Heather drives her Super-Beetle around a turn on a circular track which has a radius of 200 m. The Super-Beetle has a mass of 1500 kg and the coefficient of static friction between the road and tires is 0.6.

a. What is the force of static friction the road can apply batore the car starts to selon (use Ft= uFn).
b. What is the maximum speed the car can travel before it would start to slide?

Answer:

carbon.

Explanation:

the reaction would then create c02 as a product

Answer:

1750km

Explanation:

Answer:

Organ system because multiple organs make up an organ system and multiple organ systems make up an organism

The plunger is transferring energy to the gas particles.

When Cecily is applying pressure to the plunger, the gas inside is being compressed, and the speed of gas molecules increases.

When these air molecules enter the tire, adiabatically, the temperature of the gas rises.

It happens due to an increase in the average kinetic energy of the gas particles.

Thus, the gas particles receive energy from the plunger.

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Answer:

Explanation:

The total distance travelled by ball before first bounce

= 160 + 160 = 320 ft

Distance travelled between first bounce and second bounce

= 80 + 80 = 160 ft

Distance travelled between second bounce and third bounce

= 40 + 40 = 80 ft

Distance travelled between third bounce and fourth bounce

= 20 + 20 = 40 ft .

Distance travelled in fourth bounce = 10 ft

Total distance travelled = 320 + 160 + 80 + 40 + 10

= 610 ft .

answer is convex mirror

Explanation:

A

Because convex mirror will provide maximum view

Answer:

sultan's displacement is

[tex]20 \sqrt{13} [/tex] km

Answer:

a 10 kg bag of hot water at the same temperature

Explanation:

A 10kg bag of hot water at the same temperature will retain heat much better and keep the tent warmer at night compared to the iron pellet.

Answer:

The coefficient of static friction between the object and the disk is 0.087.

Explanation:

According to the statement, the object on the disk experiments a centrifugal force due to static friction. From 2nd Newton's Law, we can represent the object by the following formula:

[tex]\Sigma F_{r} = \mu_{s}\cdot N = m\cdot \frac{v^{2}}{R}[/tex] (1)

[tex]\Sigma F_{y} = N - m\cdot g = 0[/tex] (2)

Where:

[tex]N[/tex] - Normal force from the ground on the object, measured in newtons.

[tex]m[/tex] - Mass of the object, measured in newtons.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]v[/tex] - Linear speed of rotation of the disk, measured in meters per second.

[tex]R[/tex] - Distance of the object from the center of the disk, measured in meters.

By applying (2) on (1), we obtain the following formula:

[tex]\mu_{s}\cdot m\cdot g = m\cdot \frac{v^{2}}{R}[/tex]

[tex]\mu_{s} = \frac{v^{2}}{g\cdot R}[/tex]

If we know that [tex]v = 0.8\,\frac{m}{s}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]R = 0.75\,m[/tex], then the coefficient of static friction between the object and the disk is:

[tex]\mu_{s} = \frac{\left(0.8\,\frac{m}{s} \right)^{2}}{\left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.75\,m)}[/tex]

[tex]\mu_{s} = 0.087[/tex]

The coefficient of static friction between the object and the disk is 0.087.

Answer:

Explanation:

C. The energy on the macroscopic scale decreased, and the energy on the molecular scale increased.

A. friction converts some energy on the macroscopic scale to energy on the molecular scale.

B. The mechanical energy of the system decreased because of friction.

B. The mechanical energy of the system at the beginning of the experiment is equal to the mechanical energy of the system at the end of the experiment.

B. the mechanical energy of the system decreased due to the transfer of energy on a macroscopic scale to energy on a molecular scale.

The  ball rolling on the floor eventually comes to a stop which means that

the energy on the macroscopic scale decreased, and the energy on the

molecular scale increased.

This is a scale in which an object can be seen with the eyes. When

an object is in motion, the ball rolls away and becomes less visible hence a

decrease in the macroscopic scale.

During motion, friction converts some macroscopic energy into molecular

scale which is why there was an increase in it.

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Answer:

Explanation:

It’s devastating because when a earthquake is 7.7 magnitude the

Answer:

30 m/h

Explanation:

Have A Wonderful Day !!

