help! geometry

find the arc length of the shaded sector

arc length = blank cm

Answer:

Alli khanaw .................

Answer:

8x^36

Step-by-step explanation:

first term (a) = [tex]8x^{8}[/tex]

Second term (t2)= [tex]8x^{12}[/tex]

common ratio (r)

= [tex]\frac{8x^{12} }{8x^{8} }[/tex]

= [tex]x^{4}[/tex]

now the 8th term of the G.S is

t8 = [tex]ar^{n-1}[/tex]

  = [tex]8x^8 * (x^4)^8^-^1[/tex]

  = [tex]8x^8 * (x^4)^7\\[/tex]

  = [tex]8x^8 *x^2^8\\= 8x^3^6[/tex]

hope it will help

Answer:

17.3 ft

Step-by-step explanation:

To find the second leg, use the following: √c² - a². Substitute c for 28, and a for 22.

b = √28² - 22² {Square 28 to get 784, and square 22 to get 484.}

b = √784 - 484 {Subtract 484 from 784 to get 300.}

b = √300 {Find the square root of 300.}

b = 17.32051 {Round to the nearest tenth.}

b = 17.3 ft.

The bottom of the ladder will be 17.3 ft from the bottom of the building.

I hope this helps! ^w^

the answer would be 0.9583

you should add two sums to get higher equation that means he took 45 minutes last year that is

42+3=45

Answer:

Once Kenny gets 6 hats sold, he could gain the $3 he spent back, and once Ben sells 4 hats, he could gain the $1 he spent back.

Step-by-step explanation:

Answer:

the closest answer I got was A

Step-by-step explanation:

hope this helped at all

Answer:

It's B

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

okAy

Step-by-step explanation:

hypo(square) = altitude(square)+base,(square)

so hypo(square) =300(square)+400(square)

Answer:

500

Step-by-step explanation:

300² + 400² = 500²

pythagorean theorem

Answer:

x = 6

Step-by-step explanation:

3x - 6 = 12

3x = 18

x = [tex]\frac{18}{3}[/tex]

x = 6

Answer:

-6

Step-by-step explanation:

Answer:

Answer B will be the best answer for your question.

Step-by-step explanation:

Polygons usually have straight sides, but this one does not.

Answer:

Step-by-step explanation:

We can do this quite simply by using Newton's equation: forcegravity = G × M × mseparation2 .

Suppose: your mass, m, is 60 kilogram; the mass of your colleague, M, is 70 kg; your centre-to-centre separation, r, is 1 m; and G is 6.67 × 10 -11 newton square metre kilogram-2.

Answer:

30 degrees

Step-by-step explanation:

<ACB is a central angle while <ADB is an inscribed angle.

Central angles are twice the size of inscribed angles.

Therefore, <ADB*2 = <ACB . 15*2=30

Answer:

3.280

Step-by-step explanation:

You just add a 0

Answer: 4

Step-by-step explanation:

4^2=16

Answer:

4

Step-by-step explanation:

When we square something we just multiply it by itself.

2 x 2 = 4 so not 2

3 x 3 = 9 so not 3 either

4 x 4 = 16 this one is correct!

8 x 8 = 64 not this one either

So the answer is 4 BOOM

17 meters because 5^2+12^2=17 meaning the answer must be d

Answer:

yes you are right! the answer is c

Step-by-step explanation:

**reminder: the hypotnuse is always your longest side**

first do 5 square = 25

then do 12 squared = 144

now add 25+144= 169

and finally you do 169 square root which equals 13

Hope this helped!

Answer:

C.

