The reaction between N2O4 and is at equilibrium at this time.2 Given by K = 0.028 is NO2. The amount of NO2 in the sample is 0.042 M.
K = [NO2] is the equilibrium expression for the reaction.²/[N₂O₄] When K and [NO2] are substituted in the equilibrium expression, we obtain 0.028 = (0.042).²/[N₂O₄]
We get at [N2O4] = 0.028/0.0422 = 0.0075 M after solving for [N2O4].
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Please show all the work
1- How many grams are in 12.3 moles of Dinitrogen Pentoxide?
2-How many grams are in 2.7 moles of Iron (III) Nitrate? (Fe(NO3)3)
3- How many grams are in 0.16 moles of Sucrose? (C12H22011)
4- How many grams are in 0.87 moles of Potassium Iodide? (KI)
We haver the mass from the moles of each of the compounds below.
Number of moles1) Mass/Molar mass = number of moles
=Mass = Molar Mass * Molar Number
= 12.3 moles x g/mol 108
= 1328.4 g
2) Mass/Molar mass = number of moles
=Mass = Molar Mass * Molar Number
2.7 moles times 242 g/mol
= 653 g
3)) Molar mass divided by the number of moles
=Mass = Molar Mass * Molar Number
= 3.42 g/mol * 0.16 moles
= 54.72 g
4) Moles = mass / molecular mass
=Mass = Molar Mass * Molar Number
= 166 g/mol * 0.87 moles
= 144 g
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Look at the situations below and determine which ones are examples of weathering. Select ALL that apply.
Wind blows rocks, sand, and dirt away
A river carries rocks and sand downstream,
Plant roots break rocks apart
Rain wears rocks down
Wind wears rocks down
Water dissolves limestone
Rainwater washes dirt and rock downhill
Weathering processes, both physical and chemical, break down rocks into smaller particles that mix with organic matter to form soil. Physical weathering, such as freeze-thaw cycles, root growth, and abrasion, mechanically break rocks into smaller fragments.
Chemical weathering, such as oxidation, dissolution, and hydrolysis, alters the mineral composition of rocks and releases nutrients for plant growth. The products of weathering, such as clay minerals and soluble salts, affect soil properties like texture, structure, porosity, and nutrient availability. Weathering also affects the pH of soil, which influences the solubility and availability of nutrients. Overall, weathering plays a critical role in soil formation and the availability of nutrients for plant growth.
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--The complete Question is, How does the process of weathering, such as the physical and chemical breakdown of rocks, affect the composition and properties of soil?--
Find the pressure of the gas
Please!!
Answer:
Gas pressure= 766.4 mmHg
Explanation:
Gas pressure greater than atmospheric pressure = Atmospheric pressure + height
750.0 mmHg + 26.4 cm = 766.4 mmHg
In which set of apparatus A-D in the figure would the metal key be electroplated with copper?
Answer:
the answer is the option C
If 7.50 g of ammonia hydroxide react, how many moles of ammonia will be produced?
The balanced chemical equation for the reaction of ammonia hydroxide (NH4OH) producing ammonia (NH3) is:
NH4OH → NH3 + H2O
The equation shows that 1 mole of NH4OH produces 1 mole of NH3.
To determine the number of moles of NH3 produced from 7.50 g of NH4OH, we need to first calculate the molar mass of NH4OH:
NH4OH = 1 x 14.01 (atomic mass of N) + 4 x 1.01 (atomic mass of H) + 1 x 16.00 (atomic mass of O) = 35.05 g/mol
Next, we can use the following formula to calculate the number of moles:
moles = mass / molar mass
moles of NH4OH = 7.50 g / 35.05 g/mol = 0.214 mol
Since 1 mole of NH4OH produces 1 mole of NH3, the number of moles of NH3 produced is also 0.214 mol.
Therefore, 7.50 g of NH4OH produces 0.214 moles of NH3.
The acid-dissociation constant for benzoic acid (C6H5COOH) is 6.3×10−5.
Equilibrium concentration of C₆H₅COO⁻ in the solution is calculated as 2.008 × 10⁻⁴ M.