Answer:

The magnitude of the force = 7.2 × 10⁻¹⁵ C

Explanation:

The total quantization of charge q on an electron = n × e

where;

n = 30

e = 1.6 × 10⁻¹⁸ C

q = 30 ×  1.6 × 10⁻¹⁸ C

q = 4.8 × 10⁻¹⁸ C

Now, the magnitude of the force is determined by using the formula:

F = qE

F = ( 4.8 × 10⁻¹⁸ C) ( 1500  N/C)

F = 7.2 × 10⁻¹⁵ C

Answer: water freezes and expands in the crevice

Explanation:

Answer:

Water freezes and expands in the crevice

Explanation:

Answer:

the longer wavelength is 1.2552 cm

Explanation:

given that

beat frequency [tex]f_{b}[/tex] = 100 MHz = 100 × 10⁶ Hz

λ₁ = 1.250 cm = 0.0125 m

we know that beat frequency [tex]f_{b}[/tex] of two simultaneous frequencies f₁ and f₂ is expressed as;

[tex]f_{b}[/tex]  = | f₁ - f₂ |

we know that microwave travels at a speed of light, so for any electromagnetic wave traveling at speed of light c with wavelength λ; frequency is;

f = c / λ

hence our beat frequency [tex]f_{b}[/tex] becomes

[tex]f_{b}[/tex] = c ( 1/λ₁ - 1/λ₂)

to find the longer wavelength,  λ₂

[tex]f_{b}[/tex] = c ( 1/λ₁ - 1/λ₂)

divide both side by c

[tex]f_{b}[/tex] /c =  ( 1/λ₁ - 1/λ₂)

1/λ₂ = 1/λ₁ - [tex]f_{b}[/tex] /c

λ₂ =  [1/λ₁ - [tex]f_{b}[/tex] /c ]⁻¹

so we substitute in our values

we know that speed of light c = 3 × 10⁸

so

λ₂ =  [ (1/0.0125) - (100 × 10⁶ /3 × 10⁸) ]⁻¹

λ₂ =  [80 - 0.3333 ]⁻¹

λ₂ =  [79.6667 ]⁻¹

λ₂ =  0.01255 m

λ₂ =  0.012552 × 100 cm

λ₂ =  1.2552 cm

Therefore, the longer wavelength is 1.2552 cm

Answer:

Net force = 15 N

Explanation:

Given that,

Applied force on an object = 20 N

Frictional force = 5 N

We need to find the net force acting on the object.

Friction is an opposing force. It acts in the opposite direction.

Net force = Applied force - Frictional force

= 20 N - 5 N

= 15 N

Hence, the net force acting on the object is 15 N.

The distance walked by the woman at the given speed an time, is 15 miles.

The speed of an object is defined as the rate of change of the distance travelled by the object.

Here,

Speed with which the woman is walking,

v = 5 miles/hour

Time taken by the woman for walking,

t = 3 hours

We know speed is the rate of change of distance,

v = d/t  where d is the distance travelled by the woman

So, d = v x t

 d = 5 x 3

 d = 15 miles

Hence,

The distance walked by the woman at the given speed an time, is 15 miles.

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Answer:

12.31 m/s

Explanation:

If we recall from the previous knowledge we had about speed,

we will know that:

speed = distance/ time.

As such:

The average speed of the rider bicycle is

average speed = total distance/ total time

Mathematically, it can be computed as:

[tex]v_{avg} = \dfrac{d+d}{\dfrac{d}{v_1}+ \dfrac{d}{v_2}}[/tex]

[tex]v_{avg} = \dfrac{2d}{\dfrac{d}{10 \ m/s}+ \dfrac{d}{16 \ m/s}}[/tex]

[tex]v_{avg} = \dfrac{2}{\dfrac{1}{10 \ m/s}+ \dfrac{1}{16 \ m/s}}[/tex]

[tex]v_{avg} = \dfrac{2}{\dfrac{13}{80 \ m/s}}[/tex]

[tex]\mathbf{v_{avg} =12.31 \ m/s}[/tex]

Answer:

Given :  A bus of mass 760 kg requires 120 m to reach certain velocity value Vf.

the bus engine exerts a constant forward force F.

To Find : When the bus is towing a 330-kg small car, how long distance needed to reach same Vf?

Solution:

V²  - U² = 2aS

V = Vf

U = 0

S = 120 m

=> Vf² - 0 = 2a(120)

=> Vf² = 240a

m = 760  kg

Force = F

F = ma

=> F =760 a

=> a = F/760

Vf² = 240F/760

Case 2  :When the bus is towing a 330-kg small car,

m = 760 + 330 = 1090 kg

a = F/1090

Vf²  = 2aS

=> 240F/760  = 2 (F/1090) S

=> S = 120 x 1090 /760

=> S = 172.1   m  

172.1   m   distance needed to reach same Vf

Explanation:

Answer:

The charge of the negative one is 13.27 microcoulombs and the positive one has a charge of 58.27 microcoulombs.

Explanation:

Electric potential energy between two point charges is derived from concept of Work, Work-Energy Theorem and Coulomb's Law and described by the following formula:

[tex]U_{e} = \frac{k\cdot q_{A}\cdot q_{B}}{r}[/tex] (1)

Where:

[tex]U_{e}[/tex] - Electric potential energy, measured in joules.

[tex]q_{A}[/tex], [tex]q_{B}[/tex] - Electric charges, measured in coulombs.

[tex]r[/tex] - Distance between charges, measured in meters.

[tex]k[/tex] - Coulomb's constant, measured in kilogram-cubic meters per square second-square coulomb.

If we know that [tex]U_{e} = -24\,J[/tex], [tex]q_{A} = 45\times 10^{-6}\,C+ q_{B}[/tex], [tex]k = 9\times 10^{9}\,\frac{kg\cdot m^{3}}{s^{2}\cdot C^{2}}[/tex] and [tex]r = 0.29\,m[/tex], then the electric charge is:

[tex]-24\,J = -\frac{\left(9\times 10^{9}\,\frac{kg\cdot m^{3}}{s^{2}\cdot C^{2}} \right)\cdot (45\times 10^{-6}\,C+q_{B})\cdot q_{B}}{0.29\,m}[/tex]

[tex]-6.96 = -405000\cdot q_{B}-9\times 10^{9}\cdot q_{B}^{2}[/tex]

[tex]9\times 10^{9}\cdot q_{B}^{2}+405000\cdot q_{B} -6.96 = 0[/tex] (2)

Roots of the polynomial are found by Quadratic Formula:

[tex]q_{B,1} = 1.327\times 10^{-5}\,C[/tex], [tex]q_{B,2} \approx -5.827\times 10^{-5}\,C[/tex]

Only the first roots offer a solution that is physically reasonable. The charge of the negative one is 13.27 microcoulombs and the positive one has a charge of 58.27 microcoulombs.

Answer:

Essentials. A battery is a device that stores chemical energy and converts it to electrical energy. The chemical reactions in a battery involve the flow of electrons from one material (electrode) to another, through an external circuit. The flow of electrons provides an electric current that can be used to do work.

Answer: B- a doctor, by law, must treat every patient who shows up in a medical facility

Explanation:

Answer:

A is the best character that defines an electron.

Answer:

v = 80.62 km/h

Explanation:

Given that,

An airplane normally flying at 80 km/h north encounters a wind from the west of 10km/h at right angle to its forward motion a crosswind.

We need to find the resultant velocity of the airplane. It can be calculated as follows :

[tex]v=\sqrt{80^2+10^2} \\\\v=80.62\ km/h[/tex]

So, the required velocity is 80.62 km/h.

Answer:

[tex]9\:\mathrm{J}[/tex]

Explanation:

Kinetic energy is given by the following equation:

[tex]KE=\frac{1}{2}mv^2[/tex], where [tex]m[/tex] is mass in [tex]\mathrm{kg}[/tex] and [tex]v[/tex] is velocity in [tex]\mathrm{m/s}[/tex].

Since the cell phone's mass is given in grams, we need to convert this into kilograms:

[tex]80\:\mathrm{g}\cdot \frac{1\:\mathrm{kg}}{1000\:\mathrm{g}}=0.08\:\mathrm{kg}[/tex].

Therefore, the kinetic energy of the cell phone is:

[tex]KE=\frac{1}{2}\cdot 0.08\cdot 15^2=\fbox{$9\:\mathrm{J}$}[/tex].

Answer:

P = 490500 [Pa]

Explanation:

The pressure at the bottom of a vessel and even of a lake or sea can be calculated by means of the following hydrostatic equation.

[tex]P=Ro*g*h[/tex]

where:

P = pressure [Pa] (units of pascal)

Ro = water density = 1000 [kg/m³]

g = gravity acceleration = 9.81 [m/s²]

h = elevation = 50 [m]

Now replacing:

[tex]P=1000*9.81*50\\P=490500[Pa][/tex]