 1.5 m. Find the gravitational attraction between them.
Two spherical objects have masses of 8000 KG and 1500 KG their centers are separated by a distance of 1.5 M, the gravitational attraction between them is 3.56 × 10⁻⁴N.
How does gravitational force work?The gravitational force, also known as gravity, pulls objects with mass in the same direction. We frequently think about the Earth's gravitational pull. This force is firmly holding your body in place. But every mass-bearing object attracts other mass-bearing objects toward it through gravity.
Using the formula of gravitational attraction
F = G× M₁M₂/d²
where G = 6.67 × 10⁻¹¹ Nm²Kg⁻²
M₁ = 8000Kg
M₂ = 1500 Kg
F = 6.67 × 10⁻¹¹ × 8000 × 1500 / (1.5)²
F = 3.56 × 10⁻⁴ N
The gravitational force of attraction between them is 3.56 × 10⁻⁴ N.
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The direction of the velocity of the planet is _______________________ (alwaysThe direction of the velocity of the planet is _______________________ (always, seldom, never) perpendicular to the net force acting upon the planet., seldom, never) perpendicular to the net force acting upon the planet.
According to the satellites' orbits and the speed at which they move, it either happens frequently or always.
As we begin to examine satellite orbits, we find that a circular orbit places the satellite always perpendicular to the object's net force and speed.
The orbit is stretched, just like in elliptical orbits. This informs us that the orbit has four points. As a result, the satellite rarely faces the satellite's net force in a perpendicular direction.
Rarely and always for elliptical orbits. According to the satellites' orbits and the speed at which they move, it either happens frequently or always.
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A baseball bat strikes a ball resting on a tee with a force with a magnitude of 2. 0x10^4 newtons. If the bat stays in contact with the ball for a distance of 5. 0x10^-3 meter, what kinetic energy will the ball acquire from the bat?
The kinetic energy will the ball acquire from the bat is 1.0x10^1 joules or 100 joules. This calculation is based on the equation Energy = Force x Distance, which is a fundamental equation of physics.
The kinetic energy of the ball is equal to the work done by the bat on the ball. The work done by the bat on the ball is equal to the force applied by the bat multiplied by the distance the bat stays in contact with the ball. Therefore, the kinetic energy of the ball would be equal to 2.0x10^4 newtons multiplied by 5.0x10^-3 meters, which is equal to 1.0x10^1 joules or 100 joules.
This calculation is based on the equation of Energy which is Force x Distance. Additionally, this equation can be rearranged to solve for any of the variables, depending on what is known and what needs to be calculated. In this case, the known variables were the force applied by the bat and the distance the bat stayed in contact with the ball, and the variable that needed to be calculated as the kinetic energy of the ball.
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An object is dropped from the edge of a cliff and is moving at 26.5 m/s just before it hits the ground. How high is the cliff
Here initial speed u=0m/s final speed v=26.5 m/s and acceleration due to gravity g=9.81 m/s^2
CalculationWhere:
m = mass of the object (kg)
g = acceleration due to gravity (9.8 m/s^2)
h = height of the cliff (m)
We know the velocity of the object just before it hits the ground, which is 26.5 m/s. We can use this velocity to calculate the kinetic energy of the object just before it hits the ground.
KE = (1/2)mv^2
As the object is dropped from the cliff, its initial potential energy is converted to kinetic energy. Therefore, the initial potential energy is equal to the final kinetic energy.
GPE = KE
mgh = (1/2)mv^2
We can solve for h by rearranging the equation and substituting the known values for GPE, KE, m, and g.
How can I determine the speed of a falling object before it reaches the ground?Simply multiply the acceleration of gravity by the period of time since the object was released to determine the object's speed (or velocity). In other words, velocity is equal to -9.81 m/s2 * time, or V = gt. The item is just traveling downwards when there is a negative sign.
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A student heats 3.55 g of copper and 4.60 g of iodine for 6.25 g of a new compound. All of the iodine reacted, but there is some copper left over unused. How much copper is left?
The mass of copper that is left unreacted at the end of the chemical reaction is 1.90 g
What mass of copper is left unreacted at the end of the reaction?The mass of copper that is left untreated at the end of the chemical reaction is determined as follows:
Mass of copper before the reaction = 3.55 g
Mass of iodine before the reaction = 4.60 g
Mass of product = 6.25 g
According to the law of conservation of mass;
Mass of reactant = mass of product + mass of unreacted copper
Mass of reactants = 3.55 + 4.60
Mass of reactants = 8.15 g
The difference in the mass of the product obtained and the mass of the unreacted copper
Mass of unreacted copper = 8.15 g - 6.25 g
Mass of unreacted copper = 1.90 g
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A 1. 5-mole sample of an ideal gas is gently cooled at constant temperature 320 K. It contracts
from initial volume 19 L to final volume V2. A total of 1. 2 kJ of heat is removed from the gas during the contraction process. What is V2? Let the ideal-gas constant R = 8. 314 J/(mol. K).
