Find the length of the missing leg.

Answer:

I am not 100%

#1 = C,D,E

#2 = 1/2

Its d because 16/12=1.33 same with 20/15 and 40/30 so its 24x1.33 which is 32 there for d is correct

Answer: The last one

Step-by-step explanation:

Answer:

D. 4th Option.

Explanation:

The cause is that a team is from your town and the effect is that you'll try to be a fan. The italicized words if and then indicate a cause and effect.

Answer:

403909578

Step-by-step explanation:

Answer:

w=31.5

Step-by-step explanation:

w proportional to y

w=ky

k is a constant

k=w/y

w1/y1=w2/y2

w1=14,w2=?,y1=4,y2=9

14/4=w/9

cross multiply and divide by 4

w=14×9/4

w=31.5

Answer:

a = 105 in²

Step-by-step explanation:

Front and back, triangles

a = 2 * (1/2)(5 * 6)

a = 30

Sides, squares

a = 3 * (5 * 5)

a = 75

Total

a = 30 + 75

a = 105 in²

Answer: [tex]146\ in.[/tex]

Step-by-step explanation:

Given

The dimension of the rectangular sandcastle is

length [tex]l=41\ in.[/tex]

width [tex]w=32\ in.[/tex]

Perimeter is the sum of the sides of rectangle

[tex]\therefore\ \text{Perimeter= }2\left(l+w\right)\\\Rightarrow \text{Perimeter= }2(41+32)\\\Rightarrow \text{Perimeter= }2\times 73\\\Rightarrow \text{Perimeter= }146\ in.[/tex]

Answer:

800

Step-by-step explanation:

Answer:

47

Step-by-step explanation:

to find the mean we add all numbers and divide by how many there are

14+79+77+11+14+78+77+65+31+56+16/ 11 ≈ 47

Answer:

33

Step-by-step explanation:

Values beyond the whiskers of the boxplot are called the outliers :

For a right side Outlier :

Values > Q3 ± 1.5(IQR) ;

IQR = Q3 - Q1)

From the data given:

IQR = (40 - 18) = 22

Hence ; the maximum value of right side whisker will be :

1.5(22) = 33

The maximum possible length of the right-side "whisker" is 33

The given parameters are:

Start by calculating the interquartile range (IQR) using:

[tex]IQR = Q3 -Q1[/tex]

So, we have

[tex]IQR = 40 - 18[/tex]

[tex]IQR = 22[/tex]

The maximum possible length of the right side whisker is then calculated as:

[tex]L = 1.5 \times IQR[/tex]

This gives

[tex]L = 1.5 \times 22[/tex]

Multiply 1.5 by 22

[tex]L = 33[/tex]

Hence, the maximum possible length of the right-side "whisker" is 33

Read more about box and whisker plots at:

https://brainly.com/question/3293067

Answer:

So its just 4,500 yw

Step-by-step explanation:

4,500 so b i think                                              

Answer:

50i

Step-by-step explanation:

Answer:

width is 2√33 cm

Step-by-step explanation:

you will make a right triangle with hypothenuse 14 , one side 8 and the other side x is the width.

use Pythagorean Th.

14² = 8² + x²

x² = 14² -8²

x² = 132

x = √132 = 2√33

Answer:

True

Step-by-step explanation:

Pretty sure it's true.

Answer:

See below

Step-by-step explanation:

Center:   (-3, 4)

radius = r = [tex]\sqrt{25}[/tex] = 5

diameter = 2r = 10

Answer:

Center= (3,-4)   Radius=5   Diameter=10

Step-by-step explanation:

The numbers (3,-4) are the coordinates in the center of a circle. The radius is squared to get the end number so to get the radius, you have to find its square root- [tex]\sqrt{25[/tex] =5. The diameter is 2 times bigger than the radius so 5 times 2= 10.

