Gigi graphs the parabola (x+1)2=2(y−3).

How does she proceed?

Drag a value, coordinates, equation, or word to the boxes to correctly complete the statements.

Answer:

C. y= -2x^2 + 4

Step-by-step explanation:

Graph the parabola using the direction, vertex, focus, and axis of symmetry.

Direction: Opens Down

Vertex:  

(

0

,

−

4

)

Focus:  

(

0

,

−

33

8

)

Axis of Symmetry:  

x

=

0

Directrix:  

y

=

−

31

8

x

y

−

2

−

12

−

1

−

6

0

−

4

1

−

6

2

−

12

________________

Graph the parabola using the direction, vertex, focus, and axis of symmetry.

Direction: Opens Up

Vertex:  

(

0

,

4

)

Focus:  

(

0

,

33

8

)

Axis of Symmetry:  

x

=

0

Directrix:  

y

=

31

8

x

y

−

2

12

−

1

6

0

4

1

6

2

12

______________

Graph the parabola using the direction, vertex, focus, and axis of symmetry.

Direction: Opens Down

Vertex:  

(

0

,

4

)

Focus:  

(

0

,

31

8

)

Axis of Symmetry:  

x

=

0

Directrix:  

y

=

33

8

x

y

−

2

−

4

−

1

2

0

4

1

2

2

−

4

_______________

Graph the parabola using the direction, vertex, focus, and axis of symmetry.

Direction: Opens Up

Vertex:  

(

0

,

−

4

)

Focus:  

(

0

,

−

31

8

)

Axis of Symmetry:  

x

=

0

Directrix:  

y

=

−

33

8

x

y

−

2

4

−

1

−

2

0

−

4

1

−

2

2

4

To prove that tan(u - v) does not equal tan u - tan v, we start by assuming values for u and v.

To do this, we assume the following values

[tex]\mathbf{u = 75}[/tex]

[tex]\mathbf{v = 45}[/tex]

So, we have:

[tex]\mathbf{tan(u - v) \ne tan(u) - tan(v)}[/tex]

Substitute the assumed values for u and v

[tex]\mathbf{tan(75 - 45) \ne tan(75) - tan(45)}[/tex]

Subtract 45 from 75

[tex]\mathbf{tan(30) \ne tan(75) - tan(45)}[/tex]

Using a calculator, calculate the values of tan(30), tan(45) and tan(75)

So, we have:

[tex]\mathbf{0.5774 \ne 3.7321 - 1}[/tex]

Subtract 1 from 3.7321

[tex]\mathbf{0.5774 \ne 2.7321}[/tex]

Notice that the expression on the left-hand side and the expression on the right-hand side are not equal.

Hence, [tex]\mathbf{tan(u - v) \ne tan(u) - tan(v)}[/tex] is true

Read more about proofs of trigonometry at:

https://brainly.com/question/22698523

Answer:

Below!

Step-by-step explanation:

First, let's simplify the roots for each.

Please check out the file so you can see the graphed points on the line. I apologize for the bad mouse-writing.

Hoped this helped.

[tex]BrainiacUser1357[/tex]

Answer:

C

Step-by-step explanation:

For a relation to be a function then every value of x must map to exactly one unique value of y.

Here every x- value corresponds to exactly one y- value

Then the ordered pairs represent a function

Answer:

9. x=102

10. x=56

11. x=104

12. x=138

Step-by-step explanation:

9.  In this problem, they are alternate exterior angles, meaning they are the same value.  x=102

10.  x is a corresponding angle, meaning they are the same. x=56

11. There are consecutive interior angles. The sum of these two angles is 180. to find x, subtract 76 from 180.  180-76 = 104  x = 104

12. These two angles are verticle angles, meaning they are equivalent. x = 138

$10.50

10 Tickets would be $105.00

$105.00 - $10.50 = $94.50 so 9 Tickets would be $94.50

$105.00 + $94.50 = $199.50

$205.00 - $199.50 = $5.50 which isn't enough for another ticket.