A mole sample of an ideal gas is gently cooled at constant temperature 320 K.
What happens when gas is cooled at constant temperature?Since the internal energy of an ideal gas is proportional to temperature, it does not change when the temperature is held constant. The first law, which governs changes in internal energy, changes to 0 = Q - W, resulting in Q = W. Both the temperature and the volume of the gas decrease as it cools at a constant pressure. The fundamental behaviour of fluids with respect to volume, pressure, and temperature is described by Boyle's, Charles', and Gay Lussac's Laws. When heat is applied at constant pressure, some of it is utilised to cause gas to expand while the remainder is used to raise the gas' temperature, which increases the gas' internal energy.To learn more about constant temperature refer to:
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Trends are easier to detect when the signal-to-noise ratio is low.
a True
b False
Answer:
I think it's b. False
Explanation:
For the charge distribution provided, indicate the region (a to e) along the horizontal axis where a point exists at which the net electric field is zero. (figure 1) if no such region exists on the horizontal axis choose the last option (nowhere). View available hint(s)
The region (A to E) along the horizontal axis where a point exists at which the net electric field is zero is point C.
An electric field refers to the physical field surrounding electrically charged particles which exerts force on all other charged particles in the field, either attracting or repelling them. It also refers to the physical field for a system of charged particles. It is defined as the electric force per unit charge. The field direction is taken as the direction of the force it would exert on a positive test charge. The direction of the electric field is always away from the positive charge and towards the negative charge. As seen in the diagram, both positive charges are equidistant from region C, and the strength of charges of the particle is the same in magnitude but opposite in direction, so the net electric field of both charges will be zero in region C.
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A 74 kg student, starting from rest, slides down an 11.8 meter high water slide. What is his kinetic energy at the bottom of the slide
The kinetic energy of the student at the bottom of the slide with a velocity of 15.21 m/s is 8,557.36 J
The mass of the student = 74 kg
The distance of the slide = 11.8 m
The final velocity at the bottom of the slide can be found using
v² = u² + 2ax
where v is the final velocity
u is the initial velocity
a is the acceleration due to gravity
x is the distance
Let us substitute the known values,
v² = 0 + 2 x 9.8 x 11.8
v² = 231.28
= √231.28
v = 15.21
Therefore, the kinetic energy at the bottom of the slide is
K.E = 1/2mv²
= 1/2 x 74 x 231.28
= 8,557.36 J
The kinetic energy of the student is 8,557.36 J
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Find the y-component of this vector: 22.3 m 77.1° Remember, angles are measured from the +x axis.
Answer:
-21.7m
Explanation:
To find the y-component of the vector, we need to find the vertical displacement from the point at the bottom of the vector to the x-axis (or its y-coordinate value).
To calculate this we can create a triangle with the vector as the hypotenuse, the y-axis as the second side and draw an imaginary line from the end of the vector directly horizontally across to the y-axis.
We can use the given angle to find the angle between the y-axis and the angle. Since the angle of a quadrant is 90 degrees, the angle within our triangle must be [tex]90-77.1=12.9[/tex] degrees.
From here, to find the length of the side on the y-axis we can use the trigonometric cos function.
[tex]cos \theta =\frac{adjacent side}{hypotenuse}[/tex]
Therefore [tex]cos 12.9=\frac{y-component}{22.3}[/tex] and [tex]ycomponent = 22.3cos12.9[/tex]
This gives us a value of 21.7 (3.s.f) for our y-component.
Finally, the y-component is also a vector so it also needs a direction. Therefore like its coordinate, its value will be -21.7m.
A car drives to the right. There is a large amount of air resistance, and the car's engine provides the car's forward motion. Which force on the free-body diagram below represents the normal force acting on the car?
A force on the free-body diagram above which represents the normal force acting on the car include the following: D. Force A.
What is a free-body diagram?In Science, a free-body diagram can be defined as a graphical illustration which is typically used in the field of science to visualize moments, tension, and applied forces that are acting on an isolated or rigid object (body), while using arrows to point in the direction of these forces.
Since this car was driven to the right, with a large amount of air resistance acting on it, and its engine provides the forward motion, we can reasonably infer and logically deduce that the normal force which is acting on the car is represented by Force A as illustrated by the free-body diagram shown in the image attached above.
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When using a 20 ft ladder how far from a building should the base of the ladder be?
