In the given reaction CH3COOH → CH3COO^- + H+, the statement "CH3COO^- is a conjugate base" is true.The statement "CH3COO^- is a conjugate base" is true for the given reaction.
In the Brønsted-Lowry theory of acids and bases, an acid is a species that donates a proton (H+), while a base is a species that accepts a proton. In this reaction, CH3COOH donates a proton to form CH3COO^- and H+. The species that remains after the acid donates a proton is called the conjugate base.
In the reaction, CH3COOH acts as the acid by donating a proton, and CH3COO^- is the species that forms after the donation. Since CH3COO^- accepts the proton, it is considered the conjugate base of CH3COOH.
To determine whether a species is an acid or a base, we need to consider its behavior in a given reaction. In this case, CH3COOH donates a proton, making it the Brønsted-Lowry acid, while CH3COO^- accepts the proton, making it the conjugate base.
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3. A volume of gas at 1.65 atm was measured at 27°C and 343 mL. What will be the volume if the gas
is cooled to -12°C and the pressure is adjusted to 2.10 atm?
Answer:
Homework hint: P1V1 = nRT1 and V1, n, and R are constant. Remember to use Kelvin.
What is the standard free-energy change ΔG° at 25°C for the following reaction? H2(g) + Br2(l) → 2HBr(g) Calculate the value of the thermodynamic equilibrium constant K. ΔG°f (HBr(g)) = -53.50 kJ/mol ΔG° = ___ kJ K = ___
The standard free-energy change ΔG° at 25°C for the reaction H2(g) + Br2(l) → 2HBr(g) is -95.6 kJ/mol. The thermodynamic equilibrium constant K is 1.1 × 10^8.
To calculate ΔG°, we need to know the value of R and the temperature in Kelvin. The gas constant R is approximately 8.314 J/(mol·K), and to convert 25°C to Kelvin, we add 273.15 to the temperature, giving us 298.15 K. Plugging these values into the equation, we can solve for ΔG°.
Once we have the value of ΔG°, we can rearrange the equation ΔG° = -RT ln(K) to solve for K. Rearranging the equation gives us K = e^(-ΔG°/(RT)), where e is the base of the natural logarithm.
Therefore, in order to provide the specific value of ΔG° and calculate K, we need the standard free-energy change ΔG° at 25°C for the reaction H2(g) + Br2(l) → 2HBr(g).
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consider a solution containing 1.82e-4 m lead(ii) nitrate and 2.25e-2 m sodium chloride. given that ksp of pbcl2 = 1.6 x 10-5, what is the value of qc?
The value of Qc for the given solution is approximately 3.67425e⁻⁶.
To find the value of Qc (the reaction quotient) for the given solution, we need to determine the concentrations of the respective ions and use them to calculate Qc.
The balanced equation for the dissolution of lead(II) chloride (PbCl₂) in water is:
PbCl₂(s) ⇌ Pb²⁺(aq) + 2Cl⁻(aq)
From this equation, we can see that one mole of PbCl₂ dissociates to yield one mole of Pb²⁺ ions and two moles of Cl⁻ ions.
Given that the concentration of lead(II) nitrate (Pb(NO₃)₂) is 1.82e⁻⁴ M and the concentration of sodium chloride (NaCl) is 2.25e⁻² M, we can use the stoichiometry of the balanced equation to determine the concentrations of Pb²⁺ and Cl⁻ ions.
Since lead(II) nitrate dissociates completely, the concentration of Pb²⁺ ions is equal to the concentration of lead(II) nitrate:
[Pb²⁺] = 1.82e⁻⁴ M
Sodium chloride dissociates into one mole of Na⁺ ions and one mole of Cl⁻ ions. Since we're interested in the concentration of Cl⁻ ions, we'll use the given concentration of NaCl to calculate it:
[Cl⁻] = 2 * 2.25e⁻² M
= 4.5e⁻² M
Now, we can write the expression for Qc using the concentrations of the respective ions:
Qc = [Pb²⁺][Cl⁻]²
Putting in the values we obtained:
Qc = (1.82e⁻⁴ M)(4.5e⁻² M)²
= 1.82e⁻⁴ (20.25e⁻⁴)
= 36.7425e⁻⁸
Simplifying the expression:
Qc = 3.67425e⁻⁶
Therefore, the value of Qc for the given solution is approximately 3.67425e⁻⁶.
