Fitting a straight line to a set of data yields the following prediction line.

Y_i = 14 - 0.2X_i I

nterpret the meaning of the Y-intercept, b_0.

Step-by-step explanation:

area: 28/4=7

7x7=49

diagonal=square root 7²+7²

9.89949

9.90

hope it can help you

Answer:

1).  (x - 4 = 13)

2).  (r + 17 = 51)

3). (7/9x =28)

4). (2/3x = 2)

5). { 3(x-2) = -9 }

6). (x -1.75 = 8.85)

7). Natalie buys organic almonds priced at $77 from the grocery store. How much did

she pay the cashier, if she received $23 in change?

Step-by-step explanation:

1. add 4 on both sides and it will be x=17

2. subtract 17 on both sides and it will be x= 34

3. multiply 9/7 on both sides and it will be x= 257/7 then you divide 257 by 7 then the final answer will be x= 36

4. multiply 3/2 on both sides and it will be x=6/2 then you divide 6 from 2 and the finial answer will be x= 3

5. you will distribute 3 into x and 2 and you will be 3x-6=-9 then you will add 6 on both sides so you will get 3x=3 and then divide 3 on both side so you will get x=1

6. add 1.75 on both sides so x= 10.6

7. the equation will be 23 +x = 77 so first you will subtract 23 on both sides and x will equal 54 so Natalie paid $54

Answer:

i'm taking that test rn

Step-by-step explanation:

Answer:

It's 11.72

Step-by-step explanation:

Area=)1/2×15/4×25/4

Answer》11.72

Hope it helps...

Have a great day

Answer:

i have made it in above picture

At t = 0.03 s, the charge on the capacitor in the LRC-series circuit is 0.8630 C.

In an LRC-series circuit, the charge on the capacitor can be calculated using the formula Q(t) = Q(0) * e^(-t/(RC)), where Q(t) is the charge at time t, Q(0) is the initial charge on the capacitor, R is the resistance, C is the capacitance, and e is the base of the natural logarithm.

Given the values L = 0.05 H, R = 3.12 Ω, C = 0.008 F, E(t) = 0 V, Q(0) = 4 C, and i(0) = 0 A, we can substitute these values into the formula. Using the given time t = 0.03 s, we can calculate the charge on the capacitor.

Plugging in the values, we have Q(0.03) = 4 * e^(-0.03/(3.12*0.008)). Evaluating this expression gives us Q(0.03) ≈ 0.8630 C, rounded to four decimal places.

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Given z-score is z = 2.58 and the null hypothesis isH0: p = 0.85, where p is the true proportion, and we need to find the p-value.

We know that for a two-tailed test, the p-value is the probability that a z-score is greater than or equal to the absolute value of the calculated z-score or less than or equal to its negative value. So, the p-value for a two-tailed test is: p-value = P(z ≥ 2.58) + P(z ≤ -2.58)  ..............(1) Here, z = 2.58 represents the upper critical value, and the negative of it is the lower critical value (z = -2.58)

As the given hypothesis is a two-tailed test, we need to calculate the probabilities for both critical values. From the standard normal distribution table, the probabilities for these critical values are:

P(z ≥ 2.58) = 0.0049 (approx.)  P(z ≤ -2.58) = 0.0049 (approx.)

Substituting these values in equation (1), we get: p- value = 0.0049 + 0.0049 p-value = 0.0098Hence, the p-value is 0.0098 (approx.)

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Answer:

There will be 225 cars on the lot.

A car dealership has 180 cars on their lot. If they increase their inventory be 25%, how many cars will be on the lot?

25/100 * 180

= 5 * 9 = 45

Therefore:

180 + 45 = 225 cars

Answer:

There will be 225 cars on the lot.

The expectation (mean) of the company's daily loss due to blackouts is $200, and the variance is $350.

To compute the expectation of the company's daily loss, we multiply each possible loss value by its corresponding probability and sum them up. In this case, we have three possible loss values (0, 1, and 2) with their respective probabilities (0.7, 0.2, and 0.1). Multiplying each loss value by its probability and summing them gives us the expected value of $200.

