determine the value of x in each triangle

Answer:

9-3=b

Step-by-step explanation:

9-3=b

Answer:

B=6

Step-by-step explanation:

Let "b" be the number of books Shemel has.

Let "a" be the number of books Wawra has.

Eqution:

A-3=B ("3" is given in question)

9-3=B (Substituting with variables given)

B=9-3

B=6

Hence, Shemel has "6" books.

Hope it helps !

Answer:

x and y are the variables

Given that

The cost of 1 m ribbon = Rs.75

The cost of 7/5 m ribbon

→ (7/5)×75

→ (7×75)/5

→7×15

→₹ 105

The cost of 7/5 m ribbon is ₹105.

Answer:

the answer is >

Step-by-step explanation:

I took the test

Answer:

  y = 5

Step-by-step explanation:

The base angles of this isosceles triangle are congruent, so the angle at A is ...

  A = 180° -2(75°) = 30°

  (4y +10)° = 30° . . . . . substitute the given expression for angle A

  4y = 20 . . . . . . . . . . divide by °, subtract 10

  y = 5 . . . . . . . . . divide by 4

_____

Additional comment

The value of x is 25.

x is found from 3x=75, by dividing both sides of this equation by 3.

Answer:

thats what i said

Step-by-step explanation:

Answer:

  (a)  8 1/2 ÷ 1/4

Step-by-step explanation:

Katie's total mileage is the product of the miles per day (1/4) and the number of days (n).

  miles = (1/4)n

If Katie jogged 8 1/2 miles, then we have ...

  8 1/2 = (1/4)n

We find the value of n (the number of days) by dividing both sides of this equation by the coefficient of n:

  (8 1/2) ÷ (1/4) = n

_____

Additional comment

If you consider the units, you know that the only possible operation is division. The number 8 1/2 has units of miles. The number 1/4 has units of miles per day.

  [tex]\dfrac{\text{miles}}{\left(\dfrac{\text{miles}}{\text{day}}\right)}=\dfrac{\text{miles}\cdot\text{day}}{\text{miles}}=\text{days}[/tex]

If you multiply, the product units are miles²/day. You cannot add or subtract numbers with different units. (They are not "like terms".)

As here, "units analysis" often tells you what math operations are needed, and which ones make no sense whatever.

Often time we want to relate one amount or quantity with another, from the given options the one that best describes a ratio is option

A.  A comparison of two numbers

A ratio indicates how many times one number contains another. E.g, if there are five balls and nine lemons in a bowl of fruit, then the ratio of balls to lemons is five to nine. Similarly, the ratio of lemons to oranges is 5∶8

Learn more on ratios:

https://brainly.com/question/2328454

Answer: 400,00 km

Step-by-step explanation: 1:50,000 = 8:x

8 * 50,000 = 400,000

So, 8km on the map is 400,000 km in real life.

Would appreciate brainly <3

\well the answrnist that brcause if u think it guys up

Answer:

Shifted, reflected, and stretched

Step-by-step explanation:

Horizontal Shift: Right 1 Unit

Vertical Shift: Up 3 Units

Reflection about the x-axis: Reflected

Vertical Stretch: Stretched

Answer:

Not a function

Step-by-step explanation:

H =20

G = 8 mor than I

the measure of H is 28 because it says that g is 8 more so that means I can be 0 and that means G is 8 and then H is 20. therefore solving your answer

Answer:

1/3

Step-by-step explanation:

Answer:

Decrease amount: $1484 Year-end amount: $4116

Step-by-step explanation:

26.5% of 5600 is 1484. We then subtract 1484 from 5600 because that is how the percentage of decrease, which gives us 4116 dollars. This means her year-end account is 4116 dollars, and the decrease amount is 1484 dollars. Hope this helps!

Answer:

I think the other side on top is 129 degrees

Step-by-step explanation:

Im not 100 percent sure sorry if im wrong!!!

Answer:

$1449.15

Step-by-step explanation:

currently paying 815

to pay next year: 41% increase + 25 extra per month

⇒ 141%·815 + 12·25

    = 1149.15 + 300

    = 1449.15

Answer:

168 cups of sugar

Step-by-step explanation:

36 cookies require you to use what the recipes calls for plus one half.

