Help me with these please

Answer:

Length of side e is 4.12

Length of side f is 4.24

The length of side f is larger than length of side e

Step-by-step explanation:

We are given two line segments e and f. We need to find lengths of both e and f and determine which is larger.

We can use distance formula to calculate lengths of line segments.

The Distance Formula is: [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Finding length of side e:

We are given points (-2,3) and (-1,-1)

here we have [tex]x_1=-2, y_1=3, x_2=-1 , y_2=-1[/tex]

Putting values in distance formula and finding length

[tex]Length \ of \ side \ e= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Length \ of \ side \ e= \sqrt{((-1)-(-2))^2+(-1-(3))^2}\\Length \ of \ side \ e= \sqrt{(-1+2)^2+(-1-3)^2}\\Length \ of \ side \ e= \sqrt{(1)^2+(-4)^2}\\Length \ of \ side \ e= \sqrt{1+16}\\Length \ of \ side \ e= \sqrt{17}\\Length \ of \ side \ e= 4.12[/tex]

So, Length of side e is 4.12

Finding length of side f:

We are given points (2,2) and (-1,-1)

here we have [tex]x_1=2, y_1=2, x_2=-1 , y_2=-1[/tex]

Putting values in distance formula and finding length

[tex]Length \ of \ side \ f= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Length \ of \ side \ f= \sqrt{((-1)-(2))^2+(-1-(2))^2}\\Length \ of \ side \ f= \sqrt{(-1-2)^2+(-1-2)^2}\\Length \ of \ side \ f= \sqrt{(-3)^2+(-3)^2}\\Length \ of \ side \ f= \sqrt{9+9}\\Length \ of \ side \ f= \sqrt{18}\\Length \ of \ side \ f= 4.24[/tex]

So, Length of side f is 4.24

The length of side f is larger than length of side e

Answer: 11.5

Step-by-step explanation:

It’s delta y over delta x so you would take any two combination of coordinates and subtract and divide. I used 57.50-23 over 5-2... this gets you 34.5 over 3. This is also equal to 11.5 :)

Answer:

x=10

Step-by-step explanation:

[tex]6x-14=46\\6x=60\\x=10[/tex]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

In the lower triangle, one of the angles of which is 45 degrees, we know:

In the triangle, the side facing the angle 45° is √2 / 2 times the hypothenuse.

Thus ;

[tex]10 = hypothenuse \times \frac{ \sqrt{2} }{2} \\ [/tex]

[tex]hypothenuse \times \frac{ \sqrt{2} }{2} = 10 \\ [/tex]

Multiply sides by 2

[tex]hypothenuse \times \sqrt{2} = 2 \times 10[/tex]

Divide sides by √2

[tex]hypothenuse = \frac{2 \times 10}{ \sqrt{2} } \\ [/tex]

[tex]hypothenuse = \frac{ \sqrt{2} \times \sqrt{2} \times 10 }{ \sqrt{2} } \\ [/tex]

[tex]hypothenuse = 10 \sqrt{2} [/tex]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

The common side of the triangles is hypothenuse for both.

[tex]hypothenuse \times \cos(60) = x[/tex]

[tex]10 \sqrt{2} \times \frac{1}{2} = x \\ [/tex]

[tex]x = \frac{2 \times 5 \sqrt{2} }{2} \\ [/tex]

[tex]x = 5 \sqrt{2} [/tex]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

The correct answer is the Third Option .

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Answer:

9/10

Step-by-step explanation:

Answer:

9/10

Step-by-step explanation:

right on EDG2020 trust me:P

Answer:

Width = 25 feet

Step-by-step explanation:

Perimeter of a rectangle = 2L + 2W

W = L - 20

P = 140

Hence,

140 = 2L + 2(L - 20)

140 = 2L + 2L - 40

Collect like terms

140 + 40 = 4L

180 = 4L

L = 180/40

L = 45 feet

Length = 45 feet

Width = L - 20 feet

=( 45 - 20) feet

= 25 feet

Answer:

A

Step-by-step explanation:

I included the steps in the picture I attached. lmk if you need me to explain more

Answer:

250

Step-by-step explanation:

Pretty much every time it asks for the abasloute value it just asks how much to get the zero on the number line. It will ALWAYS be positive. For example -5 will be 5 to get to zero on the numberline. Same thing with a positive 5.

Answer:

corresponding I believe

Step-by-step explanation:

if I'm wrong someone tell me and I'll go in the corner

Answer:

D) Alternate interior

Step-by-step explanation:

Its a bit hard to explain for me, since I did this stuff in 5th grade and now I'm in 10th.

P.S: Please mark my answer as brainliest, I need it to rank up.

Answer:

La ecuación simplificada es  [tex]a = \frac{11}{19}[/tex].