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The increase in the rate of solvation with a rise in solvent temperature is mainly due to a(n)
a. increase in the activaton energy
b. increase in the movement of molecules leading to more collisions.
c. None of the above
Which of the following is a nonelectrolyte in aqueous solution?
a) NH4F
b) NH4Cl
c)NaHS
d)CH4
e)Na2S
The one which is a non-electrolyte in aqueous solution among the options is the compound (d) CH4 is the non-electrolyte in aqueous solution.
A non-electrolyte is a substance that does not dissociate into ions when dissolved in water, meaning it does not conduct electricity. In the case of the options provided:
a) NH4F: This compound dissociates into ammonium ions (NH4+) and fluoride ions (F-) in water, making it an electrolyte.
b) NH4Cl: This compound dissociates into ammonium ions (NH4+) and chloride ions (Cl-) in water, making it an electrolyte.
c) NaHS: This compound dissociates into sodium ions (Na+) and hydrogen sulfide ions (HS-) in water, making it an electrolyte.
d) CH4: Methane does not dissociate into ions in water and does not conduct electricity, making it a non-electrolyte.
e) Na2S: This compound dissociates into sodium ions (Na+) and sulfide ions (S2-) in water, making it an electrolyte.
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What is the herbivore in the following food chain: algae → fish → herons?
Answer:
algae
Explanation:
fish and herons arent herbivores
Herbivores are typically tagged as animals that feeds directly on the plants in a food chain.
In the given food chain, Fish is the herbivore
As stated, Fish in the food chain is the herbivore as it feeds directly on the plants. The algae in this case is the producer. While the herons are the carnivore that feeds directly on the flesh of the fish but indirectly on the algae.
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A compound is found to be made up of 3.21 g Carbon and 1.02 g Oxygen. Determine the percent composition from this data?
Given :
A compound is found to be made up of 3.21 g Carbon and 1.02 g Oxygen.
To Find :
The percent composition from this data.
Solution :
We know, percentage composition is given by :
[tex]\%mass = \dfrac{mass}{mass of compound}\times 100[/tex]
So, percentage composition of Carbon is :
[tex]\%Carbon = \dfrac{3.21}{3.21+1.02}\times 100\\\\\%Carbon = \dfrac{3.21}{4.23}\times 100\\\\\%Carbon = 75.89 \%[/tex]
Since, compound is made up of Carbon and Oxygen.
So, %Oxygen is ( 100 - 75.89 )% = 24.11%
Hence, this is the required solution.
Write the formula of the coordination compound lithium pentacyanocobaltate(II). and Write the formula of the coordination compound pentaamminechlorocobalt(III) nitrate. Enclose the coordination complex in square brackets, even if there are no counter ions. Do not enclose a ligand in parentheses if it appears only once. Enter water as H2O
The formula of the coordination compound lithium pentacyanocobaltate(II) is [LiCo(CN)₅]²⁻.
What is lithium pentacyanocobaltate(II) ?
Pentacyanocobaltate attracted attention as an early example of a metal complex that reacts with hydrogen. It contains low-spin cobalt(II) with a doublet ground state.
Let's break down the formula to understand its components:
The central metal ion is cobalt (Co) in the +2 oxidation state, denoted as Co(II).
The ligands are pentacyanocobaltate, which means there are five cyanide ligands (CN⁻) bonded to the cobalt ion.
The coordination complex is negatively charged, with a charge of 2-, so it requires two lithium ions (Li⁺) as counter ions to balance the charge.
Therefore, the complete formula is [LiCo(CN)₅]²⁻, where the square brackets indicate the coordination complex and the superscript 2- indicates the charge.
The formula of the coordination compound pentaamminechlorocobalt(III) nitrate is [Co(NH₃)₅Cl]NO₃.
Breaking down the formula:
The central metal ion is cobalt (Co) in the +3 oxidation state, denoted as Co(III).
The ligands are pentaamminechlorocobalt, indicating there are five ammonia ligands (NH₃) and one chloride ligand (Cl⁻) bonded to the cobalt ion.
There is no need for any counter ions to balance the charge in this compound.
Thus, the complete formula is [Co(NH₃)₅Cl]NO₃, where the square brackets denote the coordination complex, and NO₃ indicates the presence of nitrate ions as the counter ions.
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what is the mass of 2.31 x 10^23 formula units of SrF2?
Mole measure the number of elementary entities of a given substance that are present in a given sample. Therefore, 40.51 g is the mass of 2.31x10²³ formula units of SrF[tex]_2[/tex].