112 divided by two is 56

112 + 56 = 168 cups

I hope that this helps!

For this case we have the following data:

24 cookies require 1 1/2 cups of sugar. To know the amount of sugar that is required to make 36 cookies, we make a rule of three:

24 -----------> 1 1/2

36 -----------> x

Where x represents the amount of sugar required to make 36 cookies.

Thus,   cups of sugar are required to make 36 cookies.

Answer:

36

Step-by-step explanation:

You would multiply 6x8+6x(-2), and that would equal 48+(-12) which is basically 48-12 = 36.

Answer:

you draw a T. form and then you can start to in debit and credit

9514 1404 393

Answer:

  $66,027.66

Step-by-step explanation:

The multiplier for the salary with each raise is (1 + raise). That means the original salary is multiplied by ...

  (1.04^3)×(1.02^2)×(1.10) = 1.28733935616 = k

Your original salary (O) satisfies ...

  O×k = $85,000

  O = $85,000/k ≈ $66,027.66 . . . original salary

Answer:

you are back in your place.

Step-by-step explanation:

Answer:

[tex]\huge\boxed{\dfrac{5}{12}x-5}[/tex]

Step-by-step explanation:

[tex]\left(\dfrac{3}{4}x-1\right)-\left(\dfrac{1}{3}x+4\right)=\dfrac{3}{4}x-1-\dfrac{1}{3}x-4=\left(\dfrac{3}{4}x-\dfrac{1}{3}x\right)+(-1-4)\\\\=\left(\dfrac{3\cdot3}{4\cdot3}x-\dfrac{1\cdot4}{3\cdot4}x\right)+(-5)=\left(\dfrac{9}{12}x-\dfrac{4}{12}x\right)-5=\dfrac{9-4}{12}x-5\\\\=\dfrac{5}{12}x-5[/tex]

Answer:

xxxx

Step-by-step explanation:

1. The given equation is probably supposed to read

y'' - 2y' - 3y = 64x exp(-x)

First consider the homogeneous equation,

y'' - 2y' - 3y = 0

which has characteristic equation

r² - 2r - 3 = (r - 3) (r + 1) = 0

with roots r = 3 and r = -1. Then the characteristic solution is

[tex]y = C_1 e^{3x} + C_2 e^{-x}[/tex]

and we let y₁ = exp(3x) and y₂ = exp(-x), our fundamental solutions.

Now we use variation of parameters, which gives a particular solution of the form

[tex]y_p = u_1y_1 + u_2y_2[/tex]

where

[tex]\displaystyle u_1 = -\int \frac{64xe^{-x}y_2}{W(y_1,y_2)} \, dx[/tex]

[tex]\displaystyle u_2 = \int \frac{64xe^{-x}y_1}{W(y_1,y_2)} \, dx[/tex]

and W(y₁, y₂) is the Wronskian determinant of the two fundamental solutions. This is

[tex]W(y_1,y_2) = \begin{vmatrix}e^{3x} & e^{-x} \\ (e^{3x})' & (e^{-x})'\end{vmatrix} = \begin{vmatrix}e^{3x} & e^{-x} \\ 3e^{3x} & -e^{-x}\end{vmatrix} = -e^{2x} - 3e^{2x} = -4e^{2x}[/tex]

Then we find

[tex]\displaystyle u_1 = -\int \frac{64xe^{-x} \cdot e^{-x}}{-4e^{2x}} \, dx = 16 \int xe^{-4x} \, dx = -(4x + 1) e^{-4x}[/tex]

[tex]\displaystyle u_2 = \int \frac{64xe^{-x} \cdot e^{3x}}{-4e^{2x}} \, dx = -16 \int x \, dx = -8x^2[/tex]

so it follows that the particular solution is

[tex]y_p = -(4x+1)e^{-4x} \cdot e^{3x} - 8x^2\cdot e^{-x} = -(8x^2+4x+1)e^{-x}[/tex]

and so the general solution is

[tex]\boxed{y(x) = C_1 e^{3x} + C_2e^{-x} - (8x^2+4x+1) e^{-x}}[/tex]

