Help me please because of the points

Answer:

  34.5%

Step-by-step explanation:

If we assume the relationship is approximately linear with time, we can use technology to draw a line of best fit through the given data. Extrapolating to the year 2030 predicts the value to be 34.5%.

In 2030, we might expect about 34.5% of male first-year college students to claim no religious affiliation.

_____

Additional comment

When it comes to religion, many factors are in play. The assumption we have made has no justification whatever, except that it provides a method for answering the question. (It also predicts the percentage to be 0 in 1963, which we believe to be unrealistic.) An exponential fit is better (r^2 = 0.97), and it predicts about 46.0%.

Answer:

5

Step-by-step explanation:

Since, A, B, C, D are collinear.

[tex] \implies A - B - C - D \\

\therefore \: AD = (AB + BC) + CD \\ \therefore \: 18 = AC + CD.. (\because AB + BC =AC) \\ \therefore \: 18 = 8 + CD \\ \therefore \: 18 - 8 = CD \\ \therefore \: 10 = CD \\ \\ \because \: BC + CD = BD \\ BC = BD - CD \\ BC = 15 - 10 \\ BC = 5 \\ [/tex]

Answer:

Rs.15

Step-by-step explanation:

3% = 3/100 × 500 = 15

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

3y = 5x - 1

y = 5/3x - 1/3

perpendicular slope is -3/5

Answer:

25. 8ft

26. 3m

27. 7cm

Step-by-step explanation:

Because it says each is an area of a sqare the square root will give you the side length

Answer: 6/11

Work Shown:

22 people total, 10 men, so 22-10 = 12 women are in the class.

12/22 = (2*6)/(2*11) = 6/11 is the fraction of women in the class

Answer:

I'm pretty sure the answer they want is 12/22 or 6/11 students are women although some people are not men or women which technically makes the question impossible to solve.

Answer:

The answer is "[tex]\bold{\frac{343 \ \pi}{24} \ \text{cubic units}}[/tex]"

Step-by-step explanation:

The volume of the mass whose cross-sectional area has been perpendicular is usually sliced by the method The cross-section, which is based to parallel to y-axis;  

[tex]V = \int_{a}^{b} A (x)dx[/tex]

The semi-circular segment of the strong and seems to be perpendicular to foundation and  

Y-axis parallel.  

Its cross-section does have a diameter of: [tex](7-x)[/tex].  

It also transverse radius is: [tex]\frac{1}{2}(7-x)[/tex].  

The semi-circular segment area is,

[tex]Formula: \\\\ A(x)=\frac{1}{2} \times \pi \times r^2[/tex]

        [tex]=\frac{1}{2} \times \pi \times (\frac{(7-x)}{2})^2\\\\=\frac{1}{2} \times \pi \times (\frac{(7-x)^2}{4})\\\\=\frac{1}{8}\pi(7-x)^2\\[/tex]

when

[tex]0 \leq \ x \ \leq 7[/tex]

Calculating the volume from the solid accordingly:

[tex]V= \int_{0}^{7}\frac{1}{8} \times\pi \times (7-x)^2 dx[/tex]

   [tex]= \frac{1}{8} \pi \int_{0}^{7}(7-x)^2 dx \\\\= \frac{1}{8} \pi [\frac{(7-3)^3}{-3}]_{0}^{7}\\\\= \frac{\pi}{24} \times [7^3-0]\\\\= \frac{\pi}{24} \times 343\\\\= \frac{343 \pi}{24} \\[/tex]

Answer:

a. Line

b. Plane

c. All of R^3

Step-by-step explanation:

In order to answer this question, we need to study the linear independence between the vectors :

1 - A set of three linearly independent vectors in R^3 generates R^3.

2 - A set of two linearly independent vectors in R^3 generates a plane.

3 - A set of one vector in R^3 generates a line.

The next step to answer this question is to analyze the independence between the vectors of each set. We can do this by putting the vectors into the row of a R^(3x3) matrix. Then, by working out with the matrix we will find how many linearly independent vectors the set has :

a. Let's put the vectors into the rows of a matrix :

[tex]\left[\begin{array}{ccc}-2&5&-3\\6&-15&9\\-10&25&-15\end{array}\right][/tex] ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix  ⇒

[tex]\left[\begin{array}{ccc}-2&5&-3\\0&0&0\\0&0&0\end{array}\right][/tex]

We find that the second vector is a linear combination from the first and the third one (in fact, the second vector is the first vector multiply by -3).

We also find that the third vector is a linear combination from the first and the second one (in fact, the third vector is the first vector multiply by 5).