Step-by-step explanation:

Tenemos la siguiente ecuación simultánea: [tex]16\cdot a - [3\cdot a - (6-9\cdot a)] = 30\cdot a +[-(3\cdot a+2)-(a+3)][/tex]. El procedimiento consiste en destruir los paréntesis desde dentro hacia fuera, agrupar los términos semejantes y simplificar. Presentamos el proceso paso por paso:

1) [tex]16\cdot a - [3\cdot a - (6-9\cdot a)] = 30\cdot a +[-(3\cdot a+2)-(a+3)][/tex] Dado

2) [tex]16\cdot a -\{3\cdot a + (-1)\cdot [6+(-1)\cdot 9\cdot a]\} = 30\cdot a +\{(-1)\cdot (3\cdot a +2)+(-1)\cdot (a+3)\}[/tex]  [tex]-b = (-1)\cdot b[/tex]

3) [tex]16\cdot a -\{[(-1)\cdot (6)+(-1)\cdot (-1)\cdot 9\cdot a]\}= 30\cdot a +\{\left[(-1)\cdot (3\cdot a) + (-1)\cdot (2)\right] +[(-1)\cdot a +(-1)\cdot (3)] \}[/tex] Propiedad distributiva

4) [tex]16\cdot a -(-6+9\cdot a) = 30\cdot a +(-3\cdot a -2-a-3)[/tex] [tex]-b = (-1)\cdot b[/tex]/ [tex](-b)\cdot (-c) = b\cdot c[/tex]

5) [tex]16\cdot a +(-1)\cdot (-6+9\cdot a) = 30\cdot a -4\cdot a-5[/tex] Propiedad distributiva/Definiciones de adición y sustracción/[tex]-b = (-1)\cdot b[/tex]

6) [tex]16\cdot a +[(-1)\cdot (-6)+(-1)\cdot (9\cdot a)] = 26\cdot a -5[/tex] Propiedad distributiva/Definiciones de adición y sustracción/Propiedad modulativa.

7) [tex]16\cdot a +6-9\cdot a = 26\cdot a - 5[/tex]  [tex]-b = (-1)\cdot b[/tex]/ [tex](-b)\cdot (-c) = b\cdot c[/tex]

8) [tex]7\cdot a +6 = 26\cdot a - 5[/tex] Propiedad distributiva/Definiciones de adición y sustracción.

9) [tex]6+5 = 26\cdot a -7\cdot a[/tex] Compatibilidad con la adición/Definición de sustracción.

10) [tex]11 = 19\cdot a[/tex] Propiedad distributiva/Definiciones de adición y sustracción.

11) [tex]19\cdot a = 11[/tex] Simetría de la igualdad.

12) [tex]a = \frac{11}{19}[/tex] Compatibilidad con la multiplicación/Existencia del inverso multiplicativo/Propiedad modulativa/Definición de división/Resultado.

La ecuación simplificada es  [tex]a = \frac{11}{19}[/tex].

Answer:

A. 3x - 6

General Formulas and Concepts:

Pre-Alg

Step-by-step explanation:

Step 1: Define expression

3(x - 2)

Step 2: Expand

Answer:

1.78

Step-by-step explanation:

7 is repeating but i rounded to the tenths its this. also, i just divided it by three because he cuts into three parts.

1. x<=20

2. k<0

3. d<-3

4. m<=11

5. a>=3

6. 6<-5

This should help

Answer:

45.88 seconds

Step-by-step explanation:

[tex]t_1[/tex] = Time taken to sing the fist time = [tex]48.7\ \text{s}[/tex]

Time taken to sing the second time was [tex]2.9\ \text{s}[/tex] less than the first time so

[tex]t_2=t_1-2.9\\\Rightarrow t_2=48.7-2.9\\\Rightarrow t_2=45.8\ \text{s}[/tex]

Time taken to sing the third time was [tex]0.47\ \text{s}[/tex] less than the the second time

[tex]t_3=t_2-0.47\\\Rightarrow t_3=45.8-0.47\\\Rightarrow t_3=45.88\ \text{s}[/tex]

So the time it took the choir to sing the third time was 45.88 seconds.

Answer:

9 years old.

Step-by-step explanation:

Since the ages of all of these students are being represented in relation to the middle student's age then we can create formulas for each student and then apply them to the formula for the sum of their ages and solve for the middle child's age (M) like so... (oldest child's age is represented by variable O and youngest child's age is represented by variable Y)

O = M + 6

Y = M - 3

30 = (M+6) + M + (M-3)  ... combine like terms

30 = 3M + 3  ... subtract 3 from both sides

27 = 3M  ... divide both sides by 3

9 = M

Now we know that the middle child is 9 years old.

Answer:

14... since all of it is equal

Step-by-step explanation:

Answer:

Kindly check explanation

Step-by-step explanation:

Given that:

Credit card balance = $34

Amount of sandwich purchased = $40

The cost of sandwich purchased us added to the Initial credit card balance as the balance in a credit card is amount owed.

Hence it could be interpreted as though Joe has made purchases which amounts to $34 with his card before purchasing sandwich that costs $40

Hence; new card balance :

(Intial card balance + cost of sandwich)

$34 + $40 = $74

Answer:

18.75 feet

Step-by-step explanation:

Step 1

we find the length of Philip's rectangular deck in yards

The ratio of the width to the length is 4 to 5.

