find the surface area to the nearest tenth

Answer: Use the figures to complete the statements.

The height of the triangle h is

✔ 12

in.

The area of the triangle is

✔ 48

in.2.

The area of the parallelogram is

✔ 80

in.2.

The area of the irregular figure is

✔ 128

in.2.

Step-by-step explanation: I js now got it right by the power of guessing

Answer:

8/15

Step-by-step explanation:

In a right triangle, where B is an acute angle, the tan B is equal to the measure of the side opposite B divided by the measure of the shorter side at B

tanB = 16/30 = 8/15

Answer:

1 1/3

Step-by-step explanation:

Answer:

12/9= 1 and 1/3

Step-by-step explanation:

Solution :

Given :

[tex]$n_1 = n_2 = 40$[/tex]

[tex]$\overline X_1 = 18$[/tex]

[tex]$S_1 = 4$[/tex]

[tex]$\overline X_2 = 12$[/tex]

[tex]$S_2 =10$[/tex]

So we want to test :

[tex]$H_0 : \mu_1=\mu_2 $[/tex]   vs [tex]$H_1 : \mu_1 \neq \mu_2 $[/tex]

a). For 98% confidence interval :

[tex]$=\left((\overline X_1 - \overline X_2) \pm Tn_1+n_2-2, \alpha / 2 \sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}\right)$[/tex]

[tex]$=\left((18-12) \pm 2.375 \sqrt{\frac{4^2}{40}+\frac{10^2}{40}}\right)$[/tex]

[tex]$=(6 \pm 4.0445)$[/tex]

= (1.956, 10.045)

Answer:

25/500 or 5% said 'other'

Step-by-step explanation:

55% = 275 (dog)

1/10 = 50 (cat)

0.3 = 150 (bird)

Total = 475

475 out of 500 (95%) gave an answer other than 'other'

Answer:

88 yd.²

Hope this helps!

Answer:

Area= 88 sq. yd.

Step-by-step explanation:

The formula for the area of a triangle is A= h b/2.

This means you just divide 16 (the base) by 2 to get 8, and then multiply it by 11 (the height). This gives you 88

Answer:

28yd²

Step-by-step explanation:

area of square = side *side

=6*6= 36²

area of rectangle (patio)= length* breadth

=4*2=8²

area of garden= area of square - area of rectangle

=36-8

=28 yd²

Answer:

Step-by-step explanation:

First Case:

Given,

Side of the big square = 6 yd

Therefore,

Area of the big square = side × side

= 6yd × 6yd

[tex] = 36 {yd}^{2} [/tex]

Second Case:

Length of the patio = 4 yd

Breadth of the patio = 2 yd

Therefore,

Area of the patio = Length × Breadth

= 4yd × 2yd

[tex] = 8 {yd}^{2} [/tex]

Last Case:

According to first and second cases,

Area of the garden

= Area of the big square - Area of the patio

[tex] = 36 {yd}^{2} - 8 {yd}^{2} [/tex]

[tex] = 28 {yd}^{2} [/tex]

Required area of the garden is 28 sq. yd (Ans)

Answer:

40

Step-by-step explanation:

100 - 68 = 32

32/100 = ?/125

125 x 32 = 4,000

4,000 ÷ 100 = 40

Answer:

200

Step-by-step explanation:

First we need to find the decimal version of 40%

to do this we can move the decimal point 2 spaces to the left.

40% ---> 0.40

then we can multiply by 500

This is equal to 200

Answer: 200

Step-by-step explanation: 40%=.40

500•.4=200

Answer:

x - intercept - ( 10 , 0)

y - intercept - (0 , 8)

Step-by-step explanation:

Answer: soo

(4x^3+5x^2-3x-6)-(4x-5)

the answer is 4-^3+5x^2-7x-1

Step-by-step explanation:

Answer: 500.

Step-by-step explanation:

Your answer is 500.

Answer:

[tex]165 + 12c = 465[/tex]

Is the right answer

Answer:$25 per chair

Step-by-step explanation:

It’s $165 for only the table. Minus that from the $465 and you get $300. Do $300 divided by 12(amount of chairs) And you get $25. It’s $25 per 1 chair.

Answer:

1017.88 inches

Step-by-step explanation:

Area = πr2 = π x 182 ≈ 1017.87602

Answer:

mode is the number listed most often and data can have more then 1 mode

the numbers most listed in the image are: 5 and zero

Step-by-step explanation:

I hope this helped!

Answer:

90

Step-by-step explanation:

mode = A number that appears most often is the mode.

Answer:

About 4 days

Step-by-step explanation:

Convert 39 and 42 degrees C to a z score and then use the z-table

The number of days in June when the midday temperature was between 39°C and 42°C is equal to 4.0 days.

Given the following data:

Mean midday temperature = 36°C.

Standard deviation = 3°C.

In order to determine the number of days in June when the midday temperature was between 39°C and 42°C, we would determine the z-score as follows:

Let the midday temperature be M.

P(39 < M < 42) = 1 - [P(M < 39) + P(M < 42)]

Evaluating, we have:

P(M < 39) = P(Z < [39 -36/3])

P(M < 39) = P(Z < [3/3])

P(M < 39) = P(Z < 1).

P(M < 39) = 0.84134.

P(M < 42) = P(Z < [42 -36/3])

P(M < 42) = P(Z < [6/3])

P(M < 42) = P(Z < 2)

P(M < 42) = 0.02275.

Substituting the parameters into the formula, we have;

P(39 < M < 42) = 1 - [P(M < 39) + P(M < 42)]

P(39 < M < 42) = 1 - [0.84134 + 0.02275]

P(39 < M < 42) = 1 - 0.86409

P(39 < M < 42) = 0.13591‬.

Now, we can determine the number of days in June when the midday temperature was between 39°C and 42°C:

No. of days = 0.13591 × 30

No. of days = 4.0 days.

Note: There are 30 days in the month of June.

Read more on z-scores here: https://brainly.com/question/4302527

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Answer:

1845/15=123

Step-by-step explanation:

Step-by-step explanation:

I don't now just paiattention to the problem that willed be more like it thx

Answer:

9 cubic feet

Answer:

Step-by-step explanation:

6). Surface area of a triangular prism = Area of the triangular bases + (Perimeter of the triangular base)×height

Area of one triangular base = [tex]\frac{1}{2}(\text{Base})(\text{Height})[/tex]

                                              = [tex]\frac{1}{2}\times 4\times 3[/tex]

                                              = 6 km²

Perimeter of the triangular base = (4 + 3 + 5)

                                                      = 12 km

Height of the triangular prism = 7 km

Surface area of the given triangular prism = 2(6) + (12)(7)

                                                                      = 12 + 84

                                                                      = 96 km²

7). Surface area of a rectangular prism = 2(lb + bh + hl)

Here, l = Length, b = Width and h = Height

By substituting the values from the given question,

l = 9 in, b = 9 in, h = 4 in

Surface area of the rectangular prism = 2(9×9 + 9×4 + 4×9)

                                                               = 2(81 + 36 + 36)

                                                               = 2(153)

                                                               = 306 in²                              

Answer:

(Length x Width x Height)

6x18x12=

I hope this helped! ♡+*

Answer:

If the length of any one side is greater than the sum of the length of the other two, the line segments cannot be used to create a triangle. It is possible to create a triangle using 3 line segments if the sum of the lengths of any two line segments is greater than the length of the third.

Answer:

c hope it nhelps

Step-by-step explanation:it takes away time

Answer:

the person above me is correct!

Step-by-step explanation:

Answer:

Step-by-step explanation:

70

The domain of the function graphed in this problem is given as follows:

(-∞, -1) U (-1, ∞).

The vertical asymptote of the rational function graphed in this problem is given as follows:

x = -1.

Hence the function is defined for all real values except x = -1, meaning that the domain is given as follows:

(-∞, -1) U (-1, ∞).

Learn more about domain and range at https://brainly.com/question/26098895

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Answer:

she has 15 dog toys

Step-by-step explanation:

mutlipy 3 by five because the top number is one

Answer:

4

Step-by-step explanation:

they are divisible by either 3 or 5 but not both of these numbers

Answer:

378

Step-by-step explanation:

1 digit numbers - 9

2 digit numbers - 90

Now, subtract the repeating numbers 90-9 = 81

3 digit numbers = 4*9*8 = 288  

Distinct numbers = 9+81+288 = 378 numbers

Answer:

c. (x +3)(x + 1)

Step-by-step explanation:

Factoring an equation is a way of expressing an equation as the product of other linear expressions. The following expression,

[tex]x^2 +4x +3[/tex]

Can be represented as the product of the following,

[tex](x+3)(x+1)[/tex]

To check this, one can distribute, one of the expressions over the other, then simplify, the result should be the starting expression,

[tex](x+3)(x+1)\\[/tex]

Distribute,

[tex](x)(x)+(1)(x)+(3)(x)+(3)(1)[/tex]

Simplify,

[tex]x^2 +x +3x + 3\\[/tex]

[tex]x^2 +4x +3[/tex]