What is mole?The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity of amount of substance. It measure the number of elementary entities of a given substance that are present in a given sample.
Given number of atoms= 2.31x10²³atoms
we know one mole of any element contains 6.022×10²³ atoms which is also called Avogadro number
mole =given number of atoms ÷ 6.022×10²³(Avogadro number)
Substituting the values
mole= 2.31x10²³÷ 6.022×10²³
mole = 0.38 moles of SrF[tex]_2[/tex]
mass of SrF[tex]_2[/tex]= moles of SrF[tex]_2[/tex] × Molar mass of SrF[tex]_2[/tex]
mass of SrF[tex]_2[/tex]= 0.38 × 106.6184
mass of SrF[tex]_2[/tex] = 40.51 g
Therefore, 40.51 g is the mass of 2.31x10²³ formula units of SrF[tex]_2[/tex].
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Which of Graphs 1 correctly represents the relationship between the pressure and volume of a gas?
Answer:
D
Explanation:
pressure is inversely proportional to gas volume
What do these two changes have in common? snails growing shells a slice of banana turning brown
Answer:
both are done due to the enviroment??
50 POINTS PLEASE ANSWER CORRECTLY
What happens to the momentum of two cars when they collide?
A. The total momentum after the collision increases.
B. The total momentum after the collision decreases.
C. The total momentum after the collision is equal to the total momentum before the collision.
D. The total momentum before and after the collision is not conserved.
Answer: I honestly think it might be C
Explanation: Collisions between objects are governed by laws of momentum and energy. When a collision occurs in an isolated system, the total momentum of the system of objects is conserved. ... In the collision between the two cars, total system momentum is conserved.
Answer: C. The total momentum after the collision is equal to the total momentum before the collision.
Hope this helps
Explanation: Collisions between objects are governed by laws of momentum and energy. When a collision occurs in an isolated system, the total momentum of the system of objects is conserved. ... In the collision between the two cars, total system momentum is conserved.
Identify which of the following functions are eigenfunctions of the operator d/dx: (a) eᶦᵏˣ, (b) cos kx, (c) k, (d) kx, (e) e⁻ᵃˣ^². Give the corresponding eigenvalue where appropriate.
Among the given functions, (a) e^ikx, (c) k, and (d) kx are eigenfunctions of the operator d/dx. The corresponding eigenvalues are (a) ik, (c) 0, and (d) k, respectively.
To determine whether a function is an eigenfunction of the operator d/dx, we need to check if applying d/dx to the function yields a scalar multiple of the original function.
(a) For the function e^ikx, we have d/dx(e^ikx) = ike^ikx. This shows that e^ikx is an eigenfunction of d/dx with an eigenvalue of ik.
(b) Taking the derivative of cos(kx) with respect to x gives us -ksin(kx), which is not proportional to the original function. Therefore, cos(kx) is not an eigenfunction of d/dx.
(c) For the constant function k, d/dx(k) = 0. This implies that k is an eigenfunction of d/dx with an eigenvalue of 0.
(d) The function kx has a derivative of d/dx(kx) = k. Hence, kx is an eigenfunction of d/dx with an eigenvalue of k.
(e) The derivative of e^(-ax^2) with respect to x is -2axe^(-ax^2). Since -2ax is not proportional to e^(-ax^2), e^(-ax^2) is not an eigenfunction of d/dx.
(a) e^ikx, (c) k, and (d) kx are eigenfunctions of d/dx, with corresponding eigenvalues of (a) ik, (c) 0, and (d) k, respectively. On the other hand, (b) cos(kx) and (e) e^(-ax^2) are not eigenfunctions of d/dx.
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How many grams is 0.02 moles of CuCl2
Answer:
2.69g
Explanation:
The molar masses of
Cu = 63.5
Cl = 35.5
So the molar mass of [tex]CuCl_{2}[/tex] is 63.5 + (35.5 x 2) = 134.5
134.5 x 0.02 = 2.69g
which statement best describes the reflection of a wave?
The best statement that describes the reflection of a wave is: When a wave reflects off a surface, it retains its characteristics and changes direction.
A wave is defined as a disturbance that moves through space and matter with the transfer of energy from one place to another. When the wave moves from one medium to another, it reflects off the surface. Reflection of a wave is described as the change in the direction of the wave when it bounces back from the surface on which it strikes.
When a wave reflects off a surface, the angle of incidence is equal to the angle of reflection, which is known as the law of reflection. The normal line, which is perpendicular to the surface, splits the incident and reflected waves at the point of incidence. The angle between the normal line and the incident wave is the angle of incidence, and the angle between the normal line and the reflected wave is the angle of reflection.
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The atmosphere helps regulate Earth's temperature so that life can exist. It also provides the oxygen and carbon dioxide that organisms need
to live. Air is an important natural resource that forms part of the atmosphere. Which of these claims provides a main reason that air is an
important natural resource?
Air affects surface currents in the oceans.
Air gives animals and humans a means of transportation.
Air protects organisms from harmful radiation from the sun.
Air provides a way for harmful pollutants to move away from Earth.
Answer: it is an importtant resource because it is what keeps most things alive in earth.
Explanation:
2. Below is a chemical reaction in which two solutions are combined:
CdSO. (aq)+KS(aq) → CdS(s)+ K₂SO4(aq)
a) What does the (s) mean?
b) For the reactants, cadmium sulfate and potassium sulfide, write a chemical equation showing that each of these dissolve in water.
c) On the products side, potassium sulfate is aqueous and cadmium sulfide is solid. What is the difference? How can you observe this difference in the lab?
d) What is the name for this type of reaction?
The reaction between CdSO₄ and K₂S is a precipitation reaction where cadmium sulfide precipitates as a solid, while potassium sulfate remains in the aqueous form.
a) The "(s)" in the chemical equation CdS(s) represents that cadmium sulfide is a solid precipitate. It indicates that the product formed in the reaction is solid.
b) The chemical equation for the dissolution of cadmium sulfate (CdSO₄) in water is:
CdSO₄(s) → Cd²⁺(aq) + SO₄²⁻(aq)
The chemical equation for the dissolution of potassium sulfide (K₂S) in water is:
K₂S(s) → 2K⁺(aq) + S²⁻(aq)
c) The difference between potassium sulfate being aqueous (K₂SO₄(aq)) and cadmium sulfide being a solid (CdS(s)) lies in their solubility in water. Potassium sulfate is soluble in water, meaning it dissolves and dissociates into its respective ions (K⁺ and SO₄²⁻) in the solution. On the other hand, cadmium sulfide is insoluble in water and forms a solid precipitate, indicating that it does not dissolve but instead forms solid particles.
In the lab, the difference can be observed by visual inspection. When the reaction between CdSO₄ and K₂S takes place, a yellow precipitate of cadmium sulfide will form, indicating the presence of the solid. The potassium sulfate, being in an aqueous form, will remain dissolved and not form any visible solid.
d) The name for this type of reaction is a precipitation reaction or double displacement reaction. In this reaction, the ions from two compounds exchange to form an insoluble solid (precipitate) and a soluble compound.
In the given reaction between CdSO₄ and K₂S, cadmium sulfide (CdS) is the insoluble solid (precipitate), and potassium sulfate (K₂SO₄) is the soluble compound formed in solution.
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a sample of gas at 32.6 torr and 735 k is heated to 1035 k. what is the new pressure of the gas
The new pressure of the gas is [tex]45.906 torr.[/tex]
To calculate the new pressure:
[tex]P2 = P1 * (T2 / T1)[/tex]
where:
P1 is the initial pressure[tex](32.6 torr)[/tex]
T1 is the initial temperature [tex](735 K)[/tex]
P2 is the final pressure (unknown)
T2 is the final temperature [tex](1035 K)[/tex]
Substituting the values into the formula, we get:
[tex]P2 = 32.6 torr * (1035 K / 735 K)[/tex]
[tex]P2 = 45.906 torr[/tex]
Therefore, the new pressure of the gas is [tex]45.906 torr.[/tex]
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How many molecules is 6.11 moles of Zn?
The answer is 0.015295197308045
We assume you are converting between moles Zinc and gram. You can view more details on each measurement unit: molecular weight of Zinc or grams The molecular formula for Zinc is Zn
0.29 pts each molecule of nitric acid has the formula hno3 . if there are 6000 oxygen atoms present and 6000 nitrogen atoms present, how many hydrogen atoms will be required to convert all of the oxygen atoms into nitric acid? select one:
The number of hydrogen atoms required to convert all of the oxygen atoms into nitric acid is 6000.