Philip's rectangular deck is 5 yards wide.

Hence,

Hence:

4/5 = 5/x

Cross Multiply

4x = 5 × 5

4x = 25

x = 25/4

x = 6.25 yards

The length of Philip's field = 6.25 yards

Hint: 1 yard = 3 feet.

Converting the yard to feet

1 yard = 3 feet

6.25 yards = x

Cross Multiply

x = 6.25 × 3 feet

x = 18.75 feet

Therefore, the length of Philip's field in feet = 18.75 feet

The pickup truck travels 19[tex]\frac{2}{7}[/tex] Miles in gallon.

A unit rate means a rate for one of something.

Given that a pickup truck travels 45 miles on 2[tex]\frac{1}{3}[/tex] gallons of gas,

Since there are 45 miles in 7/3 gallons

So, 45*3/7 in one gallon = 19[tex]\frac{2}{7}[/tex] Miles in one gallon

Hence, The pickup truck travels 19[tex]\frac{2}{7}[/tex] Miles in gallon.

For more references on unit rate, click;

https://brainly.com/question/11258929

#SPJ2

=================================

Work Shown:

Solve the second equation for f(b)

2f(b) = 28

f(b) = 28/2

f(b) = 14

----------

Plug in x = b and solve for b

f(x) = 3x-1

f(b) = 3b-1 ... replace every x with b

14 = 3b-1 ..... plug in f(b) = 14

3b-1 = 14

3b = 14+1

3b = 15

b = 15/3

b = 5

-----------

f(x) = 3x-1

f(2b) = 3(2b)-1 .... replace every x with 2b

f(2b) = 3(2*5)-1 .... plug in b = 5

f(2b) = 3*10-1

f(2b) = 30-1

f(2b) = 29

Answer:

60°

Step-by-step explanation:

Angle 1 is a vertical angle to 60° by the definition of a vertical angle.

Answer:

∠1 = 60°

Step-by-step explanation:

Answer:

∠ 2 = 70°

Step-by-step explanation:

110° and ∠ 1 are corresponding angles and congruent, thus

∠ 1 = 110°

∠ 1 and ∠ 2 are adjacent angles and are supplementary, thus

∠ 2 = 180° - ∠ 1 = 180° - 110° = 70°

Answer:

The function rule be 100 × x

The independent variables i.e. (2, 3, and 4) are considered to be the domain

The dependent variable (200,300,400) are considered to be the range

Step-by-step explanation:

The computation is shown below:

As we know that

1 m = 100 cm

So

2 m = 200 cm

3 m = 300 cm

4 m = 400 cm

The function rule be 100 × x

The independent variables i.e. (2, 3, and 4) are considered to be the domain

The dependent variable (200,300,400) are considered to be the range

Answer:

90 minutes

Step-by-step explanation:

In order to calculate a percentage of the minutes of video we simply need to divide the percentage by 100 and then multiply that value by the total number of minutes that the flash drive can hold. Since we are given this total number of minutes then we can simply plug it in and solve for x which represents the percentage of memory used in minutes.

x = 200 * (45 / 100)

x = 200 * 0.45

x = 90 minutes

Therefore, Kenzie has already used 90 minutes of video on the flash drive.

Answer:

6 1/2

Step-by-step explanation:

Answer:6 1/2

Step-by-step explanation: do the math search it up

Problem 4

Note the markings at the top indicate that angle y represents half the angle BAC. In other words, we need 2 copies of angle y to make up angle BAC.

So we know that angle BAC = 2y

Due to the fact that triangle ABC is isosceles, we know that base angles B and C are congruent to 47.

Focusing on triangle ABC we have

So,

A+B+C = 180 .... for any triangle, the angles always add to 180

2y+47+47 = 180

2y+94 = 180

2y = 180-94

2y = 86

y = 86/2

y = 43

Turn your attention to triangle ABD.

Here we have

We'll use the same idea as above, that all angles add to 180, to get...

A+B+D = 180

y+47+x = 180

43+47+x = 180

x+90 = 180

x = 180-90

x = 90

===================================================

Problem 5

Let x be the angle formed by the diagonal sides and the horizontal ground. This is considered the base angle because this triangle is isosceles.

We have two base angles x and the third angle up top is 34

x+x+34 = 180

2x+34 = 180

2x = 180-34

2x = 146

x = 146/2

x = 73

Answer:

D

Step-by-step explanation:

Midpoint Formula:

[tex]\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}[/tex]

[tex]\frac{3+1}{2}[/tex] ⇒ [tex]\frac{4}{2}[/tex] ⇒ [tex]2[/tex]

[tex]\frac{8+-4}{2}[/tex] ⇒ [tex]\frac{8-4}{2}[/tex] ⇒ [tex]\frac{4}{2}[/tex] ⇒[tex]2[/tex]

[tex](2,2)[/tex]