Find the area of the trapezoids

Find The Area Of The Trapezoids

Answers

Answer 1

Answer:

48 square units

Step-by-step explanation:

Each square on the grid is 2 units by 2 units.

Bases: AT = 8; RS = 4

Height: 8

area = (b1 + b2)h/2

area = (8 + 4)(8)/2

area = 48 square units

Answer 2

Answer:

The area of trapezoid is 48 sq units.

Step-by-step explanation:

According to the question,

➻ Trapezoid is consist of many square shapes. Each grid square equals 2 units. We need to find the area of trapezoid.

➻ To find area we need to find the length if base and height of trapezoid.

Calculate the square grids to find base and height. we get.

Base ; SR = 4 units and TA = 8units

Height = 8 units.

Finding the area of trapezoid.

We know that,

Area of trapezoid = ( Base1 + Base2 ) ×Height / 2

plug the values of both base and a height.

Area of trapezoid = ( 4 + 8 ) × 8 / 2

Add the numbers which are in bracket and multiply by 8.

Area of trapezoid = 12 × 8 / 2 = 96/2

Divide 96 by 2.

Area of trapezoid = 48 sq units.

Hence,

The area of trapezoid is 48 sq units.


Related Questions

How many real solutions exist for this system of equations? Y = -x + 1 y = -x2 + 4x − 2 A. Zero B. One C. Two D. Infinite

Answers

Answer:

Two solutions

Step-by-step explanation:

Given the functions Y = -x + 1 y = -x² + 4x − 2

Since they are both y values, we will equate them to have:

-x+1 = -x² + 4x − 2

Equate to zero

x²-x-4x+1+2=0

x²-5x+3 = 0

Since the resulting equation is quadratic (highest degree being 2), hence there will be two solutions to the equation

There are 40 batteries in 10 packs.
Gavin wants to know how many batteries are in 1 pack.
Kylie wants to know how many batteries are in 5 packs.
Drag an expression to answer each question.

Help me Please I would appreciate your help!

Answers

:-):-):-):-):-)

Step-by-step explanation:

1) 40÷10

2) 40÷2

encontre as raízes quadradas dos números:
a)²√625​

Answers

25

porque al multiplicar 25×25 nos da 625

Answer:

25

Step-by-step explanation:

25x25=625

Mario tiene 4 pantalones de diferente color (azul, café, negro y blanco) y 6 camisas también de diferente color (blanca, negra, azul, café, gris y verde). Si Mario escoge una combinación al azar, ¿cuál es la probabilidad de que se vista con pantalón azul y camisa blanca?

Answers

1/15 es la posibilidad que existe

Use the box method to distribute and simplify (2 + 1)(2x - 3). Drag and drop the
terms to the correct locations of the table.

Answers

Answer:

2x^2-x-3

(2x)(-3)

(x)

(1)

Step-by-step explanation:

Distribute

(2x^2) (-3x)

(2x) (-3)

HELP PWEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE

Answers

Answer:

rap music

Step-by-step explanation:

^

Answer:

i’m not sure if these are right or not but

Step-by-step explanation:

the first one is no

i think the second one is no

i think the third one is yes

i think the fourth one is yes

i am not sure and i’m REALLY sorry if its wrong

What is the probability of 4 consecutive 2-sided coin tosses all coming up heads?

Answers

The probability of getting four consecutive heads in four 2-sided coin tosses is 1/16 or 0.0625 or 6.25%.

The Probability is defined as a measure of the likelihood or chance that an event will occur, expressed as a value between 0 and 1, where 0 represents impossibility and 1 represents certainty.

To calculate the probability of getting four consecutive heads in a row, we multiply the probabilities of each individual toss.

The Probability of heads (H) is = 1/2,

So, The Probability of four consecutive heads (HHHH) is :

= (1/2) × (1/2) × (1/2) × (1/2) = (1/2)⁴ = 1/16,

Therefore, the required probability is 1/16 or 6.25%.