10 Tickets + 9 Tickets = 19 Tickets.

Answer:

X is 120° I hope this helps you

Answer:

Step-by-step explanation:

all angles are congruent:false

B.consecutive angles are congruent:false

corresponding angles are congruent:true.

c.diagonals bisect eachother:true.

d.diagonals bisect opposite angles:false.

Answer:

21

Step-by-step explanation:

The average rate of change of function f(x) from x = a to x = b is

[tex] \dfrac{f(b) - f(a)}{b - a} [/tex]

Here we have

a = -1

b = 2

f(a) = f(-1) = 1

f(b) = f(2) = 64

[tex] \dfrac{f(b) - f(a)}{b - a} = [/tex]

[tex] = \dfrac{f(2) - f(-1)}{2 - (-1)} = [/tex]

[tex] = \dfrac{64 - 1}{2 + 1} [/tex]

[tex] = \dfrac{63}{3} [/tex]

[tex] = 21 [/tex]

Answer:

Step-by-step explanation:

Direct variation is represented by the equation y = k × x and inverse variation is represented by y = k/x

Table 1:

y = k × x

30 = k × 5

30 = 5k

k = 30/5

k = 6

So,

y = 30

y = 30 k = 6

y = 30 k = 6x = 5

y = 30 k = 6x = 5Equation: y = 6x

y = k × x

y = 10 × 8

y = 80

So,

y = 80

y = 80 k = 10

y = 80 k = 10x = 8

y = 80 k = 10x = 8Equation: y = 10x

y = 3x

18 = 3x

x = 18/3

x = 6

So,

y = 18

y = 18k = 3

y = 18k = 3x = 6

y = 18k = 3x = 6Equation: y = 3x

y = 2x²

72 = 2x²

x² = 72/2

x² = 36

x = √36

x = 6

So,

y = 72

y = 72k = 2

y = 72k = 2x = 6

y = 72k = 2x = 6Equation: y = 2x²

Table 2:

y = k/x

5 = k/6

5 × 6 = k

30 = k

So,

y = 5

y = 5k = 30

y = 5k = 30x = 6

y = 5k = 30x = 6Equation: y = 30/x

y = k/x

y = 36/4

y = 9

So,

y = 9

y = 9k = 36

y = 9k = 36x = 4

y = 9k = 36x = 4Equation: y = 36/x

y = 60/x

20 = 60/x

20x = 60

x = 60/20

x = 3

So,

y = 20

y = 20k = 60

y = 20k = 60x = 3

y = 20k = 60x = 3Equation: y = 60/x

y = 24/x

y = 24/12

y = 2

So,

y = 2

y = 2k = 24

y = 2k = 24x = 12

y = 2k = 24x = 12Equation: y = 24/x

Read more:

https://brainly.com/question/472621

Let A be a 3×2 matrix, L its left inverse, and R its right inverse. L and R are then matrices such that LA = I₂ (the 2×2 identity matrix) and AR = I₃ (the 3×3 identity matrix). Clearly L must be 2×3 and R must be 3×2 in order for the matrix products to be defined.

To find L and R, we start by introducing a square matrix on the the left sides of either equation above. In particular, we uniformly multiply both sides by the transpose of A, then solve for the inverse.

For the left inverse, we have

[tex]LA=I[/tex]

[tex](LA)A^\top = IA^\top[/tex]

[tex]L\left(AA^\top\right) = A^\top[/tex]

[tex]\left(L\left(AA^\top\right)\right)\left(AA^\top\right)^{-1} = A^\top \left(AA^\top\right)^{-1}[/tex]

[tex]L\left(\left(AA^\top\right)\left(AA^\top\right)^{-1}\right) = A^\top \left(AA^\top\right)^{-1}[/tex]

[tex]LI = A^\top \left(AA^\top\right)^{-1}[/tex]

[tex]L = A^\top \left(AA^\top\right)^{-1}[/tex]

We do the same thing for the right inverse, but take care with how we multiply both sides of AR = I₃.

[tex]AR=I[/tex]

[tex]A^\top(AR)=A^\top I[/tex]

[tex]\left(A^\top A\right)R = A^\top[/tex]

[tex]\left(A^\top A\right)^{-1} \left(\left(A^\top A\right)R\right) = \left(A^\top A\right)^{-1} A^\top[/tex]

[tex]\left(\left(A^\top A\right)^{-1} \left(A^\top A\right)\right) R = \left(A^\top A\right)^{-1} A^\top[/tex]

[tex]IR = \left(A^\top A\right)^{-1} A^\top[/tex]

[tex]R = \left(A^\top A\right)^{-1} A^\top[/tex]

Answer:

3:4

Step-by-step explanation:

18 = 2 * 3 * 3

24 = 2 * 2 * 2 * 3

HCF = 2 * 3 = 6

Divide by 6

18: 24 = 18÷6  : 24÷6

          = 3 : 4

Answer:

it's 3:4

Step-by-step explanation:

18 ÷ 6 : 24 ÷ 6

3 : 24 ÷ 6

=3:4

Answer:

  33 m/s

Step-by-step explanation:

  120 km/h × (1 h)/(3600 s) × (1000 m)/(1 km) ≈ 33 m/s

_____

Additional comment

In general, units conversion is done by multiplying by a factor whose numerator and denominator have equal values, but different units. The units in that fraction need to be arranged to cancel the units you don't want and leave the units you do want.

Answer:

His answer was correct:

(200*0.09)=18

18*16=288

200+288=488

Answer:

step 1: what have you learned?

We cant help you because we do not know what you have learned.

but if you comment your vocab words and what u learned  i can help you  

   Step-by-step explanation:

Answer:

(1, 24 )

Step-by-step explanation:

Substitute any value of x into the equation and evaluate for y

x = 1 → y = 3(1) + 21 = 3 + 21 = 24 , then

(1, 24 ) is a a solution to the equation

Answer:

c i think

Step-by-step explanation:

I'm sorry if not

Answer:

$10.91

Step-by-step explanation:

7 gallons cost:

[tex](\frac{7.79}5}) (7)=\frac{(7.79)(7)}{5} =10.906[/tex]  

rounded to cents: 10.91

I hope this help you

Answer:

B

Step-by-step explanation:

He added 4 to 2 instead of multiplying.

Answer:

16

Step-by-step explanation:

2^-2=0.25

2^6=64

times

=16

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

The second differential of the function is 3/7

Given the differential function [tex](x +2y)=\frac{dy}{dx} (2x-y)[/tex]

Differentiate both sides with respect to x implicitly

[tex](x +2y)=\frac{dy}{dx} (2x-y)[/tex]

[tex]1+2y'=y"(2x-y)+y'(2-y') \\y''=\frac{1+2y'}{(2x-y)+y'(2-y') }[/tex]

Get the first derivative at the point (3, 0)

[tex]y'=\frac{2x-y}{x+2y} \\y'=\frac{2(3)-0}{0+2(3)}\\y'=\frac{6}{6} \\y'=1[/tex]

Substitute into the second derivative to have:

[tex]y''=\frac{1+2y'}{(2x-y)+y'(2-y') }\\y''=\frac{1+2(1)}{(2(3)-0)+(1)(2-(1)) }\\y''=\frac{3}{6+1} \\y''=\frac{3}{7}[/tex]

Hence the second differential of the function is 3/7

learn more on differential equation here; https://brainly.com/question/18760518

Complete question:

If (x 2y)dy/dx=2x-y what is the value of [tex]\frac{d^2y}{dx^2}[/tex] the point (3,0)

Answer:

Step-by-step explanation:

Answer:

Interval Notation: [-2, 10]

Set Notation: {x|-2≤x≤10}

Step-by-step explanation: