Other elemental substances in that they consist of two atoms of the same element, bonded together.
What is Diatomic elements?Diatomic elements are chemical elements that exist in the form of two atoms held together by covalent bonds. The most common elements that exist as diatomic molecules are hydrogen, oxygen, nitrogen, fluorine, chlorine, bromine, and iodine. These elements are found in nature and play important roles in the formation of compounds used in everyday life.
This bond is usually covalent in nature, and the two atoms form a stable molecule. This type of molecule is very stable and present in the form of gas, at room temperature and pressure. Examples of diatomic elements are hydrogen, oxygen, nitrogen, fluorine, chlorine, and bromine. Due to the fact that these elements are already in a stable, two-atom form, they exhibit different chemical and physical properties than other elements. For example, diatomic oxygen is highly reactive and can easily combine with other elements, while diatomic nitrogen is relatively inert. This difference in reactivity is due to the fact that the two atoms in the diatomic form share electrons more easily than atoms in other elemental forms.
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what will be the hexadecimal value of al after these instructions execute? mov al,0cfh and al,2bh
0Bh will be the hexadecimal value of AL (Aluminium)after these instructions execute
#D9DAD9 is the hex code for aluminum. (217, 218, 217) are the corresponding RGB values, indicating that it is made up of 33% red, 33% green, and 33% blue. Printers employ the CMYK color coding, which are C:1 M:0 Y:1 K:15. Aluminum has a brightness value of 85%, a saturation value of 0%, and a hue value of 120° on the HSV/HSB scale.Hexadecimal is the most practical number system to work with when dealing with long strings of numbers due to its compactness, aligned correspondence of 4 bits to 1 symbol, and freedom from the need to perform multiplication and addition when switching between bases (compare switching from binary to decimal and back).
complete question:What will be the hexadecimal value of AL after these instructions execute?
mov al, 0CFh
and al, 2Bh
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A compound with a molecular mass of 56.104 grams is found to be 86% carbon. The rest of the compound is hydrogen. Find its molecular formula. Group of answer choices C3H6 C4H8 C2H4 C6H10
The molecular formula for this compound is C4H8 that can be calculated from its empirical formula.
The empirical formula of a chemical compound is the simplest whole number ratio of atoms present in a compound. The compound is made up of only carbon and hydrogen atoms thus it is known as hydrocarbon. The percentage of carbon is 86%, therefore the percentage of hydrogen is 14%.
The molecular mass of the compound is given i.e., 56.104 grams.
Moles of C= 86 g * 1 mol/12 g =7 moles
Moles of H=14 g* 1 mol/1 g= 14 moles
Thus, the mole ratio of C:H can be given as:
Moles of C/ Moles of H= 7/14=1/2
Thus, the empirical formula is CH2 while its molecular formula is C4H8.
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What does an element box contain?
The element box contains name and symbol of the element, number of protons and electrons, atomic mass, and electron configuration.
Each container represents an detail and incorporates its atomic size, symbol, common atomic mass, and (sometimes) name. The factors are organized in seven horizontal rows, referred to as intervals or series, and 18 vertical columns, referred to as groups. The container containing every detail's records is called the detail key. Each key incorporates an detail's name, precise symbol, atomic weight and atomic variety. Oxygen, for example, has an atomic variety of 8, an atomic weight of 15.996 and a completely unique symbol, O. The table is split into 4 more or less square regions referred to as blocks. The rows of the desk are referred to as intervals, and the columns are referred to as groups. Elements from the equal institution of the periodic table display comparable chemical characteristics.
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10. A body is found at 2:00 pm on New Year's Eve. The temperature of the liver registers 75. 5° F. What is the approximate TOD of the victim?
The estimated time of death is approximately 10:30 pm the night before.
Estimating the time of death (TOD) can be a complex process, and the methods used will depend on the specific circumstances of the case. Some of the factors that may be taken into consideration include:
The stage of decomposition of the body: As a body decomposes, it will go through several distinct stages, each of which can provide information about the TOD.The temperature of the body: As a body cools after death, the temperature will drop at a predictable rate. By measuring the temperature of the body at different points in time, it may be possible to estimate the TOD.The body's position: The position of the body can provide clues about the time that has passed since death. For example, if a body is found lying on its back, it may indicate that it has been dead for a longer period of time than if it is found on its stomach.The presence of insects or animals: Certain insects and animals are attracted to dead bodies at different stages of decomposition. By examining the presence of these insects or animals, it may be possible to estimate the TOD.Scene examination: The scene examination and any possible evidence collected can give a rough estimate of the time of death.It is important to note that estimating the TOD is not an exact science and there are often significant margins of error. A professional forensic examination is typically needed to determine the TOD.
