find the missing part of the proof for m A. m B. m C. m D. m

Answer:

The diameter of Earth that would appear the same size as the Sun from the Moon is approximately 54304839.858 kilometers

Step-by-step explanation:

To find the diameter of Earth that would appear the same size as the Sun from the Moon, we need to know the distance from the Moon to the Sun and the distance from the Moon to Earth.

Since the distance from the Moon to the Sun is much greater than the distance from the Moon to Earth, the angle subtended by the Sun at the Moon will be much smaller than the angle subtended by Earth at the Moon.

Therefore, the size of Earth as seen from the Moon will be much larger than the size of the Sun as seen from the Moon.

To find the ratio of the size of Earth to the size of the Sun as seen from the Moon, we can use the formula:

size ratio = (distance to Earth / distance to Sun) x (Sun's diameter / Earth's diameter)

Substituting in the given values, we get:

size ratio = (384400km / 149600000km) x (1391000km / Earth's diameter)

Simplifying, we get:

size ratio = 0.00257 x (1391000km / Earth's diameter)

To find the diameter of Earth that would appear the same size as the Sun from the Moon, we need to solve for Earth's diameter. Dividing both sides of the equation by 0.00257, we get:

Earth's diameter = (1391000km / 0.00257) = 54304839.858km

Therefore, the diameter of Earth that would appear the same size as the Sun from the Moon is approximately 54304839.858 kilometers.

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Answer:

y = -1

Step-by-step explanation:

The equation is y = mx + b

m = the slope

b = y-intercept

To find slope we look for the rise/run or (y2 - y1) / (x2 - x1)

The slope here is 0, and the y-intercept is located at (0,-1), so the equation is

y = -1

Answer:

y = -1

Step-by-step explanation:

The area of a square playground which has a side measures 40metres would be 100[tex]m^2[/tex].

step1

Perimeter of square = 40m

We have given that perimeter of square is 40m. To find its area, we have to calculate its side first.

Perimeter of square = 4× side

Substituting values in formula

Area of square = 4 × side

=> 40 = 4 × side

=> side = 40÷4

=> side = 10m

Side of square is 10m.

step 2

Calculating area of square :

We found that side of square is 10m. To find it area, required formula is:

Area of square = (side)²

To find area, substitute values in formula :-

Substituting values in formula :-

Area of square = (side)²

=> Area of square = (10)²

=> Area of square = 10 × 10

=> Area of square = 100m

so if the perimeter of square is 40m then the area is 100m.

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The fraction that is bigger than 2/5 and smaller than 2/3 is 8/15.

A fraction is written in the form of a numerator and a denominator where the denominator is greater that the numerator.

Example: 1/2, 1/3, 1/5 is a fraction.

We have,

Let the fraction be a/b.

2/5 < a/b < 2/3

Now,

a/b

= (2/3 + 2/5) / 2

= (10 + 6) / 30

= 16/30

= 8/15

= 0.533

Thus,

The fraction is 8/15.

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Answer:

9.1

Step-by-step explanation:

For the first one, I just multiplied 4.55 and 0.5 by 2 somthey are proportional. Or divide distance by time!

h = 7 is the solution to the equation 1/ (h - 5) + 2/ (h + 5) = 16 / (h² - 25)

The meaning of such an equations in algebra is just a mathematical expression stating the equality between two mathematical terms. For instance, 6x + 5 = 11 is an equation where 6x + 5 and 11 are two expressions separated by the 'equal' sign.

Identity equations and conditional equations are the two types of equations. For just any value of both the variables, an equality remains true. Only such variables have values that make a condition expression true. Two expressions joined by an equals sign ("=") form an equation.

