guys please help this is graded
For the number line shown, which statement is not true?

Answer:

Step-by-step explanation:

Let q represent the quantity of 15% dressing used. Then the amount of 5% dressing is (390 -q). The amount of vinegar in the mix is ...

  0.15q + 0.05(390 -q) = 0.08(390)

  0.10q = 31.2 -19.5 = 11.7 . . . . . . subtract 0.05(390) and simplify

  q = 117 . . . . . . . . . . . . . . . . . . multiply by 10

  390-q = 273

The chef should use 273 mL of the first brand (5% vinegar) and 117 mL of the second brand (15% vinegar).

__

Additional comment

You may have noticed that the value of q is (0.08 -0.05)/(0.10 -0.05)×390. The fraction of the mix that is the highest contributor is the ratio of the difference between the mix value and least contributor, divided by the difference between the contributors: (8-5)/(15-5) = 3/10, the fraction that is 15% vinegar. This is the generic solution to mixture problems.

Answer:

sqrt299

Step-by-step explanation:

Because the loading dock and the ground are perpendicular we know that they are at a 90° angle. Therefore we can use the equation :

a=5

b= ?

c=18

(Then we can move all of the numbers together but what you do to one side you must do to the other)

 Therefore,

 (Now to make b a single variable we must square root both sides)

 Therefore,

Now with all of these as numbers, we can plug this into a calculator *For all of those who have teachers who need EVERY Step see below I continue

  Where  and

(approximately)

Answer:

1/3

Step-by-step explanation:

Answer:

you draw a T. form and then you can start to in debit and credit

Answer:

f ( 3 ) = 81

Step-by-step explanation:

→ Substitute in x = 3

9 × 3² - 3

→ Simplify

9 × 9 - 3

→ Simplify again

78

Answer:

Not a function

Step-by-step explanation:

Answer:

  10%

Step-by-step explanation:

If 40% failed chemistry then 60% passed chemistry.

If 19% failed both chemistry and physics, and 25% failed physics, then 6% passed chemistry and failed physics.

If we let p' represent failing physics and c represent passing chemistry, then ...

  P(p'|c) = P(p'c)/P(c)

  P(p'|c) = 6%/60% = 0.10 = 10%

If the randomly chosen student passed chemistry, the probability is 10% that he failed physics.

__

Your answer is correct.

To solve this problem, we can use conditional probability.

Let's assume that there were 100 students in the final exam.

According to the problem, 40% of the students failed chemistry, which means that 60% of the students passed chemistry.

To find the probability that a randomly selected student failed physics given that he passed chemistry, we need to use Bayes' theorem:

[tex]\sf P(Failed\: Physics | Passed\: Chemistry) = \dfrac{P(Failed\: Physics\: and\: Passed\: Chemistry)}{ P(Passed\: Chemistry)}[/tex]

We already know that P(Failed Physics and Passed Chemistry) = 6 students (from the Venn diagram), and P(Passed Chemistry) = 60 students (since 60% of the students passed chemistry).

Therefore,

[tex]\sf P(Failed\: Physics | Passed\: Chemistry) = \dfrac{6}{60} = 0.1\: or\: 10\%[/tex]

So the probability that a randomly selected student failed physics given that he passed chemistry is 10%.

Answer:

Decrease amount: $1484 Year-end amount: $4116

Step-by-step explanation:

26.5% of 5600 is 1484. We then subtract 1484 from 5600 because that is how the percentage of decrease, which gives us 4116 dollars. This means her year-end account is 4116 dollars, and the decrease amount is 1484 dollars. Hope this helps!

Answer:

thats what i said

Step-by-step explanation:

Answer:

36

Step-by-step explanation:

You would multiply 6x8+6x(-2), and that would equal 48+(-12) which is basically 48-12 = 36.

9514 1404 393

Answer:

  $66,027.66

Step-by-step explanation:

The multiplier for the salary with each raise is (1 + raise). That means the original salary is multiplied by ...

  (1.04^3)×(1.02^2)×(1.10) = 1.28733935616 = k

Your original salary (O) satisfies ...

  O×k = $85,000

  O = $85,000/k ≈ $66,027.66 . . . original salary

Answer:

$1449.15

Step-by-step explanation:

currently paying 815

to pay next year: 41% increase + 25 extra per month

⇒ 141%·815 + 12·25

    = 1149.15 + 300

    = 1449.15

Answer:

I think the other side on top is 129 degrees

Step-by-step explanation:

Im not 100 percent sure sorry if im wrong!!!

Answer:

Shifted, reflected, and stretched

Step-by-step explanation:

Horizontal Shift: Right 1 Unit

Vertical Shift: Up 3 Units

Reflection about the x-axis: Reflected

Vertical Stretch: Stretched

Answer:

[tex]\huge\boxed{\dfrac{5}{12}x-5}[/tex]

Step-by-step explanation:

[tex]\left(\dfrac{3}{4}x-1\right)-\left(\dfrac{1}{3}x+4\right)=\dfrac{3}{4}x-1-\dfrac{1}{3}x-4=\left(\dfrac{3}{4}x-\dfrac{1}{3}x\right)+(-1-4)\\\\=\left(\dfrac{3\cdot3}{4\cdot3}x-\dfrac{1\cdot4}{3\cdot4}x\right)+(-5)=\left(\dfrac{9}{12}x-\dfrac{4}{12}x\right)-5=\dfrac{9-4}{12}x-5\\\\=\dfrac{5}{12}x-5[/tex]

Answer: 400,00 km

Step-by-step explanation: 1:50,000 = 8:x

8 * 50,000 = 400,000

So, 8km on the map is 400,000 km in real life.

Would appreciate brainly <3

Answer:

25/15

Step-by-step explanation:

H =20

G = 8 mor than I

the measure of H is 28 because it says that g is 8 more so that means I can be 0 and that means G is 8 and then H is 20. therefore solving your answer

Answer:

8/64 = 0.125 = 12.5%

Step-by-step explanation:

8/64 = 0.125 = 12.5%

[tex] \frac{39 \: \: days}{15 \: \: days} \\ = \frac{39}{15} \\ dividing \: \: \: both \: \: \: numerator \: \: \: and \: denominator \: \: \: by \: \: \: 3 \\ = \frac{13}{5} \\ = 13 : 5[/tex]

13:5

Hope it helps.

Do comment if you have any query.

Answer:

9-3=b

Step-by-step explanation:

9-3=b

Answer:

B=6

Step-by-step explanation:

Let "b" be the number of books Shemel has.

Let "a" be the number of books Wawra has.

Eqution:

A-3=B ("3" is given in question)

9-3=B (Substituting with variables given)

B=9-3

B=6

Hence, Shemel has "6" books.

Hope it helps !

Answer:

xxxx

Step-by-step explanation:

Often time we want to relate one amount or quantity with another, from the given options the one that best describes a ratio is option

A.  A comparison of two numbers

A ratio indicates how many times one number contains another. E.g, if there are five balls and nine lemons in a bowl of fruit, then the ratio of balls to lemons is five to nine. Similarly, the ratio of lemons to oranges is 5∶8

Learn more on ratios:

https://brainly.com/question/2328454

Answer:

x and y are the variables

Given that

The cost of 1 m ribbon = Rs.75

The cost of 7/5 m ribbon

→ (7/5)×75

→ (7×75)/5

→7×15

→₹ 105

The cost of 7/5 m ribbon is ₹105.

Answer:

Step-by-step explanation:

24)

3x - 10 > 2

3x - 10 + 10 > 2 + 10

3x > 12

3x/3 > 12/3

x > 4

5x - 15 < -5

5x - 15 + 15 < -5 + 15

5x < 10

5x/5 < 10/5

x < 2

B)  x > 4 or x < 2

25)   1.5/60 = 12/x

x = 12(60) / 1.5

x = 480

B) 480 miles

This distance from Old Faithful to Mammoth Hot Springs is actually about 52 miles by road, so there must have been MASSIVE number of road closures to get this result...or else their scale is incorrect. 1.5 inch to 6.0 miles would be a much more accurate scale making the distance 48 miles.

\well the answrnist that brcause if u think it guys up

1. The given equation is probably supposed to read

y'' - 2y' - 3y = 64x exp(-x)

First consider the homogeneous equation,

y'' - 2y' - 3y = 0

which has characteristic equation

r² - 2r - 3 = (r - 3) (r + 1) = 0

with roots r = 3 and r = -1. Then the characteristic solution is

[tex]y = C_1 e^{3x} + C_2 e^{-x}[/tex]

and we let y₁ = exp(3x) and y₂ = exp(-x), our fundamental solutions.

Now we use variation of parameters, which gives a particular solution of the form

[tex]y_p = u_1y_1 + u_2y_2[/tex]

where

[tex]\displaystyle u_1 = -\int \frac{64xe^{-x}y_2}{W(y_1,y_2)} \, dx[/tex]

[tex]\displaystyle u_2 = \int \frac{64xe^{-x}y_1}{W(y_1,y_2)} \, dx[/tex]

and W(y₁, y₂) is the Wronskian determinant of the two fundamental solutions. This is

[tex]W(y_1,y_2) = \begin{vmatrix}e^{3x} & e^{-x} \\ (e^{3x})' & (e^{-x})'\end{vmatrix} = \begin{vmatrix}e^{3x} & e^{-x} \\ 3e^{3x} & -e^{-x}\end{vmatrix} = -e^{2x} - 3e^{2x} = -4e^{2x}[/tex]

Then we find

[tex]\displaystyle u_1 = -\int \frac{64xe^{-x} \cdot e^{-x}}{-4e^{2x}} \, dx = 16 \int xe^{-4x} \, dx = -(4x + 1) e^{-4x}[/tex]

[tex]\displaystyle u_2 = \int \frac{64xe^{-x} \cdot e^{3x}}{-4e^{2x}} \, dx = -16 \int x \, dx = -8x^2[/tex]

so it follows that the particular solution is

[tex]y_p = -(4x+1)e^{-4x} \cdot e^{3x} - 8x^2\cdot e^{-x} = -(8x^2+4x+1)e^{-x}[/tex]

and so the general solution is

[tex]\boxed{y(x) = C_1 e^{3x} + C_2e^{-x} - (8x^2+4x+1) e^{-x}}[/tex]

2. I'll again assume there's typo in the equation, and that it should read

y''' - 6y'' + 11y' - 6y = 2x exp(-x)

Again, we consider the homogeneous equation,

y''' - 6y'' + 11y' - 6y = 0

and observe that the characteristic polynomial,

r³ - 6r² + 11r - 6

has coefficients that sum to 1 - 6 + 11 - 6 = 0, which immediately tells us that r = 1 is a root. Polynomial division and subsequent factoring yields

r³ - 6r² + 11r - 6 = (r - 1) (r² - 5r + 6) = (r - 1) (r - 2) (r - 3)

and from this we see the characteristic solution is

[tex]y_c = C_1 e^x + C_2 e^{2x} + C_3 e^{3x}[/tex]

For the particular solution, I'll use undetermined coefficients. We look for a solution of the form

[tex]y_p = (ax+b)e^{-x}[/tex]

whose first three derivatives are

[tex]{y_p}' = ae^{-x} - (ax+b)e^{-x} = (-ax+a-b)e^{-x}[/tex]

[tex]{y_p}'' = -ae^{-x} - (-ax+a-b)e^{-x} = (ax-2a+b)e^{-x}[/tex]

[tex]{y_p}''' = ae^{-x} - (ax-2a+b)e^{-x} = (-ax+3a-b)e^{-x}[/tex]

Substituting these into the equation gives

[tex](-ax+3a-b)e^{-x} - 6(ax-2a+b)e^{-x} + 11(-ax+a-b)e^{-x} - 6(ax+b)e^{-x} = 2xe^{-x}[/tex]

[tex](-ax+3a-b) - 6(ax-2a+b) + 11(-ax+a-b) - 6(ax+b) = 2x[/tex]

[tex]-24ax+26a-24b = 2x[/tex]

It follows that -24a = 2 and 26a - 24b = 0, so that a = -1/12 = -12/144 and b = -13/144, so the particular solution is

[tex]y_p = -\dfrac{12x+13}{144}e^{-x}[/tex]

and the general solution is

[tex]\boxed{y = C_1 e^x + C_2 e^{2x} + C_3 e^{3x} - \dfrac{12x+13}{144} e^{-x}}[/tex]

Answer:

168 cups of sugar

Step-by-step explanation:

36 cookies require you to use what the recipes calls for plus one half.

112 divided by two is 56

112 + 56 = 168 cups

I hope that this helps!

For this case we have the following data:

24 cookies require 1 1/2 cups of sugar. To know the amount of sugar that is required to make 36 cookies, we make a rule of three:

24 -----------> 1 1/2

36 -----------> x

Where x represents the amount of sugar required to make 36 cookies.

Thus,   cups of sugar are required to make 36 cookies.