2,520
Estimate 627 to 630
3.73's closest estimate is 4
So, 630*4=2,520
Evaluate the expression for the given variable 4y-12, when y =7
Answer:
16
Step-by-step explanation:
y = 7
4(7)-12
28-12 = 16
Domain:
Range:
HELP I BEG
It takes Shawn 4 more hours to stain a deck than Michelle. Together it takes them 4.8 hours to complete the work. How long would it take Shawn to stain the deck by himself?
Answer:
4.4 hours
Step-by-step explanation:
It would take Shawn 4.4 hours, as this would give a time of .4 hours to Michelle, totaling 4.8 hours
To get in shape for the upcoming track season two brothers, Scott and Brian, begin running home after school. Scott runs at a rate of 6 mph and Brian runs at a rate of 4 mph. If they leave school at the same time, Scott arrives home a half-hour before Brian. How long does it take Brian to get home from school
It takes Brian 1.5 hours to get home from school
Speed is the ratio of distance travelled to time taken. It is given by:
Speed = distance / time
Let d represent the distance from their school to the house and t represent the time (hours) it takes Brian to teach home.
For Brian:
4 = d/t
d = 4t
For Scott:
6 = d / (t - 1/2)
d = 6t - 3
4t = 6t - 3
2t = 3
t = 1.5 hours
Therefore it takes Brian 1.5 hours to get home from school
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Y = ___x + ____
Find the equation of the line.
Differentiate the function
Answer:
[tex]-\frac{9}{r^4}[/tex]
Step-by-step explanation:
Using Power rule
[tex]\frac{d}{dr} (r^n)=nr^{n-1}\\-\frac{9}{r^4}[/tex]
The answer is F'(r) = [tex]\mathrm {-\frac{9}{r^{4}}}[/tex].
We can rewrite the function as :
F(r) = 3r⁻³
Now, differentiate by power rule :
F'(r) = (-3)3r⁻³⁻¹
F'(r) = -9r⁻⁴
F'(r) = -9/r⁴
5(9/12−1/4)+0.5 pls answer correctly
Answer:
3
Step-by-step explanation:
5(9/12 -1/4) +0.5
= 5(9/12 -3/12) +1/2 . . . . . . express the fractions using a common denominator
= 5(6/12) +1/2 . . . . . . . add the fractions
= 5(1/2) +1/2 . . . . . . reduce the result
= (5 +1)(1/2) . . . . factor out 1/2 (easier than adding mixed numbers)
= 6/2 = 3
_____
A calculator can be a useful tool for evaluating numerical expressions.
Need help with this assignments
Given values:-
P= 0.97
V= 2.85
R= 0.082
T= 295
n= ?
we have given formula,
PV=n RT
so,
n = PV/RT
[tex]n = \frac{0.97 \times 2.85}{0.082 \times 295} \\ = \frac{2.7645}{24.19} \\ = 0.1142 \\ = 0.11[/tex]
0.11 is your answer.
How much would $125 invested at 8% interest compounded continuously be
worth after 16 years? Round your answer to the nearest cent.
A(t)= Poet
A. $428.24
B. $285.00
C. $449.58
D. $367.26
c$449.58
hfufhfthcuxjyfus4hxtstcyztf
–4x – 5 + 2x = –11
i need help solving for x in this equation
Answer:
x is 3
Step-by-step explanation:
-2x is -6
2x is 6
x is 3
Answer:
X=3
Step-by-step explanation:
-4(3)=-12
-12-5=-17
2(3)=6
-17+6=-11
The janitor at a school discovered a leak in a pipe. The janitor found that it was leaking at a rate of 7 fl oz per minute. How fast was the pipe leaking in gallons per hour? PLLLLLLLLLLLLZZZZZZZZZZZ
Answer:
It leaks 420 gallons per hour.
Step-by-step explanation:
7g/m
?/h
7/1 = x/60
(Cross Multiplication)
7 × 60 = x × 1
420 = x
It leaks 420 gallons per hour.
Answer:
3.28 gallons per hour
Step-by-step explanation:
Given that the pipe is leaking at a rate of 7 fluid ounce per minute, and that we need to determine the equivalent leaking rate in gallons per hour. It is important to establish the necessary conversion rates of fluid ounces (fl oz) to gallons (gal), and minutes to an hour.
Conversion rate for fluid ounces (fl oz) to 1 gallon (gal): 128 fl oz = 1 galConversion rate of minutes to hour: 60 minutes = 1 hour.Now that we have established the conversion rates, we can set up the following mathematical operations that will allow us to convert the leaking rate from fluid ounces per minute, to gallons per hour. We can express the conversion process in fraction form:
[tex](\frac{7 fl. oz.}{min})[/tex] × [tex](\frac{1 gal}{128 fl. oz.})[/tex] × [tex](\frac{60 min}{1 hr})[/tex]
Start by multiplying the first two fractions together:
[tex](\frac{7 fl. oz.}{min})[/tex] × [tex](\frac{1 gal}{128 fl. oz.})[/tex] = 0.546875 gallons per minute, or 0.546875 gal/min
Next, multiply 0.546875 gal/min by 60 min/hr. This cancels out the "minute" as a unit of measurement, leaving you with gal/hr.
[tex](\frac{0.546875 gal}{min})[/tex] × [tex](\frac{60 min}{1 hr})[/tex] = 3.28125 gallons per hour, or 3.28 gal/hr.
Therefore, the pipe is leaking at a rate of 3.28 gallons per hour.
PLEASE HELP BRAINLEST TO WINNER!!!!!!!
The coordinates of a point on a coordinate grid are (−1, 5). The point is reflected across the x-axis to obtain a new point. The coordinates of the reflected point are
(1, −5)
(−1, 5)
(1, 5)
(−1, −5)
(-1, -5)
x-axis is to flip the y - coordinates
y-axis is to flip the x - coordinates
Please help please please help me please help please please
Answer:
y - 6 = -3 ( x - 7)
Step-by-step explanation:
Use one of the points.
m is the slope
Y - Y1 = m(X - X1)
y - 6 = -3(x - 7)
y - 6 = -3x + 21
y - 6 + 3x - 21 = 0
y - 27 + 3x = 0
3x + y - 27 = 0
it is the onion of set of whole numbers and the opposition of the set counting or natural numbers A. integers B. inverse C. Positive D. Negative
integers is your answer
PLEASE HELP ME
It snowed 2/3 of a foot in January and 1/2 of a foot in February. How much more did it snow in January than in February?
Answer:
Step-by-step explanation:
2/3 - 1/2 ?=?
4/6 - 3/6 = 1/6 ft more
a. What is the probability that this couple spends 45 dollars or more?
b. Suppose that the restaurant is currently running a promotion with a 10% discount if the total amount spent by a table is 45 dollars or more. What is expected total amount the couple actually has to pay?
Using the probability table, it is found that:
a) There is a 0.25 = 25% probability that this couple spends 45 dollars or more. b) The expected amount the couple actually has to pay is $36.85.Item a:
To find the probabilities involving the total cost, we have to add the variables X and Y from the table, then:
[tex]P(X = 30) = P(X = 15|Y = 15) = 0.2[/tex]
[tex]P(X = 35) = P(X = 15|Y = 20) + P(X = 20|Y = 15) = 0.15 + 0.15 = 0.3[/tex]
[tex]P(X = 40) = P(X = 15|Y = 25) + P(X = 20|Y = 20) + P(X = 25|Y = 15) = 0.05 + 0.15 + 0.05 = 0.25[/tex]
[tex]P(X = 45) = P(X = 20|Y = 25) + P(X = 25|Y = 20) = 0.1 + 0.1 = 0.2[/tex]
[tex]P(X = 50) = P(X = 25|Y = 25) = 0.05[/tex]
The probability involving values of 45 or more is:
[tex]P(X \geq 45) = P(X = 45) + P(X = 50) = 0.2 + 0.05 = 0.25[/tex]
0.25 = 25% probability that this couple spends 45 dollars or more.