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How many molecules are in 10.0 g of aspartame?
There are 0.034 x 1019 = 10¹⁹ moles of molecules in 10 g of aspartame.
Avogadro's constant, 6.022 1023, and the molar mass of the material are used to calculate the number of molecules in a given mass of the substance. Aspartame's molecular formula is C14H18N2O5.
Aspartame has a molecular mass of 294 (12 * 14 + 1 * 18 + 14 * 2) + 16 * 5)
Let's convert the 10 mg mass supplied to aspartame moles as follows:
Amount of moles =
= 0.034 × 10 ⁻⁵ mole
We may convert this number to molecules using Avogadro's constant as follows:
= 0.034 × 10 ⁻⁵ (6.022 × 10²³)
= 0.034 × 10¹⁹
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1
2
3
6
8
g
10
Which two pieces of fossil evidence support the idea of continental drift?
bacteria and petrified wood
O Glossopteris and bacteria
O Lystrosaurus and Glossopteris
O petrified wood and Tyrannosaurus
Lystrosaurus and Glossopteris are two pieces of fossil evidence support the idea of continental drift.
One of the geologist's first theories about how continents moved over time was continental drift. The science of plate tectonics has been largely supplanted the hypothesis of the continental drift. Alfred Wegener has been most closely associated with the continental drift idea. Wegener released a paper in the early twentieth century describing his notion that continental landmasses were "drifting" across the Earth, occasionally ploughing through seas and into one other. He developed the term "continental drift" to describe this process.
Wegener found similarities in the coasts of eastern South America as western Africa and hypothesised that those countries had originally been part of a supercontinent called Pangaea, which had separated and travelled many kilometres away over geologic time. He also mentioned nearly comparable fossil creatures and rock layers that happened on vastly different continents. Colbert discovered Lystrosaurus fossils in the Transantarctic Mountains of Antarctica. Such fossils belonged to something like a species previously discovered in Africa, proving that the world's two most distant continents were formerly linked.
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Answer: C. Lystrosaurus and Glossopteris
Explanation:
I need help
What causes winter in the Northern Hemisphere. Include a labelled diagram.
Answer:
It's Simple earth just moves noob
Classify: Drag out different combinations of molecules in the Gizmo and categorize them. Give at least three examples of molecule combinations for each intermolecular force.
Dipole-dipole forces
Dipole-induced dipole forces
London dispersion forces
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Diatomic elements are important. what makes them different from other elemental substances?
Diatomic elements are elements that exist as molecules composed of two atoms of the same element.
What is Diatomic?Diatomic molecules are molecules composed of two atoms, such as Oxygen (O2), Hydrogen (H2), Nitrogen (N2), and Fluorine (F2). Diatomic molecules are the most common type of molecules in nature and are found in all three states of matter (solid, liquid, and gas). Diatomic molecules contain only two atoms and do not contain any other elements or molecules.
This is in contrast to other elemental substances, which exist as individual atoms or molecules composed of different elements. Diatomic elements have unique chemical and physical properties due to the strong bond between the two atoms.
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A 5.05 g sample of quartz (SiO 2) contains 2.36 g of silicon. What are the percentages of silicon and oxygen in quartz
In quartz, silicon has a mass percent of 46.7% while oxygen has a mass percent of 53.3%.
Given the total mass of a sample of quartz (SiO2) (m1) = 5.05g
Mass of silicon (m2) = 2.36g
The percent composition of an element in a chemical compound is referred to as mass percent. Mass percent may be expressed as follows:
mass percent = mass of element/mass of sample x 100
The percent mass of silicon (p1) = 2.36/5.05 x100 = 46.7%
The substance was made of silicon and oxygen.
Thus, 100% Quartz =%Silicon +%Oxygen can be used to express the mass percentage of quartz.
100% Quartz = 46.7% + % Oxygen
% Oxygen = 53.3%
Hence the percentages of silicon and oxygen in quartz are 46.7% and 53.3%.
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A second row element has a large jump between its third and fourth ionization energies. What is the element
Be is the second element with two valence elements When a core electron is eliminated, the energy of ionization increases. From an element's electrical configuration, it is simple to see a significant change in ionization energy.
Electronically, beryllium is configured as 1s2 2s2. The outermost shell of beryllium has two valence electrons, hence the data on ionization energy will show a sharp rise or leap from the second to the third ionization energy due to the elimination of a core electron. Nitrogen has the following electrical configuration: 1s2 2s2 2p3. The outermost shell of nitrogen has five valence electrons, thus when one of them is removed, the ionization energy data for nitrogen will show a sharp rise or leap from the fifth to sixth ionization energy.
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Help Please!! How do I do this?
A sample of nitrogen is heated from STP to 100°C at constant pressure. Calculate the volume at 100°C.
Considering the Charles' law and STP conditions, the volume at 100°C is 30.60 L.
Charles' lawCharles' law establishes the relationship between the volume and the temperature of a sample of gas at constant pressure and establishes that when the temperature is increased the volume of the gas also increases and that when cooling the volume decreases.
Mathematically, Charles's law is expressed as:
V÷T=k
where:
V is the volume.
T is the temperature.
k is a constant.
Analyzing an initial state 1 and a final state 2, it is fulfilled:
V₁÷T₁= V₂÷T₂
STP conditionsThe STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.
Volume at 100°CIn this case, you know:
V₁= 22. 4 LT₁= 0°C= 273 KV₂= ?T₂= 100 °C= 373 KReplacing in Charles' law:
22.4 L÷ 273 K= V₂÷ 373 K
Solving:
(22.4 L÷ 273 K)× 373 K= V₂
30.60 L= V₂
Finally, the final volume is 30.60 L.
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PLS HELP ME ON 4 CHEMISTRY ASAP
The percent composition of cesium weighs 100 g in a sample with total mass of 400 g is 25 %.
What is mass percent?The mass percent of an element in a compound is the contribution from the element to the total mass of the compound. It is the ratio of the mass fraction of the element to the total mass multiplied by 100.
Mass percent is a common term used to express the concentration of an ion or element in a mixture.
Given that total mass of the compound = 400 g
mass of cesium in the compound = 100 g.
Mass percent of cesium = mass of Cs/total mass
mass % = 100 /400 × 100 = 25%
Therefore, the mass % of Cs in the compound is 25%.
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Consider the feedback loop that occurs when you je rk your hand away from something hot. How does this reflex help to maintain homeostasis?
Considering the feedback loop that occurs when you quickly remove your hand away from something hot, this reflex helps to maintain homeostasis by ensuring that the body is free from danger and thus maintains the internal condition of the body.
What is homeostasis?The stable internal, external, and chemical conditions that are maintained by living systems are known as homeostasis. In order for the organism to function at its best, a number of factors, including body temperature and fluid balance, must be maintained within predetermined ranges.
The body's reflexes help to maintain homeostasis in the body such as heart rate, breathing rate, blood pressure, and digestion.
Some reflexes that maintain homeostasis in the body include:
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Consider the combustion of propane:
C3H8 +502 3CO2 + 4H₂O
- →
Which of the following unit factors below is correct? (Select all that may apply)
A. There are 5 oxygen molecules reacting for every six oxygen atoms produced in CO2.
B. There are 5 oxygen atoms reacting for every 3 CO₂ molecules produced.
C. There are 10 oxygen atoms reacting for every four water molecules produced.
D. There are 10 oxygen atoms reacting for every six oxygen atoms produced in CO2.
Four water molecules are created for every ten oxygen atoms that are reacting.
Propane:A three carbon alkane, propane has the chemical formula C3H8. At room temperature and pressure, it is a gas, but it can be compressed into a liquid for transportation.
What is the primary use of propane?Its primary applications include home and water heating, food preparation and storage, clothing drying, and the powering of industrial and farm machinery. The production of plastics and other chemicals in the chemical sector also uses propane as a raw ingredient.
What are propane's three drawbacks?Cons of propane heating
Compared to oil heating, propane produces fewer BTUs per gallon.Equipment that burns propane is frequently more expensive to buy than heating systems that use heating oil.To use the apparatus properly, care must be taken because propane is flammable in air.To know more about alkane :
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5. Calculate the heat energy required, in joules, to melt 5.00 x 10² grams of ice at 0.0°C.
Here is the Conclusion 240. Heat energy affects a substance’s intermolecular forces as the substance changes between states.
How to get the State changes?Heat energy increases during the following state changes
Solid - (melting)
Liquid -gas (evaporation)
Solid- gas (sublimation)
Heat energy decreases during the following state changes
Gas- liquid (condensation)
Liquid → solid (freezing)
Gas –solid (deposition)
An intermolecular force (IMF) (or secondary force) is the force that mediates the interaction of molecules, including electromagnetic forces of attraction or repulsion that act between atoms and other types of nearby particles, such as atoms or ions.
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The heat energy required, in joules, to melt 5.00 x 10² grams of ice at 0.0°C. 2016.6 J.
How does heat energy become created?When the temperature rises, molecules and atoms move faster and collide, creating heat generated (also known as heat energy). Thermal energy is the heat that results from heated substance's temperatures.
Calculation :The following phrase may be used to determine the change in heat energy in a process like melting.
S = H * m / T
where:
S = entropy [kJ]
H = fusion heat = 3.36*10¹ [J/kg]
m = mass = 0.02 [kg]
T = temperature in kelvin = 273 [K]
S = 0.02 * 5.00 * 10² / (273 + 0)
S = 2016.6 J
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The complete question is -
Calculate the heat energy of 5.00 * 10² g of ice when it melts at 0.0°C. The heat of fusion of ice is 3.36 x 10'J/kg.
What are the branches of multi national company called?
Explanation:
decentralized multinational corporations, centralised global corporations, international companies, and transnational enterprises.
Give the orbital configuration of the following elements using the s, p, d, f type representation. (Answer format is: 1se2
The orbital configuration of following elements is as follows: i) helium- 1 s² ii)nitrogen- 1 s² 2 s² 2 p³ iii)silicon-1 s² 2 s² 2 p⁶ 3 s² 3 p²
What are elements?It is defined as a substance which cannot be broken down further into any other substance. Each element is made up of its own type of atom. Due to this reason all elements are different from one another.
Elements can be classified as metals and non-metals. Metals are shiny and conduct electricity and are all solids at room temperature except mercury. Non-metals do not conduct electricity and are mostly gases at room temperature except carbon and sulfur.
The number of protons in the nucleus is the defining property of an element and is related to the atomic number. All atoms with same atomic number are atoms of same element.
Here,
The orbital configuration of following elements is as follows: i) helium- 1 s² ii)nitrogen- 1 s² 2 s² 2 p³ iii)silicon-1 s² 2 s² 2 p⁶ 3 s² 3 p²
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Calculate the percentage composition (by mass) of oxygen in K2SO4.
36.72 %
18.35 %
9.18 %
23.66 %
76.34 %
Answer:
it's option no A as described in the image
A calibrated flask was filled to the 25.00 mL mark with ethyl alcohol. By weighing the flask before and after adding the alcohol, it was determined that the flask contained 19.7325 g of alcohol. In a second experiment, 25.1060 g of metal beads were added to the flask, and the flask was again filled to the 25.00 mL mark with ethyl alcohol . The total mass of the metal plus alcohol in the flask was determined to be 38.6794 g.
The density of the metal beads, given that total mass of the metal plus alcohol in the flask was determined to be 38.6794 g is 3.22 g/mL
How do I determine the density of the metal beads?We'll begin by obtaining the density of the alcohol in the flask with the metal beads. This is illustrated below:
Mass of alcohol = 19.7325 gVolume of alcohol = 25 mLDensity = ?Density = mass / volume
Density of alcohol = 19.7325 / 25
Density of alcohol = 0.7893 g/mL
Next, we shall determine the volume of the alcohol in the 25 mL flask. This can be obtained as follow:
Density of alcohol = 0.7893 g/mLMass of metal beat = 25.1060 gTotal mass of metal beat and alcohol = 38.6794 gMass of alcohol in flask = 38.6794 - 25.1060 = 13.5734 gVolume of alcohol in flask =?Volume = mass / density
Volume of alcohol in flask = 13.5734 / 0.7893
Volume of alcohol in flask = 17.2 mL
Finally, we shall determine the density of the metal beads. Details below:
Mass of metal beat = 25.1060 gVolume of alcohol in flask = 17.2 mLVolume of flask = 25 mLVolume of metal beads = 25 - 17.2 = 7.8 mLDensity of metal beads =?Density = mass / volume
Density of metal beads = 25.1060 / 7.8
Density of metal beads = 3.22 g/mL
Thus, we can conclude that the density of the metal beads is 3.22 g/mL
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Complete question:
A calibrated flask was filled to the 25.00 mL mark with ethyl alcohol. By weighing the flask before and after adding the alcohol, it was determined that the flask contained 19.7325 g of alcohol. In a second experiment, 25.1060 g of metal beads were added to the flask, and the flask was again filled to the 25.00 mL mark with ethyl alcohol . The total mass of the metal plus alcohol in the flask was determined to be 38.6794 g. What is the density of the metal in g/mL?