Step-by-step explanation:

Answer:

a) X  = 2/15 , 8/15, 1/3

b) attached below ( probability plot )

C) F(x )     attached below

d) cumulative probability plot

Step-by-step explanation:

a) Determine the probability of Function X

P( x = 0 ) =  6 / 45 = 2 /15  = 0.1333

P( x = 1 )  = 8/15  = 0.5333

P( x = 2 ) = 1/3  = 0.3333

Hence the probability of Function X = 2/15 , 8/15, 1/3

b) Graph of the probability Function of X

 x           0              1               2        

p(x)    0.1333     0.5333     0.3333

attached below is the plot ( probability plot )

c) Determine the Distribution function of CX

using the results achieved in part ( a )

attached below is the solution

d) Graph of distribution function of X

x              0                  1           2

p(x)     0.1333          0.6667     1

attached below is the plot ( cumulative probability plot )

Answer:wheres the question

sadStep-by-step explanation:

sadsadsa

There is 1820 ways of teams of 4 can she make without repetition using combination formula.

What is combination?

  Selections are another name for combinations. The choice of items from a predetermined group of items corresponds to combinations. We don't want to organise anything here. We are going to choose them. We use the notation nCr to indicate how many distinct r-selections or combinations there are among a set of n objects. A combination is distinct from an arrangement or a permutation. No matter how the objects are arranged, combinations are produced by choosing some or all of them.

Here There are 16 total swim team members and 4 swimmers that will be chosen for each relay team.

So, n=16 and r=4. Then

=> nCr =  [tex]\frac{n!}{r!(n-r)!}[/tex]

=> 16C4 = [tex]\frac{16!}{4!(16-4)!}[/tex]

=> 16C4 = [tex]\frac{16!}{4!*12!}[/tex]

=> 16C4 = [tex]\frac{16*15*14*13}{4*3*2*1}[/tex]

=>16C4 = 4*5*7*13 = 1820

Hence there is 1820 ways  of teams of 4 can she make without repetition.

To learn more about combination refer the below link

https://brainly.com/question/28065038

#SPJ1

Answer:

need points

Step-by-step explanation:

Answer:

70 yd²

Step-by-step explanation:

Area of triangle = (1/2)(base)(perpendicular height)

= (1/2)(20)(7)

= 70 yd²

Answer:

NO

Step-by-step explanation:

The sum of the lengths of any two sides of a triangle is greater than the length of the third side. And this MUST true for ALL combinations

12 +8    IS NOT greater than 20

4x +2x+2 +x+3 = 40

7x +5=40

7x =3 5

x=5

side 4x  =  20

side x+3 = 8

side 2x+2 = 12

            20 +8 is bigger than 12

             20+12 is   bigger than 8

             12 + 8  IS NOT BIGGER than 20  (it's just the same)

The limit as g(x) approaches 11 doesn't exist.

[tex]\lim_{x \to 11} g(x) = DNE[/tex]

It looks like you are working with the following piecewise defined function:

[tex]g(x)=\left \{ {{-9;x<11} \atop {7;x\geq11}} \right.[/tex]

There is a rule in calculus that tells us that for a limit to exist, both lateral limits must be the same as x approaches a given value. This is:

[tex]\lim_{x \to a^{-}} f(x)=\lim_{x \to a^{+}} f(x)[/tex]

if and only if this is true, then:

[tex]\lim_{x \to a^{-}} f(x)=\lim_{x \to a^{+}} f(x)=\lim_{x \to a} f(x)[/tex]

if that condition isn't met, then the limit doesn't exist.

So let's calculate the lateral limits for this function:

[tex]\lim_{x \to 11^{-}} g(x) = -9[/tex]

This means that as x approaches 11 from the left, the function will return a value close to -9

Now, let's calculate the lateral limits for this function:

[tex]\lim_{x \to 11^{+}} g(x) = 7[/tex]

This means that as x approaches 11 from the right, the function will return a value close to 7

You can better visualize this in the graph of the function which I attached to this answer.

Notice that both lateral limits are different, from the left you got a -9 and from the right you got a 7. Therefore, according to the rule I wrote above, the limit does not exist.

For more information on this topic, you can go to the following link:

https://brainly.com/question/17334531?referrer=searchResults

Answer:

D) DNE

Step-by-step explanation:

edge 2021

Answer:

Candice

Step-by-step explanation: