Find the volume (to the nearest cubic foot) of a cone with base radius 4 ft. and height 8 ft.

Answer:

Solution = (2,1)

Step-by-step explanation:

Make them equal each other and solve for x.

2x - 3 = 1

2x = 4

x = 2

2 * 2 - 3 = 1

Solution = (2,1)

Answer:

When -3v = -18 is solved, the result is:

21v

The result of this mathematical sentence is v=6

First degree equation is a mathematical sentence - having at least one unknown. Its representation is given by ax + b = 0. To calculate an equation, as it is in the expression in the statement, simply: isolate x and divide the second to the first member.

*Note: Equal signs, the result will be equated as positive.

-3v = -18

v = -18/-3

v = 6

Therefore, the correct value of this equation is v = 6.

Answer:

3.9 degrees celsius

Step-by-step explanation:

(°F − 32) × 5/9 = °C

input 39

7 times 5/9 = c

35/9 = c

c = 3.9

Answer:

3.9 degrees Celsius.... it's 3.8888 when translated from Farenheit

Answer:

0.2683281573

Step-by-step explanation:

The update of the completed graph is given in the image attached as it shows the possible combinations of Yellow or Xanadu party favors that might choose will be ( 48, 0).

For this graph, we shall make Xanadu party favors  as X

and yellow favors  as  Y

Therefore note that: X + Y = 48

In the graph of X - Intercept

Y = 0, X = 48

In the graph of Y- intercept,

Y = 48 , X = 0

Therefore, the graphical representation of the combinations is given in the image attached.

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Answer: The answer is 2289.06

Step-by-step explanation: I assume it’s a circle as it has a radius so simply multiply 3.14 by the radius 27^2

Answer:

4hours

Step-by-step explanation:

1hour =85+85

=170km/h

time= distance÷

speed=170km/h

680÷170=time

=4h

The table that represents an exponential function of the form y = [tex]b^{x}[/tex] when 0 < b < 1 is Table - 2. See the attached tables.

A function is exponential when its value is a constant that is raised to the power of the argument. This is so especially when the function of the constant is e.

Recall that the exponential function y = [tex]b^{x}[/tex] given that 0 < b < 1. Notice that the table number 2 see to the exponential function that has the following form:

y(x) = (1/3)ˣ

substituting the values of x into the equation, we have:

y(-3) = (1/3) ⁻³ = 27

x = -2; thus

y(-2) =  (1/3) ⁻³ = 9

x = -1; thus

y(-1) =  (1/3) ⁻³ = 3

x = 0; thus

y(0) =  (1/3) ⁻⁰ = 1

x = 1; thus

y(1) =  (1/3) ¹ = 1/3

x = 2; thus

y(2) =  (1/3) ⁻² = 1/9

x = 3; thus

y(3) =  (1/3) ⁻³ = 1/27

Therefore, according to the obtained values, one can summarize that the table that depicts the exponential function y  = bˣ is table 2.

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Explanation:

Given f(x) : (2, -3)

f(x) + 2 then graph translates up by 2 units up =  [tex]\boxed{\sf (2, -1)}[/tex]

f(x) - 3 then graph translates down 3 units down = [tex]\boxed{\sf (2, -6)}[/tex]

f(x + 5) then graph translates left 5 units = [tex]\boxed{\sf (-3, -3)}[/tex]

-f(x) then graph reflects over x axis = [tex]\sf \boxed{\sf (2, 3)}[/tex]

f(-x)  then graph reflects over y axis = [tex]\sf \boxed{\sf (-2,-3)}[/tex]

f(2x) then graph has horizontal compression = (2/2, -3) = [tex]\boxed{\sf (1, -3)}[/tex]

2f(x) then graph has vertical compression = (2, (-3)2) = [tex]\boxed{\sf (2, -6)}[/tex]

-f(x - 4) then graph reflects over x axis, moves 4 units to right = [tex]\sf \boxed{\sf (6, 3)}[/tex]

Parent function: y = x²

Graph function: f(x) = (x + 8)² - 4

After Identification:

D. The graph has a translation of 8 units left and 4 units down.

Answer:

Translations

For [tex]a > 0[/tex]

[tex]f(x+a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units left}[/tex]

[tex]f(x-a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units right}[/tex]

[tex]f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}[/tex]

[tex]f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}[/tex]

[tex]y=a\:f(x) \implies f(x) \: \textsf{stretched parallel to the y-axis (vertically) by a factor of}\:a[/tex]

[tex]y=f(ax) \implies f(x) \: \textsf{stretched parallel to the x-axis (horizontally) by a factor of} \: \dfrac{1}{a}[/tex]