What is the relationship between CO2 and O2 for sea urchins?
The relation between CO₂ and O₂ for sea urchins is impacted by the rise in carbon dioxide and oxygen is absorbed from the water.
The exoskeleton of sea urchins, which are found in the ocean, is comprised of calcium carbonate. They create calcium carbonate by absorbing the carbon dioxide from the water. As waste, they discharge carbon dioxide out of the anus.
The sea urchin takes its oxygen from the water. In the canals, oxygen diffuses. Oxygen diffuses into the cells from canals. The ocean's pH may rise as a result of the increased carbon dioxide. A higher pH has a deleterious impact on the calcification process. Therefore, the increased carbon dioxide has an impact on how the larvae and adults of sea urchins calcify.
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The compound NaCl consists of 60.7% chlorine. How many grams of chlorine can be obtained from 49.6 grams of NaCl?
Answer:92.1g
Explanation:
This means that the reaction consumed4.004moles NaCl⋅2 moles Na2moles NaCl=4.004 moles NaConvert this to grams by using the element's molar mass4.004moles Na⋅22.99 g1mole Na=92.1 g
86. Consider the carbon-nitrogen bonds shown below:
CEN and
Η
Η
|
H-C-N:
||
Η Η
Which bond is shorter? Which is stronger?
Answer: I belive it is HH to h-c-n
Explanation: yea
Ethylene burns in oxygen to form carbon dioxide and water vapor:
C2H4(g) + 3 02(g) --> 2 CO2(g) + 2 H2O(g)
How many liters of water can be formed if 1. 25 liters of ethylene at 1. 00 atm and 298K are
consumed in this reaction?
67.0L of H₂O can be formed if 1. 25 liters of ethylene at 1. 00 atm and 298K are consumed in this reaction.
What do you mean by mole?A mole is know to be the unit used in chemistry to measure the amount of a substance. It is defined as the amount of matter that contains as many atoms, molecules, or other particles as there are in 12 grams of carbon-12. Moles are a convenient way to measure large numbers of very small particles such as atoms, molecules, ions and electrons.
The molar volume of gas at 1.00 atm and 298 K is 22.41 L/mol.
Given that
2 moles of water are produced from 1 mole of ethylene,
The number of liters of water produced can be calculated with the following formula:
1.25 L C₂H₄ x (2 mol H₂O / 1 mol C₂H₄) x (22.41 L H₂O / 1 mol H₂O)
= 67.0 l H₂O
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to produce 4.00 L of a 250. mM solution of sodium hydroxide, how many grams of NaOH must bee dissolved
You may determine the number of moles of solution you need by multiplying the volume in liters (4.00L) by the solution's molar concentration (0.250M), and then by the mass of sodium hydroxide (39.99 g/mol) in molar form. 1L = 39.99g × 4.00L x 0.250 M x 39.99g
The number sodium hydroxide of moles of solute dissolved in one liter of a solution is known as its molarity.
where,
250 mM Molarity =
moles of solute = n
= liquid volume in milliliters = 4L = 4000 ml
Now, using the molarity formula to combine all the values provided, we obtain
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like tobacco smoke, the aerosol given off by an e-cigarette can contain dangerous chemicals.
The title "e-cigarettes," sometimes known as "electronic nicotine delivery systems" (ENDS) and infrequently "electronic non-nicotine delivery systems," refers to a wide range of distinct products (ENNDS).
By heating the liquid, these systems can produce aerosols that the user inhales. These so-called e-liquids typically contain additives, flavours, and chemicals that can be harmful to people's health, alongside nicotine (but no tobacco), which could or may not been present.
The deadly mixture of 7,000 hazardous substances in cigarette smoke is generally lower prevalent in e-cigarette aerosol than it is. 3 Aerosol produced e-cigarettes is not risk-free, though.
It may include toxic or carcinogenic drugs include tobacco, contaminants like lead, volatile compounds, and melanoma agents.
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Iron undergoes a synthesis reaction to form Iron (III) Oxide when it is heated in air.