One molecule of nitric acid has a formula of HNO3, containing one nitrogen atom, one hydrogen atom, and three oxygen atoms. Therefore, if there are 6000 nitrogen atoms and 6000 oxygen atoms present, this means that there are 6000/3 = 2000 nitric acid molecules. Each nitric acid molecule has one hydrogen atom. Therefore, to convert all 6000 oxygen atoms into nitric acid, we need 3 times as many hydrogen atoms, which is 3 x 2000 = 6000 hydrogen atoms. This is because each molecule of nitric acid requires three oxygen atoms and one hydrogen atom.So, the number of hydrogen atoms required to convert all of the oxygen atoms into nitric acid is 6000.
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What variable represents thermal energy in the equation Q = mcΔT?
A.
The variable c
B.
The variable Q
C.
The variable T
D.
The variable m
Answer:
The variable Q
Explanation:
i just took the test and got it right.... i hope this helps :)
The variable Q represents thermal energy in the equation Q = mcΔT. Hence, option B is correct.
What is specific heat capacity?The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases by 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).
Q = mcΔT
Q = heat energy
m = mass
c = specific heat capacity
ΔT = change in temperature
Hence, option B is correct.
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What happens in a redox reaction?
why an indicator is a necessary part of the titration experiment?
Answer:
In a titration, you determine an unknown concentration of a sample by adding a second reactant of known concentration. In many titrations, you use a chemical called an indicator, which lets you know when the titration finishes.
Explanation:
Which of the following ionic compounds will be more soluble in acid solution than in water?
O CuI
O PbCl2
O Fe(OH)3
O CaCO3
In comparison to the other ionic compounds, CaCO₃ is more soluble in acid solution.
Calcium carbonate (CaCO₃) is sparingly soluble in water. It undergoes a limited degree of dissociation and forms a weakly soluble salt.
However, when CaCO₃ is exposed to an acid solution, such as hydrochloric acid (HCl), it reacts to form a soluble salt, calcium chloride (CaCl₂), carbon dioxide (CO₂), and water (H2O). The following illustrates the reaction:
[tex]CaCO_3 + 2HCl \rightarrow CaCl_2+ CO_2 + H_2O[/tex]
Increased solubility of the CaCO₃ is the result of this reaction, which makes it easier for it to dissolve in an acidic solution as opposed to water.
Contrarily, the solubility of CuI (copper(I) iodide), PbCl₂ (lead(II) chloride), and Fe(OH)₃ (iron(III) hydroxide) in water and acid is limited and they are not greatly influenced by acid solutions.
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What is the absolute magnitude of the rate of change for [NH₃] if the rate of change for [H₂] is 8.70 m/s in the reaction 2 NH₃(g) → N₂(g) + 3 H₂(g)?
a. 4.35 m/s
b. 8.70 m/s
c. 17.40 m/s
d. 26.10 m/s
Given, the balanced chemical equation is:
2 NH₃(g) → N₂(g) + 3 H₂(g)
The absolute magnitude of the rate of change for [NH₃] is 4.35 m/s.
Therefore, option A is the correct answer.
Given, the balanced chemical equation is:
2 NH₃(g) → N₂(g) + 3 H₂(g)
The rate of change for H2 is 8.70 m/s.
To find the absolute magnitude of the rate of change for [NH₃], we have to use the stoichiometric coefficient in the balanced chemical equation. From the balanced chemical equation, 2 mol NH₃ reacts with 3 mol H₂
We can write,
Rate of change of NH₃ (in m/s) = -1/2 * rate of change of H₂ (in m/s)
So,Rate of change of NH₃ = -1/2 * 8.70 m/s= -4.35 m/s
The absolute magnitude of the rate of change for [NH₃] is 4.35 m/s.
Therefore, option A is the correct answer.
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Write the Kb expression for the reaction of propylamine, C3H7NH2 with water.
a. [C3H7NH+3][OH−][C3H7NH2]
b. [C3H7NH2][H2O][C3H7NH+3][OH−]
c. [C3H7NH2][C3H7NH+3][OH−]
d. [C3H7NH+3][OH−][C3H7NH2][H2O]
The Kb expression for the reaction of propylamine, C3H7NH2, with water is [C3H7NH2][C3H7NH+3][OH−] . Hence, option (c) is correct.
The Kb expression for the reaction of propylamine (C3H7NH2) with water can be determined by considering the equilibrium between the amine (C3H7NH2) and its conjugate acid (C3H7NH+3) with hydroxide ions (OH−) in water. The reaction can be represented as follows:
C3H7NH2 + H2O ⇌ C3H7NH+3 + OH−
The equilibrium constant expression for this reaction, Kb, is given by the product of the concentrations of the products (C3H7NH+3 and OH−) divided by the concentration of the reactant (C3H7NH2):
Kb = [C3H7NH+3][OH−] / [C3H7NH2]
Therefore, the correct Kb expression for the reaction is [C3H7NH2][C3H7NH+3][OH−] (option c).