When using a 20 ft ladder the distance from a building should be the base of the ladder by 5 ft
The base of a ladder should be positioned one-quarter of the working length of the ladder from the building. Therefore, when using a 20 ft ladder, the base should be positioned 5 ft from the building. Additionally, the ladder should be placed on a solid and level surface, and the feet of the ladder should be securely wedged to prevent slipping.
Extend the top of the ladder three feet above the work table to get access to it, or fasten the ladder at the top.
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20 points! I was thinking B.) Scatter plot but want to check.
A student collected data about the speed of an object over time.
Which type of graph should the student use to represent the data?
Responses
circle graph
scatterplot
histogram
bar graph
How do the overload and progression principles work together for strength training?
If you are exercising with a specific goal in mind, such as improved strength or cardio fitness. Exercise training's guiding principles include overload, recuperation, progression, reversibility, and specificity.
Your muscles will remain challenged and you'll get stronger if you change or advance your workouts.
To get the most out of any training programme, you must follow certain rules. You won't benefit much from your workouts if you don't adhere to these rules. Exercise training's guiding principles include overload, recuperation, progression, reversibility, and specificity. The concept of specificity is especially important if your exercise programme is designed to help you achieve a particular goal, like increased strength or improved aerobic fitness.
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What is the potential energy of a passenger jet weighing 7.0 x 10^5 N when it reaches a cruising altitude of 10.0 km?
Upon travelling at an altitude of 10.0 km, a passenger aircraft weighing 7.0 x [tex]10^{6}[/tex] N potential is the energy.
What similarities and differences do kinetic and potential energy share?Potential energy and kinetic energy are fundamentally different from one another because one is the energy of what can be and the other is the energy of what is. Or to put it another way, potential energy is immobile and ready to be unleashed;
When compared to potential energy, is kinetic energy greater?Due to the object's motion, kinetic energy loses some energy in the form of light energy, heat energy, and friction; these things do not occur in the potential energy, which is the reason why kinetic energy is not more than the potential energy.
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A tsunami caused by an earthquake occurring in Alaska in 1946 consisted of several huge waves which were found to travel a distance of 3607 km. The first of the waves reached Hawaii 4.567 hours after the earthquake occurred. From this data, calculate the speed of the tsunami.
From the given data, the speed of the tsunami is 789.8 km/h.
What is the speed of the tsunami?The speed of the tsunami is calculated from the relationship between distance travelled by the wave and the time of motion of the wave.
Mathematically, this formula is given as;
v = d / t
where;
d is the distance travelled by the wave of the earthquaket is the time of motion of the waveFrom the given data, the speed of the tsunami is calculated as follows;
v = ( 3607 km ) / ( 4.567 hr )
v = 789.8 km/h
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Turn your head _______ and right and glance over your shoulder to view what cannot be seen in the side-view mirrors. back down left up Submit answer
Turn your head left and right and glance over your shoulder to view what cannot be seen in the side-view mirrors.
What is mirror ?
An item that reflects an image is a mirror or looking glass. When focused through the lens of the eye or a camera, light that reflects off a mirror will reveal a picture of whatever is in front of it. Mirrors reflect light at an equal but opposite angle, which changes the direction of the image.
What is direction?
Direction can refer to a thing's course, the route one must take to get there in particular, the direction something is beginning to take shape, or the direction you are facing. Going straight instead than left is an example of direction.
Therefore, Turn your head left and right and glance over your shoulder to view what cannot be seen in the side-view mirrors.
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On a wheel and axle, if the large wheel has a radius of 20 cm and the small wheel has a radius of 4 cm, what is the ideal mechanical advantage
The ideal mechanical advantage is 5.
Here, we have value larger radius , R = 20 cm and smaller radius = 4 cm
So, as per the problem, mechanical advantage will be 20/4 = 5.
A wheel and axle must be permanently joined in order to be considered a simple machine, and the wheel must by definition have a bigger radius than the axle. A point on the wheel moves a distance of 2 R whereas a point on the axle moves a distance of 2 r when you turn the wheel through a full revolution, which likewise causes the axle to turn through a full revolution.
The force you apply F R times the distance the point moves equals the effort W required to move a point on the wheel through one full revolution. Work is energy, and since energy must be conserved, a point on the axle must be subjected to a larger force F r because it moves a shorter distance.
The mathematical relationship is:
W = Fr (subscript) ×2πr/θ =F r(subscript) ×2πR/θ
Where θ is the angle that the wheel is turned.
And therefore:
Fr(r in subscript) / FR(R in subscript) = R/r
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How can you tell which elements will form ions?
Answer: The position of an element on the periodic table, see resources, tells you the type of ions it will form, with the elements on the right forming anions (negative charge) and those further to the left forming cations (positive charge).
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