f(x) = 8x-3 and g(x) =4x +5; find (f /g) (x)

The product of given binomial and trinomial is given by below polynomial:

[tex]x^5 + 9x^4 + 15x^3 -10x^2 + 14x - 4[/tex]

The expression formed by the sum of sub expressions which are product of constant integers with variables raised to some exponent is called polynomial.

Their product is given by:

[tex](x^3 + 3x^2 - x + 2) \times (x^2 + 6x -2)\\= x^5 + 6x^4 - 2x^3 + 3x^4 + 18x^3 - 6x^2 -x^3 -6x^2 + 2x +2x^2 + 12x - 4\\= x^5 + 9x^4 + 15x^3 -10x^2 + 14x - 4[/tex]

Thus the product of given binomial and trinomial is given by below polynomial:

[tex]x^5 + 9x^4 + 15x^3 -10x^2 + 14x - 4[/tex]

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Answer:

IP information is attached to each packet, and this information helps routers to send packets to the right place. Every device or domain that connects to the Internet is assigned an IP address, and as packets are directed to the IP address attached to them, data arrives where it is needed.

Step-by-step explanation:

hope i helped!

Answer:

The answer is t^-1 (r)=120r/120-r

i hope this is right sry if im wrong have a good day :)

The inverse of Janine's equation is [tex]r = \frac{120t}{120-t}[/tex] .

Resistance is a measure of the opposition to current flow in an electrical circuit. Resistance is measured in ohms, symbolized by the Greek letter omega (Ω).

According to the question

Janine is building a circuit that contains two lightbulbs in parallel.

One of the lightbulbs has a resistance of 120 ohms.

R = 120ohms

r = resistance of the second lightbulb

t = total resistance in the circuit  

[tex]t = \frac{120r}{r+120}[/tex]

Now,

The inverse of Janine's equation in which we will make r independent

[tex]t = \frac{120r}{r+120}[/tex]

[tex]t(r+120) = 120r[/tex]

[tex]tr + 120t = 120r[/tex]

[tex]120t = 120r - tr[/tex]

[tex]120t = r(120-t)[/tex]

[tex]r = \frac{120t}{120-t}[/tex]

Hence, the inverse of Janine's equation is [tex]r = \frac{120t}{120-t}[/tex] .

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Answer:

B

D

C

Glad I coild help you out.

Answer:

B,C and D

Step-by-step explanation:

They all expand back to 16x + 20.

Answer:

2nd option

Step-by-step explanation:

Given f(x) then the graph of f(x + a) is a horizontal translation of f(x)

• If a > 0 then a shift left of a units

• If a < 0 then a shift right of a units

g(x) = f(x + 4)

Is the graph of f(x) shifted 4 units to the left

Answer:

  a) 47.7%

  b) 87.2%

Step-by-step explanation:

Find the ratio of interest, and convert it to a percentage.

  (messy right-handed writers)/(right-handed writers)

  = 31/65 = 31/65 × 100% ≈ 47.7%

__

  (neat right-handed writers)/(neat writers)

  = 34/39 = 34/39 × 100% ≈ 87.2%

Answer:

Assuming the 2 in 3x2 is an exponent, then it is binomial.

Step-by-step explanation:

A binomial is an expression with two terms, in this case those two terms are 3x^2 and 5

Answer:

2.binomial

Step-by-step explanation:

3x2=1

5=2

so its a binomial

Answer:

  432 characters

Step-by-step explanation:

There are 36 inches in a yard, so there will be 36 times 12 characters:

  (36 in/yd)(12 char/in) = 432 char/yd

432 characters can be expected per yard of text.

Answer:

HOPE THIS HELPS

Step-by-step explanation:

[tex]x^{2}[/tex]-14x-32 =(X+2)(X-16)

A=1

B=2

C=1

D=-16

An equation that models the path of Johnny’s ball is [tex]y = -\frac{40}9(x - 1.5)^2 + 10[/tex]

The maximum height is given as:

[tex]h_{max}= 10ft[/tex]

And the time spent is:

[tex]t = 3s[/tex]

So, the vertex of the ball would be:

[tex]Vertex = (t/2,h_{max})[/tex]

This gives

[tex]Vertex = (3/2,10)[/tex]

[tex]Vertex = (1.5,10)[/tex]

Rewrite properly as:

[tex](h,k) = (1.5,10)[/tex]

The ball is on the floor after 3 seconds.

So, another point on the graph is:

[tex](x,y) = (3,0)[/tex]

A quadratic equation is represented as:

[tex]y=a(x - h)^2 + k[/tex]

Substitute [tex](x,y) = (3,0)[/tex] and [tex](h,k) = (1.5,10)[/tex] in [tex]y=a(x - h)^2 + k[/tex]

[tex]0=a(3 - 1.5)^2 + 10[/tex]

[tex]0=a(1.5)^2 + 10[/tex]

Evaluate the exponent

[tex]0=2.25a + 10[/tex]

Subtract 10 from both sides

[tex]2.25a =- 10[/tex]

Divide both sides by 2.25

[tex]a = -\frac{10}{2.25}[/tex]

Multiply by 4/4

[tex]a = -\frac{40}{9}[/tex]

Substitute [tex]a = -\frac{40}{9}[/tex] and [tex](h,k) = (1.5,10)[/tex] in [tex]y=a(x - h)^2 + k[/tex]

[tex]y = -\frac{40}9(x - 1.5)^2 + 10[/tex]

See attachment for the graph that models the path

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Answer:

11 weeks

Step-by-step explanation:

If we multiply 50 by 11 we get 550 with a remainder of 100, if we're to take out another 50 for another week we would have 50 dollars remanding but the question says that we need to have at least 75 remaining so this will not be possible. Therefor 11 weeks is our answer.

I hope this helps have a great day :)

the only one i could figure out was that q= 24 and i think r=48

[tex]\text{Consider the slope - intercept form} ~y = mx +c,\\\\ \text{where m is the slope and and c is the y-intercept.}\\\\(a) \\\\y = -\dfrac 12 x +8 \\\\\text{This is in a form of y = mx +c, so}\\\\\text{Slope, m =}-\dfrac 12 ~ \text{and}~ \text{y - intercept , c =8}\\\\(b)\\\\y = 9x -2 \\\\\text{This is in a form of y = mx +c, so}\\\\\text{Slope, m =9}~ \text{and}~ \text{y - intercept ,}~ c =-2\\\\[/tex]

Answer: I think it's 6

Step-by-step explanation:

[tex]\sqrt{x^2 -\dfrac nm} = \dfrac{a^2}b\\\\\implies x^2 - \dfrac nm = \dfrac{a^4}{b^2}\\\\\implies x^2 = \dfrac{a^4}{b^2} + \dfrac nm}\\\\\implies x = \pm \sqrt{ \dfrac{a^4}{b^2} + \dfrac nm}}[/tex]

The value of k to the nearest integer is 21

If the number of international tourist arrivals in Russia in 2012 was 13.5% greater than in 2011 will be expressed as:

k = 24.7 - (13% of 24.7)

k = 24.7 - (0.135 * 24.7)

k = 24.7 - 3.3345

k = 21.3655

Hence the value of k to the nearest integer is 21

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The quadratic equation is given by y = -2x² + 4x + 1

The standard form of a quadratic equation is given by:

y = ax² + bx + c

At point (1, 3):

3 = a(1)² + b(1) + c

a + b + c = 3      (1)

At point (2, 1):

1 = a(2)² + b(2) + c

4a + 2b + c = 1      (2)

At point (-2, -15):

-15 = a(-2)² + b(-2) + c

4a - 2b + c = -15      (3)

Solving equations 1, 2 and 3 simultaneously gives:

a = -2, b = 4, c = 1

The quadratic equation is given by y = -2x² + 4x + 1

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Answer:

x = 29

Step-by-step explanation:

(x + 3) + (x - 1) + (x + 1) = 90

3x + 3 = 90

3x = 87

x = 29

Answer:

x = 29

Step-by-step explanation:

(x+3)+(x-1)+(x+1) = 90

90 = 3x +3

3x = 87

x = 29

Answer:

1) The value of the 6 in 5,416.2 is 100 times greater than the value of the 6 in 54.162.

2) The 6 in 54.162 has a smaller value than the 6 in 5,416.2.

Step-by-step explanation:

1) 0.06 times 100 equals 6

2) 0.06 < 6

Answer:

16, and 16.3

Step-by-step explanation:

Answer:

1. 16     2.16.3

Step-by-step explanation:

2.16.281 is 16.28 which is near 16.3 so you round. Also anything above 5 you round and anything below 5 you round down.

Answer:

Solved: w = 2  

Step-by-step explanation:

Combine like terms

5w+4w = 9w

Isolate or make w alone

9w= 18 so divide both sides by 9 to make w alone

9w ÷ 9 = w

18 ÷ 9 = 2

w = 2

Answer:

you just add 5w and 4w and taht is 9w

[tex]9x = 18 \\ w = 18 \div 9 \\ w = 2[/tex]

Answer:

x=[tex]\frac{3c-q^2}{5p}[/tex]

Step-by-step explanation:

5px+q^2=3c

subtract q^2 from both sides

5px=(3c)-q^2

divide by 5p from both sides

x=[tex]\frac{3c-q^2}{5p}[/tex]

Answer:

x=9,-7

Step-by-step explanation:

(x+3)(x-5)=48

x^2-2x-15-48=0

x^2-2x-63=0

(x-9)(x+7)=0

x=9,-7

dont use the negative number becuase it would not make sense in this scenario

width = 12

length=4

Answer:

GCF 4, LCM 80

Step-by-step explanation:

Since both 16 and 20 have two 2s as factor, their greatest common factor is 4.

The LCM is found by multiplying all of the remaining factors by the LCM:

16 still has (2 x 2), 20 still has (5), times the GCF (4)  so 2 x 2 x 5 x 4 = 80.

Answer:

4

Step-by-step explanation:

firstly you separate y

y=-x-1

which means that the slope is equal to -1

then you flip the slope so -1 over -1 which is equal 1

Answer:

1/8 + 1/4 = 3/8

Step-by-step explanation:

Answer:

what are you asking?

Step-by-step explanation:

[tex]\mathfrak{7x(-4)} [/tex]

[tex]\mathfrak{=7x*-4} [/tex]

[tex]\boxed{\mathfrak{=-28x}} [/tex]

[tex]\mathbb{MIREU} [/tex]

Answer:

|x-480|<=40

Step-by-step explanation:

The absolute distance on the number-line from x to 480 has to be 40.

|x-val| <= error-margin

|x-480| <= 40