To calculate the variance, we need to find the squared differences between each possible loss value and the expected value, multiply them by their respective probabilities, and sum them up. Squaring the differences ensures that negative differences do not cancel out positive differences. In this case, the variance is calculated as (0 - 200)^2 * 0.7 + (1 - 200)^2 * 0.2 + (2 - 200)^2 * 0.1, resulting in a variance of $350.

The expectation and variance provide useful measures of the central tendency and variability, respectively, of the company's daily loss due to blackouts.

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a) The solution to x²-2x-3≥0 is x ≤ -1 or x ≥ 3, expressed in interval notation as (-∞, -1] ∪ [3, ∞).

b) The solution to 6x-2x² > 0 is x < 0 or x > 3, expressed in interval notation as (-∞, 0) ∪ (3, ∞).

c) The solution to 9x+17 ≤ 0 is x ≤ -17/9, expressed in interval notation as (-∞, -17/9].

a) To solve the inequality x²-2x-3≥0, we can factor the quadratic expression as (x-3)(x+1) ≥ 0. We find that the inequality is satisfied when x ≤ -1 or x ≥ 3. The solution is expressed in interval notation as (-∞, -1] ∪ [3, ∞).

b) To solve the inequality 6x-2x² > 0, we can factor out 2x from the expression to get 2x(3-x) > 0. We find that the inequality is satisfied when x < 0 or x > 3. The solution is expressed in interval notation as (-∞, 0) ∪ (3, ∞).

c) To solve the inequality 9x+17 ≤ 0, we isolate x by subtracting 17 from both sides to get 9x ≤ -17. Dividing both sides by 9, we find x ≤ -17/9. The solution is expressed in interval notation as (-∞, -17/9].

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Answer:

x= 8/5

Step-by-step explanation:

Let's solve your equation step-by-step.

1

3

(x+3)+

1

6

=

1

2

(x−1)−(x−3)

Step 1: Simplify both sides of the equation.

1

3

(x+3)+

1

6

=

1

2

(x−1)−(x−3)

1

3

(x+3)+

1

6

=

1

2

(x−1)+−1(x−3)(Distribute the Negative Sign)

1

3

(x+3)+

1

6

=

1

2

(x−1)+−1x+(−1)(−3)

1

3

(x+3)+

1

6

=

1

2

(x−1)+−x+3

(

1

3

)(x)+(

1

3

)(3)+

1

6

=(

1

2

)(x)+(

1

2

)(−1)+−x+3(Distribute)

1

3

x+1+

1

6

=

1

2

x+

−1

2

+−x+3

(

1

3

x)+(1+

1

6

)=(

1

2

x+−x)+(

−1

2

+3)(Combine Like Terms)

1

3

x+

7

6

=

−1

2

x+

5

2

1

3

x+

7

6

=

−1

2

x+

5

2

Step 2: Add 1/2x to both sides.

1

3

x+

7

6

+

1

2

x=

−1

2

x+

5

2

+

1

2

x

5

6

x+

7

6

=

5

2

Step 3: Subtract 7/6 from both sides.

5

6

x+

7

6

−

7

6

=

5

2

−

7

6

5

6

x=

4

3

Step 4: Multiply both sides by 6/5.

(

6

5

)*(

5

6

x)=(

6

5

)*(

4

3

)

x=

8

5

Answer:

(1, 2.5 (or 3/2))

Step-by-step explanation:

It's the point the two lines meet

Answer:

Subtract 23 from both sides

Step-by-step explanation:

This is how algebra works, to get a variable by itself you have to do the opposite to both sides. Hope this helped.

Answer:

It's D: subtract 23 from both sides of the equation because inverse operations  

Step-by-step explanation:

Answer:

-5/4 is the slope of the line.

Answer:

2

Step-by-step explanation:

The formula to find the slope given 2 points is y2-y1/x2-x1. Now lets plug in the numbers. (2,2) is the first set of points and (-1,-4) is the second set of points. So we have -4-2/-1-2. We have -6/-3. Now we must simplify, giving us 2.

Step-by-step explanation:

Use soh cah toa to solve

it is cos(α)=.839

so the angle of α is 32.9653

Hope that helps :)

Trigonometric identity is cosine. And a is 32.965327740597°.

Equations using trigonometric functions that hold true for all possible values of the variables are known as trigonometric identities.

Given:

A triangle with an adjacent leg to hypotenuse ratio value of 0.839.

Assume the triangle is a right-angled triangle.

In the right-angled triangle,

the ratio of adjacent leg to hypotenuse is cosine.

So,

Cos(a) = Adjacent leg/Hypotenuse

Cos(a) = 0.839

a = Cos⁻¹(0.839)

a = 32.965327740597°

Therefore, angle measure of a is 32.965327740597°.

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Answer:

Area = 24.75 sqr units

Step-by-step explanation:

You will need these formulas:

[tex]d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}[/tex]

Midpoint = [tex](\frac{x_{1} + y_{1} }{2} , \frac{x_{2} + y_{2} }{2})[/tex]

Area = b x h

Let us treat CD as the base. Find the length of the base with the distance formula. Use the coordinates for points C & D.

[tex]d = \sqrt{(-2 - (-8))^2 + (-8-(-7))^2}[/tex]

[tex]d = \sqrt{37}[/tex]

The base is [tex]\sqrt{37}[/tex].

The height is the distance between point E and the midpoint of line CD.

Midpoint of CD = [tex](\frac{-8 + (-7) }{2} , \frac{-2 + (-8) }{2})[/tex] = ([tex]-\frac{15}{2}[/tex], [tex]-5[/tex])

Use the distance formula to find the height.

[tex]d = \sqrt{(-5 - (-\frac{15}{2} ))^2 + (-2-(-5))^2}[/tex]

[tex]d = \frac{\sqrt{61} }{2}[/tex]

Find the area with the two distances that were found.

Area = [tex](\sqrt{37}) (\frac{\sqrt{61} }{2})[/tex]

Area = [tex]\frac{\sqrt{2257} }{2}[/tex]

Area = 24.75 sqr units

Answer:

radius = 62 cm

Step-by-step explanation:

radius = diameter/2

radius = 124/2 = 62 cm

Answer:

the radius 62

Step-by-step explanation:

the radius is really just the diameter split in half.

So, 124/2 = 62

Answer:

139°

Step-by-step explanation:

Corresponding angles theorem:

When a transversal line intersects two parallel lines, the angles formed from the intersection are congruent in pairs. For example with your problem, using the Corresponding Angles Theorem (one of the few theorems/postulates used to find angles on transversals), the angles are paired on the same place on the first parallel line as they are on the second. Since the corresponding pair of (x)° is given, the angle of x is given. (x)° = 139°

I've provided an image courtesy of tutors.com that will help remember corresponding angles for you.

Answer:

[tex] - 49 \times (49 \times 5982 + 3) {}^{2} \\ = - 49 \times 85919920641 \\ = - 4,210,076,111,409[/tex]

Answer:

x =  √ 40

Step-by-step explanation:

Juan should order approximately 1,813 T-shirts from his China supplier at a time.

This inventory management problem can be categorized as the EOQ (Economic Order Quantity) model with continuous demand distribution. In this case, the demand for T-shirts is approximately normally distributed, and the EOQ model assumes a continuous demand pattern.

In order to calculate the optimal order quantity (EOQ), we can use the following formula:

EOQ = ✓((2 * D * S) / H)

where:

D = Annual demand (mean) = 30 T-shirts/day * 365 days/year = 10,950 T-shirts/year

S = Ordering cost per order = $150

H = Holding cost per unit = 20% of wholesale cost = 0.2 * $5 = $1

EOQ = ✓((2 * 10,950 * 150) / 1)

= ✓(3,285,000)

≈ 1,812.99

Therefore, Juan should order approximately 1,813 T-shirts from his China supplier at a time.

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Answer:

Hey Aryabd interested to talk with me. Come in comments.

The  US Dollars for Rs 21000 would be 200 USD

Multiplication is the mathematical operation that is used to determine the product of two or more numbers. If an event can occur in m different ways and if following it, a second event can occur in n different ways, then the two events in succession can occur in m × n different ways.

We are given that  the rate of Rs 105 per US Dollar,

We have to calculate the US Dollars for Rs 21000.​

105 Rs = 1 USD

21000 Rs = x USD

Now the proportion can be;

105x =21000

x =21000 /105

x= 200 USD

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do it in your own answer

Answer:

I think it is A

Step-by-step explanation:

A. the dimension of A is 3x3. the dimension of B is 3x2.

B. the dimension of AB will be 3x2.

C. The value of AB = [[ -15 14] [ 4 -2] [ 13 -9]]

A. The dimension of a matrix is given by the number of rows and columns it has.

For matrix A, we have:

A = [[-1 -4 1], [0 2 2], [2 3 0]]

The matrix A has 3 rows and 3 columns, so the dimension of A is 3x3.

For matrix B, we have:

B = [[2 0], [3 -3], [-1 2]]

The matrix B has 3 rows and 2 columns, so the dimension of B is 3x2.

B. To multiply two matrices, the number of columns in the first matrix must be equal to the number of rows in the second matrix. In this case, A has 3 columns and B has 3 rows, so we can multiply them.

The dimension of AB will be the number of rows of A and the number of columns of B. Therefore, the dimension of AB will be 3x2.

C. [-1 -4 1] * [2 0]

   [0 2 2]    [3 -3]

   [2 3 0]    [-1 2]

  [-2-12-1   0+12+2]

= [0+6-2    0-6+4]

  [4+9+0   0-9+0]

  [ -15     14]

= [ 4         -2]

  [ 13       -9]

The value of AB = [[ -15 14] [ 4 -2] [ 13 -9]]

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Given question is incomplete, the complete question is below

For matrices: A =[[ -1 -4 1] [0 2 2][ 2 3 0]] B =[[2 0] [3 -3 ][-1 2] ]

A. What is the dimension of A and B?

B. What is the dimension of A*B?

C. What is A*B?

Answer:

27/50 is the fraction.

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

Answer:

The answer is the Last one

Answer:

59

Step-by-step explanation:

[tex](12*3)-5*(-4)+3=59[/tex]

The probability of selecting a value at random and discovering that it has a value of less than 395 pounds is 0.3085.

a. The area between 415 pounds and a mean of 400 pounds is:

0.9332 - 0.5 = 0.4332.

b. The area between the mean and 395 pounds is:

0.5 - 0.3085 = 0.1915

c.The probability of selecting a value at random and discovering that it has a value of less than 395 pounds is 0.3085.

Given the mean of a normal probability distribution as 400 pounds and the standard deviation as 10 pounds.

We have to calculate the area between 415 pounds and a mean of 400 pounds, the area between the mean and 395 pounds, and the probability of selecting a value at random and discovering that it has a value of less than 395 pounds.

a. What is the area between 415 pounds and a mean of 400 pounds?

The Z-score can be calculated as follows:

Z = (x - μ) / σ

= (415 - 400) / 10

= 1.5

From the Z-table, the area to the left of 1.5 is 0.9332.

Therefore, the area between 415 pounds and a mean of 400 pounds is:

0.9332 - 0.5 = 0.4332.

b. What is the area between the mean and 395 pounds?

The Z-score can be calculated as follows:

Z = (x - μ) / σ

= (395 - 400) / 10

= -0.5

From the Z-table, the area to the left of -0.5 is 0.3085.

Therefore, the area between the mean and 395 pounds is:

0.5 - 0.3085 = 0.1915.

c. What is the probability of selecting a value at random and discovering that it has a value of less than 395 pounds?

The Z-score can be calculated as follows:

Z = (x - μ) / σ

= (395 - 400) / 10

= -0.5

From the Z-table, the area to the left of -0.5 is 0.3085.

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