What is meant by acid-dissociation constant?Measure of the strength of acid in any solution is called acid-dissociation constant.
The dissociation reaction of benzoic acid (C₆H₅COOH) in water can be represented as follows: C₆H₅COOH + H₂O ⇌ C₆H₅COO⁻ + H₃O⁺
Ka = [C₆H₅CO⁻][H₃O⁺] / [C₆H₅COOH]
Ka = [C₆H₅COO⁻][H₃O⁺] / [C₆H₅COOH]
6.3 × 10⁻⁵ = [C₆H₅COO⁻[H₃O⁺] / 0.0064
[C₆H₅COO-][H₃O⁺] = 6.3 × 10⁻⁵ × 0.0064
[C₆H₅COO⁻][H3O⁺] = 4.032 × 10⁻⁷
[C₆H₅COO⁻] = x
[H₃O⁺] = x
x² = 4.032 × 10⁻⁷
x = √(4.032 × 10⁻⁷)
x = 2.008 × 10⁻⁴
Therefore, the equilibrium concentration of C₆H₅COO⁻ in the solution is 2.008 × 10⁻⁴ M.
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Complete the balanced molecular chemical equation for the reaction below. If no reaction occurs, write NR after the reaction arrow. Be sure to include the proper phases for all species within the reaction.
ZnC|2(aq) + Hgz(NOs)2(aq)—>
Zinc carbonate reacts with hydrogen nitrate in the following balanced chemical equation: 2ZnCO3(aq) + HNO3(aq) 2Zn(NO3)2(aq) + CO2(g) + H2O(l). The reactant on the left side of the equation is the solid zinc carbonate (ZnCO3).
The reactant on the right side of the equation is an aqueous solution of hydrogen nitrate (HNO3). The end results are water (H2O), carbon dioxide (CO2) as a gas, and zinc nitrate (Zn(NO3)2) also in an aqueous solution. For a reaction to take place, each of the reactants and products must be in the appropriate phase.
The mole ratio of the reactants is 1:1, hence each species' coefficient in the balanced equation must be equal. The coefficient in the balanced equation is two.
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5g of Zinc is reacted with excess hydrochloric acid. The equation for the reaction is:
Zn + HCI -> ZnCl2 + H₂
a. Balance this chemical equation then write down Ar, Mr and Given mass.
b. Calculate the mass of zinc chloride formed
c. Calculate the volume of hydrogen gas produced
Given: Zn = 65, H = 1, C1 = 35.5, 2g of H2 has 22.4L
A. The balanced equation is: Zn + 2HCI -> ZnCl₂ + H₂
B. The mass of zinc chloride formed is 10.43 g
C. The volume of hydrogen gas produced is 1.68 L
B. How do i determine the mass zinc chloride formed?First, we shall write the balanced equation for the reaction. This is given below:
Zn + 2HCI -> ZnCl₂ + H₂
Now, we shall determine the mass of zinc chloride, ZnCl₂ formed. Details below:
Zn + 2HCI -> ZnCl₂ + H₂
Molar mass of Zn = 65.38 g/molMass of Zn from the balanced equation = 1 × 65.38 = 65.38 g Molar mass of ZnCl₂ = 136.38 g/molMass of ZnCl₂ from the balanced equation = 1 × 136.38 = 136.38 gFrom the balanced equation above,
65.38 g of Zn reacted to produce 136.38 g of ZnCl₂
Therefore,
5 g of Zn will react to produce = (5 × 136.38) / 65.38 = 10.43 g of ZnCl₂
Thus, the mass of ZnCl₂ formed is 10.43 g
C. How do i determine the volume of hydrogen gas produced?First, we shall obtain the mass of hydrogen gas produced. Details below:
Zn + 2HCI -> ZnCl₂ + H₂
Molar mass of Zn = 65.38 g/molMass of Zn from the balanced equation = 1 × 65.38 = 65.38 g Molar mass of H₂ = 2 g/molMass of H₂ from the balanced equation = 1 × 2 = 2 gFrom the balanced equation above,
65.38 g of Zn reacted to produce 2 g of H₂
Therefore,
5 g of Zn will react to produce = (5 × 2) / 65.38 = 0.15 g of H₂
Finally, we shall determine the volume of H₂ produced. Details below:
2 g of H₂ = 22.4 L
Therefore
0.15 g of H₂ = (0.15 g × 22.4 L) / 2 g
0.15 g of H₂ = 1.68 L
Thus, the volume of H₂ produced is 1.68 L
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15kg of iron (lll) oxide was used in a reaction to produce iron.calculate the mass of iron produced in this reaction
10.50 kg of iron will be produced from 15 kg of iron (III) oxide.
