Evaluate g(t) for the given values of t.

g(t)=|17-t|

A)g(11)=
B)g(12)=

Answer:

The answer to the question provided is 53°.

Answer: There are no values of x that make the equation true. No solution.

Answer:

SSA (or AS*)

Step-by-step explanation:

SSA cannot booe used

just remember that

First, we see a rectangle shape with little squares in it. The length is 5 and the width is 4. If we multiply them, we get 20 square units. However, we will use the 20 to solve the question. Also, we see that there are only 3 squares.

3/20

Let's divide the fraction. 3 / 20 is 0.15. We result with 0.15. Now, we multiply  the decimal by 100 to get a percent; we are converting from decimal to percent. As a result, we get 15% as our answer.

3/20 = 0.15 x 100 = 15%

Answer:

C: Two solutions

Step-by-step explanation:

If you try to solve the problame you can find to solution's

Hope this Help's

Answer:

lol too bad laurenercsp6fpli

Step-by-step explanation:

Answer:

The equation of line that passes through point (2,-1) and has a slope of -3 is [tex]\mathbf{y=-3x+5}[/tex]

Option A is correct.

Step-by-step explanation:

We need to write equation of line that passes through point (2,-1) and has a slope of -3

The equation is written in slope-intercept form: [tex]y=mx+b[/tex] where m is slope and b is y-intercept.

We are given slope: m = -3

We need to find y-intercept (b)

Using the point (2,-1) and slope m=-3, we can find y-intercept

[tex]y=mx+b\\-1=-3(2)+b\\-1=-6+b\\b=-1+6\\b=5[/tex]

So, we get y-intercept b = 5

Now, the required equation having slope m =-3 and y-intercept b = 5 will be:

[tex]y=mx+b\\y=-3x+5[/tex]

So, the equation of line that passes through point (2,-1) and has a slope of -3 is [tex]\mathbf{y=-3x+5}[/tex]

Option A is correct.

Answer:

For 1. it's 13 degrees 2. For B it is 15 degrees.

Step-by-step explanation:

thats all i could really answer you should try separating this a little more

Answer:

26

Step-by-step explanation:

7x - 28 = 5x + 12 and 5x + 12 + y = 180

The angle (7y - 28) and angle y are supplementary angles which means their sum is 180°

7y - 28 + y = 180 add like terms

8y - 28 = 180 add 28 to both sides

8y = 208 divide both sides by 8

y = 26

Answer:

The answer is c

Step-by-step explanation:

Answer:the answer is c mark me brainiest remember  

Step-by-step explanation:

Answer:

Step-by-step explanation:

1) AC⊥BD and BD bisects AC                         1) given

2) AD≅DC                                                        2) linear bisector thm.

3) ∠ADB and ∠CDB are right angles              3) perpendicular bisector thm.

4) ∠ADB ≅ ∠CDB                                             4) all right ∡'s are congruent

5) BD ≅ BD                                                       5) reflexive POV

6) ΔABD ≅ ΔCBD                                             6) SAS

Hope this helps!

btw, I was not able to put the lines on top of some of the letters, so my apologies.

Answer:

The correct answer is: Option 1: x≤-3

Step-by-step explanation:

Given inequality is:

[tex]-6x-4\geq -2(x-4)[/tex]

First of all, we will distribute -2 into the bracket

[tex]-6x-4\geq -2x+8[/tex]

Then we will add 4 on both sides

[tex]-6x-4+4\geq -2x+8+4\\-6x \geq -2x+12[/tex]

Adding 2x on both sides

[tex]-6x+2x\geq -2x+12+2x\\-4x\geq 12[/tex]

Dividing both sides by 4

[tex]\frac{-4x}{4} \geq \frac{12}{4}\\-x \geq 3[/tex]

As there should be only x on the left side of the inequality we will multiply the inequality with -1.

Multiplying the inequality with -1 reverses the sign of inequality

So,

[tex]x \leq -3[/tex]

Hence,

The correct answer is: Option 1: x≤-3

Answer:

[tex]y = -2[/tex]

Step-by-step explanation:

Given

Horizontal Line

[tex](x_1,y_1) = (4,-2)[/tex]

Required

Determine the equation

The equation is calculated using:

[tex]y - y_1 =m(x-x_1)[/tex]

Where

[tex]m = slope[/tex]

Because the line is a horizontal line, then:

[tex]m = 0[/tex]

Substitute 0 for m and values for x1 and y1 in [tex]y - y_1 =m(x-x_1)[/tex]

[tex]y - (-2) = 0(x -4)[/tex]

[tex]y +2 = 0(x -4)[/tex]

[tex]y +2 = 0[/tex]

Subtract 2 from both sides

[tex]y +2-2 = 0-2[/tex]

[tex]y = -2[/tex]

Hence, the equation is: [tex]y = -2[/tex]

Answer:

1

Step-by-step explanation:

1212112

Answer:

37.5%

Step-by-step explanation:

Answer:

The greatest common factor of 6x(z + 14)+(z + 14) is 1

and if you want it in factored form it is (z + 14)(6x + 1)

Answer:

1. 3 x 2 = 6 / 4 x 3 = 12 = 6/12 [simplify] = 1/2 thats the first answer, just do how i did it to get the others, its pretty simple

Answer:

c is the answer to this

Step-by-step explanation:

Answer:

[tex] \frac{1}{6} [/tex]

Step-by-step explanation:

[tex] \frac{2}{3} \times \frac{2}{8} = \frac{2 \times 2}{3 \times 8} = \frac{4}{24} [/tex]

Lets divide the numerator and denominator with 4.

[tex] = > \frac{4 \div 4}{24 \div 4} = \frac{1}{6} [/tex]

Answer:

2 4/12

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

Number cube, 5, and 3/16

Answer:

its a scale factor of 4

Step-by-step explanation:

Answer:

edfsefesfwefwefwf

Step-by-step explanation:

fwefewfweefwefwefwefewfwefwefwefwef

Answer:

372/12=31

31mpg

Step-by-step explanation:

This question is incomplete, the complete question is;

Consider a set of data in which the sample mean is 73.4 and the sample standard deviation is 4.9. Calculate the z-score given that x  = 69.5.

Round your answer to two decimal places.

Answer: the z-score is -0.80

Step-by-step explanation:

Given that;

mean μ = 73.4

standard deviation σ = 4.9

x = 69.5

z-score = ?

z = (x - μ) / σ

we substitute

z =  (69.5 - 73.4) / 4.9

z = -3.9 / 4.9

z = - 0.7959 ≈ -0.80    { 2 decimal places }

Therefore, the z-score is -0.80

Answer:

9,000

Step-by-step explanation:

Answer:

633

Step-by-step explanation:

(a) Applying T to p(t) = 2 - t + t ² gives

T ( p(t) ) = (t - 2) (2 - t + t ²) = -4 + 4t - 3t ² + t ³

(b) T is a linear transformation if for any p(t) and q(t) in P₂ and complex scalars a and b, the image of any linear combination of p and q is equal to the linear combination of the images of p and q. In other words,

T ( a p(t) + b q(t) ) = a T ( p(t) ) + b T ( q(t) )

Let

p(t) = α₀ + α₁ t + α₂ t ²

q(t) = β₀ + β₁ t + β₂ t ²

Compute the images of p and q :

T ( p(t) ) = (t - 2) (α₀ + α₁ t + α₂ t ²)

… = -2α₀ + (α₀ - 2α₁) t + (α₁ - 2α₂) t ² + α₂ t ³

Similarly,

T ( q(t) ) = -2β₀ + (β₀ - 2β₁) t + (β₁ - 2β₂) t ² + β₂ t ³

Then

a T ( p(t) ) + b T ( q(t) ) = a (-2α₀ + (α₀ - 2α₁) t + (α₁ - 2α₂) t ² + α₂ t ³) + b (-2β₀ + (β₀ - 2β₁) t + (β₁ - 2β₂) t ² + β₂ t ³)

… = c₀ + c₁ t + c₂ t ² + c₃ t ³

where

c₀ = -2 (a α₀ + b β₀)

c₁ = a (α₀ - 2α₁) + b (β₀ - 2β₁)

c₂ = a (α₁ - 2α₂) + b (β₁ - 2β₂)

c₃ = a α₂ + b β₂

Computing the image of a p(t) + b q(t) would give the same result; just multiply it by t - 2 and expand. This establishes that T is indeed linear.

(c) Find the image of each vector in the basis for P₂ :

T (1) = (t - 2) × 1 = t - 2

T (t ) = (t - 2) t = t ² - 2t

T (t ²) = (t - 2) t ² = t ³ - 2t ²

Then

[tex]T=\begin{bmatrix}-2&0&0\\1&-2&0\\0&1&-2\\0&0&1\end{bmatrix}[/tex]