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Use the following diagram to answer question 4 and 5
Exterior Angle Theorem
8.6 points
The measure of ZA is
Given the following diagram, find the measures of
LA and ZB
Type your answer...
B (2x + 4)
5
8.6 points
The measure of ZB is
Type your answer...
(3x - 13)
116°
А

Answers

Answer:

3x-13+2x+4=116( the sum of two interior angle is epual to the sum of exterior angle )

5x =116-9

5x=107

x=21.4 degree

then

angle a= 3*21.4-13

a=51.2degree

angle b=2*21.4+2

b =44.8degree

Step-by-step explanation:

plz make me brainliest

You invest $32,000 in an account that earns 5.75% interest compounded yearly. What is
the total amount of money you will have in the account after 20 years if you never
deposit any additional funds?

Answers

Answer:

$97,894.33.

Step-by-step explanation

A rectangular prism has a base perimeter of 28 inches and a height of 6 inches. What is the lateral surface area of the prism?​

Answers

Answer:

uhuhuhuhuhuhuhuhuhuhuh oh yeah

Step-by-step explanation:

Simplify this expression

Answers

I think this would be 7st^6 u^8 v^4 because the other two terms cancel each other out.

I NEEED HELP match the equation with the term it belongs to. 3.14 *r *r. 2* 3.14 *r

Answers

Answer:

3.14 * r * r = area of circle, 2 * 3.14 * r = circumference

Step-by-step explanation:

Remember these formulas, very important.

Help pls I’m on a time limit. Please and thank you <33

Answers

Answer: the answer is 3/10

Step-by-step explanation: because its 3/10

Answer:

es

3/ 10

Step-by-st

find the area of this polygon

Answers

Answer:

answer is 65 in²

hope this helps

Saul decides to use the IQR to measure the spread of the data. Saul calculates the IQR of the data set to be . Saul asks Jasmine to check his work. Saul copies the data in numerical order from least to greatest for Jasmine.

Answers

The question is incomplete. The compete question is :

Saul decides to use the IQR to measure the spread of data. Saul calculates the IQR of the data set to be 27. Saul asks Jasmine to check his work. Saul copies the data in numerical order from least to greatest for Jasmine. 25, 30, 50, 50, 50, 50, 56, n, 250. What is the value of n that will make the IQR of the data set equal to 27?

Solution :

The inter quartile range is being measured as : 3rd quartile - 1st quartile

The 1st quartile = 25% mark

The 3rd quartile = 75% mark

The data set as given in the question is :

25, 30, 50, 50, 50, 50, 56, n, 250

Therefore, the total number of the sample = 9

And the median is = 50

The median separates the given data sets into two equal halves-- that is the upper half and the lower half.

Let the middle of a lower half is the 1st quartile be [tex]$Q_1$[/tex]

And the middle of a 2nd half is the 3rd quartile be [tex]$Q_3$[/tex]

∴ [tex]$Q_1=\frac{30+50}{2}$[/tex]

        [tex]$=40$[/tex]

  [tex]$Q_3=\frac{56+n}{2}$[/tex]

Now for the IQR of the data set to be equal to [tex]$27$[/tex],

[tex]$\frac{56+n}{2}-40=27$[/tex]

[tex]$\frac{56+n}{2}=27+40$[/tex]

[tex]$\frac{56+n}{2}=67$[/tex]

[tex]$56 +n=134$[/tex]

[tex]$n=134-56$[/tex]

[tex]$n=78$[/tex]

Im giving brainliest

Answers

Answer:

√17 - 3   >   -2 + √5

In desperate need of help. If anyone could help it would be greatly appreciate. Will rate brainliest!

Answers

Answer:

7 people

Step-by-step explanation:

Chocolate: 350 / 100 = 3.5 x 2 = 7

Butter: 45 / 10 = 4.5 x 2 = 9

Eggs: 8 / 2 = 4 x 2 = 8

The amount of chocolate is the limiting factor as you have enough eggs for 8 people and enough butter for 9 people, but only enough chocolate for 7 people

Please help me, GodBless.

Answers

Answer:

Rate of change is 1

Step-by-step explanation:

Well rate of change in a function is basically slope

theres 1 rise and.1 run

1/1=1

So rate of change is 1

Compute r''(t) and r'''(t) for the following function. r(t) = (9t² +6,t + 5,6) Find r'(t). r(t) = 0.00

Answers

The derivatives of the vector function are r'(t) = (18 · t, 1, 0), r''(t) = (18, 0, 0) and r'''(t) = (0, 0, 0).