What is mass?The amount of matter in an item is measured by its mass, which is a fundamental physical quantity. It is a scalar amount that is measured in kilograms (kg) or grams (g). Regardless of an object's location or the force pressing against it, its mass always remains constant.
How do you determine it?Iron (III) oxide and elemental iron react chemically in the following balanced chemical equation:
2 Fe2O3+ 3 C = 4 Fe + 3 CO2
Due to the reaction between 2 moles of Fe2O3 and 4 moles of Fe, the mole ratio of Fe2O3 to Fe is either 2:4 or 1:2.
The amount of iron created from 15 kg of Fe2O3 can be calculated using this mole ratio:
Fe2O3 = 2 moles of Fe per mole.
Fe2O3's molecular weight is 159.69 g/mol.
Fe2O3 has a mass of 15 kg and a density of 15,000 g/mol, or 94.00 moles.
We can figure out how many moles of Fe were produced using the mole ratio of 1:2:
We can figure out how many moles of Fe were produced using the mole ratio of 1:2:
2 moles of Fe for each mole of Fe2O3 94.00 moles of Fe2O3 multiplied by (2 moles of Fe for each mole of Fe2O3) results in 188.00 moles of Fe.
The molar mass of Fe can then be used to convert the moles of iron to mass as follows:
Fe's molecular weight is 55.85 g/mol.
188.00 moles of Fe produced at a rate of 55.85 g/mol result in a mass of 10,499.80 g or 10.50 kg.
Hence, 10.50 kg of iron will be produced from 15 kg of iron (III) oxide.
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How many grams of iron are produced when 450 grams of iron (lll) oxide are reacted
To answer this question, we need to know the balanced chemical equation for the reaction between iron (III) oxide and another substance that would produce iron.
How many grams of iron will be produced when 450 grams of iron (lll) oxide are reacted?Assuming the reaction is:
Fe₂O₃ + 3CO → 2Fe + 3CO₂
This equation tells us that one mole of Fe₂O₃ reacts with three moles of CO to produce two moles of Fe. We can use this information to calculate the number of moles of Fe that can be produced from 450 grams of Fe₂O₃.
Convert the mass of Fe₂O₃ to moles in the first step:
Molar mass of Fe₂O₃ = 2 x atomic mass of Fe + 3 x atomic mass of O = 2 x 55.85 + 3 x 16.00 = 159.69 g/mol
Number of moles of Fe₂O₃ = 450 g / 159.69 g/mol = 2.82 mol
According to the balanced chemical equation, 1 mole of Fe₂O₃ produces 2 moles of Fe. Therefore, the number of moles of Fe that can be produced from 2.82 mol of Fe₂O₃ is:
Number of moles of Fe = 2.82 mol x (2 mol Fe / 1 mol Fe₂O₃) = 5.64 mol
Convert the number of moles of Fe to grams in the final step:
Molar mass of Fe = 55.85 g/mol
Mass of Fe produced = 5.64 mol x 55.85 g/mol = 315.89 g
Therefore, if 450 grams of iron (lll) oxide are reacted with carbon monoxide to produce iron, the amount of iron produced would be 315.89 grams.
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Reviewing Main Ideas
1. What is meant by reaction mechanism?
2. What factors determine whether a molecular collision produces a reaction?
3. What is activation energy?
4. What is an activated complex?
5. How is activation energy related to the energy of reaction?
6. What is the difference between an activated complex and an intermediate?
7. Explain why, even though a collision may have energy in excess of the activation energy, a reac- tion may not occur. Critical Thinking
8. ANALYZING INFORMATION Which corresponds to the faster rate: a mechanism with a small activation energy or one with a large activation energy? Explain your answer.