The equation given that,

1/ (h - 5) + 2/ (h + 5) = 16 / (h² - 25)

The least common multiple of the denominators is:

h² - 25 = (h - 5) (h + 5)

We multiply through with the LCM to obtain:

= [(h - 5) × (h + 5)] × [1 / (h - 5)] + [(h - 5) × (h + 5)] × [2 / (h - 5)]

= 16 / (h² - 25) × [(h - 5) × (h + 5)]

We cancel out common factors to obtain:

= 1 (h + 5) + 2 (h - 5)

= 16

We expand the brackets to obtain

= h + 5 +2h - 10

We group like terms to get:

h + 2h = 16 - 5 + 10

This simplifies to:

3h = 21

We now divide through by 3 to obtain:

h = 7

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The numbers of milligrams of the vitamin that are in a drink is 60 milligrams.

The recommended daily allowance (RDA) for the vitamin is 40 mg. A new health drink has 150% of the RDA.

To find out how many milligrams of the vitamin are in a drink, you can use the following formula:

(RDA) x (percentage/100) = milligrams in a drink

So,

(40mg) x (150/100)

= 60mg

Therefore, there are 60 milligrams of the vitamin in a drink.

Note that the RDA of vitamins can vary depending on age, gender, and other factors, so always consult a doctor or nutritionist before starting to consume any new supplement.

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The prove of given limit lim θ → 0 ( sin θ / θ ) = 1 is shown in below.

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

We have to given that;

⇒ lim θ → 0 ( sin θ / θ ) = 1

Here, The form of given limit is 0/0, so we can apply the L - Hospital Rule.

⇒ lim θ → 0 ( sin θ / θ ) = 1

Take LHS;

⇒ lim θ → 0 ( d/dθ (sin θ)/ dθ/dθ )

⇒ lim θ → 0 ( cos θ / 1 )

⇒ ( cos 0 )

⇒ 1

⇒ RHS

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If the pickup charge for taxi is $3.50 and additional charge of $0.75 per mile , then the cost for riding 5 miles is $7.25  and cost for riding m miles is $[tex]3.50+0.75m[/tex]   .

The pickup charge that taxi service charges is = $3.50  ;

the additional charge for per miles driven is = $0.75  ;

we have to find the cost for riding 5 miles ;

So , the total cost for riding 5 miles is = [tex]Pickup Charge + (Additional Charge)\times(Number Of Miles Driven)[/tex] ;

substituting the values , the total cost equation becomes ;

[tex]Total Cost = 3.50 + 0.75\times5[/tex]

= [tex]3.50+3.75[/tex]

= 7.25

So , the cost for 5 miles is = $7.25  ;

to find cost for driving "m" miles ,we substitute the number of miles = m;

[tex]Total Cost = 3.50+0.75\times m[/tex]

= [tex]3.50+0.75m[/tex]

Therefore , the cost for riding m miles is $ [tex]3.50+0.75m[/tex] .

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The measure of angle TQW from the given figure is 25°.

A perpendicular is a straight line that makes an angle of 90° with another line. 90° is also called a right angle and is marked by a little square between two perpendicular lines as shown in the figure. Here, the two lines intersect at a right angle, and hence, are said to be perpendicular to each other.

Given that, QT⊥PQR at Q, QW⊥QS at Q, and m∠SQP=25°.

From the given figure, m∠SQP+m∠SQT=90° -------(I)

m∠TQW+m∠SQT=90° -------(II)

Here, equation (I)=(II), we get

m∠SQP+m∠SQT=m∠TQW+m∠SQT

m∠SQP=m∠TQW

25°=m∠TQW

Therefore, the measure of angle TQW from the given figure is 25°.

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Answer: The answer is C

Step-by-step explanation: i took the test and got it right

Answer:

7.14%

Step-by-step explanation:

Any comparison with the increase or decrease in price has to be compared to the ORIGINAL price. (at the beginning of the month.)

The price increased from $3.50 to $3.75, an increase of $0.25

To find what percent it is use:[tex]\frac{change}{original}[/tex]×100%

[tex]\frac{0.25}{3.50}[/tex]×100%

Answer:

7.1428571% increase

7  1/7 % increase

Step-by-step explanation:

To find the percent increase ( we know this is an increase since the amount went up), take the new amount and subtract the original amount

3.75 - 3.50 = .25

Divide by the original amount

.25 / 3.50

.071428571

Multiply by 100 %

7.1428571%

7 1/7 %

to get the equation of any straight line, we simply need two points off of it, let's use those from the picture below.

[tex](\stackrel{x_1}{-10}~,~\stackrel{y_1}{-100})\qquad (\stackrel{x_2}{30}~,~\stackrel{y_2}{140}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{140}-\stackrel{y1}{(-100)}}}{\underset{\textit{\large run}} {\underset{x_2}{30}-\underset{x_1}{(-10)}}} \implies \cfrac{140 +100}{30 +10} \implies \cfrac{ 240 }{ 40 } \implies 6[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-100)}=\stackrel{m}{ 6}(x-\stackrel{x_1}{(-10)}) \\\\\\ y +100 = 6 ( x +10)\implies y+100=6x+60\implies {\Large \begin{array}{llll} y=6x-40 \end{array}}[/tex]

The X-intercept is the point where the line crosses the x-axis. This happens where the Y is equals to zero.

The point slope form of a line is an equation of the line that takes on the form y - y1 = m(x - x1). In this equation, m is the slope of the line, and (x1, y1) is a point on the line. The x-intercept of a line is the x-coordinate of the point where the line crosses the x-axis. This always happens at the point where y is equal to 0. Therefore, we find the x-intercept of a line in point-slope form by plugging y = 0 into the equation and then solving for x. The point-slope formula is composed of a specific point of coordinates and a slope indicating a type of change over a given variable, such as distance over time. It is said to be as the x-coordinate of a point where a line, curve, or surface intersects the x-axis.

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Therefore, the interval (0, 1) must be countless and infinite. Since the interval (0, 1) is as large as R, R is also infinite.

Interval:

In mathematics, a (real) interval is a set of real numbers containing all real numbers between any two numbers in the set. For example, the set of numbers x such that 0 ≤ x ≤ 1 is an interval containing (0, 1), and all numbers in between. Other examples of intervals are the set of numbers with 0 < x < 1, the set of all real numbers, the set of non-negative real numbers, the set of positive real numbers, the empty set, and any Singleton (a set of one element).

Real intervals play an important role in integral theory. This is because real intervals are the simplest set whose "length" (or "scale" or "magnitude") is easy to define. The notion of measure can be extended to more complex sets of real numbers, leading to the Boral measure and finally the Lebesgue measure.

Intervals are central to interval arithmetic, a general numerical technique that automatically provides guaranteed bounds for any mathematical expression, even in the presence of uncertainties, mathematical approximations, and arithmetic rounding.

Open Interval:

Open intervals do not include endpoints and are indicated by parentheses.  For example, (0, 1) means greater than 0 and less than 1. This is (0, 1) = {x | 0 This interval can also be expressed as ]0, 1[ . Please refer to the following.

Closed Interval:

A closed interval is an interval that contains all boundary points and is indicated by square brackets. For example, [0, 1] means greater than or equal to 0 and less than or equal to 1.

Half- Open Interval:

A half-open interval contains only one of its endpoints and is represented by a combination of open and closed interval notation. Example: (0, 1) means greater than 0 and less than or equal to 1, [0, 1) means greater than or equal to 0 and less than 1.

Complete Question:

II. Identify the following terms described in each item. Quantitative & Quaeritated. It can be separated into different categories that are distinguished by some nonnumeric characteristics. 2. It consists of numbers representing counts or measurements. Quantitative Quantitative 3. The result from either a finite number of possible values or countable number of possible values as 0, or 1, or 2, and so on 4. The result from infinitely many possible values that can be associated with points on a continuous scale in such a way that there are no gaps or interruptions 5. It is characterized by data that consist of names, labels, or categories only. 6. It involves data that may be arranged in some order, but differences between data values either cannot be determined or are meaningless. 7. It involves meaningful amounts of differences between data. It has no true zero point or absolute zero. 8. It contains all the properties of the interval level but has true zero point or absolute zero. 9. It is a complete collection of all elements to be studied. 10. It is a branch of Mathematics that deals with the collection, organization presentation, analysis, and interpretation of data.​

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Answer:

Gianna has $760 to spend and she has already spent $356.46 on a new bicycle, $10.01 on 2 bicycle reflectors, and $20.72 on a pair of bike gloves.

The total amount spent on these items is $356.46 + $10.01 + $20.72 = $387.19.

Gianna has $760 - $387.19 = $<<760-387.19=372.81>>372.81 left to spend on biking outfits.

She wants to buy biking outfits that cost $45.35 each.

We can write an inequality to represent the number of outfits Gianna can purchase while staying within her budget as follows:

45.35o <= 372.81

This inequality can be solved by dividing both sides by 45.35:

o <= 8.24

Therefore, Gianna can purchase 8 biking outfits while staying within her budget.

Step-by-step explanation:

The total value of the furniture that was sold by Dennis is 3,500 dollars.

What is the percentage?

The amount of something is expressed as if it is a part of the total which is a hundred. The ratio can be expressed as a fraction of 100. The word percent means per 100. It is represented by the symbol ‘%’.

Dennis made an extra $245.00 for selling furniture.

Let the cost of the furniture be x.

Let the total value of the furniture be x + 245.

The extra $245.00 was 7% of the total value of the furniture he sold.

0.07(x + 245) = 245

        x+ 245 = 3500

                  x = 3255

Then the total value of the furniture is (3,255 + 245 =) $3,500.

Hope it helped!

On solving the provided question, we can say that by equation 60 miles from his home is the appointment

An equation is a mathematical formula that connects two assertions using the equal sign (=) to denote equivalence. In algebra, an equation is a mathematical statement that establishes the equivalence of two mathematical expressions. For instance, an equal sign separates the components 3x + 5 and 14 in the equation 3x + 5 = 14. A mathematical formula is used to explain the connection between two sentences on either side of a letter. Frequently, there is just one variable, which is also the symbol. for example, 2x - 4 = 2.

for d and t

60 = d/t

45 = d / t + 0.33

60t = d

45( t + 0.33) = d

60t = 45t + 15

t = 1 hour

d = 60 X 1 miles = 60 mile

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The equation of the line perpendicular to x - 4y = 7 can be written as:

y = 4*x + b

Where b could be any real number.

Two lines are perpendicular if the product between the slopes of the lines is equal to -1.

Where a general line in the slope-intercept form is written as:

y  =a*x +b

And the given line is:

x - 4y = 7

Writing this in the slope-intercept form we will get:

-4y = -x - 7

y = (-1/4)*x + 7/4

So the slope is -1/4, then the slope of our line must be such that:

a*(-1/4) = -1

a = -4*-1 = 4

a =4

So the line perpendicular to the given one is:

y = 4*x + b

Where b can be any real number.

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Answer: AAS

Step-by-step explanation:

AAS, because the side congruence isn't between the angles as it should be in order for it to be ASA.

The total number of workers in the factory is = 240.

It is given that,  

     Male =    85%

    Female = 36

If we assume that the total workers account for 100%, then we know that Female workers account for 15% of the workforce (as 100-85= 15).

Now,

       => 15% = 36

      If,   1%  = 36/15

then, 100% = 36/15*100

                  = 12*20

                  = 240.

Therefore, the answer is 240.

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7x and 7x2 are NOT like terms.

Terms with identical variables (like x or y) and any exponents (like the 2 in x2). Similar phrases can be combined. Similar or like terms are those that only differ in numerical coefficient but have the same literal coefficients raised to the same powers. Related terms are those that have the same exponent applied to similar variables. Dissimilar or unlike terms are those that do not have the same literal coefficients raised to the same powers. Only the numerical coefficients can change in terms similar to those of algebra.

However, because to the various exponents, 7x and 7x2 are NOT similar expressions.

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The formula for an isosceles triangle is A = (1/2) * b * h, where b is the base, h is the height, and A is the area.

The formula for an isosceles triangle is A = (1/2) * b * h. This formula is used to calculate the area of an isosceles triangle. To use the formula, you need to know the base, b, and the height, h, of the triangle. The base is the length of any one of the two equal sides of the isosceles triangle, and the height is the distance from the base to the opposite vertex. Once you have these measurements, you can plug them into the formula to calculate the area of the triangle. The formula multiplies the base, b, by the height, h, and then divides the product by two. This will give you the area of the triangle, A.

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To change logarithmic form to exponential form, spot the logarithmic equation's base and move the base to another side to the equal sign. Moving the base will make the current number or variable into the exponent.

Do not move something but the base: the other numbers or value will not change sides, and the word "log" will be release.

Log Rules:

1. the first rule is logb(mn) = logb(m) + logb(n)

2. the second rule is logb(m/n) = logb(m) – logb(n)

3. the third rule is: log b (mn) = n · logb(m)

1. Multiplication can be turned outside the log into addition and vice versa can be turned.

2. Division can be spin outside the log into a subtraction, and vice versa.

3. An exponent can be proceeded as a multiplier outward on all within a log, and vice versa.

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Answer:

Submarine must descend by 12 feet in the fifth minute.Average of the data:Average of a data set is calculated by dividing the sum of terms by the number of the terms of the set.From the table given in picture,Let the distance descended by submarine in 5th minute = x feetAverage distance descended by the submarine =                                                                                 =                                                                                 =  feet per minuteStatement given in the question → "Submarine must descend at an average rate of at least 10 feet per minute"So the inequality for the statement will be,38 + x ≥ 50x ≥ 50 - 38x ≥ 12    Therefore, submarine must descend 12 feet in the 5th minute.

Step-by-step explanation:

[tex] \longmapsto \: 7x + 5x + 2x = 35820 \\ \\ x = \frac{35840}{14} = 2560[/tex] length equals to 7 into 2560 = 1792

Answer:

Obtuse and isosceles

Step-by-step explanation:

obtuse because an angle is more than 90* and isosceles because two sides are equal.

Hope this helps!

Eli could travel 12 miles and 3/4x+2x>11 inequality matches the statement Three-fourths times x added to two times x is more than eleven

a relationship between two expressions or values that are not equal to each other is called 'inequality.

Given that a taxi charges a flat rate of $1.75 and an additional $0.65 per mile.

Eli has at most $10 to spend on the cab ride

We need to find how far could he travel

1.75+0.65x≤10

Subtract 1.75 on both sides

0.65x≤10-1.75

0.65x≤8.25

x≤8.25/0.65

x≤12.6

So he could travel 12 miles.

Three-fourths times x added to two times x is more than eleven

3/4x+2x>11

Hence,  Eli could travel 12 miles and 3/4x+2x>11 inequality matches the statement Three-fourths times x added to two times x is more than eleven

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Answer:

[tex]x = -7\\x = -3[/tex]

Step-by-step explanation:

The steps are in the image attached to this response.

Equivalent fractions are those that, despite their visual differences, reflect the same value. we consumed half of a cake, for instance, if you have one, divide it into two equal pieces, and then eat one of the pieces.

Any number of equal portions, or parts of a whole, are described by fractions. Fractions in standard English indicate the number of pieces of a specific size. 8, 3/4 of .Part of an entire is a fraction. The ratio of the numerator to the denominator is how numbers are expressed in mathematics. Each of these is an integer in simple fractions. In the numerator or denominator of a complex fraction is a fraction. When a fraction is true, its numerator is smaller than its denominator.

If the denominators differ, similar fractions with a common denominator must be used. This requires figuring out the LCM of the two denominators. To be used as a denominator in fractions with various denominators, rename the fractions with a similar denominator.

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