Write the balanced chemical equation for this reaction. [2]
4 Fe(s) + 3 02(g) - 2 Fez03(s)
(Complete)
What amount of iron reacts with 15 mol of oxygen? [3]
What amount of iron (III) oxide is produced? [3]
If 4.60 g of iron (III) oxide is produced, what mass of iron is reacted? [3]
Ferric oxide, is the product that is formed when iron undergoes oxidation
What is the Reaction?Upon reacting with oxygen, iron will be oxidized to either the +3 oxidation state in iron (III) oxide, or to a combination of the +2 and +3 oxidation states in iron (II, III) oxide.The balanced chemical equations for these reactions look like this
#4”Fe”_text((s]) + 3”O”_text(2(g]) -> 2”Fe”””_2”O”_text(3(s])#
And
#3”Fe”_text((s]) + 2”O”_text(2(g]) -> “Fe”””_3”O”_text(4(s])#
The first compound, iron (III) oxide, also called ferric oxide, is dark red/brown in color
While the second compound, iron (II, III) oxide, also called ferrous ferric oxide, is dark brown/black in color.The [Fe(H2O)6]3+ ion is colorless (or pale pink), but many solutions containing this ion are yellow or amber-colored because of hydrolysis.
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Using your prior knowledge of reaction stoichiometry, what is the final percentage of each reactant remaining if each reaction went to completion? show work and reasoning to justify your answer
i) No reactant will be left as all of them have been converted to product after completion of this reaction.
ii) Final percentage of each reactant remaining if each reaction went to completion is about 99.9%.
What is molar ratio?The difference between the moles (or molecules) of reactants consumed and the moles (or molecules) of products produced in a chemical reaction is known as the molar ratio.
i) Now given the molar ratio of CV : NaOH is 1:1 . That means Equal moles of CV and NaOH are present in the solution. That means all the CV and NaOH molecules will react to form equal number of products.
So in this case, no reactant will be left as all of them have been converted to product after completion of reaction.
ii) In this case, the given NaOH : CV = 1000 : 1. That means per 1000 moles of NaOH, we have only 1 mole of CV. Now since 1 mole of CV can react with only 1 mole of NaOH, then after the reaction of this 1 mole CV, there will be no CV left . And only 999 NaOH molecules will be left in the solution
So here % CV left = 0%
% of NaOH left = 999 / 1000 × 100
% of NaOH left = 99.9 %
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Complete question is attached below
How can you deduce if a compound is optically active or not ?
Answer:
look for evidence that the molecules are chiral.
Explanation:
The instrument with which optically active compounds are studied is a polarimeter, shown in the figure below. Imagine a horizontal line that passes through the zero of a coordinate system.
in an experiment a piece of magnesium ribbon was cleaned with steel wool 2.4g of the clean ribbon was placed in a crucible and completely... In an experiment a piece of magnesium ribbon was cleaned with steel wool 2.4g of the clean ribbon was placed in a crucible and completely burnt in oxygen.after cooling the product weighted 4.0g. (a)explain why it was necessary to clean the magnesium ribbon? (b)what observation was made in the crucible after burning? (c)why was there an increase in mass? (d)write the equation for reaction which took place in the crucible? (e)the product in the crucible was shaken with water and filtered.
(a) It was necessary to clean the magnesium ribbon in order to remove any impurities or contaminants that might be present on the surface of the ribbon. These impurities could interfere with the burning process or alter the final products of the reaction.
(b) After burning, it is likely that an ash or residue was observed in the crucible.
(c) The increase in mass may be due to the production of new products during the burning process. These products may include magnesium oxide, which is a white solid, or other compounds formed through the reaction of magnesium with oxygen.
(d) The equation for the reaction that took place in the crucible is:
2Mg + O2 -> 2MgO
(e) When the product in the crucible is shaken with water, it is likely that any soluble products, such as magnesium hydroxide, will dissolve in the water. The remaining solid material can then be filtered out, leaving a solution containing the dissolved products.
The magnesium ribbon was cleaned to remove any impurities that could affect the reaction. After burning magnesium in oxygen, the resulting product is magnesium oxide, and the mass increases because the magnesium combines with the oxygen. The reaction equation is 2Mg + O2 -> 2MgO.
Explanation:(a) It was necessary to clean the magnesium ribbon with steel wool to remove any surface oxidation or impurities that could affect the reaction.
(b) After burning, an observation that could be made in the crucible would be a white ash-like substance, which is magnesium oxide.
(c) There was an increase in mass because when magnesium reacts with oxygen, it gains mass as it combines with the oxygen to form magnesium oxide.
(d) The equation for the reaction is: 2Mg + O2 -> 2MgO
(e) When the product in the crucible was shaken with water and filtered, this procedure would typically be used to isolate the product from any remaining unreacted magnesium or other reaction by-products.
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