A reaction mechanism is a detailed explanation of the steps involved in a chemical reaction. As a result of the reaction, intermediates, transition states, and products are produced.
The least amount of energy required for a reaction to take place is called activation energy. An intermediate state in a reaction where the reactants have sufficient energy to generate a reaction product is known as an activated complex
. Because the activation energy is the quantity of energy required to break down the energy barrier separating the reactants and the products, it is connected to the energy of reaction
Even though a collision has more energy than the activation energy, a reaction might not happen because the reactants need to be in the right orientation and at the right distance for a reaction product to develop.
Because it takes less energy to break through the energy barrier separating the reactants and the products, the mechanism with the lower activation energy will operate at a quicker rate.
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A reaction mechanism is a detailed explanation of the steps involved in a chemical reaction. As a result of the reaction, intermediates, transition states, and products are produced.
The least amount of energy required for a reaction to take place is called activation energy. An intermediate state in a reaction where the reactants have sufficient energy to generate a reaction product is known as an activated complex
. Because the activation energy is the quantity of energy required to break down the energy barrier separating the reactants and the products, it is connected to the energy of reaction
Even though a collision has more energy than the activation energy, a reaction might not happen because the reactants need to be in the right orientation and at the right distance for a reaction product to develop.
Because it takes less energy to break through the energy barrier separating the reactants and the products, the mechanism with the lower activation energy will operate at a quicker rate.
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What is the heat released when 25g water is condensed at 100 C?
1017.5 Joules is the heat released when 25g water is condensed at 100 C.
When water is condensed, it changes from a gas to a liquid, releasing heat in the process. The amount of heat released can be calculated using the formula:
q = m * ΔH
where:
q = heat released (in Joules)
m = mass of water (in grams)
ΔH = heat of vaporization of water (in J/g)
The heat of vaporization of water at 100°C is 40.7 kJ/mol, or 40.7 J/g. Therefore, substituting the values in the formula, we get:
q = 25 g * 40.7 J/g
q = 1017.5 J
So the heat released when 25 g of water is condensed at 100°C is approximately 1017.5 Joules.
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In the laboratory a "coffee cup" calorimeter, or constant pressure calorimeter, is frequently used to determine the specific heat of a solid, or to measure the energy of a solution phase reaction.
A student heats 67.38 grams of chromium to 97.97 °C and then drops it into a cup containing 85.09 grams of water at 21.20 °C. She measures the final temperature to be 27.35 °C.
The heat capacity of the calorimeter (sometimes referred to as the calorimeter constant) was determined in a separate experiment to be 1.74 J/°C.
Assuming that no heat is lost to the surroundings calculate the specific heat of chromium.
The specific heat of chromium is 0.436 J/g·°C, assuming no heat is lost to the surroundings.
Using the principle of conservation of energy, we can determine the heat gained by the water, which is equal to the heat lost by the chromium.
The heat gained by the water can be calculated using the formula:
q₁ = m₁ × C₁ × ΔT
where q₁ is the heat gained by the water, m₁ is the mass of water, C₁ is the specific heat of water, and ΔT is the change in temperature of the water.
Substituting the given values, we get:
q₁ = (85.09 g) × (4.184 J/g·°C) × (27.35 °C - 21.20 °C)
q₁ = 1,454.67 J
The heat lost by the chromium can be written as:
q₂ = -q₁ = -1,454.67 J
The heat lost by the chromium can also be expressed as:
q₂ = m₂ × C₂ × ΔT
where m₂ is the mass of chromium, C₂ is the specific heat of chromium, and ΔT is the change in temperature of the chromium.
Substituting the given values and solving for C₂, we get:
C₂ = -q₂ ÷ (m₂ × ΔT)
C₂ = -1,454.67 J ÷ (67.38 g × (97.97 °C - 27.35 °C))
C₂ = 0.436 J/g·°C
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A piece of iron at 25 °C is dropped into a glass of water at 15 °C. Which statement is correct? (4 points)
a Heat will flow from the iron to the water in the glass until both reach the same temperature.
b Heat will flow from the water in the glass to the iron until both reach the same temperature.
c The final temperature of the water in the glass and the iron will be 25 °C.
d The final temperature of the water in the glass and the iron will be 15 °C.
Answer:
When a piece of iron that is 25 °C is dropped into water that is 15 °C, the heat from the iron will dissipate into the water until the temperature is the same by conduction. Thus, option A is correct.
What is conduction?
Conduction is the transfer of the dissipated energy from the hot iron metal at 25 °C to the water at a lower temperature. The heat or the energy molecules gets transferred from the region of high to lower temperature.
This occurs through the diffusion that allows the hot iron to release the energy from its body that diffuses and gets transferred to the water molecules that have a tempearture of 15 °C, which is lower than that of the iron.
Therefore, the piece of the iron loses its heat to the water till both have the same tempearture.
Why would a flare be observed in visible light, when they are so much brighter in x-ray and ultraviolet light?
A. Flares can damage x-ray and ultraviolet detectors and these therefore must be turned off during these events, leaving only visible observatories that can be used.
B. The proximity of the sun allows us to be able to view solar flares in visible light because at this distance, they are still very bright.
C. The distance to the Sun is so vast that the x-ray and ultraviolet light from the flares dim before they can reach Earth leaving only the visible light.
D. In order to observe x-ray and ultraviolet light, the telescopes have to be in space.
A flare would be seen in visible light even though they are much brighter in x-ray and ultraviolet light because (D) The telescopes need to be in space in order to observe x-ray and ultraviolet light.
The reason solar flares are so brilliant?When the Sun's powerful magnetic fields get too twisted, flares happen. The tangled magnetic fields snap when they are overtwisted, much like a rubber band that snaps when overtwisted.
What triggers the flares and explosions that we observe on the sun's surface?A quick explosion of energy known as a solar flare is brought on by the tangling, crossing, or reorganisation of magnetic field lines close to sunspots. It contains electrically charged gases that produce strong magnetic fields in some regions.
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When the end product of protein hydrolysis enter the cytoplasm of a cell , they may become building blocks for the synthesis of
A) glycogen
B) starches
C) enzymes
D) lipids
Answer: C) enzymes
When the end product of protein hydrolysis enter the cytoplasm of a cell, they may become building blocks for the synthesis of enzymes
HELPPPPPPP ASPA!!!!60 POINTS TO ANSWER
1) Nuclear energy is sometimes classified as a renewable source.
However, it also has aspects that classify it as non-renewable. Describe
how nuclear energy is both renewable and non-renewable.
2) Imagine that you are part of a team deciding which energy resource, coal or wind, should
power your community’s electrical grid. Write two pros and two cons on the chart for each resource below. its coal and wind i need 2 pros and 2 cons for both.
Answer:
1) Nuclear energy is a non-renewable resource because it relies on uranium to generate power. Uranium is a radioactive element not found in large quantities on Earth. Once it is used to fuel a nuclear reactor, it cannot be reused. This means that once all the uranium is gone, we will no longer be able to generate nuclear power.
2)
Wind power pros and cons
ProsWind power is a clean and renewable energy sourceWind power is cost-effective2. Cons
Construction can cause local disturbances Can negatively impact local wildlife if not carefully designedCoal power pros and cons
1. Pros
Inexpensive Energy SourceIndependent of the Weather2. Cons
It is not a renewable resourceCoal contains a high level of carbon dioxide72g of water is broken down by electricity to form hydrogen and oxygen.
a. Write the chemical equation.
b. Find the mass of the obtained hydrogen.
c. Find the volume of the obtained hydrogen and oxygen at STP.
(H = 1, 0=16, At STP: 2g of H2 and32g of O₂2 has 22.4L)
A. The balanced equation is: 2H₂O -> 2H₂ + O₂
B. The mass of hydrogen obtained is 8 g
Ci. The volume of hydrogen produced is 89.6 L
Cii. The volume of oxygen produced is 44.8 L
A. How do i write the balanced equation?The balanced equation for the reaction is written as follow:
Water -> Hydrogen + oxygen
2H₂O -> 2H₂ + O₂
B. How do i determine the mass hydrogen obtained?first, we shall write the balanced equation for the reaction. This is given below:
2H₂O -> 2H₂ + O₂
Molar mass of H₂O = 18 g/molMass of H₂O from the balanced equation = 2 × 18 = 36 g Molar mass of H₂ = 2 g/molMass of H₂ from the balanced equation = 2 × 2 = 4 gFrom the balanced equation above,
36 g of H₂O reacted to produce 4 g of H₂
Therefore,
72 g of H₂O will react to produce = (72 × 4) / 36 = 8 g of H₂
Thus, the mass of hydrogen obtained is 8 g
Ci. How do i determine the volume of hydrogen produced?The volume of hydrogen produced can be obtained as follow:
2 g of H₂ = 22.4 L
Therefore
8 g of H₂ = (8 g × 22.4 L) / 2 g
8 g of H₂ = 89.6 L
Thus, the volume of hydrogen produced is 89.6 L
Cii. How do i determine the volume of oxygen produced?First, we shall obtain the mass of oxygen gas produced. Details below:
2H₂O -> 2H₂ + O₂
Molar mass of H₂O = 18 g/molMass of H₂O from the balanced equation = 2 × 18 = 36 g Molar mass of O₂ = 32 g/molMass of O₂ from the balanced equation = 1 × 32 = 32 gFrom the balanced equation above,
36 g of H₂O reacted to produce 32 g of O₂
Therefore,
72 g of H₂O will react to produce = (72 × 32) / 36 = 64 g of O₂
Finally, we shall determine the volume of oxygen produced. Details below:
32 g of O₂ = 22.4 L
Therefore
64 g of O₂ = (64 × 22.4) / 32 g
64 g of O₂ = 44.8 L
Thus, the volume of oxygen produced is 44.8 L
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What are the bond angles?
Answer:
109.5º
Explanation:
The leftmost carbon has four bonds and no lone pairs attached to it. According to the VSEPR model, this carbon has a tetrahedral geometry. Thus, each bond angle is 109.5º
find k given [S0₂ 2] =1.50 M, [O₂] = 1.25 M [SO₃] = 3.50 M 2 SO₂ + 1 O₂ ← →2 SO₃
The rate constant value for the given reaction is 1.8×10⁻⁵. The chemical kinetics rate law, which connects the molecular concentration of reactants with reaction rate
The chemical kinetics rate law, which connects the molecular concentration of reactants with reaction rate, uses the rate constant as a proportionality factor. The letter k in an equation designates it, which is also referred by the term the reaction constant of rate and reaction rate coefficient.
2SO[tex]_2[/tex](g) + O[tex]_2[/tex](g) →2SO[tex]_3[/tex](g)
Keq = [SO[tex]_3[/tex]]² / ([SO[tex]_2[/tex]]² [ O[tex]_2[/tex]])
= [3.50]² / ([1.50]² [ 1.25)
= 1.8×10⁻⁵
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A valid Lewis structure of _____ cannot be drawn without violating the octet rule.
a)
NF3
b)
IF3
c)
PF3
d)
SbF3
A valid Lewis structure of IF[tex]_3[/tex] cannot be drawn without violating the octet rule. Therefore, the correct option is option B.
Lewis structures, often referred to as Lewis dot calculations, Lewis dot constructions, electron dot frameworks, especially Lewis electron dot configurations (LEDS), represent diagrams that depict the interactions of atoms inside molecules as well as any single pairs of electrons which may be present. A valid Lewis structure of IF[tex]_3[/tex] cannot be drawn without violating the octet rule.
Therefore, the correct option is option B.
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PLS HELP!!!!!
Convert the following measurements. Show all work, including units that cancel.
18.2 g -> ? mol
Answer: To convert grams (g) to moles (mol), we need to use the molar mass of the substance. We can use the following formula:
moles = mass (in grams) / molar mass
We will assume that we are given the mass of a pure substance. If the substance is a compound, we will need to look up the molar mass in the periodic table or calculate it using the atomic masses of its elements.
Let's assume that we are given 18.2 g of a pure substance and we want to convert it to moles. We will need to look up the molar mass of the substance. For example, let's say the substance is water (H2O):
Molar mass of H2O = 2(1.008 g/mol) + 1(15.999 g/mol) = 18.015 g/mol
Now we can use the formula to convert grams to moles:
moles = 18.2 g / 18.015 g/mol = 1.009 mol
Therefore, 18.2 g of the substance is equivalent to 1.009 mol of the substance.
The aldol condensation can also be catalysed by acid. Write the mechanism for the acid- catalysed condensation of acetophenone with benzaldehyde.
The mechanism is: Step 1: Protonation of carbonyl group, Step : Formation of enol intermediate, Step 3: Nucleophilic attack by benzaldehyde, Step 4: Proton transfer, Step 5: Rearrangement,
The overall reaction can be represented as: Acetophenone + Benzaldehyde → Aldol intermediate → α,β-unsaturated ketone + H₂O. The acid catalyst (such as HCl or H₂SO₄) protonates the carbonyl group of the acetophenone, making it more susceptible to nucleophilic attack by the benzaldehyde, then protonated acetophenone then loses a water molecule to form an enol intermediate. The enol intermediate acts as a nucleophile and attacks the carbonyl group of the benzaldehyde, forming a new carbon-carbon bond.
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Calculate the percent by mass of the indicated element in the following compounds. Recall that 2 decimal places should be used for all molar masses, except for hydrogen.
a) CaH2: calcium =
b) UF4:: uranium =
c) C12H4Cl4O2: carbon =
hydrogen =
oxygen =
d) CaCO3: calcium =
Identify the term associated with each description about ionic solutions.
Can use the term more than once
- Activity coefficient
- Activity
-Ionic Strength
Concentration of species capable of effective interactions_______
Correction factor applied to concentrations based on the ionic strength of the solution____
Approaches unity for very dilute solutions______
An increased value decreases the effective interactions of species in solution_____
Represents the concentration of all ions present in solution______
Concentration of species capable of effective interactions: Ionic Strength
Correction factor applied to concentrations based on the ionic strength of the solution: Activity coefficient.
What is a coefficient ?Coefficient is a numerical or constant quantity that is placed in front of a variable or term. The term "coefficient" comes from the Latin word "coefficiente which means "a joint or mutual agreement."
In algebra, coefficients are used to represent the relative size or weight of a variable or term. For example, in the expression 3x + 2y, the coefficients are 3 and 2, which indicate that the variable x has a weight of 3 and the variable y has a weight of 2.
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In the laboratory a "coffee cup" calorimeter , or constant pressure calorimeter, is frequently used to determine the specific heat of a solid, or to measure the energy of a solution phase reaction.
Since the cup itself can absorb energy, a separate experiment is needed to determine the heat capacity of the calorimeter. This is known as calibrating the calorimeter and the value determined is called the calorimeter constant.
One way to do this is to use a common metal of known heat capacity. In the laboratory a student heats 90.80 grams of nickel to 98.73 °C and then drops it into a cup containing 84.70 grams of water at 24.03 °C. She measures the final temperature to be 31.63 °C.
Using the accepted value for the specific heat of nickel (See the References tool), calculate the calorimeter constant.
The specific heat capacity of nickel is given as 0.444 J/g·°C and the calorimeter constant is calculated to be 14.86 J/°C.