How to determine the first three derivatives in a vector function

In this question we find the definition of a vector function in terms of time, whose first, second and third derivatives must be found. This can be done by using derivative rules several times. First, define the vector function:

r(t) = (9 · t² + 6, t + 5, 6)

Second, find the first derivative:

r'(t) = (18 · t, 1, 0)

Third, find the second derivative:

r''(t) = (18, 0, 0)

Fourth, find the third derivative:

r'''(t) = (0, 0, 0)

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Write an expression in factored form to represent the area of each shaded region. Include the area formula and full steps and write your answer in simplified form. 3x a) (3 marks) 3x + y 2x +y 3x b) 3y (3 marks) B 2x 2x

Answers

a. The area of the shaded region = (3x)(5x + 2y).

b. The area of shaded region = 2x(2xπ - 3x).

Given that,

We have to write an expression in factored form to represent the area of each shaded region.

We know that,

a. In the picture we can see that the shaded region.

The area of the shaded region is area of rectangle with vertical + area of rectangle Horizontal

The area of rectangle is length × width.

The area of the shaded region = (3x)(3x + y) + (2x + y)(3x)

The area of the shaded region = (3x)(3x + y + 2x + y)

The area of the shaded region = (3x)(5x + 2y)

Therefore, The area of the shaded region = (3x)(5x + 2y)

b. In the picture we can see that circle with shaded region,

The area of shaded region is area of the circle - area of the rectangle

The area of the circle is πr² and area of rectangle is length × width.

The area of shaded region = πr² - (l×w)

The area of shaded region = π(2x)² - (2x × 3x)

The area of shaded region = 4x²π - 6x²

The area of shaded region = 2x(2xπ - 3x)

Therefore, The area of shaded region = 2x(2xπ - 3x).

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what is the volume of a right triangular prism whose height is 20 units and whose base is a right triangle with side lengths of 3,4, and 5?

Answers

Area of base= 1/2(3x4) = 6
Multiply that with the height:
6x20=120

Answer: 120

A 5 meter ladder is leaning against a house when its base starts to slide away. By the time the base is 3 meter from the house, the base is moving at the rate of 2 m/sec. (a) How fast is the top of the ladder sliding down the wall then? (b) At what rate is the angle between the ladder and the ground changing then?

Answers

(a) The top of the ladder is sliding down the wall at a rate of 3/2 m/sec.

(b) The angle between the ladder and the ground is changing at a rate of 1/2 rad/sec.

To solve this problem, we can use related rates, considering the ladder as a right triangle formed by the ladder itself, the wall, and the ground.

Let's denote:

x: the distance from the base of the ladder to the house (in meters)

y: the height of the ladder on the wall (in meters)

θ: the angle between the ladder and the ground (in radians)

Given:

dx/dt = -2 m/sec (the rate at which the base of the ladder is moving away from the house)

Using the Pythagorean theorem, we have:

x^2 + y^2 = 5^2 (since the ladder has a length of 5 meters)

Taking the derivative of both sides with respect to time (t), we get:

2x(dx/dt) + 2y(dy/dt) = 0

(a) To find dy/dt:

We can solve the equation above for dy/dt:

2x(dx/dt) + 2y(dy/dt) = 0

2(3)(-2) + 2y(dy/dt) = 0 (substituting x = 3 and dx/dt = -2)

-12 + 2y(dy/dt) = 0

2y(dy/dt) = 12

dy/dt = 12/(2y)

dy/dt = 6/y

Now, we need to find y. Using the Pythagorean theorem again:

x^2 + y^2 = 5^2

3^2 + y^2 = 5^2

9 + y^2 = 25

y^2 = 25 - 9

y^2 = 16

y = 4 (taking the positive value as y represents a length)

Substituting y = 4 into dy/dt = 6/y:

dy/dt = 6/4

dy/dt = 3/2 m/sec

Therefore, the top of the ladder is sliding down the wall at a rate of 3/2 m/sec.