Answer: 9.82 cm

Step-by-step explanation:

Answer:

98 - 84 = 14(this is the change) now we convert this to a percent

14/1 x 100/100 = 14%

Answer:

144

Step-by-step explanation:

you have to use this formula

m CBA>= a

BA ( =2a

CBA>=72

BA )=72×2

hopefully its helpful

Answer:

A

Step-by-step explanation:

The inscribed angle ABC is half the measure of its intercepted arc AB, then

arc AB = 2 × ∠ ABC = 2 × 72° = 144° → A

Answer:

189 yd²

Step-by-step explanation:

so in a prism, there are total 5 surfaces;

3 rectangular(all of same size)

2 triangular (of same sizes too)

so the area of trangle = 1/2× base × height = 1/2 × 6× 4 = 12yd²

for two triangles, Area= 24 yd²

area of a rectangle= length× breadth = 11× 5 = 55yd²

for three rectangles, area= 165yd²

now you add them

total surface area = 24+ 165= 189yd²

Answer:

it should be C sry if I'm wrong <3

Answer:

7.33 * 10^-11 s

Step-by-step explanation:

Period, T = 1 / f

c = fλ

λ = 2.20 × 10^–2 m

c = speed of light = 3 * 10^8 m

f = c / λ

f = 3 * 10^8 ÷ 2.20 × 10^–2 m

f = (3/2.2) * 10^(8-(-2))

f = 1.364 * 10^10

T = 1/f

T = 1 / 1.364 * 10^10

T = 7.33 * 10^-11 s

Answer:

hi i think you answer will be 28 square units

Answer:

2.5, 16,3,32

Step-by-step explanation:

Yeah, the ex member of Exo.

I have watched his movie

Never Gone

Answer:

y = 2x

Step-by-step explanation:

1. attendee = x

2. cost = y

3. for each attendee [x], you have $2 of cost, so for each 1 x, you have 2 as result

4. Thus, y = 2x

Answer:

V = 96 pi m^3

Step-by-step explanation:

V = (1/3) pi(r^2)h

Radius = 1/2(Diameter)

R = 1/2(12)

R = 6

Input.  

V = (1/3) pi(6^2)8

Solve.

V = (1/3) pi(36)8

V = (1/3) 904.32

V = 301.44

V = 301.44/pi

V = 96 pi m^3

Answer:

The correct answer is option (C) 96π m³.

Step-by-step explanation:

As per given question we have provided that :

Here's the required formula to find the volume of cone :

[tex]{\longrightarrow{\pmb{\sf{V_{(Cone)} = \dfrac{1}{3}\pi{r}^{2}h}}}}[/tex]

Substituting all the given values in the formula to find the volume of cone :

[tex]{\implies{\sf{V_{(Cone)} = \dfrac{1}{3}\pi{r}^{2}h}}}[/tex]

[tex]{\implies{\sf{V_{(Cone)} = \dfrac{1}{3}\pi{(6)}^{2}8}}}[/tex]

[tex]{\implies{\sf{V_{(Cone)} = \dfrac{1}{3}\pi{(6 \times 6)}8}}}[/tex]

[tex]{\implies{\sf{V_{(Cone)} = \dfrac{1}{3}\pi \times {(36)} \times 8}}}[/tex]

[tex]{\implies{\sf{V_{(Cone)} = \dfrac{1}{3} \times \pi \times 36 \times 8}}}[/tex]

[tex]{\implies{\sf{V_{(Cone)} = \dfrac{1}{\cancel{3}} \times \pi \times \cancel{36} \times 8}}}[/tex]

[tex]{\implies{\sf{V_{(Cone)} = \pi \times 12 \times 8}}}[/tex]

[tex]{\implies{\sf{V_{(Cone)} = \pi \times 96}}}[/tex]

[tex]{\implies{\sf{V_{(Cone)} =96\pi}}}[/tex]

[tex]\star{\underline{\boxed{\sf{\red{V_{(Cone)} =96\pi \: {m}^{3}}}}}}[/tex]

Hence, the volume of cone is 96π m³.

[tex]\rule{300}{2.5}[/tex]