[tex]y=-f(x) \implies f(x) \: \textsf{reflected in the} \: x \textsf{-axis}[/tex]

[tex]y=f(-x) \implies f(x) \: \textsf{reflected in the} \: y \textsf{-axis}[/tex]

Given:  [tex]f(x)=(2,-3)[/tex]

[tex]f(x)+2 \implies (x, y+2)= (2,-3+2)=(2,-1)[/tex]

[tex]f(x)-3 \implies (x,y-3)=(2,-3-3)=(2,-6)[/tex]

[tex]f(x+5)\implies (x-5,y)=(2-5,-3)=(-3,-3)[/tex]

[tex]-f(x) \implies (x,-y)=(2,-(-3))=(2,3)[/tex]

[tex]f(-x) \implies (-x,y)=(-(2),-3)=(-2,-3)[/tex]

[tex]f(2x) \implies \left(\dfrac{x}{2},y\right)=\left(\dfrac{2}{2},-3\right)=(1,-3)[/tex]

[tex]2f(x) \implies (x,2y)=(2,2 \cdot -3)=(2,-6)[/tex]

[tex]-f(x-4) \implies (x+4,-y)=(2+4,-(-3))=(6,3)[/tex]

[tex]\begin{array}{| c | c | c | c | c | c | c | c |}\cline{1-8} & & & & & & &\\f(x)+2 & f(x)-3 & f(x+5) & -f(x) & f(-x) & f(2x) & 2f(x) & -f(x-4)\\& & & & & & &\\\cline{1-8} & & & & & & &\\(2,-1) & (2,-6) & (-3,-3) & (2,3) & (-2,-3) & (1,-3) & (2,-6) & (6,3)\\& & & & & & &\\\cline{1-8} \end{array}[/tex]

Parent function:  [tex]y=x^2[/tex]

Given function:  [tex]f(x)=(x+8)^2-4[/tex]

[tex]f(x+8) \implies f(x) \: \textsf{translated}\:8\:\textsf{units left}[/tex]

[tex]f(x)-4 \implies f(x) \: \textsf{translated}\:4\:\textsf{units down}[/tex]

Therefore, a translation 8 units to the left and 4 units down.

The sample mean for the data is 21.38 and the sample standard deviation for the data is 56.19

To do this, we start by calculating the midpoint of each class using:

Midpoint= (Lower + Upper)/2

Using the above formula, we have:

Age (x)        Frequency (f)

2                   24.8

9.5               422

17                  194

22                 256

29.5             50.7

39.5              35.7

54.5             75.2

70                 54.3

This is calculated using:

[tex]\bar x = \frac{\sum fx}{\sum f}[/tex]

So, we have:

[tex]\bar x = \frac{2*24.8 + 9.5*422 + 17*194 + 22*256 + 29.5*50.7 + 39.5*35.7 + 54.5*75.2+70*54.3}{24.8 + 422 + 194 + 256 + 50.7 + 35.7 + 75.2 + 54.3}[/tex]

Evaluate

[tex]\bar x = \frac{23793.8}{1112.7}[/tex]

[tex]\bar x = 21.38[/tex]

Hence, the sample mean for the data is 21.38

This is calculated using:

[tex]\sigma_x = \sqrt{\frac{\sum f(x- \bar x)^2}{\sum f - 1}}[/tex]

So, we have:

[tex]\sigma_x = \sqrt{\frac{2*(24.8-21.38)^2 + .............+70*(54.3-21.38)^2}{24.8 + 422 + 194 + 256 + 50.7 + 35.7 + 75.2 + 54.3 - 1}}[/tex]

Evaluate

[tex]\sigma_x = \sqrt{\frac{3509508.4556}{1111.7}}[/tex]

[tex]\sigma_x = \sqrt{3156.88446128}[/tex]

[tex]\sigma_x = 56.19[/tex]

Hence, the sample standard deviation for the data is 56.19

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Answer:

62.

Step-by-step explanation:

because I subtract 70 to 8 equal to 62

Answer:

I think

Step-by-step explanation:

I think 62 hope you have a good day

The range of a graph of a function is (-∞, 3) U (3, ∞) option (D) (-∞, 3) U (3, ∞) is correct.

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

It is given that:

The graph of a hyperbola function is given.

As we know the graph of an inverse of a function is reflections over the line y=x.

We get the same graph as given in the picture.

The range of a graph of a function:

Range: (-∞, 3) U (3, ∞)

Thus, the range of a graph of a function is (-∞, 3) U (3, ∞) option (D) (-∞, 3) U (3, ∞) is correct.