The Kb expression for the reaction of propylamine, C3H7NH2, with water is [C3H7NH2][C3H7NH+3][OH−] (option c).
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preparing a given volume of a solution that has a specific molarity is a very important skill for a chemist. one step in that process is calculating the mass of solute required.
What mass of solute is required to produce 429.5 mL of a 0.256 M solution of KBr? _______ g KBr
13.1 g of KBr is required to produce 429.5 mL of a 0.256 M solution of KBr.
To calculate the mass of solute required to produce 429.5 mL of a 0.256 M solution of KBr, we can use the formula below;
Mass of solute = Molarity × Volume (liters) × Molecular weight of solute
We can also convert the volume of the solution from milliliters to liters by dividing by 1000.
Thus,429.5 mL = 429.5/1000 = 0.4295 Liters
Therefore,
Mass of KBr required = Molarity × Volume × Molecular weight of KBr= 0.256 mol/L × 0.4295 L × 119 g/mol= 13.1 g KBr
Thus, 13.1 g of KBr is required to produce 429.5 mL of a 0.256 M solution of KBr.
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Which of the following is true about the coefficients in a balanced chemical equation?
Answer:
Where is the chemical equations?
A balanced equation obeys the law of conservation of mass. The coefficient represent the number of molecules in a chemical equation.
What is a balanced chemical equation?An equation in which the number of reactants and products on the both sides of the reaction are equal can be defined as the balanced chemical equation. The coefficient are the numbers in front of the formula.
The coefficients are the numbers that must be added in front of the species involved in the reaction in order to balance it. It tells how many number of atoms or molecules are present in a reaction.
In the reaction N₂ + 3H₂ → 2NH₃ which is called Haber's process.
The coefficients are:
1 for Nitrogen molecule, 3 for Hydrogen molecule and 2 for the compound Ammonia.
Thus coefficients are numbers in front of each formula.
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Using standard heats of formation, calculate the standard enthalpy change for the following reaction. Fe(s) + 2HCl(aq)FeCl2(s) + H2(g) ANSWER: ___ kJ
The standard enthalpy change for the given reaction is approximately -156.87 kJ.
To calculate the standard enthalpy change (ΔH°) for the given reaction using standard heats of formation, the balanced equation for the reaction is:
Fe(s) + 2HCl(aq) → [tex]FeCl_2[/tex](s) + [tex]H_2[/tex](g)
The standard heats of formation (ΔH°f) for the compounds involved are as follows:
Fe(s): 0 kJ/mol
HCl(aq): -92.31 kJ/mol (source: NIST Chemistry WebBook)
[tex]FeCl_2[/tex](s): -341.49 kJ/mol (source: NIST Chemistry WebBook)
[tex]H_2[/tex](g): 0 kJ/mol
Now, let's calculate the standard enthalpy change (ΔH°):
ΔH° = Σ(ΔH°f products) - Σ(ΔH°f reactants)
ΔH° = [ΔH°f([tex]FeCl_2[/tex]) + ΔH°f([tex]H_2[/tex])] - [ΔH°f(Fe) + 2ΔH°f(HCl)]
ΔH° = [-341.49 kJ/mol + 0 kJ/mol] - [0 kJ/mol + 2(-92.31 kJ/mol)]
ΔH° = -341.49 kJ/mol + 2(92.31 kJ/mol)
ΔH° = -341.49 kJ/mol + 184.62 kJ/mol
ΔH° = -156.87 kJ/mol
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calculate the percent by mass of a solution made from 17 g nacl (the solute) and 59 g water.
The percent by mass of the solution made from 17 g sodium chloride, NaCl (the solute) and 59 g water is 22.4%
How do i determine the percent by mass of the solution?First, we shall obtain the mass of the solution. Details below:
Mass of NaCl = 17 gramsMass of water = 59 gramsMass of solution = ?Mass of solution = Mass of NaCl + mass of water
Mass of solution = 17 + 59
Mass of solution = 76 grams
Finally, we shall determine the percent by mass of the solution. Details below:
Mass of NaCl = 17 gramsMass of solution = 76 gramsPercent by mass =?Percent by mass = (mass of NaCl / mass of solution) × 100
= (17 / 76) × 100
= 22.4%
Thus, the percent by mass of the solution is 22.4%
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