Item b:
For a discrete distribution, the expected value is the sum of each outcome multiplied by it's respective probability, hence, involving the 10% discount for prices above $45:
[tex]E(X) = 0.2(30) + 0.3(35) + 0.25(40) + 0.9[0.2(45) + 0.05(50)] = 36.85[/tex]
The expected amount the couple actually has to pay is $36.85
A similar problem is given at https://brainly.com/question/25782059
7.
Find all solutions to the following triangle. (Round your answers for angles A, C, A', and to the nearest minute. Round your answers for sides a and a'to two decimal places. If either triangle is not
possible, enter NONE In each corresponding answer blank.)
B = 65° 20', b = 5.38 inches, c = 4.88 inches
First triangle (assume C greater than or equal to 90°):
A= ____ degrees ____’
C=____ degrees ____’
a= ____ in
The measures of the angles and the lengths of the sides of the triangle can
be found using sine rule.
The correct responses are;
A = 59 degrees 9'C = Nonea = 5.083 in.Reasons:
The given parameter are;
∠B = 65°20', b = 5.38 inches, c = 4.88 inches
∠C ≥ 90°
By sine rule, we have;
[tex]\dfrac{5.38}{sin(65^{\circ} 20')} = \mathbf{ \dfrac{4.88}{sin(\angle C)}}[/tex]
[tex]sin(\angle C) = \mathbf{ \dfrac{sin(65^{\circ} 20') \times 4.88}{5.38}}[/tex]
[tex]\angle C = arcsin \left(\dfrac{sin(65^{\circ} 20') \times 4.88}{5.38} \right) \approx \mathbf{ 55.517 ^{\circ}}[/tex]
∠C = 55.517° < 90°, therefore, the correct response is; None
[tex]\dfrac{sin(65^{\circ} 20')}{5.38} = \dfrac{4.88}{sin(\angle C)}[/tex]
∠A = 180° - 65°20' - 55.517° = 59.15° = 59°9'
∠A = 59°9'
Therefore;
[tex]\dfrac{5.38}{sin(65^{\circ} 20')} = \mathbf{ \dfrac{a}{sin(59.15^{})}}[/tex]
[tex]a = \dfrac{5.38 \times sin(59.15^{\circ}) }{sin(65^{\circ} 20')} \approx \mathbf{ 5.083}[/tex]
a ≈ 5.083 inches
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What is the measure of QTR?
What is the measure of PTR?
Answer:
QTR is 36
PTR is 62
Step-by-step explanation:
P+R+T=180
hint: 180 *
1. Find the missing angle.
29
R
61
T
Answer:
∠ R = 90°
Step-by-step explanation:
The sum of the 3 angles in a triangle = 180° , that is
∠ R + ∠ S + ∠ T = 180° , substitute values
∠ R + 29° + 61° = 180°
∠ R + 90° = 180° ( subtract 90° from both sides )
∠ R = 90°
I Need help with 4-7
Answer:
Step-by-step explanation:
4) parallel because 118° is a supplement to 62° and the corresponding angles are both 118°
5) NOT parallel. The labeled angles sum to 120° and would sum to 180° for parallel lines.
6) NOT parallel. see pic.
If parallel, extending a line to intersect ℓ₁ makes an opposite internal angle which would also be 48°. The created triangle would have its third angle at 180 - 90 - 48 = 42° which is opposite a labeled 48° angle, which is false, so the lines cannot be parallel
7)
b = 78° as it corresponds with a labeled angle above it
a = 180 - 78 = 102° as angles along a line from a common vertex sum to 180
f = is an opposite angle to 180 - 78 - 44 = 58° as angles along a line from a common vertex sum to 180
e = 180 - 90 - 64 = 26° as angles along a line from a common vertex sum to 180
c = 58° as it corresponds with f
d = 180 - 58 = 122° as angles along a line from a common vertex sum to 180
Donny jumped from a rock into a lake. The rock is 35 feet above water. He dove 15 feet below the surface of the water. His brother says he traveled 20 feet in all. Donny says he traveled 50 feet in all. Who correct?