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Answer:

Step-by-step explanation:

What is 20 divided by 1/2 inches

20 : 1/2 =

20 * 2 =

40

Answer:

See Below

Step-by-step explanation:

Since PQ is perpendicular to RS, the angles PQR and PQS would be right angles, and right anglers are congruent, so <PQR ≅ <PQS. We are given that <R and <S are the same length, so they are congruent(<R ≅ <S). Since PQ is included in both triangles and it is the same length as itself(PQ ≅ PQ).

We have three congruent parts, two angles and one side. Therefore, using AAS, ΔPQR ≅ ΔPQS

Answer:

See below ~

Step-by-step explanation:

Given :

⇒ PQ ⊥ RS

⇒ ∠R = ∠S

===============================================================

Solving :

⇒ PQ = PQ (common side)

⇒ ∠R = ∠S (given)

⇒ ∠PQS = ∠PQR = 90° (⊥ bisector forms equal right angles)

⇒ ΔPQR ≅ ΔPQS (by ASA congruence)

Answer:

1) x + 1

2) y - 0

3) 9

Step-by-step explanation:

Answer:

the first answer is (x+1) the second box (y-0) and the last box is 9

Step-by-step explanation:

Answer:

the answer to that question is 12,600 rupees

Answer:

79.8

Step-by-step explanation:

Answer:

[tex]\huge\boxed{\sf R. 16.75}[/tex]

Step-by-step explanation:

*Assuming commas are used for decimals.

2.6 kg potatoes = R 13.20

Divide 2.6 to both sides

1 kg potatoes = R 13.20/2.6

1 kg potatoes = R 5.1

Multiply 3.3 to both sides

3.3 kg potatoes = R 5.1 × 3.3

3.3 kg potatoes = R 16.75

[tex]\rule[225]{225}{2}[/tex]

Evaluation:

The answe for the function is -1.

Answer: (4,-4)

Step-by-step explanation:

Reflection across the x axis means [tex](x,y) \longrightarrow (x,-y)[/tex], so [tex](3,7) \longrightarrow (3,-7)[/tex].

Reflection across the y axis means [tex](x,y) \longrightarrow (-x,y)[/tex], so [tex](3,-7) \longrightarrow (-3,-7)[/tex].

Then, [tex](-3,-7) \longrightarrow R'\boxed{(4,-4)}[/tex]

Answer:

D

Step-by-step:

The y-coordinates will change, not the x. Size and shape will also remain the same.

Answer:

the leftover piece of ribbon is 5 3/4 feet long.

Step-by-step explanation:

if she has 7 1/2 feet of ribbon, and she removes (by cutting it off) 1 3/4 feet of ribbon.

So, if we set up this scenario like a math problem, we can write it as this:

7 1/2 feet of ribbon - 1 3/4 feet of ribbon = remaining ribbon

[ - = take away]

so, we are solving the equation:

7 1/2 - 1 3/4

To solve this, it is easiest to make the fractions have the same denominators

1 / 2 is equal to 2 / 4

However, 2/4 is less than 3/4, so we need to make this fraction a larger number.

To do this, we can take away 1 foot from the 7, and write it as if it were fourths

1 [foot] = 4/4 quarter foot

So, we can add 4/4 + 2/4 = 6/4

Now, we can re-write our situation.

6 6/4  -   1 3/4 = left over ribbon

   6      6/4

-   1       3/4

__________

   5      3/4

So, the leftover piece of ribbon is 5 3/4 feet long.

Hope this helps!

Answer:

x=5.24-9+180n,174.75+180n

Step-by-step explanation:

Modern:

Where there are two open slits, the resulting pattern will simply be the sum of the two single-slit patterns (two vertical lines). But again and again, the experiment demonstrated that the coherent beams of light were interfering, creating a pattern of bright and dark bands on the screen.

Young's

In the end, the double slit experiment discovered that electrons, and all quantum particles, both exist as particles and probability waves. Quantum particles existing as probability waves means that we don't know for certain where these particles are, we can only know the probability of where they will be.

Answer:

246

Step-by-step explanation:

h = 2

t = 4

u = 6

t - h = 4 - 2 = 2

u = h + t = 2 + 4 = 6

Hi Student!

Looking at the problem statement, we are asked to find the place value of the 1 in the number 742.513.  Let's go from right to left and name each of the place values.  7 is in the hundreds place, 4 is in the tens place, 2 is in the ones place, 5 is in the tenths place, 1 is in the hundredths place, 3 is in the thousandths place.

Therefore, our final answer for which place value the number 1 in 742.513 is, we come to the conclusion of the hundredths place.