At the end, we only have one vector in R^3 ⇒ The set of all linear combinations of the set a. is a line in R^3.

b. Again, let's put the vectors into the rows of a matrix :

[tex]\left[\begin{array}{ccc}1&2&0\\1&1&1\\4&5&3\end{array}\right][/tex] ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix ⇒

[tex]\left[\begin{array}{ccc}1&1&1\\0&1&-1\\0&0&0\end{array}\right][/tex]

We find that there are only two linearly independent vectors in the set so the set of all linear combinations of the set b. is a plane (in fact, the third vector is equivalent to the first vector plus three times the second vector).

c. Finally :

[tex]\left[\begin{array}{ccc}0&0&3\\0&1&2\\1&1&0\end{array}\right][/tex] ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix ⇒

[tex]\left[\begin{array}{ccc}1&1&0\\0&1&2\\0&0&3\end{array}\right][/tex]

The set is linearly independent so the set of all linear combination of the set c. is all of R^3.

Answer:

39. r = 13.4

40. m = 12

Step-by-step explanation:

39. Given the equation, [tex] -0.8 + r = 12.6 [/tex], to solve for r, the following are the correct steps to take to arrive at the solution:

[tex] -0.8 + r = 12.6 [/tex] (given)

Add 0.8 to both sides of the equation (addition property of equality)

[tex] -0.8 + r + 0.8 = 12.6 + 0.8 [/tex] (this is where the error occurred.)

[tex] r = 13.4 [/tex]

40. The correct steps to take in solving the equation, [tex] -\frac{m}{3} = -4 [/tex] is as follows:

[tex] -\frac{m}{3} = -4 [/tex] (given)

Multiply both sides by 3 (multiplication property of equality)

[tex] 3*-\frac{m}{3} = 3*(-4) [/tex]

[tex] -m = -12 [/tex] (this is where the error occurred. This is what we should have at this line/step)

[tex] m = 12 [/tex] (dividing both sides by -1)

Answer:

x = -3n/4

Step-by-step explanation:

Answer:

800,000

Step-by-step explanation:

The numbers are above 5 making it round up not down

Answer:

The length is 12yd and the width is 6yd.

Step-by-step explanation:

there are (1/6)/(1/3) one-third in one sixth

Step-by-step explanation:

that means

no. of one-third is 1/2

Answer:

there are 2 one third in one sixth

Answer:

Step-by-step explanation:

Change all numbers to their decimal form.

37.5 % = 37.5 / 100 = 0.375

1/3 = 0.3333

0.3 = 0.3

40% = 40/100 = 0.4

3/5 = 0.6

Order

0.3

0.33333

0.375

0.4

0.6

Answer:  t > 6/5

In decimal form, this would be t > 1.2

==============================================

Work Shown:

6t > t+6

6t-t > t+6-t ...... subtracting t from both sides

5t > 6

5t/5 > 6/5 .... dividing both sides by 5

t > 6/5

t > 1.2

Answer: He has 7 at the moment, technically, if he still has the bag, he still has all 36

Step-by-step explanation:

Answer:

he has noob 7

Step-by-step explanation:

Answer:

rational

Best of luck!

Answer:

x=(-9)

PQ=2

PR=3

Step-by-step explanation:

Answer:

11

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Answer:

$220 is the amount of simple interest you will earn

Step-by-step explanation:

I = p * r * t

Principle = $2000

Rate = 5.5% (you need to change this to a decimal by dividing by 100) or

         0.055

Time = 2 years

I = 2000 * 0.055 * 2

I = $220

Answer:

No Solution

Step-by-step explanation:

Step 1:

17 + 28 = - 5 ( 4x - 9 )

Step 2:

45 = - 20x + 45

Step 3:

- 20x = 0

Answer:

No Solution

Hope This Helps :)

Its the Right Answer on the Test. Hopes This Helps.

Thank You

Answer:

104

Step-by-step explanation:

5/8x. - - - - - - - >. 3/8x

56+x---------------> 24+x

Then solve for x

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Answer:

c

Step-by-step explanation:

They are not commutative because the domains of f(x) and g(x) are different.

The functions  [tex]f(x) = x^{3}[/tex] and [tex]g(x) = \frac{1}{x^{3} }[/tex] are not commutative because domains of f(x) and g (x) are different.

Here,

The functions are [tex]f(x) = x^{3}[/tex] and [tex]g(x) = \frac{1}{x^{3} }[/tex] and graph of the function are shown in figure.

We have to check the function are composite or not.

What is Domain of function?

The domain of a function is the set of all possible inputs for the function.

Now,

Domain of function  [tex]f(x) = x^{3}[/tex] is ( -∞, ∞).

And, Domain of function [tex]g(x) = \frac{1}{x^{3} }[/tex] is ( -∞,0 ) U ( 0, ∞).

Hence, the domain of the functions are different so they are not commutative.

So, The functions  [tex]f(x) = x^{3}[/tex] and [tex]g(x) = \frac{1}{x^{3} }[/tex] are not commutative because domains of f(x) and g (x) are different.

Learn more about the Domain of function visit:

https://brainly.com/question/9242848

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