To calculate the calorimeter constant, we need to use the heat gained by the water and the heat lost by the nickel. The heat gained by the water can be calculated using the equation:
q₁ = m₁ × C₁ × ΔT
where m₁ is the mass of water, C₁ is the specific heat capacity of water (4.184 J/g·°C), and ΔT is the change in temperature of the water (final temperature - initial temperature).
q₁ = 84.70 g × 4.184 J/g·°C × (31.63 °C - 24.03 °C)
q₁ = 2,550 J
The heat lost by the nickel can be calculated using the equation:
q₂ = m₂ × C₂ × ΔT
where m₂ is the mass of nickel (90.80 g), C₂ is the specific heat capacity of nickel (0.444 J/g·°C)
q₂ = 90.80 g × 0.444 J/g·°C × (98.73 °C - 31.63 °C)
q₂ = 2,654 J
Since the heat lost by the nickel is equal to the heat gained by the water, we can write:
q₂ = q₁ + q₃
where q₃ is the heat absorbed by the calorimeter. Solving for q₃, we get:
q₃ = q₂ - q₁
q₃ = 2,654 J - 2,550 J
q₃ = 104 J
The calorimeter constant can now be calculated using the equation:
C₃ = q₃ ÷ ΔT
C₃ = 104 J ÷ (31.63 °C - 24.03 °C)
C₃ = 14.86 J/°C
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Determine the pH of a 3.4x10^-6 M solution of HNO3
Answer: pH of the solution is 5.47
Explanation: Since HNO3 is a strong acid the concentration of H+ is the same as NO3- only because they are in 1-to-1 ratio. Both ions will have 3.4 x 10^-6 M.
The formula of pH is: pH = -log( the equilibrium concentration of H+ )
When you plug in the concentration of H+:
pH = -log (3.4 x 10^.6 M)
pH = 5.47
Remember: Only the digits after the decimal point are significant figures in logarithms.
For example: 5.47 only has 2 significant figures.
Epsom salts are a common household item used for mineral baths a 5 g sample is epsom salts contain 1.01 g magnesium 1.33 g of sulfur and 2.66 g of oxygen determine the empirical formula for this compound
The empirical formula for Epsom salts is MgSO₄, which means that for every one magnesium atom in the compound, there is one sulfur atom and four oxygen atoms.
To determine the empirical formula of Epsom salts we have to calculate the moles of each element in the sample:
Moles of magnesium = 1.01 g ÷ 24.31 g/mol = 0.0415 mol
Moles of sulfur = 1.33 g ÷ 32.06 g/mol = 0.0415 mol
Moles of oxygen = 2.66 g ÷ 16.00 g/mol = 0.1663 mol
Divide the number of moles of each element by the smallest number of moles:
0.0415 mol Mg ÷ 0.0415 mol = 1
0.0415 mol S ÷ 0.0415 mol = 1
0.1663 mol O ÷ 0.0415 mol = 4
If necessary, multiply each ratio by a whole number to get the smallest possible whole-number ratio:
1 : 1 : 4
This ratio is 1:1:4 for magnesium, sulfur, and oxygen respectively.
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A 11.27-g block of solid gold at 68.23 °C is immersed in a 23.16-g pool of liquid ethanol with a temperature of 10.76 °C. When thermal equilibrium is reached, what is the temperature of the gold and ethanol?
Specific heat capacities: gold = 0.129 J/g °C; ethanol = 2.44 J/g °C
Answer:
Final Temperature = 12.20 Celsius
Explanation:
Use the equation:
ΔC*q*m = -ΔC*q*m
[tex]11.27*0.129*(T_{f}-68.23) = -23.16*2.44*(T_{f}-10.76)\\1.45T_{f} -99.19 = -56.51T_{f} +608.15\\T_{f} = 12.20 C[/tex]
Does any know the answer to the first three question
1. C) Molarity is indirectly related to volume.
2. A) The CaCl2 beaker has more ions in solution.
3. the molarity of the NaCl solution is 0.0513 M.
How to find the molarityStep 1: Convert 30g of NaCl to moles.
The molar mass of NaCl is 58.44 g/mol. To convert 30 g to moles, divide by the molar mass:
30 g NaCl / 58.44 g/mol = 0.513 mol NaCl
Step 2: List Given and asking information.
Given:
Mass of NaCl = 30g
Volume of solution = 10.0L
Asking:
Molarity of the solution = ?
Step 3: set Molarity Formula and plug the mole/ Volume into the formula.
Molarity = moles of solute / volume of solution
Molarity = 0.513 mol / 10.0 L = 0.0513 M
Therefore, the molarity of the NaCl solution is 0.0513 M.
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