2. I'll again assume there's typo in the equation, and that it should read

y''' - 6y'' + 11y' - 6y = 2x exp(-x)

Again, we consider the homogeneous equation,

y''' - 6y'' + 11y' - 6y = 0

and observe that the characteristic polynomial,

r³ - 6r² + 11r - 6

has coefficients that sum to 1 - 6 + 11 - 6 = 0, which immediately tells us that r = 1 is a root. Polynomial division and subsequent factoring yields

r³ - 6r² + 11r - 6 = (r - 1) (r² - 5r + 6) = (r - 1) (r - 2) (r - 3)

and from this we see the characteristic solution is

[tex]y_c = C_1 e^x + C_2 e^{2x} + C_3 e^{3x}[/tex]

For the particular solution, I'll use undetermined coefficients. We look for a solution of the form

[tex]y_p = (ax+b)e^{-x}[/tex]

whose first three derivatives are

[tex]{y_p}' = ae^{-x} - (ax+b)e^{-x} = (-ax+a-b)e^{-x}[/tex]

[tex]{y_p}'' = -ae^{-x} - (-ax+a-b)e^{-x} = (ax-2a+b)e^{-x}[/tex]

[tex]{y_p}''' = ae^{-x} - (ax-2a+b)e^{-x} = (-ax+3a-b)e^{-x}[/tex]

Substituting these into the equation gives

[tex](-ax+3a-b)e^{-x} - 6(ax-2a+b)e^{-x} + 11(-ax+a-b)e^{-x} - 6(ax+b)e^{-x} = 2xe^{-x}[/tex]

[tex](-ax+3a-b) - 6(ax-2a+b) + 11(-ax+a-b) - 6(ax+b) = 2x[/tex]

[tex]-24ax+26a-24b = 2x[/tex]

It follows that -24a = 2 and 26a - 24b = 0, so that a = -1/12 = -12/144 and b = -13/144, so the particular solution is

[tex]y_p = -\dfrac{12x+13}{144}e^{-x}[/tex]

and the general solution is

[tex]\boxed{y = C_1 e^x + C_2 e^{2x} + C_3 e^{3x} - \dfrac{12x+13}{144} e^{-x}}[/tex]

Answer:

25/15

Step-by-step explanation:

Answer:

  10%

Step-by-step explanation:

If 40% failed chemistry then 60% passed chemistry.

If 19% failed both chemistry and physics, and 25% failed physics, then 6% passed chemistry and failed physics.

If we let p' represent failing physics and c represent passing chemistry, then ...

  P(p'|c) = P(p'c)/P(c)

  P(p'|c) = 6%/60% = 0.10 = 10%

If the randomly chosen student passed chemistry, the probability is 10% that he failed physics.

__

Your answer is correct.

To solve this problem, we can use conditional probability.

Let's assume that there were 100 students in the final exam.

According to the problem, 40% of the students failed chemistry, which means that 60% of the students passed chemistry.

To find the probability that a randomly selected student failed physics given that he passed chemistry, we need to use Bayes' theorem:

[tex]\sf P(Failed\: Physics | Passed\: Chemistry) = \dfrac{P(Failed\: Physics\: and\: Passed\: Chemistry)}{ P(Passed\: Chemistry)}[/tex]

We already know that P(Failed Physics and Passed Chemistry) = 6 students (from the Venn diagram), and P(Passed Chemistry) = 60 students (since 60% of the students passed chemistry).

Therefore,

[tex]\sf P(Failed\: Physics | Passed\: Chemistry) = \dfrac{6}{60} = 0.1\: or\: 10\%[/tex]

So the probability that a randomly selected student failed physics given that he passed chemistry is 10%.

Answer:

8/64 = 0.125 = 12.5%

Step-by-step explanation:

8/64 = 0.125 = 12.5%

[tex] \frac{39 \: \: days}{15 \: \: days} \\ = \frac{39}{15} \\ dividing \: \: \: both \: \: \: numerator \: \: \: and \: denominator \: \: \: by \: \: \: 3 \\ = \frac{13}{5} \\ = 13 : 5[/tex]

13:5

Hope it helps.

Do comment if you have any query.