B. Hanapin ang sagot (quotient) gamit ang paghahati-hati. (1 puntos bawat bilang = 5 puntos) 26.4)448 27.800 + 10 = 1 28. 3)663 = 29.56 + 8 = 30. 120 + 6 =
answer :
120 + 6 = 126
explanation:
sa calculator lang yan haha jk
pero yan talaga ang sagot promise hindi ako ng bo-bola haha stay safe and stay positive na lang huwag lang sa c o vi d
Explain two ways you can benchmark percents to find 60% of 280
Answer:
The most common benchmark percents are 0%, 10%, 25%, 50%, 75% and 100%.
To find 60% of 280 we first find 10% of 280 which is 28. 6 x 28 = 168.
To find 60% of 280 we first find 50% of 280 which is 140. Now we add 10% which we calculated before: 140 + 28 = 168.
Answer:
Step-by-step explanation:
Explain two ways you can benchmark percents to find 60% of 280
1) 280 : 100 * 60 = 168
2) 280 * 0.6 = 168
The Bruce family set out 8 0’clock in the morning. They arrived at the old port of Ambertini at 09:05. How long their journey took?
pls
Answer:
1hr 5 minutes
Step-by-step explanation:
9hrs 5mins-8 hrs=1 hr 5 mins
mark me brainliest plz if you are helped
elect all the correct answers.
A group of scientists is conducting an experiment on the effects of media on children. They randomly select 100 children and randomly assign each child to one of four treatment groups. Each treatment group has a specific amount of screen time during a one-week time frame. The first group has no screen time, the second group has two hours of screen time, the third group has four hours of screen time, and the fourth group has six hours of screen time.
After the first week, the scientists conduct the same experiment, with the same subject groups, for three more weeks so that each group experiences each of the four treatments.
Which statements about this study are true?
This study uses blinding.
This study uses blocking.
This study uses a control group.
This study uses a repeated measures design.
This study uses random sampling.
this study uses random sampling
this study uses a control group
this study uses a repeated measures design
plato/edmentum
Answer:
This study uses a control group. This study uses a repeated measures design.
Sarah took the advertising department from her company on a round trip to meet with a potential client. Including Sarah a total of 8 people took the trip. She was able to purchase coach tickets for $160 and first class tickets for $950. She used her total budget for airfare for the trip, which was $3650. How many first class tickets did she buy? How many coach tickets did she buy?
Answer:
Money for coach tickets is $1280 and money for first class is $7600
Step-by-step explanation:
8 x 160 = 1280
8x 950 = 7600
I am having a hard time on solving this question x4−85=−92 does someone know how to explain it?
Answer:
X equals positive -1.75
Step-by-step explanation:
because X is muliplying by the common number attached to it (4)
-1.75 times 4 equals -7
thus being -7-85= -92
Answer:
well you have to solve for X so -1.75 times 4 equals -7 then solve. so your answer would be- X equals positive -1.75
The width of a triangle is six more than twice the height. The area of the triangle is 88in2. Find the height and width of the triangle.
Answer:
w = 22 in, h = 8 in.
Step-by-step explanation:
Reading the problem, I immediately see two equations. This hints me towards a system of equations problem.
Statement 1 is The width of a triangle is six more than twice the height.
The width (w) of a triangle is (=) six (6) more (+) than twice (2) the height (h).
Equation 1: w = 6 + 2h
Statement 2 is The area of the triangle is 88 in2.
The formula for the area of a triangle is [tex]\frac{wh}{2}[/tex]. So, we get our second equation.
Equation 2: wh/2 = 88
We see that we have the same number of equations as unknowns, two. This is important as it lets us know that we can find two unknowns in the two equations. If there are more unknowns than equations, then we cannot find the values of all the variables. Look for another equation in the problem. However, if the # equations greater than or equal to number of unknowns, then we are ready to start solving! So, we can now move to solving.
Equation 1 isolates one of the unknowns (w). So, we can replace w in the second equation with the right side of eq 1. Then, we simplify for h.
[tex]\frac{wh}{2} = 88[/tex]
[tex]\frac{(6 + 2h)h}{2} = 88[/tex]
[tex]\frac{6h + 2h^2}{2} = 88[/tex]
[tex]6h + 2h^2 = 176[/tex]
[tex]2h^2 + 6h - 176 = 0[/tex]
[tex]h = -11, 8[/tex] (assuming you know how to solve quadratics)
Since we know that heights of triangles cannot be negative, we find that [tex]h = 8[/tex] in.
For the final step, we plug [tex]h[/tex] into our first equation to find [tex]w[/tex].
[tex]w = 6 + 2h[/tex]
[tex]w = 6 + 2(8)[/tex]
[tex]w = 6 + 16[/tex]
[tex]w = 22[/tex]
So, the answer is w = 22 in, h = 8 in.
To check if we were right, we can plug the values into both equations to see if they are equal. I will skip equation 1 since we used that equation "as-is" to find w.
[tex]\frac{wh}{2} = 88[/tex]
[tex]\frac{22 * 8}{2} = 88[/tex]
[tex]11 * 8 = 88[/tex]
[tex]88 = 88[/tex]
The solution checks out!
1. Identify the place value for the following: 162.891
Answer:
Hundreds : 1
Tens : 6
Ones : 2
.
Tenths : 8
Hundredths : 9
Thousandths : 1
[tex]{ \pink{ \displaystyle\tt \int_{0}^{1} \int_{0} ^{ x_{1}} } \sf \pink\int_{ 0 }^{x_{2}... \int_{ 0 }^{x_{99}}} ln(1 -x_{100} ) dx_{100}... dx_{1}}[/tex]
︎︎︎︎︎︎︎
Step-by-step explanation:
[tex]\small{ \displaystyle\tt \int_{0}^{1} \int_{0} ^{ x_{1}} \int_{ 0 }^{x_{2}}... \int_{ 0 }^{x_{99}} ln(1 -x_{100} ) dx_{100}... dx_{1}}[/tex]
[tex]\small{{ \displaystyle\tt = - \int_{0}^{1} \int_{0} ^{ x_{1}} \int_{ 0 }^{x_{2}}... \int_{ 0 }^{x_{98}} \sum_{n = 1}^{ \infty \frac{}{} \frac{}{} } \frac{1}{n} \int_{0}^{x_{99}} {x}^{n}_{100} \: dx_{100}...dx_{1} }}[/tex]
[tex]{{ 0 }^{x_{98}} \frac{{x}^{n + 1}_{99}}{n + 1} \: dx_{99}...dx_{1} }[/tex]
[tex]\small{ \displaystyle\tt = -\sum_{n = 1}^{ \infty \frac{}{} \frac{}{} } \frac{1}{n}\int_{0}^{1} \int_{0} ^{ x_{1}} }[/tex]
[tex]\displaystyle \tt= - \frac{1}{(100)!_{} } \sum_{n = 1}^{ \infty } \frac{(n - 1)!(100)!}{(n + 101)!}=−(100)!1n=1∑∞(n+101)!(n−1)!(100)![/tex]
[tex]\displaystyle \tt= - \frac{1}{(100)!_{} } \sum_{n = 1}^{ \infty} \int_{0}^{1} {x}^{n - 1} (1 - x {)}^{100} [/tex]
[tex]\displaystyle \sf - \dfrac{1}{(100!)} \int_{0}^{1} \dfrac{(1 - x)^{100} }{1 - x} \:[/tex]
[tex]\displaystyle\tt { = - \frac{1}{(100)!} \int_{0}^{1} {x}^{99} \: dx=−(100)!1∫01x99dx}
[/tex]
Step-by-step explanation:
[tex]{ \pink{ \displaystyle\tt \int_{0}^{1} \int_{0} ^{ x_{1}} } \sf \pink\int_{ 0 }^{x_{2}... \int_{ 0 }^{x_{99}}} ln(1 -x_{100} ) dx_{100}... dx_{1}}[/t
︎︎︎︎︎︎︎
Goal 1000 points