(b) To find dθ/dt:

We can use trigonometry to relate θ, x, and y:

tan(θ) = y/x

Differentiating both sides with respect to time (t), we get:

sec^2(θ)dθ/dt = (x(dy/dt) - y(dx/dt))/x^2

Substituting the given values:

sec^2(θ)dθ/dt = (3(3/2) - 4(-2))/3^2

sec^2(θ)dθ/dt = (9/2 + 8)/9

sec^2(θ)dθ/dt = (25/2)/9

sec^2(θ)dθ/dt = 25/18

Since sec^2(θ) is equal to 1 + tan^2(θ) and tan(θ) = y/x:

sec^2(θ) = 1 + (y/x)^2

sec^2(θ) = 1 + (4/3)^2

sec^2(θ) = 1 + 16/9

sec^2(θ) = (9 + 16)/9

sec^2(θ) = 25/9

Substituting sec^2(θ) = 25/9 into the equation:

(25/9)dθ/dt = 25/18

Simplifying and solving for dθ/dt:

dθ/dt = (25/18) * (9/25)

dθ/dt = 1/2 rad/sec

Therefore, (b) the angle between the ladder and the ground is changing at a rate of 1/2 rad/sec.

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Make r the subject of x=e+r/d

Answers

Answer:

r = dx - de

Step-by-step explanation:

x = e + r/d

x - e = r/d

d (x - e) = r

dx- de = r

r = dx - de

What is the median of the data set? {5, 3, 4, 2, 6} Enter your answer in the box. Round to the nearest tenth.

The best answer will receive brainiest.

Answers

Answer:

4

Step-by-step explanation:

To find median, arrange the data set in ascending order. Then the middle term is the median

2 , 3 , 4 , 5 , 6

Median = 3rd term  = 4

Answer:

4 is the median

Step-by-step explanation:

From least to greatest:

2,3,4,5,6

Since the total values is odd, the middle number is the median

4 is the median

What is the smallest solution to the equation 3x2 - 16 = 131?

Answers

Answer:

7,-7 are the solutions

Step-by-step explanation:

Not a perfect square so its

+-7

I would go with -7 since its the lowest amount

Answer:

-7

Step-by-step explanation:

Find the measurements of DBC

Answers

Answer:

72 degrees

Step-by-step explanation:

To determine the value of DBC, we first have to determine the value of q

Angle on a straight line = 180 degrees

7q - 46 + 3q + 6 = 180

10q - 40 = 180

collect like terms

10q = 180 + 40

10q = 220

q = 22

Substitute for q in angle dbc

3(22) + 6 = 72 degrees

What’s the opposite of -5/8

Answers

The opposite of -5/8 is 5/8.
It’s 5/8, |-5/8| = 5/8

What’s the website in this image called?

Answers

The website is called iRazoo
:D

Let be an equivalence relation on a set S, and let a, b e S. Show that two equivalence classes under ~ are either equal or disjoint, i.e. either [a] = [b] or [a] n [b] = 0.

Answers

Given, an equivalence relation ~ on a set S. Let a and b be two elements in the set S. Assuming that [a] and [b] are two equivalence classes under the equivalence relation ~. Now we need to prove that either [a] = [b] or [a] ∩ [b] = ∅ (disjoint).

Proof:If [a] and [b] are not equal, then there must be some element c in the intersection of the equivalence classes [a] and [b]. i.e, c belongs to [a] and c belongs to [b].Thus, [a] ∩ [b] is not empty.

Let x be an element in [a], then x~a, and a~c (since c belongs to [a]) and hence x~c. So, x belongs to [c] which implies that [a] is a subset of [c].Now, let y be an element in [b], then y~b, and b~c (since c belongs to [b]) and hence y~c. So, y belongs to [c] which implies that [b] is a subset of [c].Thus, both [a] and [b] are subsets of [c].

Therefore, if [a] and [b] are not equal, then [a] and [b] are both subsets of [c] and hence the intersection of [a] and [b] is not empty. Thus, [a] and [b] are not disjoint. Hence, the proof by contradiction.

Conversely, if [a] and [b] are disjoint, then [a] ∩ [b] = ∅. And thus, [a] is not equal to [b].Therefore, two equivalence classes under the equivalence relation ~ are either equal or disjoint.

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Tina drew a triangle with side lengths 6, 8, and 14. She claims it is a right triangle. Is she correct?

Answers

Answer:

No such a triangle can not exist.  

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